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Acid-Base Titration: Determination of the Percentages (%) of Sodium Carbonate (Na2Co3) and Sodium Hydroxide (Naoh) in a Mixture

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Title
Acid-base titration: Determination of the percentages (%) of sodium carbonate (Na2CO3) and sodium hydroxide (NaOH) in a mixture

Objective
To determine the respective weight per cent of sodium carbonate and sodium hydroxide in a mixture by acid-base titration.

Result and calculation
Part A
Titration 1
Titration number 1 2 3
Initial volume of burette( cm3) 5.10 2.70 9.70
Final volume of burette (cm3) 34.40 31.80 39.20
Total volume of HCl used (cm3) 29.30 29.10 29.50
Average volume of HCl required for titration =(29.30+29.10+29.50)/3 cm3
= 29.30 cm3

Titration 2
Titration number 1 2 3
Initial volume of burette( cm3) 4.50 14.00 2.70
Final volume of burette (cm3) 25.00 21.70 22.80
Total volume of HCl used (cm3) 20.50 20.30 20.10
Average volume of HCl required for titration =(20.50+20.30+20.10)/3 cm3
= 20.30 cm3

Part B
Titration number Rough 1 2 3
Initial volume of burette( cm3) 4.9 4.80 3.60 2.20
Final volume of burette (cm3) 28.3 28.90 27.70 26.20
Total volume of HCl used until phenolphthalein decolourised (cm3) , x 23.4 24.10 24.10 24.00
Initial volume of burette after adding methyl orange indicator ( cm3) 28.3 28.90 27.70 26.20
Final volume of burette (cm3) 34.1 33.40 32.10 30.70
Total volume of HCl used until phenolphthalein decolourised (cm3) , y 5.8 4.50 4.40 4.50

Average volume of HCl required to react with Na2CO3 (2y) =2(4.50+4.40+4.50)/3 cm3
= 2(4.4667) cm3
=8.9333 cm3

Average volume of HCl required to react with NaOH (x-y) =(24.10+24.10+24.00)/3 -4.4667 cm3
= (24.0667– 4.4667) cm3
= 19.60 cm3

Question
1. Calculate the respective concentration of Na2CO3 and NaOH in the sample solution.
From part A,
Average of HCl required for titration 1 is actually the amount of HCl needed to react with Na2CO3 and NaOH.
Average of HCl

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