Free Essay

11111

In:

Submitted By ashaila
Words 1506
Pages 7
Exercise (18-33)
18.n=610 ;P̂x =50.7=.507
1­α =.99 α=.01, α/2=.005 , 1­α/2 =.995 100(1- α) % C.I for P̂x is given by: P̂x-Z α/2√ P̂(1-P̂x)n <Px <P̂x + Z α/2√ P̂(1-P̂x)n
=.507-2.575√.507(1-.507)610<Px <.507+2.575√.507(1-.507)610
=.4548< Px < .5591
19(a). n=189 ;X=132; P̂x =xn=132189=.6984
1­α =.90 α=.10, α/2=.05 , 1­α/2 =.95 100(1- α) % C.I for P̂x is given by: P̂x-Z α/2√ P̂(1-P̂x)n <Px <P̂x + Z α/2√ P̂(1-P̂x)n
=.6984-1.645√.6984(1-.6984)189<Px <.6984+1.645√.6984(1-.6984)189
=.6436< Px < .7533
(b)Wider
20. n=323; P̂x =.479
100(1- α) % C.I for P̂x is given by:
P̂x-Z α/2√ P̂(1-P̂x)n <Px <P̂x + Z α/2√ P̂(1-P̂x)n
P̂x-Z α/2√ P̂(1-P̂x)n =.458
=>.479--Z α/2 √ .479(1-.479)323 =.458
=> Z α/2 .24955323 =.479-.458
=> Z α/2 *0.027796 =0.021
=> Z α/2 =.755
=>P( Z <α/2) =.755
=>1- P( Z >α/2) =.755
=> P( Z >α/2) =1-.755
=> P( Z >α/2 ) =.245
=> α/2 =.245
=> α =.49
=>1- α =1-.49
=>1- α =.51
21. n=134; x=82 P̂x =Xn=82134=.6119
1­α =.95 α=.05, α/2=.025 , 1­α/2 =.975
100(1- α) % C.I for P̂x is given by:
P̂x-Z α/2√ P̂(1-P̂x)n <Px <P̂x + Z α/2√ P̂(1-P̂x)n
=.6119-1.96√.6119*.3881134 <Px<.6119+1.96√.6119*.3881134
=.5294 <Px<.6944
22.(a) n=95 ;X=29; P̂x =xn=2995=.3052
1­α =.99 α=.01, α/2=.005 , 1­α/2 =.995 100(1- α) % C.I for P̂x is given by: P̂x-Z α/2√ P̂(1-P̂x)n <Px <P̂x + Z α/2√ P̂(1-P̂x)n
=.3052-2.575√.3052(1-.3052)95<Px <.3052+2.575√.3052(1-.3052)95
=.183< Px < .426
(b) Narrower
23. n=96 ;X=32; P̂x =xn=3296=.3333
1­α =.80 α=.20, α/2=.10 , 1­α/2 =.90 100(1- α) % C.I for P̂x is given by: P̂x-Z α/2√ P̂(1-P̂x)n <Px <P̂x + Z α/2√ P̂(1-P̂x)n
=.3333-1.285√.3333(1-.3333)96<Px <.3333+1.285√.3333(1-.3333)96
=.2714< Px < .3951
24. n=198; X=98 P̂x =98198=.4949
100(1- α) % C.I for P̂x is given by:
P̂x-Z α/2√ P̂(1-P̂x)n <Px <P̂x + Z α/2√ P̂(1-P̂x)n
P̂x-Z α/2√ P̂(1-P̂x)n =.445
=>.4949--Z α/2 √ .4949(1-.4949)198 =.445
=> Z α/2 .4949*.506198 =.4949-.445
=> Z α/2 *0.0355 =0.0499
=> Z α/2 =1.40
=>P( Z <α/2) =.9192
=>1- P( Z >α/2) =.9192
=> P( Z >α/2) =1-.9192
=> P( Z >α/2 ) =.0808
=> α/2 =.0808*2
=> α =.1616
=>1- α =1-.1616
=>1- α =.8384
25.n=15; Sx=.880;V=n-1=15-1=14
1­α =.95 α=.05, α/2=.025 , 1­α/2 =.975 sx(n-1)Xv,α/2<σx< sx(n-1)Xv,1-α/2
=.880(15-1)X14,.025 <σx< .880(15-1)X14,.975
=.7744*1426.12 <σx<.7744*145.63
=.4150 <σx< 1.925
26.n=7;V=6
∑Xi=79+73+68+77+86+71+69=523
X̅=∑Xin=5237=74.714
∑Xi=79+73+68+77+86+71+69 =39321
Sx=∑Xi-nx̅n-1=39321-7*(74.714)6=40.954
1­α =.80 α=.20, α/2=.10 , 1­α/2 =.90
100(1- α) % C.I for σx is given by: sx(n-1)Xv,α/2<σx< sx(n-1)Xv,1-α/2 =40.954(7-1)X6,.10 <σx< 40.954(7-1)X6,.90
=245.72410.64 <σx< 245.7242.20
=23.09 <σx< 111.692

2.(a) δx=.12 ; n= 16; X̅̅= 4.07 ; 1­α =.99 1­α =.99
99 % C.I for µx is given by: α=.01
X̅ - Z α/2 δx/n< µx < X̅ + - Z α/2 δx/n α/2=.005
=4.07-(2.57)*.12/√16< µx < 4.07+ (2.57)*.12/16 1­α/2 =.995
=3.992< µx < 4.147
(b) Narrower
(c) ) Narrower
(d) Wider
3. .(a) δx=3.8 ; n= 9; 1­α =.90; µx=?
1­α =.99, α=.01, α/2=.005 , 1­α/2 =.995
Xi=18.2+13.7+15.9+17.4+21.8+16.6+12.3+18.8+16.2=150.9
X̅ = 150.9/9=16.77
90 % C.I for µx is given by:
X̅ - Z α/2 δx/n< µx < X̅ + - Z α/2 δx/n
=16.77-(1.645)*3.8/√9< µx < 16.77+(1.645)*3.8/√9
=14.686< µx < 18.854
(b) Wider
4.(a) δx=32.4 ; n= 9; X̅=187.9; 1­α =.80; µx=?
1­α =.80 α=.20, α/2=.10 , 1­α/2 =.90
80 % C.I for µx is given by:
X̅ - Z α/2 δx/n< µx < X̅ + - Z α/2 δx/n
=187.9-(1.28)*32.4/√9< µx < 187.9+(1.28)*32.4/√9
=174.07< µx < 201.724

5.(a) Sx=1.57 ; n= 1562; X̅=3.92; 1­α =.95; µx=?
1­α =.95 α=.05, α/2=.025 , 1­α/2 =.90
95 % C.I for µx is given by:
X̅ - Z α/2 sx/n< µx < X̅ + - Z α/2 sx/n
=3.92-(1.96)*1.57/√1562< µx < 3.92+(1.96)*1.57/√1562
=3.842< µx < 3.997
6.(a) Sx=1.34 ; n= 541; X̅=3.81; 1­α =.90; µx=?
1­α =.90 α=.10, α/2=.05 , 1­α/2 =.95
90 % C.I for µx is given by:
X̅ - Z α/2 sx/n< µx < X̅ + - Z α/2 sx/n
=3.81-(1.645)*1.34/√541< µx < 3.81+(1.645)*1.34/√541
=3.72< µx < 3.90
(b) narrower

7. ) Sx=1.045 ; n= 457; X̅=3.59; 3.49< µx < 3.69 1­α =?
100(1- α ) % C.I for µx is given by: X̅ - Z α/2 sx/n< µx < X̅ + - Z α/2 sx/n
=3.59- Z α/2 *1.045/√457< µx < 3.59 + Z α/2 *1.045/√457
3.59- Z α/2 *1.045457=3.49 3 .59 + Z α/2 *1.045/457= 3.69
3.59- Z α/2 *1.045457=3.49
=>- Z α/2 *1.045457=3.59-3.49
=> Z α/2 *1.045=.1*457
=> Z α/2=2.1377/1.045
=> Fz (Z α/2)=Fz(2.045)
=>P(z< α/2)=0.97955
=>1-p(z> α/2)= 0.97955
=> p(z> α/2)=1-0.97955
=> p(z> α/2)=0.02045
=> α/2=0.02045
=> α=0.02045*2
=> α=0.0409
=>1­α =1-0.0409
=>1­α =0.9591 8. Sx=11.28 ; n= 352; X̅=60.41; 1­α =.90; µx=?
1­α =.90 α=.10, α/2=.05 , 1­α/2 =.95
90 % C.I for µx is given by:
X̅ - Z α/2 sx/n< µx < X̅ + - Z α/2 sx/n
=60.41-(1.645)*11.28/√352< µx < 60.41+(1.645)*11.28/√352
=59.42< µx < 61.399

10. Sx=38.89 ; n= 9; X̅=157.82; 1­α =.95;V=n-1=9-1=8; µx=?
1­α =.95 α=.05, α/2=.025
90 % C.I for µx is given by:
X̅ - tv, α/2 sx/n< µx < X̅ + - tv, α/2 sx/n
=157.82-(2.306)*38.89/√9< µx < 157.82+(2.306)*38.89/√9
=127.92< µx < 187.71

Similar Documents

Free Essay

11111

...I chose my first event, when I was born because well, it’s an obvious one. It was the start of my life, what lead me to all the other events on the timeline. The second one, my first birthday was my first birthday ever. The first one is a special one because I will and already did have many birthdays after that. My third event, when I started pre-school, it was the start of my school days. Each year after that until I’m 18, I would have to be in school. It was the beginning of something big. For the fourth one, when I went into elementary school, it was just the start of something new. I was in there for 6 years of my life. I picked my fifth event, my 7th birthday because it was my biggest party ever. It was at at Boomers and celebrated with many people. My next event, First Communion is definitely an important event. In my religion, I receive Jesus in me through the holy bread. The seventh event, I won 1st place in my elementary school in a poetry contest for Buono’s Pizzeria. I was very shocked, but also happy. I never thought I would win it. For my eighth event, it was when I turned 10. I was finally a double digit. My most memorable one today, is my ninth one, the day I entered Mary Butler Middle School. I have learned so much and am still experiencing it today. The most recent one is of course, the tenth one, the day I got my first very own dog. I have been wanting one for so long and finally got one. She is a Maltese/mix and is named Raquelle. The event that represents...

Words: 519 - Pages: 3

Premium Essay

11111

...MBAC 5101 BUSINESS AND COMMUNITY DEVELOPMENT **THREE ASSIGNMENTS** Assignment ONE: In groups of two people. Deadline: This assignment must be received by no later than Thursday November 1, 2012, at 7pm at the following email address: jasonprinceCBU@gmail.com. Late assignments will be severely penalised. Grade: This assignment is worth 10% of your mark. Description: On one page single-spaced, 12 point Times New Roman, summarize the main point or points of each section for a business plans, in your own words. Be concise. Feel free to use bullets. You can find examples of real business plans in The Business Plans Handbook, copies of which have been put on RESERVE in the CBU Library (call number: HG 4027.6 B865 5 1998 (also 1994 and 1997). Do NOT use the Internet to locate a business plan. In my experience, the ones you will be able to easily find there are of very poor quality. One of you (you decide) must be prepared to deliver a three minute statement—the ‘elevator pitch’—on this business, as if you were the general manager or president of the organisation. I expect you to prepare and practice this together as a team. Remember: bring to class on Friday morning, November 2nd:    Your copies of both business plans (the one I give you and the one you have photocopied from the Business Plans Handbook). The one-page written summary of the business plan you are going to present in three minutes An enthusiastic three-minute ‘elevator pitch’ for your business (one of you should...

Words: 859 - Pages: 4

Premium Essay

11111

...LVMH: Diversification Strategy into Luxury Goods Strategic Issues By 2002, Moet Hennessy Louis Vuitton was the world's largest luxury products company, enjoying annual sales of 12.2 billion euros. LVMH carries the most prestigious brand names in wine, champagne, fashion, jewelry, and perfume. Upon entrance of this luxury product industry, LVMH was aware that they produced products that nobody needed, but that were desired by millions across the world. This desire in some way fulfills a fantasy, making consumers feel as though they must buy it, or else they will not be in the moment, and thus will be left behind. The LVMH business portfolio began to take shape in 1987 with the merger between Louis Vuitton and Moet Hennessy which was a four billion dollar merger. Over the course of time, LVMH has acquired over 50 luxury brands, such as Donna Karen, Fendi, and Sephora. They called it, "a collection of star brands and rising stars." LVMH found this industry to be timeless and modern, highly profitable, and very rapid growing. Despite all of the above mentioned, LVMH did experience some bumpy times. Some of these times were induced through internal problems, while others were caused by externalities, like Sept. 11. With such a wide range of product offerings, LVMH was on top of the industry in certain aspects, but has room for growth in other areas. One instance in particular nearly caused a division in the company. Hennessy believed the company should focus on wine, spirits...

Words: 2062 - Pages: 9

Premium Essay

11111

...[pic] Management Accounting and Decisions 3 (P13414) MODULE OUTLINE Semester 1 Year 2013/2014 Teaching Staff: |Staff |Room |Telephone |Email | |Andrew Edwards |AB479 |88180513 |andrew.edwards@nottingham.edu.cn | |Anna Du |AB482 |88182467 |min du@nottingham.edu.cn | CREDITS AND LEVEL 10 credits, level 3 PRE-REQUISITES AND PRIOR LEARNING Pre-requisites are MAD I and MAD II. This module assumes that you have good understanding of core management accounting techniques and concepts as taught in MAD I and MAD II. In addition, you will be expected to recall the basic principles of how to do analysis as taught in Year 2 and 3 of your degree course, but to a higher level this year. Knowledge should include the ability to both critically describe techniques and also apply numerical analysis to scenario based problems. EDUCATION AIMS The principle aim of this module is to critically review current management accounting theory and practice by reference to up to date research monographs/reports and academic papers. The secondary, related aim is to enrich students' understanding of management accounting techniques by enabling them to evaluate how such...

Words: 1270 - Pages: 6

Premium Essay

11111

...No Child Left Behind | A government attempt to fix American Education | Erica Cowan | Abstract Despite the vast majority of Americans that are educated though public school systems very successfully, many student of minority or low-income backgrounds have been “left behind.” The No Child Left Behind Act (NCLB), was the Bush administration’s attempt to help ensure that every public school student had a right to a solid education. A main goal was to have every school achieve higher scores on standardized testing each year and eventually by 2014 every student should score proficiently on their tests. Funding for NCLB was supposed to cover all the added costs that the schools would occur, but the funding ran out and schools are running out of resources to help their students. The No Child Left Behind Act of 2001 was created to ensure that all student were given a fair opportunity to receive a good education from the public school systems. Before 2001, there was a large performance gap between students with a higher economic advantage and those students with less wealth. There was also a pattern of minority groups achieving less than white students in specific areas of school. “‘[W]e understand now that there are some basic tools that have to be put in place so that we give those children who are among the most disadvantaged in our country, who go to school in some of the poorer schools that they, in fact, get a very real opportunity in education,’ Rep. George Miller of California...

Words: 333 - Pages: 2

Premium Essay

11111

...Strategic Analysis of Nestlé and its Competitor Kraft Foods Course: International Business Strategy (IB BA) Professor Lewis University of Applied Sciences Dresden Project Members: Katerina Schneiderova Sandra Merkel Nicole Klötzer Carolin Wiese Samuel Weimer Nicole Schröder Date: 11th June 2010 Executive Summary In the following, two companies and their strategic positions within the coffee consumer goods industry will be described. The focus lies on Nestlé and its competitor Kraft Foods. As coffee is one of the most popular products worldwide, this is a very demanding business. It is necessary to provide high quality products, especially when working in the more affluent segments like Nestlé and Kraft Food do. Several political, economic, social, technical, environmental and legal aspects have an impact on the industry branch they are operating in. In addition, there is not only a differentiation in Robusta and Arabica coffee, but also in filter coffee, portioned and non-portioned soluble coffee. To satisfy the diverging needs of all customers, different strategies are applied to gain more market share. In this report it is examined how those companies operate in the specific business context, what they have in common and where they differ. Furthermore, an analysis of the industry attractiveness, of the market segmentation and value chain and an overview of resources and capabilities are part of this paper. After intense research...

Words: 11935 - Pages: 48

Premium Essay

11111

...PROFESSIONAL AGRI SELLING Krannert Building Dr. Scott Downey, Assistant Professor Amy Cochran, Academic Coordinator Phone: (765) 494-0589 Spring 2015 Dear AGEC 331 Students: We are pleased that you have enrolled in our Professional Selling course. During this semester we will be examining many of the facets of professional selling and learning some of the skills that have proven to be highly useful whether you choose to become a professional salesperson or enter any other professional area. Almost every professional area will require you to sell yourself and your ideas to others. The background of this course in professional selling originates in agribusiness. While historically this area of selling was highly specialized, today’s agribusinesses share much in common with other business to business or technical selling situations. These same tools and techniques have proven highly useful in manufacturing, consumer product sales, pharmaceuticals, technical science industries, etc. AGEC 331 relies heavily on experiential learning. Special class projects are designed to involve you in the learning process through participation and many exercises that represent the "real world." Notes are provided to facilitate participation in the class, though lectures may emphasize particular points or examples to illustrate specific sections. While the concepts in the course are not particularly difficult to understand, their application and the depth of detail required may...

Words: 3150 - Pages: 13

Free Essay

11111

...新无忧健康保障计划 男性,26周岁,年缴9510元,缴费20年。 * 保障利益: 1. 重大疾病保障: 20种重疾一次性赔付30万元+增额红利对应的现金价值 2. 生命关爱金: 终末期疾病(无法医治,未来半年面临死亡的疾病)30万元 3. 身故保险金: 30万元+增额红利 * 其他利益: 1. 保单贷款:现金价值的90%,半年为期,到期无需返还本金可延期贷款。 2. 年金转换: 1) 赔付的保险金可以转换成年金分期增额领取 2) 20年以后,可以根据当时的现金价值转换成年金一次性或者分期,增额领取。 被保险人年末年龄 | 累计保险费 | 非保证利益(含高档红利) | | | 当年度红利 | 累积年度红利 | 身故保险金 | 重大疾病保险金/生命关爱保险金 | 累积年度红利对应现金价值 | 年末退保金 | 27 | 9,510.00 | 801 | 801 | 300,048.00 | 300,000.00 | 0 | 1,610.54 | 28 | 19,020.00 | 1,587.00 | 2,388.00 | 300,900.00 | 300,000.00 | 110.54 | 5,141.48 | 29 | 28,530.00 | 2,391.00 | 4,779.00 | 302,541.00 | 300,000.00 | 341.48 | 9,112.07 | 30 | 38,040.00 | 3,213.00 | 7,992.00 | 304,986.00 | 300,000.00 | 712.07 | 13,238.76 | 31 | 47,550.00 | 4,056.00 | 12,048.00 | 308,262.00 | 300,000.00 | 1,238.76 | 18,139.73 | 32 | 57,060.00 | 4,920.00 | 16,968.00 | 312,381.00 | 300,000.00 | 1,939.73 | 23,583.62 | 33 | 66,570.00 | 5,802.00 | 22,770.00 | 317,370.00 | 300,000.00 | 2,850.62 | 29,286.75 | 34 | 76,080.00 | 6,711.00 | 29,481.00 | 323,247.00 | 300,000.00 | 3,984.75 | 35,542.54 | 35 | 85,590.00 | 7,641.00 | 37,122.00 | 330,036.00 | 300,000.00 | 5,365.54 | 42,371.06 | 36 | 95,100.00 | 8,598.00 | 45,720.00 | 337,761.00 | 300,000.00 | 7,016.06 | 49,800.12 | 37 | 104,610.00 | 9,582.00 | 55,302.00 | 346,449.00 | 300,000.00 | 8,961.12 | 57,910.61 | 38 | 114,120.00 | 10,596.00 | 65,898.00 | 356,127.00 | 300,000.00 | 11,281.61 | 66,695.38 | 39 | 123,630.00 | 11,640...

Words: 1913 - Pages: 8

Free Essay

11111福音信

...为何人类没有幸福? 1. 因为人类背离了神。 (1) 不顺从—不认识神(约10:10,罗3:23) 盗贼来、无非要偷窃、杀害、毁坏。我来了、是要叫人得生命、并且得的更丰盛。(约10:10) 因为世人都犯了罪、亏缺了神的荣耀。(罗3:23) (2) 结果—陷在罪中 (罗3:10) 就如经上所记、没有义人、连一个也没有。(罗3:10) (3) 陷入痛苦之中 1) 精神上的痛苦(太11:28) 凡劳苦担重担的人、可以到我这里来、我就使你们得安息。(太11:28) 2) 没有意义,没有规律的生活 (太12:25) 耶稣知道他们的意念、就对他们说、凡一国自相分争、就成为荒场、一城一家自相分争、必站立不住。(太12:25) 3) 被肉身的病折磨 (徒8:7-8,太8:16-17) 因为有许多人被污鬼附着、那些鬼大声呼叫、从他们身上出来。还有许多瘫痪的、瘸腿的、都得了医治。 在那城里、就大有欢喜。(徒8:7-8) 到了晚上、有人带着许多被鬼附的、来到耶稣面前、他只用一句话、就把鬼都赶出去。并且治好了一切有病的人。 这是要应验先知以赛亚的话、说、他代替我们的软弱、担当我们的疾病。(太8:16-17) 4) 原因—属灵的问题 (4) 为了寻找解决对策,去迷信或去找宗教。 2. 圣经告诉我们这不信从何开始。 (1) 是从亚当,夏娃时代开始的。 (2) 原因 (创3:1-15) 耶和华神所造的、唯有蛇比田野一切活物更狡猾。蛇对女人说、神岂是真说、不许你们吃园中所有树上的果子么。 女人对蛇说、园中树上的果子我们可以吃。 唯有园当中那棵树上的果子、神曾说、你们不可吃、也不可摸、免得你们死。 蛇对女人说、你们不一定死、 因为神知道、你们吃的日子眼睛就明亮了、你们便如神能知道善恶。 于是女人间那棵树的果子好作食物、也悦人的眼目、且是可喜爱的、能使人有智慧、就摘下果子来吃了。又给他丈夫、他丈夫也吃了。 他们两人的眼睛就明亮了、才知道自己是赤身露体、便拿无花果树的叶子、为自己编作裙子。 天起了凉风、耶和华神在园中行走。那人和他妻子听见神的声音、就藏在园里的树木中、躲避耶和华神的面。 耶和华神呼唤那人、对他说、你在哪里。 他说、我在园中听见你的声音、我就害怕、因为我赤身露体。我便藏了。 耶和华说、谁告诉你赤身露体呢、莫非你吃了我吩咐你不可吃的那树上的果子么。 那人说、你所赐给我、与我同居的女人、他把那树上的果子给我、我就吃了。 耶和华神对女人说、你作的事甚么事呢。女人说、那蛇引诱我、我就吃了。 耶和华神对蛇说、你既作了这事、就必受诅咒、比一切的牲畜野兽更甚、你必用肚子行走、终生吃土。 我又要叫你和女人彼此为仇、你的后裔和女人的后裔、也彼此为仇。女人的后裔要伤你的头、你要伤他的脚跟。(创3:1-15) (3) 结果 (创3:16-19) 又对女人说、我必多多加增你怀胎的痛楚、你生产儿女必多受苦楚。你必恋慕你丈夫、你丈夫必管辖你。 又对亚当说、你既听从妻子的话、吃了我所吩咐你不可吃的那树上的果子、地必为你的缘故受诅咒。你必终生劳苦、才能从地里得吃的。 地必给你长出荆棘和蒺藜来、你也要吃田间的菜蔬。 你必汗流满面才得糊口、直到你归了土、因为你是从土而出的。你本是尘土、仍要归于尘土。(创3:16-19) 3. 这不幸延续到什么时候? (1) 现在也继续着。(弗2:1-2) 你们死在过犯罪恶之中、他叫你们活过来。 ...

Words: 634 - Pages: 3

Free Essay

111 1111 1111

...111 11111 11111 1111111 111111 1111111 111111 11111111 1111 11111111 111 11111 11111 1111111 111111 1111111 111111 1111111 1 1111 11111111 111 11111 11111 1111111 111111 1111111 111111 1111111 1 1111 11111111 111 11111 11111 1111111 111111 1111111 111111 1111111 1 1111 11111111 111 11111 11111 1111111 111111 1111111 111111 1111111 1 1111 11111111 111 11111 11111 1111111 111111 1111111 111111 1111111 1 1111 11111111 111 11111 11111 1111111 111111 1111111 111111 1111111 1 1111 11111111 111 11111 11111 1111111 111111 1111111 111111 1111111 1 1111 11111111 111 11111 11111 1111111 111111 1111111 111111 1111111 1 1111 11111111 111 11111 11111 1111111 111111 1111111 111111 1111111 1 1111 11111111 111 11111 11111 1111111 111111 1111111 111111 1111111 1 1111 11111111 111 11111 11111 1111111 111111 1111111 111111 1111111 1 1111 11111111 111 11111 11111 1111111 111111 1111111 111111 1111111 1 1111 11111111 111 11111 11111 1111111 111111 1111111 111111 1111111 1 1111 11111111 111 11111 11111 1111111 111111 1111111 111111 1111111 1 1111 11111111 111 11111 11111 1111111 111111 1111111 111111 1111111 1 1111 11111111 111 11111 11111 1111111 111111 1111111 111111 1111111 1 1111 11111111 111 11111 11111 1111111 111111 1111111 111111 1111111 1 1111 11111111 111 11111 11111 1111111 111111 1111111 111111 1111111 1 1111 11111111 111 11111 11111 1111111 111111 1111111 111111 1111111 1 1111 11111111 111 11111 11111 1111111 111111 1111111 111111 1111111 1 1111 11111111 111 11111 11111...

Words: 406 - Pages: 2

Free Essay

How to Calculate Subnets

...Decimal/Binary Subnet Ranges Borrow 2 bits S S H H H H H H # of subnets = 22 = 4 = 00000100 Subnet mask = 2 bits = 128 + 64 = 192 = 11000000 Range of hosts = 26 = 64 = 01000000 [Range ……………………………] [Useable Range …………………...] Network ID 0 – 63 00 000000 – 00 111111 64 – 127 01 000000 – 01 111111 65 - 126 01 000001 – 01 111110 128 – 191 10 000000 – 10 111111 129 – 190 10 000001 – 10 111110 Broadcast 192 – 255 11 000000 – 11 111111 Address Borrow 3 bits S S S H H H H H # of subnets = 23 = 8 Subnet mask = 3 bits = 128 + 64 + 32 = 224 = 11100000 Range of hosts = 25 = 32 = 00100000 [Range ……………………………] Network ID 0 – 31 000 00000 – 000 11111 32 – 63 001 00000 – 001 11111 64 – 95 010 00000 – 010 11111 96 – 127 011 00000 – 011 11111 128 – 159 100 00000 – 100 11111 160 – 191 101 00000 – 101 11111 192 – 223 110 00000 – 110 11111 Broadcast 224 – 255 111 00000 – 111 11111 Address [Useable Range …………………...] 33 – 62 65 – 94 97 – 126 129 – 158 161 – 190 193 – 222 001 00001 – 001 11110 010 00001 – 010 11110 011 00001 – 011 11110 100 00001 – 100 11110 101 00001 – 101 11110 110 00001 – 110 11110 ©1999 Dan Foss How to Calculate Subnets Binary Subnet Ranges Borrow 2 bits S S H H H H H H # of subnets = 22 = 4 = 00000100 Subnet mask = 2 bits = 128 + 64 = 192 =...

Words: 942 - Pages: 4

Premium Essay

Business Law & Bankruptcy

...to be located is: Tudorama, Inc. FOURTH: The total number of shares which the corporation shall have authority to issue, and a statement of the par value of each share or a statement that the shares are without par value are: 100, No Par Value. FIFTH: The secretary of state is designated as agent of the corporation upon whom process against the corporation may be shared. The address to which the Secretary of State shall mail a copy of any process accepted on behalf of the corporation is: 123 Main Street, New City, New Tutor 11111 SIXTH: The name and street address in this state of the registered agent upon whom process against the corporation may be served is: Sandra Seller, 123 Main Street, New City, New Tutor 11111 SEVENTH: The date the corporate existence shall begin is: May 30, 2011 EIGHTH: The duration of this corporation shall be perpetual. NINTH: The initial board of directors will be: Sandra Seller 123 Main Street New City, New Tutor 11111 John Seller Jr. 123 Main Street Hypoville, NY 10950 Incorporator Information John Doe Student National Paralegal College Hypoville, NY 10950...

Words: 1020 - Pages: 5

Free Essay

Wenxin

..._____ -1- τ = 0.5 TS Ps (f ) = 2f s p(1 − p) | G(f ) |2 +f s | PG (o) |2 δ (f ) 2 + 2f s2 ∑ | PG ( mf s ) |2δ (f − mf s ) m =1 ∞ fS = G(f) 1 TS P 1 τ = 0.5 TS πf 1 sa ( ) G (f ) = 2fs 2f S 1 π 1 2 = 1 sa ( ) = ⋅ 2f S 2 2f S π / 2 π f S 2p 2 sin π Θ G (f S ) = S) = ∴ P (f S π2 δ (f − f S ) 0.5 0.5 0 AMI HDB fS 0 1 0 3 0 HDB AMI fS 1 ω n = I p K o / 2πC17 , ζ = n 36 17 R36 C17 ωn 2 L BL = P ωn (1 + 4ζ 2 ) 8ζ μF f L f R36= C17 3 3 μF = F ω n = 1.4 × 10 rad / s ζ = 0.7 B L = 739.9 Hz Q = 170.5 × 10 / B L = 230 ________________________________________________________________________________________ -2- 11111 00000 10011010 10101 00000 11101100 01010 11111 00010011 11111 00000 10011010 00000 00000 01010111 10000 10000 11010111 1 0 —— 1 0 0 1 ________________________________________________________________________________________ -3- 2DPSK 1 0 180 2PSK 2PSK 2PSK º 1 0 2DPSK 2DPSK 2DPSK 2DPSK 180 º 2PSK 2PSK ________________________________________________________________________________________ -4- fH 3 fH =18 6=108Hz fP =18 4=72Hz fP V1=12V V2=8V ωn = d Kd Ko ( R25 + R68 )C11 25 ζ = R68 C11 ωn 2 Ω 68 Ω 11 fn n ωn = fn = 2π × 18 × 6.5 = 111 rad ( 2 × 10 + 5 × 10 3 ) × 2.2 × 10 −6 4 ωn = 17.6Hz 2π 170.5 ς= 5 × 10 3 × 2.2 × 10 −6 × 111 = 0.6 2 2DPSK ÷2 2fC Cos ω c t ...

Words: 408 - Pages: 2

Premium Essay

Assignment 1 Sample

...to be located is: Tudorama, Inc. FOURTH: The total number of shares which the corporation shall have authority to issue, and a statement of the par value of each share or a statement that the shares are without par value are: 100, No Par Value. FIFTH: The secretary of state is designated as agent of the corporation upon whom process against the corporation may be shared. The address to which the Secretary of State shall mail a copy of any process accepted on behalf of the corporation is: 123 Main Street, New City, New Tutor 11111 SIXTH: The name and street address in this state of the registered agent upon whom process against the corporation may be served is: Sandra Seller, 123 Main Street, New City, New Tutor 11111 SEVENTH: The date the corporate existence shall begin is: May 30, 2011 EIGHTH: The duration of this corporation shall be perpetual. NINTH: The initial board of directors will be: Sandra Seller 123 Main Street New City, New Tutor 11111 John Seller Jr. 123 Main Street Hypoville, NY 10950 Incorporator Information John Doe Student National Paralegal College Hypoville, NY 10950...

Words: 1021 - Pages: 5

Premium Essay

Bollywood

...Step7: Divide 134 by 7 = 19 remainder 1. The reminder tells you the day. Sunday 0 Monday 1 Tuesday 2 Wednesday 3 Thursday 4 Friday 5 Saturday 6 Answer: Monday Sequential Inputs of numbers with 8 1 x 8 + 1 = 9 12 x 8 + 2 = 98 123 x 8 + 3 = 987 1234 x 8 + 4 = 9876 12345 x 8 + 5 = 98765 123456 x 8 + 6 = 987654 1234567 x 8 + 7 = 9876543 12345678 x 8 + 8 = 98765432 123456789 x 8 + 9 = 987654321 Sequential 1's with 9 1 x 9 + 2 = 11 12 x 9 + 3 = 111 123 x 9 + 4 = 1111 1234 x 9 + 5 = 11111 12345 x 9 + 6 = 111111 123456 x 9 + 7 = 1111111 1234567 x 9 + 8 = 11111111 12345678 x 9 + 9 = 111111111 123456789 x 9 + 10 = 1111111111 Sequential 8's with 9 9 x 9 + 7 = 88 98 x 9 + 6 = 888 987 x 9 + 5 = 8888 9876 x 9 + 4 = 88888 98765 x 9 + 3 = 888888 987654 x 9 + 2 = 8888888 9876543 x 9 + 1 = 88888888 98765432 x 9 + 0 = 888888888 Numeric Palindrome with 1's 1 x 1 = 1 11 x 11 = 121 111 x 111 = 12321 1111 x 1111 = 1234321 11111 x 11111 = 123454321 111111 x 111111 = 12345654321 1111111 x 1111111 = 1234567654321 11111111 x 11111111 = 123456787654321 111111111 x 111111111 = 12345678987654321...

Words: 991 - Pages: 4