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Submitted By thusan1998
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Mark Scheme (Results)
Summer 2013
GCSE Mathematics (Linear) 1MA0
Higher (Non-Calculator) Paper 1H

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Summer 2013
Publications Code UG037223
All the material in this publication is copyright
© Pearson Education Ltd 2013

NOTES ON MARKING PRINCIPLES
1

All candidates must receive the same treatment. Examiners must mark the first candidate in exactly the same way as they mark the last.

2

Mark schemes should be applied positively. Candidates must be rewarded for what they have shown they can do rather than penalised for omissions.

3

All the marks on the mark scheme are designed to be awarded. Examiners should always award full marks if deserved, i.e if the answer matches the mark scheme. Examiners should also be prepared to award zero marks if the candidate’s response is not worthy of credit according to the mark scheme.

4

Where some judgement is required, mark schemes will provide the principles by which marks will be awarded and exemplification may be limited.

5

Crossed out work should be marked UNLESS the candidate has replaced it with an alternative response.

6

Mark schemes will indicate within the table where, and which strands of QWC, are being assessed. The strands are as follows:
i) ensure that text is legible and that spelling, punctuation and grammar are accurate so that meaning is clear
Comprehension and meaning is clear by using correct notation and labeling conventions. ii) select and use a form and style of writing appropriate to purpose and to complex subject matter
Reasoning, explanation or argument is correct and appropriately structured to convey mathematical reasoning. iii) organise information clearly and coherently, using specialist vocabulary when appropriate.
The mathematical methods and processes used are coherently and clearly organised and the appropriate mathematical vocabulary used.

7

With working
If there is a wrong answer indicated on the answer line always check the working in the body of the script (and on any diagrams), and award any marks appropriate from the mark scheme.
If working is crossed out and still legible, then it should be given any appropriate marks, as long as it has not been replaced by alternative work.
If it is clear from the working that the “correct” answer has been obtained from incorrect working, award 0 marks. Send the response to review, and discuss each of these situations with your Team Leader.
If there is no answer on the answer line then check the working for an obvious answer.
Any case of suspected misread loses A (and B) marks on that part, but can gain the M marks. Discuss each of these situations with your Team Leader.
If there is a choice of methods shown, then no marks should be awarded, unless the answer on the answer line makes clear the method that has been used.

8

Follow through marks
Follow through marks which involve a single stage calculation can be awarded without working since you can check the answer yourself, but if ambiguous do not award.
Follow through marks which involve more than one stage of calculation can only be awarded on sight of the relevant working, even if it appears obvious that there is only one way you could get the answer given.

9

Ignoring subsequent work
It is appropriate to ignore subsequent work when the additional work does not change the answer in a way that is inappropriate for the question: e.g. incorrect canceling of a fraction that would otherwise be correct
It is not appropriate to ignore subsequent work when the additional work essentially makes the answer incorrect e.g. algebra.
Transcription errors occur when candidates present a correct answer in working, and write it incorrectly on the answer line; mark the correct answer.

10

Probability
Probability answers must be given a fractions, percentages or decimals. If a candidate gives a decimal equivalent to a probability, this should be written to at least 2 decimal places (unless tenths).
Incorrect notation should lose the accuracy marks, but be awarded any implied method marks.
If a probability answer is given on the answer line using both incorrect and correct notation, award the marks.
If a probability fraction is given then cancelled incorrectly, ignore the incorrectly cancelled answer.

11

Linear equations
Full marks can be gained if the solution alone is given on the answer line, or otherwise unambiguously indicated in working
(without contradiction elsewhere). Where the correct solution only is shown substituted, but not identified as the solution, the accuracy mark is lost but any method marks can be awarded.

12

Parts of questions
Unless allowed by the mark scheme, the marks allocated to one part of the question CANNOT be awarded in another.

13

Range of answers
Unless otherwise stated, when an answer is given as a range (e.g 3.5 – 4.2) then this is inclusive of the end points (e.g 3.5, 4.2) and includes all numbers within the range (e.g 4, 4.1)

Guidance on the use of codes within this mark scheme
M1 – method mark
A1 – accuracy mark
B1 – Working mark
C1 – communication mark
QWC – quality of written communication oe – or equivalent cao – correct answer only ft – follow through sc – special case dep – dependent (on a previous mark or conclusion) indep – independent isw – ignore subsequent working

PAPER: 1MA0_1H
Question
(a)
1
(b)
2

Working

Answer
331.705

Mark
1

Notes
B1 cao

179300

1

B1 cao

24

4

M1 for 0.15 × 240 ( = 36) oe
M1 for × 240 ( = 180) oe
M1 (dep on both prev M1) for 240 – “180” – “36”
A1 cao
OR
M1 for 15(%) + 75(%) ( = 90(%))
M1 for 100(%) – “90(%)” ( = 10(%))
” × 240 oe
M1 (dep on both prev M1) for “
A1 cao
OR
M1 for 0.15 + 0.75( = 0.9) oe
M1 for “0.9” × 240( = 216) oe
M1 (dep on both prev M1) for 240
A1 cao

“216”

OR
M1 for 0.15 + 0.75( = 0.9) oe
M1 for 1 – “0.9”( = 0.1) oe
M1 (dep on both prev M1) for “0.1” × 240 oe
A1 cao

PAPER: 1MA0_1H
Question
3

Working

Answer
2| 4 7 8
3| 0 3 3 5 7 8 8
4| 1 1 2 4 4 5
Key,eg
4|1 is 4.1(kg)

Mark
3

Notes
B2 for correct ordered stem and leaf
(B1 for fully correct unordered or ordered with one error or omission) B1 (indep) for key (units not required)

(a)

6 + 3t

1

B1 for 6 + 3t

(b)

4

6x2 + 15x

2

m2 + 10m + 3m + 30

m2 + 13m + 30

2

B2 for 6x2 + 15x
(B1 for 6x2 or 15x)
M1 for all 4 terms (and no additional terms) correct with or without signs or 3 out of no more than four terms correct with signs A1 for m2 + 13m + 30

5|525
5|105
3|21
7

3×5×5×7

3

(c)

5

M1 for continual prime factorisation (at least first 2 steps correct) or first two stages of a factor tree correct
M1 for fully correct factor tree or list 3, 5, 5, 7
A1 3 × 5 × 5 × 7 or 3 × 52 × 7

PAPER: 1MA0_1H
Question
6

7

(a)

Working

Answer
7

Mark
3

(4,0) (3, 0) (3, -1) (2, -1)
(2, 2) (4, 2)

Correct position

2

B2 for correct shape in correct position
(B1 for any incorrect translation of correct shape)

Rotation
180°
(0,1)

3

B1 for rotation
B1 for 180° (ignore direction)
B1 for (0, 1)

(b)

Notes
M1 for 4 ×10 or 40 or or a correct equation
M1 for a complete and correct method
A1 cao

OR
B1 for enlargement
B1 for scale factor -1
B1 for (0, 1)
(NB: a combination of transformations gets B0)

PAPER: 1MA0_1H
Question
8

Working
20 300
0.5

Answer
12000

Mark
3

Notes
B1 for 20 or 300 used
" "
"
" or , values do not
M1 for “20” × “300” or
.
. need to be rounded
A1 for answer in the range 11200 –13200
SC B3 for 12000 with or without working

9

LCM (80, 50) = 400
Matt 400 ÷ 50 = 8
Dan 400 ÷80 = 5

OR
50 = 2 × 5 (× 5)
80 = 2 × 5 (× 2 × 2 × 2)

Matt 8
Dan 5

3

M1 lists multiples of both 80 (seconds) and 50
(seconds)
(at least 3 of each but condone errors if intention is clear, can be in minutes and seconds) or use of 400 seconds oe.
M1 (dep on M1) for a division of "LCM" by 80 or 50 or counts up “multiples”
(implied if one answer is correct or answers reversed)
A1 Matt 8 and Dan 5
SC B1 for Matt 7, Dan 4
OR
M1 for expansion of both 80 and 50 into prime factors.
M1 demonstrates that both expansions include 10 oe
A1 Matt 8 and Dan 5
SC B1 for Matt 7, Dan 4

PAPER: 1MA0_1H
Question
10

Working

Answer
1.5

Mark
4

Notes
M1 for correct expression for perimeter eg. 4 + 3x + x + 6 + 4 + 3x + x + 6 oe
M1 for forming a correct equation eg. 4 + 3x + x + 6 + 4 + 3x + x + 6= 32 oe
M1 for 8x = 12 or 12 ÷ 8
A1 for 1.5 oe
OR
M1 for correct expression for semi-perimeter eg. 4 + 3x + x + 6 oe
M1 for forming a correct equation eg. 4 + 3x + x + 6 = 16 oe
M1 for 4x = 6 or 6 ÷ 4
A1 for 1.5 oe

PAPER: 1MA0_1H
Question
Working
*11
× 60 = 75
QWC

Answer
Debbie + explanation Mark
4

Notes
M1 for reading 24 (mins) and 30 (km) or a pair of other values for Debbie
M1 for correct method to calculate speed eg. 30 ÷ 24 oe
A1 for 74 – 76 or for 1.2 – 1.3 and 1.1
C1 (dep on M2) for correct conclusion, eg Debbie is fastest from comparison of “74 – 76” with 66 (kph) or
“1.2 – 1.3” and 1.1 (km per minute)
OR
M1 for using an appropriate pair of values for Ian’s speed eg 66 and 60, 33 and 30, 11 and 10
M1 for pair of values plotted on graph
A1 for correct line drawn
C1 (dep on M2) for Debbie is fastest from comparison of gradients.
OR
M1 for reading 24 (mins) and 30 (km) or a pair other values for Debbie
M1 for Ian’s time for same distance or Ian’s distance for same time.
A1 for a pair of comparable values.
C1 (dep on M2) for Debbie is fastest from comparison of comparable values.

PAPER: 1MA0_1H
Question
Working
12
x – 2 -1 0 1 2 3 4 y 4 4.5 5 5.5 6 6.5 7

Answer y=½x+5 drawn

Mark
3

Notes
(Table of values/calculation of values)
M1 for at least 2 correct attempts to find points by substituting values of x.
M1 ft for plotting at least 2 of their points (any points plotted from their table must be plotted correctly)
A1 for correct line between x = -2 and x = 4
(No table of values)
M1 for at least 2 correct points with no more than 2 incorrect points
M1 for at least 2 correct points (and no incorrect points) plotted OR line segment of y = ½ x + 5 drawn A1 for correct line between x = -2 and x = 4
(Use of y=mx+c)
M1 for line drawn with gradient 0.5 OR line drawn with y intercept at 5
M1 for line drawn with gradient 0.5 AND line drawn with y intercept at 5
A1 For correct line between x = -2 and x = 4

*13
QWC

Yes with explanation 3

SC B2 for a correct line from x = 0 to x = 4
M1 for bearing ± 2 ° within overlay
M1 for use of scale to show arc within overlay or line drawn from C to ship’s course with measurement
C1(dep M1) for comparison leading to a suitable conclusion from a correct method

PAPER: 1MA0_1H
Question
Working
14
(a)
Line joins an empty circle at – 2 to a solid circle at 3
(b)

*Q15
QWC

2x ≥ 7

Answer diagram Mark
2

Notes

x ≥ 3.5

2

M1 for correct method to isolate variable and number terms (condone use of =, >, ≤, or <) or (x =) 3.5
A1 for x ≥ 3.5 oe as final answer

No + explanation 3

M1 for 500 × 9 × 10-3 oe
A1 for 4.5
C1 (dep M1) for correct decision based on comparison of their paper height with 4

B2 cao
(B1 for line from – 2 to 3)

OR
M1 for 4 ÷ 500 oe
A1 for 0.008
C1 (dep M1) for correct decision based on comparison of their paper thickness with 0.009
OR
M1 for 4 ÷ (9 × 10-3) oe
A1 for 444(.4...)
C1 (dep M1) for correct decision based on comparison of their number of sheets of paper with 500
16

£500

3

M1 for 70% = 350 or
M1 for
A1 cao

× 100 oe

PAPER: 1MA0_1H
Question
17

Working

Answer
1 hour 45 mins

Mark
6

Notes
M1 for method to find volume of pond, eg 1
(1.3 + 0.5) × 2 × 1 (= 1.8)
2

M1 for method to find the volume of water emptied in 30 minutes, eg 1 × 2 × 0.2 (= 0.4),
100 × 200 × 20 (= 400000)
A1 for correct rate, eg 0.8 m³/hr, 0.4 m³ in 30 minutes
M1 for correct method to find total time taken to empty the pond, eg “1.8” ÷ “0.8”
M1 for method to find extra time, eg 2 hrs 15 minutes − 30 minutes
A1 for 1.75 hours, 1 hours, 1 hour 45 mins or 105 mins
OR
M1 for method to find volume of water emptied in 30 minutes,.eg. 1 × 2 × 0.2 (= 0.4),
100 × 200 × 20 (= 400000)
M1 for method to work out rate of water loss eg. “0.4” × 2
A1 for correct rate, eg 0.8 m³/hr
M1 for correct method to work out remaining volume of water eg. (1.1 + 0.3) × 2 × 1 (= 1.4)
M1 for method to work out time, eg “1.4” ÷ “0.8”
A1 for 1.75 hours, 1 hours, 1 hour 45 mins or 105 mins
NB working could be in 3D or in 2D and in metres or cm throughout PAPER: 1MA0_1H
Question
Working
18
12x + 21y = 3
12x + 40y = 60
19y = 57 y= 3
3x + 10× 3 = 15
3x = – 15

Answer x= -5, y = 3

Mark
4

Notes
M1 for a correct process to eliminate either x or y or rearrangement of one equation leading to substitution (condone one arithmetic error)
A1 for either x = −5 or y = 3
M1 (dep) for correct substitution of their found value
A1 cao

-5, 5-1, 0.5 , 50

2

M1 for either 5-1 or 50 evaluated correctly
A1 for a fully correct list from correct working, accept original numbers or evaluated
(SC B1 for one error in position or correct list in reverse order)

Alternative method x= 3
+ 10y = 15
3 – 21y +40y = 60
19y = 57 x= 19

– 5, 0.2, 0.5, 1

PAPER: 1MA0_1H
Question
20

Working

Answer
5x2

Mark
4

Notes
M1 for 4x × 4x
M1 for (2x ×4x)/2 or (2x × x)/2 or(3x ×4x)/2
M1(dep M2) for “16 x2” – “4 x2”– “x2” – “6 x2”
A1 for 5x2
OR
M1 for
M1 for

2x ²
²

M1(dep M2) for
A1 for 5x2
21

(a)

Cf table: 4, 9, 25, 52,
57,60
cf graph

"√

" "√

"

(=



²

IQR = UQ – LQ

Correct Cf graph

3

B1 Correct cumulative frequencies (may be implied by correct heights on the grid)
M1 for at least 5 of “6 points” plotted consistently within each interval
A1 for a fully correct CF graph

172

(b)(i)
(ii)

4x ² (= √20 ² = √20 x)
2 ² (= √5 ² = √5 x)

3

B1 for 172 or read off at cf = 30 or 30.5 from a cf graph, ft provided M1 is awarded in (a)

12 - 14
M1 for readings from graph at cf = 15 or 15.25 and cf = 45or 45.75 from a cf graph with at least one of
LQ or UQ correct from graph (± ½ square).
A1ft provided M1 is awarded in (a)

PAPER: 1MA0_1H
Question
22

Working

Answer
1200 cm3

Mark
4

Notes
M1 for 10 × 2 × 2 and 15 × 2
M1 for “40” × “30”
A1 for 1200
B1 (indep) for cm3
OR
M1 for 10 × 15 or 23 or 8 indicated as scale factor
M1 for 10 × 15 × 2 × 2 × 2
A1 for 1200
B1 (indep) for cm3

4

23

5
24

4

5

12 ÷ 10 = 1.2
15 ÷ 5 = 3
13 ÷ 5 = 2.6
18 ÷ 10 = 1.8
3 ÷ 15 = 0.2

2
3

3
Histogram

3

SC B2 for 600 cm3 (B1 for 600)
M1 for (x ± 5)(x±3)
A1 for
B3 for fully correct histogram
(B2 for 4 correct blocks)
(B1 for 3 correct blocks)
(If B0, SC B1 for correct key eg 1cm2 = 2 (calls)
Or frequency ÷ class interval for at least 3 frequencies)
NB Apply the same mark scheme if a different frequency density is used.

PAPER: 1MA0_1H
Question
25
(a)

Working

Answer a = 4, b = 5

Mark
3

2

Notes

M1 for sight of (x – 4)
M1 for (x – 4)2 – 16 + 21
A1 for a = 4, b = 5
OR
M1 for x2 – 2ax + a2 + b
M1 for –2a = – 8 and a2 + b =21
A1 for a = 4, b = 5

(b)
26

(4, 5)
50 1 1
1 50 1
1 1 50

1

B1 ft

126
720

4

M1 for 3 fractions
,
and c < 8 or M1 for

,

+

M1 for

where a < 10, b < 9 or +

or 3 ×
A1 for

oe. eg.

Alternative Scheme for With Replacement
M1 for
(=
M1 for
× 3 (=
M0 A0 No further marks

(=

PAPER: 1MA0_1H
Question
27
(a)

Answer a-b Mark
1

(b)

28

Working

Notes

a+ b

3

M1 for a correct vector statement for
=) NQ + QR or (
=) NS + SR eg. (
M1 for SQ (+ QR) or QS (+ SR)
(SQ, QR, QS, SR may be written in terms of a and b)
A1 for (a b) + b oe or (b – a) + a oe

(a)

(90, 0)

1

B1 for (90, 0) (condone ( , 0))

(b)

Correct graph

1

B1 for graph through (0, 2) (90, 0) (180, -2) (270, 0)
(360, 2) professional judgement

B1 for a - b oe

Modifications to the mark scheme for Modified Large Print (MLP) papers. Only mark scheme amendments are shown where the enlargement or modification of the paper requires a change in the mark scheme. The following tolerances should be accepted on marking MLP papers, unless otherwise stated below:
Angles: ±5º
Measurements of length: ±5 mm

PAPER: 1MA0_1H
Question
Modification
3
Stem and leaf diagram:
Additional horizontal line was inserted in the diagram.

Notes
Standard mark scheme

4

MLP only: x changed to y.

Standard mark scheme

7

(a)

2cm grid – shape P moved up two squares.

Note that the original shape P is in a different position

(b)

2cm grid. No shading of shapes – x axis -2 and -4 removed as they would obscure shape

Standard mark scheme

10

Braille and MLP x changed to y.

Standard mark scheme

11

2 cm for 5 on both axes.

Change of scale

12

(b)

1.5 cm grid.

Standard mark scheme

PAPER: 1MA0_1H
Question
Modification
13
N line increased to 9 cm. Shading removed. ‘Land’ and ‘Sea’ labelled. Notes
037o changed to 040o

037 degrees was changed to 040 degrees.
14
17

2 cm spaces between numbers.

21

Model as well as diagram provided.
Braille only: 90 degrees written on diagram instead of the right angle sign.

Standard mark scheme

Frequency table: numbers changed to 5, 5, 10, 25, 10 and 5.

(b)

Standard mark scheme

Frequency numbers changed to 5, 5, 10, 25, 10, 5 (a) Cumulative frequencies 5, 10, 20, 45, 55, 60 (b) Greater tolerance needed. Median and IQR will be different to those in standard scheme. Standard mark scheme

Grid: 1.5 cm for 5 on both axes. Right axis labelled.

22

(b)

Models as well as diagram provided.

24

2cm grid both axes. In the table, the number of calls is changed to 12 14 13 20 6

27

vectors ‘a’ and ‘b’ in larger font size

28

Size of diagram enlarged. Cross at A changed to a filled-in circle Number of calls changed to 12, 14, 13, 20, 6
So frequency density will be 1.2, 2.8, 2.6, 2, 0.4 Standard mark scheme

Standard mark scheme

Further copies of this publication are available from
Edexcel Publications, Adamsway, Mansfield, Notts, NG18 4FN
Telephone 01623 467467
Fax 01623 450481
Email publication.orders@edexcel.com
Order Code UG037223 Summer 2013

For more information on Edexcel qualifications, please visit our website www.edexcel.com Pearson Education Limited. Registered company number 872828 with its registered office at Edinburgh Gate, Harlow, Essex CM20 2JE

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...Sample Exam 2 - MATH 321 Problem 1. Change the order of integration and evaluate. (a) (b) 2 0 1 0 1 (x y/2 + y)2 dxdy. + y 3 x) dxdy. 1 0 0 x 0 y 1 (x2 y 1/2 Problem 2. (a) Sketch the region for the integral f (x, y, z) dzdydx. (b) Write the integral with the integration order dxdydz. THE FUNCTION f IS NOT GIVEN, SO THAT NO EVALUATION IS REQUIRED. Problem 3. Evaluate e−x −y dxdy, where B consists of points B (x, y) satisfying x2 + y 2 ≤ 1 and y ≤ 0. − Problem 4. (a) Compute the integral of f along the path → if c − f (x, y, z) = x + y + yz and →(t) = (sin t, cos t, t), 0 ≤ t ≤ 2π. c → − → − → − (b) Find the work done by the force F (x, y) = (x2 − y 2 ) i + 2xy j in moving a particle counterclockwise around the square with corners (0, 0), (a, 0), (a, a), (0, a), a > 0. Problem 5. (a) Compute the integral of z 2 over the surface of the unit sphere. → → − − → − → − − F · d S , where F (x, y, z) = (x, y, −y) and S is → (b) Calculate S the cylindrical surface defined by x2 + y 2 = 1, 0 ≤ z ≤ 1, with normal pointing out of the cylinder. → − Problem 6. Let S be an oriented surface and C a closed curve → − bounding S . Verify the equality → − → − → → − − ( × F ) · dS = F ·ds − → → − if F is a gradient field. S C 2 2 1...

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...say whether I was able to learn how to be a better teacher and what the teacher did that I could possibly use in the future. While analyzing and going through the process of this assignment it is helping realize how to become a better teacher as well. I would also like to get more comfortable and experience on using this template of the paper. Memories Of A Teacher My teacher, Mr. G, used many different instructional techniques and approaches to his lessons. Mr. G had taught me math for three years in a row, so I think that I have a good grasp on his approaches to the lessons that he would teach. He would assign many homework assignments, as well as in-class assignments, which helped me and other students understand and get practice with the lesson that we were learning. I think that with math having a lot of homework is a good thing. In my mind, the only way to learn how to do math is plenty of practice. The more you practice, the easier it will be. Mr. G would also have the students do some math problems on the chalk board or smart board to show the class and go over the corrections with the whole class so that everyone would understand the problem. Playing “racing” games also helped and added fun to the class. With the “racing” games, the students would get into groups and have to take...

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...STAT2011 Statistical Models sydney.edu.au/science/maths/stat2011 Semester 1, 2014 Computer Exercise Weeks 1 Due by the end of your week 2 session Last compiled: March 11, 2014 Username: mac 1. Below appears the code to generate a single sample of size 4000 from the population {1, 2, 3, 4, 5, 6}. form it into a 1000-by-4 matrix and then find the minimum of each row: > rolls1 table(rolls1) rolls1 1 2 3 4 5 6 703 625 679 662 672 659 2. Next we form this 4000-long vector into a 1000-by-4 matrix: > four.rolls=matrix(rolls1,ncol=4,nrow=1000) 3. Next we find the minimum of each row: > min.roll=apply(four.rolls,1,min) 4. Finally we count how many times the minimum of the 4 rolls was a 1: > sum(min.roll==1) [1] 549 5. (a) First simulate 48,000 rolls: > rolls2=sample(x=c(1,2,3,4,5,6),size=48000,replace=TRUE) > table(rolls2) rolls2 1 2 3 4 5 6 8166 8027 8068 7868 7912 7959 (b) Next we form this into a 2-column matrix (thus with 24,000 rows): > two.rolls=matrix(rolls2,nrow=24000,ncol=2) (c) Here we compute the sum of each (2-roll) row: > sum.rolls=apply(two.rolls,1,sum) > table(sum.rolls) sum.rolls 2 3 4 5 6 7 8 9 10 11 742 1339 2006 2570 3409 4013 3423 2651 1913 1291 1 12 643 Note table() gives us the frequency table for the 24,000 row sums. (d) Next we form the vector of sums into a 24-row matrix (thus with 1,000 columns): > twodozen=matrix(sum.rolls,nrow=24,ncol=1000,byrow=TRUE) (e) To find the 1,000 column minima use > min.pair=apply(twodozen,2,min) (f) Finally compute the...

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...Jasmine Petersen Dr. Abdeljabbar MAT 1111 April 23, 2014 Algebra is one of the most important subjects someone can learn. It is a subject that transfers into daily life. A lot of people do not realize that they are using algebra. Algebra can be anything from calculating the amount of money you’ve spent on your grocery shopping, designing structural plans for a building, and keeping track of the calories you have in your diet. Our professor told us that in every subject, we use math. My major is chemistry and mathematics is used widely in chemistry as well as all other sciences. Mathematical calculations are absolutely necessary to explore important concepts in chemistry. You’ll need to convert things from one unit to another. For example, you need to convert 12 inches to feet. Also, we use simple arithmetic to balance equations. A lot of things I’ve had learned from this course and one of them was that we use Math for everyday life. I’ve also learned many ways how to solve equations such as linear, quadratic, exponential, and logarithmic equations. All the material that we did learn was all easy to learn and understand. I believe that the instructor did a good job explaining on how to solve problems. If my friend was asking me how to determine the differences between the equation of the ellipse and the equation of the hyperbola, I would first give he or she the definition of the two words ellipse and hyperbola. An ellipse is a set of all points in a plane such that the sum...

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...Math is used everyday – adding the cost of the groceries before checkout, totaling up the monthly bills, estimating the distance and time a car ride is to a place a person has not been. The problems worked this week have showed how math works in the real world. This paper will show how two math problems from chapter five real world applications numbers 35 and 37 worked out. Number 35 A person hired a firm to build a CB radio tower. The firm charges $100 for labor for the first 10 feet. After that, the cost of labor for each succeeding 10 feet is $25 more than the preceding 10 feet. That is, the nest 10 feet will cost $125; the next 10 feet will cost $150, etc. How much will it cost to build a 90-foot tower? Solving this problem involves the arithmetic sequence. The arithmetic sequence is a sequence of numbers in which each succeeding term differs from the preceding term by the same amount (Bluman, 2011). n = number of terms altogether n = 9 d = the common differences d = 25 ª1 = first term ª1 = 100 ªn = last term ª2 = ª9 The formula used to solve this problem came from the book page 222. ªn = ª1 + (n -1)d ª9 = 100 + (9-1)25 ª9 = 100 + (8)25 ...

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...A | Course Title & Number | Calculus II: MTH104 | B | Pre/Co-requisite(s) | Pre-requisite: MTH103 (Calculus I) | C | Number of credits | 3 | D | Faculty Name | Dr. Ghada Alobaidi | E | Term/ Year | Fall 2014 | F | Sections | Course | Days | Time | Location | MTH104.02 MTH104.04MTH104.06 | UTR UTRMW | 9:00-9:50 10:00-10:50 8:00-9:15 | PHY 113NAB 007NAB010 | | | | | | G | Instructor Information | Instructor | Office | Telephone | Email | Ghada Alobaidi | NAB 249 | 06 515 2754 | galobaidi@aus.edu | Office Hours: UT: 11:00 – 12:30 , R: 11:00 – 12:00 or by appointment. | H | Course Description from Catalog | Covers techniques of integration, improper integrals, sequences, infinite series, power series, parameterized curves, polar coordinates, integration in polar coordinates and complex numbers. | I | Course Learning Outcomes | Upon completion of the course, students will be able to: * Read, analyze, and apply to problems, written material related to the study of calculus. * Use the appropriate technique(s) – including integration by parts, trigonometric substitutions, partial fractions, etc. to integrate algebraic, logarithmic, exponential, trigonometric, and composite functions. * Evaluate improper integrals and test them for convergence. * Compute arc length and surface area of revolution of graphs and parametric curves. * Graph polar curves and find enclosed area and arc length. * Apply theorems about limits of...

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...you come to geometry, your opinion may vary. This class introduces a lot of new topics, which can be challenging, and take lots of practice outside of school if you do not pay attention or do your math homework. I strongly advise you to do your math homework everyday, not for just a grade, but it also helps you when it comes time for quizzes and tests. She rarely checks homework, but when she does, she will not tell you. It is also a great review for tests and quizzes. Ms.Hull’s tests and quizzes are not the easiest things you will take. The quizzes take new concepts and apply to the quiz. Also, her tests are usually always hard. It is a good idea to practice new concepts and review old ones from previous units, so you can get a good grade on the tests. I also advise you to be organized throughout the year. Organization is the key to success especially in math class. Tool kits are an extremely helpful resource to use. There are going to be a lot of conjectures and theorems that will be new, and it would be hard to just memorize them. My overall geometry year was not exactly the way I hoped it would turn out. It was extremely had, and it moves at a very quick pace, so keeping up was hard for me personally. If I could have done something differently, it would have been practicing math more often. Each concept was hard, and I did not have anytime to review it, because I have a lot of honors classes which require a lot of work too. The key to being successful in this course...

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...|7|SURVEY OF MATHEMATICS FALL 2015 | |8| | |8| | |8| | |8| | | |  | | |Instructor  | | |Gary F. Melendy | | | | | |Title  | | |Instructor ...

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...Math 1P05 Assignment #1 Due: September 26 Questions 3, 4, 6, 7, 11 and 12 require some Maple work. 1. Solve the following inequalities: a) b) c) 2. Appendix D #72 3. Consider the functions and . a) Use a Maple graph to estimate the largest value of at which the graphs intersect. Hand in a graph that clearly shows this intersection. b) Use Maple to help you find all solutions of the equation. 4. Consider the function. a) Find the domain of. b) Find and its domain. What is the range of? c) To check your result in b), plot and the line on the same set of axes. (Hint: To get a nice graph, choose a plotting range for bothand.) Be sure to label each curve. 5. Section 1.6 #62 6. Section 2.1 #4. In d), use Maple to plot the curve and the tangent line. Draw the secant lines by hand on your Maple graph. 7. Section 2.2 #24. Use Maple to plot the function. 8. Section 2.2 #36 9. Section 2.3 #14 10. Section 2.3 #26 11. Section 2.3 #34 12. Section 2.3 #36 Recommended Problems Appendix A all odd-numbered exercises 1-37, 47-55 Appendix B all odd-numbered exercises 21-35 Appendix D all odd-numbered exercises 23-33, 65-71 Section 1.5 #19, 21 Section 1.6 all odd-numbered exercises 15-25, 35-41, 51, 53 Section 2.1 #3, 5, 7 Section 2.2 all odd-numbered exercises 5-9, 15-25, 29-37 Section 2.3 all odd-numbered exercises...

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...find the national average cost of food for an individual, as well as for a family of 4 for a given month. http://www.cnpp.usda.gov/sites/default/files/usda_food_plans_cost_of_food/CostofFoodJan2012.pdf 5. Find a website for your local city government. http://www.usa.gov/Agencies/Local.shtml 6. Find the website for your favorite sports team (state what that team is as well by the link). http://blackhawks.nhl.com/ (Chicago Blackhawks) 7. Many of us do not realize how often we use math in our daily lives. Many of us believe that math is learned in classes, and often forgotten, as we do not practice it in the real world. Truth is, we actually use math every day, all of the time. Math is used everywhere, in each of our lives. Math does not always need to be thought of as rocket science. Math is such a large part of our lives, we do not even notice we are computing problems in our lives! For example, if one were interested in baking, one must understand that math is involved. One may ask, “How is math involved with cooking?” Fractions are needed to bake an item. A real world problem for baking could be as such: Heena is baking a cake that requires two and one-half cups of flour. Heena poured four and one-sixth cups of flour into a bowl. How much flour should Heena take out of the bowl? In this scenario of a real world problem, we have fractions, and subtraction of fractions, since Heena has added four and one-sixth cups of flour, rather than the needed...

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... h(x)= 7-x/3 First we need to compute (f-h)(4) (f*h)(4)=f(4)-h(4), each function can be done separately f(4)=2(4)+5 f(4)=8+5 f(4)=13 H h(4)=(7-4)/3 same process as above h(4)=3/3=h(4)=1 (f-h)(4)=13-1 (f-h)(4)=12 this is the solution after substituting and subtracting The next part we need to replace the x in the f function with the g (f*g)(x)=f(g(x)) (f*g)(x)=f(x2-3) (f*g)(x)=2x2-1 is the result Now we need to do the h function (h*g)(x)=h(g(x)) (h*g)(x)=h(x2-3) (h*g)(x)=7-(x2-3) (h*g)(x)=10-x2 end result The inverse function-- f-1(x)=x-5h-1(x)=-(3-7) By doing problems this way it can save a person and a business a lot of time. A lot of people think they don't need math everyday throughout their life, but in all reality people use math almost everyday in life. The more you know the better off your life will...

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