Lab#2: Activity P41: Waves on a string
Jonathan Alevy
Physics 1302.101
Partners names: Henry Haws, Johnathan Rios & Miguel Castellano

Pre-Lab
Direct Calculation of the Linear Mass Density
1. Measure the mass of a known of the string. Length = L = 1.77 meters
Mass = M = 5.7 x 10-4 kilograms µ = mass/length = 5.7 x 10-4 / 1.77m= 3.22 x 10-4 kg/m

Table 1: Change Tension – Constant Frequency and Length
Frequency = 120 Hz
Length = 1.0 m
T=mg
T=mg

Segments, n | Experimental Mass (kg) | Theoretical Mass (kg) | % difference: Exp-Theo | Tension, T (N) | 1/n2 | 1 | 1.84 | 1.89 | 2.78% | 18.0 | 1.00 | 2 | 0.463 | 0.473 | 2.14% | 4.54 | 0.250 | 3 | 0.207 | 0.210 | 1.44% | 2.03 | 0.111 | 4 | 0.113 | 0.118 | 4.33% | 1.11 | 0.0625 | 5 | 0.0720 | 0.0760 | 5.41% | 0.706 | 0.0400 |

Slope= 18
The slope is equal to = 18; = 3.125 x 10-4 kg/m

Linear mass density = 3.125 x 10-4 kg/m

Table 2: Vary Frequency
Tension = 4.9 N Tension = Mass x Gravity = 0.500kg x 9.81m/s2 = 4.9 N

Length = 1.0 m

Segments, n | Experimental Frequency (Hz) | Theoretical Frequency (Hz) | % difference Exp-Theo | 0 | 0 | 0 | 0% | 1 | 62.00 | 61.68 | 0.520% | 2 | 125.7 | 123.4 | 1.88% | 3 | 189.0 | 185.0 | 2.12% | 4 | 251.1 | 246.7 | 1.76% | 5 | 313.9 | 308.4 | 1.77% |

Slope = 62.9

The slope is equal to = 62.9; =3.096 x 10-4 kg/m

Linear mass density = 3.096 x 10-4 kg/m

Table 3: Results Method | Linear mass density | % difference | Direct | 3.22 x 10-4 | | Tension vs. 1/n2 | 3.125 x 10-4 | 3.0% | Frequency vs. n | 3.096 x 10-4 | 4.0% |

Questions 1. As the tension is increased, does the number of segments increase or decrease when the frequency is kept constant?
The number of segments decreases as tension increases

2. As the frequency is increased, does the number of segments increase or decrease when