Free Essay

Asdsad

In:

Submitted By sumanthraj
Words 5786
Pages 24
COMPLETE 8086 INSTRUCTION SET

Quick Reference:

AAA
AAD
AAM
AAS
ADC
ADD
AND
CALL
CBW
CLC
CLD
CLI
CMC
CMP
CMPSB
CMPSW
CWD
DAA
DAS
DEC
DIV
HLT
IDIV
IMUL
IN
INC
INT
INTO
IRET
JA
JAE
JB
JBE
JC
JCXZ
JE
JG
JGE
JL
JLE
JMP
JNA
JNAE
JNB
JNBE
JNC
JNE
JNG
JNGE
JNL
JNLE
JNO
JNP
JNS
JNZ
JO
JP
JPE
JPO
JS
JZ
LAHF
LDS
LEA
LES
LODSB
LODSW
LOOP
LOOPE
LOOPNE
LOOPNZ
LOOPZ
MOV
MOVSB
MOVSW
MUL
NEG
NOP
NOT
OR
OUT
POP
POPA
POPF
PUSH
PUSHA
PUSHF
RCL
RCR
REP
REPE
REPNE
REPNZ
REPZ
RET
RETF
ROL
ROR
SAHF
SAL
SAR
SBB
SCASB
SCASW
SHL
SHR
STC
STD
STI
STOSB
STOSW
SUB
TEST
XCHG
XLATB
XOR

Operand Types:

REG: AX, BX, CX, DX, AH, AL, BL, BH, CH, CL, DH, DL, DI, SI, BP, SP.
SREG: DS, ES, SS, and only as second operand: CS.
Memory: [BX], [BX+SI+7], variable, etc…
Immediate: 5, -24, 3Fh, 10001101b, etc...

Notes:

• When two operands are required for an instruction they are separated by comma. For example:

REG, memory

• When there are two operands, both operands must have the same size (except shift and rotate instructions). For example:

AL, DL DX, AX m1 DB ? AL, m1 m2 DW ? AX, m2

• Some instructions allow several operand combinations. For example:

memory, immediate REG, immediate memory, REG REG, SREG

• Some examples contain macros, so it is advisable to use Shift + F8 hot key to Step Over (to make macro code execute at maximum speed set step delay to zero), otherwise emulator will step through each instruction of a macro. Here is an example that uses PRINTN macro:

include 'emu8086.inc' ORG 100h MOV AL, 1 MOV BL, 2 PRINTN 'Hello World!' ; macro. MOV CL, 3 PRINTN 'Welcome!' ; macro. RET
These marks are used to show the state of the flags:

1 - instruction sets this flag to 1.
0 - instruction sets this flag to 0. r - flag value depends on result of the instruction.
? - flag value is undefined (maybe 1 or 0).

Some instructions generate exactly the same machine code, so disassemble may have a problem decoding to your original code. This is especially important for Conditional Jump instructions (see "Program Flow Control" in Tutorials for more information).

Instructions in alphabetical order:

|INSTRUCTION |OPERANDS |DESCRIPTION |
|AAA |No operands |ASCII Adjust after Addition. |
| | |Corrects result in AH and AL after addition when |
| | |working with BCD values. |
| | |It works according to the following Algorithm: |
| | |if low nibble of AL > 9 or AF = 1 then: |
| | |������ AL = AL + 6 |
| | |������ AH = AH + 1 |
| | |������ AF = 1 |
| | |������ CF = 1 |
| | |else |
| | |������ AF = 0 |
| | |������ CF = 0 |
| | |in both cases: |
| | |clear the high nibble of AL. |
| | |Example: |
| | |MOV AX, 15 ; AH = 00, AL = 0Fh |
| | |AAA ; AH = 01, AL = 05 |
| | |RET |
|AAD |No operands |ASCII Adjust before Division. |
| | |Prepares two BCD values for division. |
| | |Algorithm: |
| | |������ AL = (AH * 10) + AL |
| | |������ AH = 0 |
| | |Example: |
| | |MOV AX, 0105h ; AH = 01, AL = 05 |
| | |AAD ; AH = 00, AL = 0Fh (15) |
| | |RET |
|AAM |No operands |ASCII Adjust after Multiplication. |
| | |Corrects the result of multiplication of two BCD |
| | |values. |
| | |Algorithm: |
| | |������ AH = AL / 10 |
| | |������ AL = remainder |
| | |Example: |
| | |MOV AL, 15 ; AL = 0Fh |
| | |AAM ; AH = 01, AL = 05 |
| | |RET |
|AAS |No operands |ASCII Adjust after Subtraction. |
| | |Corrects result in AH and AL after subtraction |
| | |when working with BCD values. |
| | |Algorithm: |
| | |if low nibble of AL > 9 or AF = 1 then: |
| | |������ AL = AL - 6 |
| | |������ AH = AH - 1 |
| | |������ AF = 1 |
| | |������ CF = 1 |
| | |else |
| | |������ AF = 0 |
| | |������ CF = 0 |
| | |in both cases: |
| | |clear the high nibble of AL. |
| | |Example: |
| | |MOV AX, 02FFh ; AH = 02, AL = 0FFh |
| | |AAS ; AH = 01, AL = 09 |
| | |RET |
|ADC |REG, memory |Add with Carry. |
| |memory, REG |Algorithm: |
| |REG, REG |operand1 = operand1 + operand2 + CF |
| |memory, immediate |Example: |
| |REG, immediate |STC ; set CF = 1 |
| | |MOV AL, 5 ; AL = 5 |
| | |ADC AL, 1 ; AL = 7 |
| | |RET |
|ADD |REG, memory |Add. |
| |memory, REG |Algorithm: |
| |REG, REG |operand1 = operand1 + operand2 |
| |memory, immediate |Example: |
| |REG, immediate |MOV AL, 5 ; AL = 5 |
| | |ADD AL, -3 ; AL = 2 |
| | |RET |
|AND |REG, memory |Logical AND between all bits of two operands. |
| |memory, REG |Result is stored in operand1. |
| |REG, REG |These rules apply: |
| |memory, immediate |1 AND 1 = 1 |
| |REG, immediate |1 AND 0 = 0 |
| | |0 AND 1 = 0 |
| | |0 AND 0 = 0 |
| | |Example: |
| | |MOV AL, 'a' ; AL = 01100001b |
| | |AND AL, 11011111b ; AL = 01000001b ('A') |
| | |RET |
|CALL |procedure name |Transfers control to procedure, return address is |
| |label |(IP) is pushed to stack. 4-byte address may be |
| |4-byte address |entered in this form: 1234h:5678h, first value is segment second value is an offset (this |
| | |is a far |
| | |Call, so CS is also pushed to stack). |
| | |Example: |
| | |ORG 100h ; for COM file. |
| | |CALL p1 |
| | |ADD AX, 1 |
| | |RET ; return to OS. |
| | |p1 PROC ; procedure declaration. |
| | |MOV AX, 1234h |
| | |RET ; return to caller. |
| | |p1 ENDP |
|CBW |No operands |Convert byte into word. |
| | |Algorithm: |
| | |if high bit of AL = 1 then: |
| | |������ AH = 255 (0FFh) |
| | |else |
| | |������ AH = 0 |
| | |Example: |
| | |MOV AX, 0 ; AH = 0, AL = 0 |
| | |MOV AL, -5 ; AX = 000FBh (251) |
| | |CBW ; AX = 0FFFBh (-5) |
| | |RET |
|CLC |No operands |Clear Carry flag. |
| | |Algorithm: |
| | |CF = 0 |
|CLD |No operands |Clear Direction flag. SI and DI will be incremented |
| | |by chain instructions: CMPSB, CMPSW, LODSB, |
| | |LODSW, MOVSB, MOVSW, STOSB, STOSW. |
| | |Algorithm: |
| | |DF = 0 |
|CLI |No operands |Clear Interrupt enable flag. This disables |
| | |hardware interrupts. |
| | |Algorithm: |
| | |IF = 0 |
|CMC |No operands |Complement Carry flag. Inverts value of CF. |
| | |Algorithm: |
| | |if CF = 1 then CF = 0 |
| | |if CF = 0 then CF = 1 |
|CMP |REG, memory |Compare. |
| |memory, REG |Algorithm: |
| |REG, REG |operand1 - operand2 |
| |memory, immediate |result is not stored anywhere, flags are |
| |REG, immediate |set (OF, SF, ZF, AF, PF, CF) according to |
| | |result. |
| | |Example: |
| | |MOV AL, 5 |
| | |MOV BL, 5 |
| | |CMP AL, BL ; AL = 5, ZF = 1 (so equal!) |
| | |RET |
|CMPSB |No operands |Compare bytes: ES:[DI] from DS:[SI]. |
| | |Algorithm: |
| | |������ DS:[SI] - ES:[DI] |
| | |������ set flags according to result: |
| | |OF, SF, ZF, AF, PF, CF |
| | |������ if DF = 0 then |
| | |������ SI = SI + 1 |
| | |������ DI = DI + 1 |
| | |else |
| | |������ SI = SI - 1 |
| | |������ DI = DI - 1 |
|CMPSW |No operands |Compare words: ES:[DI] from DS:[SI]. |
| | |Algorithm: |
| | |������ DS:[SI] - ES:[DI] |
| | |������ set flags according to result: |
| | |OF, SF, ZF, AF, PF, CF |
| | |������ if DF = 0 then |
| | |������ SI = SI + 2 |
| | |������ DI = DI + 2 |
| | |else |
| | |������ SI = SI - 2 |
| | |������ DI = DI - 2 |
|CWD |No operands |Convert Word to Double word. |
| | |Algorithm: |
| | |if high bit of AX = 1 then: |
| | |������ DX = 65535 (0FFFFh) |
| | |else |
| | |������ DX = 0 |
| | |Example: |
| | |MOV DX, 0 ; DX = 0 |
| | |MOV AX, 0 ; AX = 0 |
| | |MOV AX, -5 ; DX AX = 00000h:0FFFBh |
| | |CWD ; DX AX = 0FFFFh:0FFFBh |
| | |RET |
|DAA |No operands |Decimal adjust After Addition. |
| | |Corrects the result of addition of two packed BCD |
| | |values. |
| | |Algorithm: |
| | |if low nibble of AL > 9 or AF = 1 then: |
| | |������ AL = AL + 6 |
| | |������ AF = 1 |
| | |if AL > 9Fh or CF = 1 then: |
| | |������ AL = AL + 60h |
| | |������ CF = 1 |
| | |Example: |
| | |MOV AL, 0Fh ; AL = 0Fh (15) |
| | |DAA ; AL = 15h |
| | |RET |
|DAS |No operands |Decimal adjust After Subtraction. |
| | |Corrects the result of subtraction of two packed |
| | |BCD values. |
| | |Algorithm: |
| | |if low nibble of AL > 9 or AF = 1 then: |
| | |������ AL = AL - 6 |
| | |������ AF = 1 |
| | |if AL > 9Fh or CF = 1 then: |
| | |������ AL = AL - 60h |
| | |������ CF = 1 |
| | |Example: |
| | |MOV AL, 0FFh ; AL = 0FFh (-1) |
| | |DAS ; AL = 99h, CF = 1 |
| | |RET |
|DEC |REG |Decrement. |
| |memory |Algorithm: |
| | |operand = operand - 1 |
| | |Example: |
| | |MOV AL, 255 ; AL = 0FFh (255 or -1) |
| | |DEC AL ; AL = 0FEh (254 or -2) |
| | |RET |
|DIV |REG |Unsigned divide. |
| |memory |Algorithm: |
| | |when operand is a byte: |
| | |AL = AX / operand |
| | |AH = remainder (modulus) |
| | |when operand is a word: |
| | |AX = (DX AX) / operand |
| | |DX = remainder (modulus) |
| | |Example: |
| | |MOV AX, 203 ; AX = 00CBh |
| | |MOV BL, 4 |
| | |DIV BL ; AL = 50 (32h), AH = 3 |
| | |RET |
|HLT |No operands |Halt the System. |
| | |Example: |
| | |MOV AX, 5 |
| | |HLT |
|IDIV |REG |Signed divide. |
| |memory |Algorithm: |
| | |when operand is a byte: |
| | |AL = AX / operand |
| | |AH = remainder (modulus) |
| | |when operand is a word: |
| | |AX = (DX AX) / operand |
| | |DX = remainder (modulus) |
| | |Example: |
| | |MOV AX, -203 ; AX = 0FF35h |
| | |MOV BL, 4 |
| | |IDIV BL ; AL = -50 (0CEh), AH = -3 (0FDh) |
| | |RET |
|IMUL |REG |Signed multiply. |
| |memory |Algorithm: |
| | |when operand is a byte: |
| | |AX = AL * operand. |
| | |when operand is a word: |
| | |(DX AX) = AX * operand. |
| | |Example: |
| | |MOV AL, -2 |
| | |MOV BL, -4 |
| | |IMUL BL ; AX = 8 |
| | |RET |
|IN |AL, im.byte |Input from port into AL or AX. |
| |AL, DX |Second operand is a port number. If required to |
| |AX, im.byte |access port number over 255 - DX register should |
| |AX, DX |be used. |
| | |Example: |
| | |IN AX, 4 ; get status of traffic lights. |
| | |IN AL, 7 ; get status of stepper-motor. |
|INC |REG |Increment. |
| |memory |Algorithm: |
| | |operand = operand + 1 |
| | |Example: |
| | |MOV AL, 4 |
| | |INC AL ; AL = 5 |
| | |RET |
|INT |immediate byte |Interrupt numbered by immediate byte (0..255). |
| | |Algorithm: |
| | |Push to stack: |
| | |������ flags register |
| | |������ CS |
| | |������ IP |
| | |������ IF = 0 |
| | |������ Transfer control to interrupt |
| | |procedure |
| | |Example: |
| | |MOV AH, 0Eh ; teletype. |
| | |MOV AL, 'A' |
| | |INT 10h ; BIOS interrupt. |
| | |RET |
|INTO |No operands |Interrupt 4 if Overflow flag is 1. |
| | |Algorithm: |
| | |if OF = 1 then INT 4 |
| | |Example: |
| | |; -5 - 127 = -132 (not in -128..127) |
| | |; the result of SUB is wrong (124), |
| | |; so OF = 1 is set: |
| | |MOV AL, -5 |
| | |SUB AL, 127 ; AL = 7Ch (124) |
| | |INTO ; process error. |
| | |RET |
|IRET |No operands |Interrupt Return. |
| | |Algorithm: |
| | |Pop from stack: |
| | |������ IP |
| | |������ CS |
| | |������ flags register |
|JA |label |Short Jump if first operand is Above second |
| | |operand (as set by CMP instruction). Unsigned. |
| | |Algorithm: |
| | |if (CF = 0) and (ZF = 0) then jump |
| | |Example: |
| | |include 'emu8086.inc' |
| | |ORG 100h |
| | |MOV AL, 250 |
| | |CMP AL, 5 |
| | |JA label1 |
| | |PRINT 'AL is not above 5' |
| | |JMP exit |
| | |label1: |
| | |PRINT 'AL is above 5' |
| | |exit: |
| | |RET |
|JAE |label |Short Jump if first operand is Above or Equal to |
| | |second operand (as set by CMP instruction). |
| | |Unsigned. |
| | |Algorithm: |
| | |if CF = 0 then jump |
| | |Example: |
| | |include 'emu8086.inc' |
| | |ORG 100h |
| | |MOV AL, 5 |
| | |CMP AL, 5 |
| | |JAE label1 |
| | |PRINT 'AL is not above or equal to 5' |
| | |JMP exit |
| | |label1: |
| | |PRINT 'AL is above or equal to 5' |
| | |exit: |
| | |RET |
|JB |label |Short Jump if first operand is Below second |
| | |operand (as set by CMP instruction). Unsigned. |
| | |Algorithm: |
| | |if CF = 1 then jump |
| | |Example: |
| | |include 'emu8086.inc' |
| | |ORG 100h |
| | |MOV AL, 1 |
| | |CMP AL, 5 |
| | |JB label1 |
| | |PRINT 'AL is not below 5' |
| | |JMP exit |
| | |label1: |
| | |PRINT 'AL is below 5' |
| | |exit: |
| | |RET |
|JBE |label |Short Jump if first operand is Below or Equal to |
| | |second operand (as set by CMP instruction). |
| | |Unsigned. |
| | |Algorithm: |
| | |if CF = 1 or ZF = 1 then jump |
| | |Example: |
| | |include 'emu8086.inc' |
| | |ORG 100h |
| | |MOV AL, 5 |
| | |CMP AL, 5 |
| | |JBE label1 |
| | |PRINT 'AL is not below or equal to 5' |
| | |JMP exit |
| | |label1: |
| | |PRINT 'AL is below or equal to 5' |
| | |exit: |
| | |RET |
|JC |label |Short Jump if Carry flag is set to 1. |
| | |Algorithm: |
| | |if CF = 1 then jump |
| | |Example: |
| | |include 'emu8086.inc' |
| | |ORG 100h |
| | |MOV AL, 255 |
| | |ADD AL, 1 |
| | |JC label1 |
| | |PRINT 'no carry.' |
| | |JMP exit |
| | |label1: |
| | |PRINT 'has carry.' |
| | |exit: |
| | |RET |
|JCXZ |label |Short Jump if CX register is 0. |
| | |Algorithm: |
| | |if CX = 0 then jump |
| | |Example: |
| | |include 'emu8086.inc' |
| | |ORG 100h |
| | |MOV CX, 0 |
| | |JCXZ label1 |
| | |PRINT 'CX is not zero.' |
| | |JMP exit |
| | |label1: |
| | |PRINT 'CX is zero.' |
| | |exit: |
| | |RET |
|JE |label |Short Jump if first operand is Equal to second |
| | |operand (as set by CMP instruction). |
| | |Signed/Unsigned. |
| | |Algorithm: |
| | |if ZF = 1 then jump |
| | |Example: |
| | |include 'emu8086.inc' |
| | |ORG 100h |
| | |MOV AL, 5 |
| | |CMP AL, 5 |
| | |JE label1 |
| | |PRINT 'AL is not equal to 5.' |
| | |JMP exit |
| | |label1: |
| | |PRINT 'AL is equal to 5.' |
| | |exit: |
| | |RET |
|JG |label |Short Jump if first operand is Greater then second |
| | |operand (as set by CMP instruction). Signed. |
| | |Algorithm: |
| | |if (ZF = 0) and (SF = OF) then jump |
| | |Example: |
| | |include 'emu8086.inc' |
| | |ORG 100h |
| | |MOV AL, 5 |
| | |CMP AL, -5 |
| | |JG label1 |
| | |PRINT 'AL is not greater -5.' |
| | |JMP exit |
| | |label1: |
| | |PRINT 'AL is greater -5.' |
| | |exit: |
| | |RET |
|JGE |label |Short Jump if first operand is Greater or Equal to |
| | |second operand (as set by CMP instruction). |
| | |Signed. |
| | |Algorithm: |
| | |if SF = OF then jump |
| | |Example: |
| | |include 'emu8086.inc' |
| | |ORG 100h |
| | |MOV AL, 2 |
| | |CMP AL, -5 |
| | |JGE label1 |
| | |PRINT 'AL < -5' |
| | |JMP exit |
| | |label1: |
| | |PRINT 'AL >= -5' |
| | |exit: |
| | |RET |
|JL |label |Short Jump if first operand is Less then second |
| | |operand (as set by CMP instruction). Signed. |
| | |Algorithm: |
| | |if SF OF then jump |
| | |Example: |
| | |include 'emu8086.inc' |
| | |ORG 100h |
| | |MOV AL, -2 |
| | |CMP AL, 5 |
| | |JL label1 |
| | |PRINT 'AL >= 5.' |
| | |JMP exit |
| | |label1: |
| | |PRINT 'AL < 5.' |
| | |exit: |
| | |RET |
|JLE |label |Short Jump if first operand is Less or Equal to |
| | |second operand (as set by CMP instruction). |
| | |Signed. |
| | |Algorithm: |
| | |if SF OF or ZF = 1 then jump |
| | |Example: |
| | |include 'emu8086.inc' |
| | |ORG 100h |
| | |MOV AL, -2 |
| | |CMP AL, 5 |
| | |JLE label1 |
| | |PRINT 'AL > 5.' |
| | |JMP exit |
| | |label1: |
| | |PRINT 'AL = 5.' |
| | |JMP exit |
| | |label1: |
| | |PRINT 'AL < 5.' |
| | |exit: |
| | |RET |
|JNB |label |Short Jump if first operand is Not Below second |
| | |operand (as set by CMP instruction). Unsigned. |
| | |Algorithm: |
| | |if CF = 0 then jump |
| | |Example: |
| | |include 'emu8086.inc' |
| | |ORG 100h |
| | |MOV AL, 7 |
| | |CMP AL, 5 |
| | |JNB label1 |
| | |PRINT 'AL < 5.' |
| | |JMP exit |
| | |label1: |
| | |PRINT 'AL >= 5.' |
| | |exit: |
| | |RET |
|JNBE |label |Short Jump if first operand is Not Below and Not |
| | |Equal to second operand (as set by CMP |
| | |instruction). Unsigned. |
| | |Algorithm: |
| | |if (CF = 0) and (ZF = 0) then jump |
| | |Example: |
| | |include 'emu8086.inc' |
| | |ORG 100h |
| | |MOV AL, 7 |
| | |CMP AL, 5 |
| | |JNBE label1 |
| | |PRINT 'AL 5.' |
| | |exit: |
| | |RET |
|JNC |label |Short Jump if Carry flag is set to 0. |
| | |Algorithm: |
| | |if CF = 0 then jump |
| | |Example: |
| | |include 'emu8086.inc' |
| | |ORG 100h |
| | |MOV AL, 2 |
| | |ADD AL, 3 |
| | |JNC label1 |
| | |PRINT 'has carry.' |
| | |JMP exit |
| | |label1: |
| | |PRINT 'no carry.' |
| | |exit: |
| | |RET |
|JNE |label |Short Jump if first operand is Not Equal to second |
| | |operand (as set by CMP instruction). |
| | |Signed/Unsigned. |
| | |Algorithm: |
| | |if ZF = 0 then jump |
| | |Example: |
| | |include 'emu8086.inc' |
| | |ORG 100h |
| | |MOV AL, 2 |
| | |CMP AL, 3 |
| | |JNE label1 |
| | |PRINT 'AL = 3.' |
| | |JMP exit |
| | |label1: |
| | |PRINT 'Al 3.' |
| | |exit: |
| | |RET |
|JNG |label |Short Jump if first operand is Not Greater then |
| | |second operand (as set by CMP instruction). |
| | |Signed. |
| | |Algorithm: |
| | |if (ZF = 1) and (SF OF) then jump |
| | |Example: |
| | |include 'emu8086.inc' |
| | |ORG 100h |
| | |MOV AL, 2 |
| | |CMP AL, 3 |
| | |JNG label1 |
| | |PRINT 'AL > 3.' |
| | |JMP exit |
| | |label1: |
| | |PRINT 'Al = 3.' |
| | |JMP exit |
| | |label1: |
| | |PRINT 'Al < 3.' |
| | |exit: |
| | |RET |
|JNL |label |Short Jump if first operand is Not Less then |
| | |second operand (as set by CMP instruction). |
| | |Signed. |
| | |Algorithm: |
| | |if SF = OF then jump |
| | |Example: |
| | |include 'emu8086.inc' |
| | |ORG 100h |
| | |MOV AL, 2 |
| | |CMP AL, -3 |
| | |JNL label1 |
| | |PRINT 'AL < -3.' |
| | |JMP exit |
| | |label1: |
| | |PRINT 'Al >= -3.' |
| | |exit: |
| | |RET |
|JNLE |label |Short Jump if first operand is Not Less and Not |
| | |Equal to second operand (as set by CMP |
| | |instruction). Signed. |
| | |Algorithm: |
| | |if (SF = OF) and (ZF = 0) then jump |
| | |Example: |
| | |include 'emu8086.inc' |
| | |ORG 100h |
| | |MOV AL, 2 |
| | |CMP AL, -3 |
| | |JNLE label1 |
| | |PRINT 'AL -3.' |
| | |exit: |
| | |RET |
|JNO |label |Short Jump if Not Overflow. |
| | |Algorithm: |
| | |if OF = 0 then jump |
| | |Example: |
| | |; -5 - 2 = -7 (inside -128..127) |
| | |; the result of SUB is correct, |
| | |; so OF = 0: |
| | |include 'emu8086.inc' |
| | |ORG 100h |
| | |MOV AL, -5 |
| | |SUB AL, 2 ; AL = 0F9h (-7) |
| | |JNO label1 |
| | |PRINT 'overflow!' |
| | |JMP exit |
| | |label1: |
| | |PRINT 'no overflow.' |
| | |exit: |
| | |RET |
|JNP |label |Short Jump if No Parity (odd). Only 8 low bits of |
| | |result are checked. Set by CMP, SUB, ADD, TEST, |
| | |AND, OR, XOR instructions. |
| | |Algorithm: |
| | |if PF = 0 then jump |
| | |Example: |
| | |include 'emu8086.inc' |
| | |ORG 100h |
| | |MOV AL, 00000111b ; AL = 7 |
| | |OR AL, 0 ; just set flags. |
| | |JNP label1 |
| | |PRINT 'parity even.' |
| | |JMP exit |
| | |label1: |
| | |PRINT 'parity odd.' |
| | |exit: |
| | |RET |
|JNS |label |Short Jump if Not Signed (if positive). Set by |
| | |CMP, SUB, ADD, TEST, AND, OR, XOR |
| | |instructions. |
| | |Algorithm: |
| | |if SF = 0 then jump |
| | |Example: |
| | |include 'emu8086.inc' |
| | |ORG 100h |
| | |MOV AL, 00000111b ; AL = 7 |
| | |OR AL, 0 ; just set flags. |
| | |JNS label1 |
| | |PRINT 'signed.' |
| | |JMP exit |
| | |label1: |
| | |PRINT 'not signed.' |
| | |exit: |
| | |RET |
|JNZ |label |Short Jump if Not Zero (not equal). Set by CMP, |
| | |SUB, ADD, TEST, AND, OR, XOR instructions. |
| | |Algorithm: |
| | |if ZF = 0 then jump |
| | |Example: |
| | |include 'emu8086.inc' |
| | |ORG 100h |
| | |MOV AL, 00000111b ; AL = 7 |
| | |OR AL, 0 ; just set flags. |
| | |JNZ label1 |
| | |PRINT 'zero.' |
| | |JMP exit |
| | |label1: |
| | |PRINT 'not zero.' |
| | |exit: |
| | |RET |
|JO |label |Short Jump if Overflow. |
| | |Algorithm: |
| | |if OF = 1 then jump |
| | |Example: |
| | |; -5 - 127 = -132 (not in -128..127) |
| | |; the result of SUB is wrong (124), |
| | |; so OF = 1 is set: |
| | |include 'emu8086.inc' |
| | |org 100h |
| | |MOV AL, -5 |
| | |SUB AL, 127 ; AL = 7Ch (124) |
| | |JO label1 |
| | |PRINT 'no overflow.' |
| | |JMP exit |
| | |label1: |
| | |PRINT 'overflow!' |
| | |exit: |
| | |RET |
|JP |label |Short Jump if Parity (even). Only 8 low bits of |
| | |result are checked. Set by CMP, SUB, ADD, TEST, |
| | |AND, OR, XOR instructions. |
| | |Algorithm: |
| | |if PF = 1 then jump |
| | |Example: |
| | |include 'emu8086.inc' |
| | |ORG 100h |
| | |MOV AL, 00000101b ; AL = 5 |
| | |OR AL, 0 ; just set flags. |
| | |JP label1 |
| | |PRINT 'parity odd.' |
| | |JMP exit |
| | |label1: |
| | |PRINT 'parity even.' |
| | |exit: |
| | |RET |
|JPE |label |Short Jump if Parity Even. Only 8 low bits of |
| | |result are checked. Set by CMP, SUB, ADD, TEST, |
| | |AND, OR, XOR instructions. |
| | |Algorithm: |
| | |if PF = 1 then jump |
| | |Example: |
| | |include 'emu8086.inc' |
| | |ORG 100h |
| | |MOV AL, 00000101b ; AL = 5 |
| | |OR AL, 0 ; just set flags. |
| | |JPE label1 |
| | |PRINT 'parity odd.' |
| | |JMP exit |
| | |label1: |
| | |PRINT 'parity even.' |
| | |exit: |
| | |RET |
|JPO |label |Short Jump if Parity Odd. Only 8 low bits of result are checked. Set by CMP, SUB, ADD, |
| | |TEST, AND, |
| | |OR, XOR instructions. |
| | |Algorithm: |
| | |if PF = 0 then jump |
| | |Example: |
| | |include 'emu8086.inc' |
| | |ORG 100h |
| | |MOV AL, 00000111b ; AL = 7 |
| | |OR AL, 0 ; just set flags. |
| | |JPO label1 |
| | |PRINT 'parity even.' |
| | |JMP exit |
| | |label1: |
| | |PRINT 'parity odd.' |
| | |exit: |
| | |RET |
|JS |label |Short Jump if Signed (if negative). Set by CMP, |
| | |SUB, ADD, TEST, AND, OR, XOR instructions. |
| | |Algorithm: |
| | |if SF = 1 then jump |
| | |Example: |
| | |include 'emu8086.inc' |
| | |ORG 100h |
| | |MOV AL, 10000000b ; AL = -128 |
| | |OR AL, 0 ; just set flags. |
| | |JS label1 |
| | |PRINT 'not signed.' |
| | |JMP exit |
| | |label1: |
| | |PRINT 'signed.' |
| | |exit: |
| | |RET |
|JZ |label |Short Jump if Zero (equal). Set by CMP, SUB, |
| | |ADD, TEST, AND, OR, XOR instructions. |
| | |Algorithm: |
| | |if ZF = 1 then jump |
| | |Example: |
| | |include 'emu8086.inc' |
| | |ORG 100h |
| | |MOV AL, 5 |
| | |CMP AL, 5 |
| | |JZ label1 |
| | |PRINT 'AL is not equal to 5.' |
| | |JMP exit |
| | |label1: |
| | |PRINT 'AL is equal to 5.' |
| | |exit: |
| | |RET |
|LAHF |No operands |Load AH from 8 low bits of Flags register. |
| | |Algorithm: |
| | |AH = flags register |
| | |AH bit: 7 6 5 4 3 2 1 0 |
| | |[SF] [ZF] [0] [AF] [0] [PF] [1] [CF] |
| | |bits 1, 3, 5 are reserved. |
|LDS |REG, memory |Load memory double word into word register and DS. |
| | |Algorithm: |
| | |������ REG = first word |
| | |������ DS = second word |
| | |Example: |
| | |ORG 100h |
| | |LDS AX, m |
| | |RET |
| | |m DW 1234h |
| | |DW 5678h |
| | |END |
| | |AX is set to 1234h, DS is set to 5678h. |
|LEA |REG, memory |Load Effective Address. |
| | |Algorithm: |
| | |������ REG = address of memory (offset) |
| | |Example: |
| | |MOV BX, 35h |
| | |MOV DI, 12h |
| | |LEA SI, [BX+DI] ; SI = 35h + 12h = 47h |
| | |Note: The integrated 8086 assembler |
| | |automatically replaces LEA with a more efficient |
| | |MOV where possible. For example: |
| | |org 100h |
| | |LEA AX, m ; AX = offset of m |
| | |RET |
| | |m dw 1234h |
| | |END |
|LES |REG, memory |Load memory double word into word register and ES. |
| | |Algorithm: |
| | |������ REG = first word |
| | |������ ES = second word |
| | |Example: |
| | |ORG 100h |
| | |LES AX, m |
| | |RET |
| | |m DW 1234h |
| | |DW 5678h |
| | |END |
| | |AX is set to 1234h, ES is set to 5678h. |
|LODSB |No operands |Load byte at DS:[SI] into AL. Update SI. |
| | |Algorithm: |
| | |������ AL = DS:[SI] |
| | |������ if DF = 0 then |
| | |������ SI = SI + 1 |
| | |else |
| | |������ SI = SI - 1 |
| | |Example: |
| | |ORG 100h |
| | |LEA SI, a1 |
| | |MOV CX, 5 |
| | |MOV AH, 0Eh |
| | |m: LODSB |
| | |INT 10h |
| | |LOOP m |
| | |RET |
| | |a1 DB 'H', 'e', 'l', 'l', 'o' |
|LODSW |No operands |Load word at DS:[SI] into AX. Update SI. |
| | |Algorithm: |
| | |������ AX = DS:[SI] |
| | |������ if DF = 0 then |
| | |������ SI = SI + 2 |
| | |else |
| | |������ SI = SI - 2 |
| | |Example: |
| | |ORG 100h |
| | |LEA SI, a1 |
| | |MOV CX, 5 |
| | |REP LODSW ; finally there will be 555h in AX. |
| | |RET |
| | |a1 dw 111h, 222h, 333h, 444h, 555h |
|LOOP |label |Decrease CX, jump to label if CX not zero. |
| | |Algorithm: |
| | |������ CX = CX - 1 |
| | |������ if CX 0 then |
| | |������ jump |
| | |else |
| | |������ no jump, continue |
| | |Example: |
| | |include 'emu8086.inc' |
| | |ORG 100h |
| | |MOV CX, 5 |
| | |label1: |
| | |PRINTN 'loop!' |
| | |LOOP label1 |
| | |RET |
|LOOPE |label |Decrease CX, jump to label if CX not zero and |
| | |Equal (ZF = 1). |
| | |Algorithm: |
| | |������ CX = CX - 1 |
| | |������ if (CX 0) and (ZF = 1) then |
| | |������ jump |
| | |else |
| | |������ no jump, continue |
| | |Example: |
| | |; Loop until result fits into AL alone, |
| | |; or 5 times. The result will be over 255 |
| | |; on third loop (100+100+100), |
| | |; so loop will exit. |
| | |include 'emu8086.inc' |
| | |ORG 100h |
| | |MOV AX, 0 |
| | |MOV CX, 5 |
| | |label1: |
| | |PUTC '*' |
| | |ADD AX, 100 |
| | |CMP AH, 0 |
| | |LOOPE label1 |
| | |RET |
|LOOPNE |label |Decrease CX, jump to label if CX not zero and Not |
| | |Equal (ZF = 0). |
| | |Algorithm: |
| | |������ CX = CX - 1 |
| | |������ if (CX 0) and (ZF = 0) then |
| | |������ jump |
| | |else |
| | |������ no jump, continue |
| | |Example: |
| | |; Loop until '7' is found, |
| | |; or 5 times. |
| | |include 'emu8086.inc' |
| | |ORG 100h |
| | |MOV SI, 0 |
| | |MOV CX, 5 |
| | |label1: |
| | |PUTC '*' |
| | |MOV AL, v1[SI] |
| | |INC SI ; next byte (SI=SI+1). |
| | |CMP AL, 7 |
| | |LOOPNE label1 |
| | |RET |
| | |v1 db 9, 8, 7, 6, 5 |
|LOOPNZ |label |Decrease CX, jump to label if CX not zero and ZF |
| | |= 0. |
| | |Algorithm: |
| | |������ CX = CX - 1 |
| | |������ if (CX 0) and (ZF = 0) then |
| | |������ jump |
| | |else |
| | |������ no jump, continue |
| | |Example: |
| | |; Loop until '7' is found, |
| | |; or 5 times. |
| | |include 'emu8086.inc' |
| | |ORG 100h |
| | |MOV SI, 0 |
| | |MOV CX, 5 |
| | |label1: |
| | |PUTC '*' |
| | |MOV AL, v1[SI] |
| | |INC SI ; next byte (SI=SI+1). |
| | |CMP AL, 7 |
| | |LOOPNZ label1 |
| | |RET |
| | |v1 db 9, 8, 7, 6, 5 |
|LOOPZ |label |Decrease CX, jump to label if CX not zero and ZF |
| | |= 1. |
| | |Algorithm: |
| | |������ CX = CX – 1 |
| | |������ if (CX 0) and (ZF = 1) then |
| | |������ jump |
| | |else |
| | |������ no jump, continue |
| | |Example: |
| | |; Loop until result fits into AL alone, |
| | |; or 5 times. The result will be over 255 |
| | |; on third loop (100+100+100), |
| | |; so loop will exit. |
| | |include 'emu8086.inc' |
| | |ORG 100h |
| | |MOV AX, 0 |
| | |MOV CX, 5 |
| | |label1: |
| | |PUTC '*' |
| | |ADD AX, 100 |
| | |CMP AH, 0 |
| | |LOOPZ label1 |
| | |RET |
|MOV |REG, memory |Copy operand2 to operand1. |
| |memory, REG |The MOV instruction cannot: |
| |REG, REG |������ set the value of the CS and IP registers. |
| |memory, immediate |������ copy value of one segment register to |
| |REG, immediate |another segment register (should copy to |
| |SREG, memory |general register first). |
| |memory, SREG |������ copy immediate value to segment register |
| |REG, SREG |(should copy to general register first). |
| |SREG, REG |Algorithm: |
| | |operand1 = operand2 |
| | |Example: |
| | |ORG 100h |
| | |MOV AX, 0B800h ; set AX = B800h (VGA memory). |
| | |MOV DS, AX ; copy value of AX to DS. |
| | |MOV CL, 'A' ; CL = 41h (ASCII code). |
| | |MOV CH, 01011111b ; CL = color attribute. |
| | |MOV BX, 15Eh ; BX = position on screen. |
| | |MOV [BX], CX ; w.[0B800h:015Eh] = CX. |
| | |RET ; returns to operating system. |
|MOVSB |No operands |Copy byte at DS:[SI] to ES:[DI]. Update SI and |
| | |DI. |
| | |Algorithm: |
| | |������ ES:[DI] = DS:[SI] |
| | |������ if DF = 0 then |
| | |������ SI = SI + 1 |
| | |������ DI = DI + 1 |
| | |else |
| | |������ SI = SI - 1 |
| | |������ DI = DI - 1 |
| | |Example: |
| | |ORG 100h |
| | |CLD |
| | |LEA SI, a1 |
| | |LEA DI, a2 |
| | |MOV CX, 5 |
| | |REP MOVSB |
| | |RET |
| | |a1 DB 1,2,3,4,5 |
| | |a2 DB 5 DUP(0) |
|MOVSW |No operands |Copy word at DS:[SI] to ES:[DI]. Update SI and |
| | |DI. |
| | |Algorithm: |
| | |������ ES:[DI] = DS:[SI] |
| | |������ if DF = 0 then |
| | |������ SI = SI + 2 |
| | |������ DI = DI + 2 |
| | |else |
| | |������ SI = SI - 2 |
| | |������ DI = DI - 2 |
| | |Example: |
| | |ORG 100h |
| | |CLD |
| | |LEA SI, a1 |
| | |LEA DI, a2 |
| | |MOV CX, 5 |
| | |REP MOVSW |
| | |RET |
| | |a1 DW 1,2,3,4,5 |
| | |a2 DW 5 DUP(0) |
|MUL |REG memory |Unsigned multiply. |
| | |Algorithm: |
| | |when operand is a byte: |
| | |AX = AL * operand. |
| | |when operand is a word: |
| | |(DX AX) = AX * operand. |
| | |Example: |
| | |MOV AL, 200 ; AL = 0C8h |
| | |MOV BL, 4 |
| | |MUL BL ; AX = 0320h (800) |
| | |RET |
|NEG |REG |Negate. Makes operand negative (two's |
| |memory |complement). |
| | |Algorithm: |
| | |������ Invert all bits of the operand |
| | |������ Add 1 to inverted operand |
| | |Example: |
| | |MOV AL, 5 ; AL = 05h |
| | |NEG AL ; AL = 0FBh (-5) |
| | |NEG AL ; AL = 05h (5) |
| | |RET |
|NOP |No operands |No Operation. |
| | |Algorithm: |
| | |������ Do nothing |
| | |Example: |
| | |; do nothing, 3 times: |
| | |NOP |
| | |NOP |
| | |NOP |
| | |RET |
|NOT |REG |Invert each bit of the operand. |
| |memory |Algorithm: |
| | |������ if bit is 1 turn it to 0. |
| | |������ if bit is 0 turn it to 1. |
| | |Example: |
| | |MOV AL, 00011011b |
| | |NOT AL ; AL = 11100100b |
| | |RET |
|OR |REG, memory |Logical OR between all bits of two operands. |
| |memory, REG |Result is stored in first operand. |
| |REG, REG |These rules apply: |
| |memory, immediate |1 OR 1 = 1 |
| |REG, immediate |1 OR 0 = 1 |
| | |0 OR 1 = 1 |
| | |0 OR 0 = 0 |
| | |Example: |
| | |MOV AL, 'A' ; AL = 01000001b |
| | |OR AL, 00100000b ; AL = 01100001b ('a') |
| | |RET |
|OUT |im.byte, AL |Output from AL or AX to port. |
| |im.byte, AX |First operand is a port number. If required to |
| |DX, AL |access port number over 255 - DX register should |
| |DX, AX |be used. |
| | |Example: |
| | |MOV AX, 0FFFh ; Turn on all |
| | |OUT 4, AX ; traffic lights. |
| | |MOV AL, 100b ; Turn on the third |
| | |OUT 7, AL ; magnet of the stepper-motor. |
|POP |REG |Get 16 bit value from the stack. |
| |SREG |Algorithm: |
| |memory |������ operand = SS:[SP] (top of the stack) |
| | |������ SP = SP + 2 |
| | |Example: |
| | |MOV AX, 1234h |
| | |PUSH AX |
| | |POP DX ; DX = 1234h |
| | |RET |
|POPA |No operands |Pop all general purpose registers DI, SI, BP, SP, |
| | |BX, DX, CX, AX from the stack. SP value is ignored, it is Popped but not set to SP |
| | |register). |
| | |Note: this instruction works only on 80186 CPU |
| | |and later! |
| | |Algorithm: |
| | |������ POP DI |
| | |������ POP SI |
| | |������ POP BP |
| | |������ POP xx (SP value ignored) |
| | |������ POP BX |
| | |������ POP DX |
| | |������ POP CX |
| | |������ POP AX |
|POPF |No operands |Get flags register from the stack. |
| | |Algorithm: |
| | |������ flags = SS:[SP] (top of the stack) |
| | |������ SP = SP + 2 |
|PUSH |REG |Store 16 bit value in the stack. |
| |SREG |Note: PUSH immediate works only on 80186 |
| |memory |CPU and later! |
| |immediate |Algorithm: |
| | |������ SP = SP - 2 |
| | |������ SS:[SP] (top of the stack) = operand |
| | |Example: |
| | |MOV AX, 1234h |
| | |PUSH AX |
| | |POP DX ; DX = 1234h |
| | |RET |
|PUSHA |No operands |Push all general purpose registers AX, CX, DX, |
| | |BX, SP, BP, SI, DI in the stack. |
| | |Original value of SP register (before PUSHA) is |
| | |used. |
| | |Note: this instruction works only on 80186 CPU |
| | |and later! |
| | |Algorithm: |
| | |������ PUSH AX |
| | |������ PUSH CX |
| | |������ PUSH DX |
| | |������ PUSH BX |
| | |������ PUSH SP |
| | |������ PUSH BP |
| | |������ PUSH SI |
| | |������ PUSH DI |
|PUSHF |No operands |Store flags register in the stack. |
| | |Algorithm: |
| | |������ SP = SP - 2 |
| | |������ SS:[SP] (top of the stack) = flags |
|RCL |memory, immediate |Rotate operand1 left through Carry Flag. The |
| |REG, immediate |number of rotates is set by operand2. |
| |memory, CL |When immediate is greater then 1, assembler |
| |REG, CL |generates several RCL xx, 1 instructions because |
| | |8086 has machine code only for this instruction |
| | |(the same principle works for all other shift/rotate |
| | |instructions). |
| | |Algorithm: |
| | |shift all bits left, the bit that goes |
| | |off is set to CF and previous value of |
| | |CF is inserted to the right-most |
| | |position. |
| | |Example: |
| | |STC ; set carry (CF=1). |
| | |MOV AL, 1Ch ; AL = 00011100b |
| | |RCL AL, 1 ; AL = 00111001b, CF=0. |
| | |RET |
|RCR |memory, immediate |Rotate operand1 right through Carry Flag. The |
| |REG, immediate |number of rotates is set by operand2. |
| |memory, CL |Algorithm: |
| |REG, CL |shift all bits right, the bit that |
| | |goes off is set to CF and previous |
| | |value of CF is inserted to the leftmost |
| | |position. |
| | |Example: |
| | |STC ; set carry (CF=1). |
| | |MOV AL, 1Ch ; AL = 00011100b |
| | |RCR AL, 1 ; AL = 10001110b, CF=0. |
| | |RET |
|REP |chain instruction |Repeat following MOVSB, MOVSW, LODSB, |
| | |LODSW, STOSB, STOSW instructions CX times. |
| | |Algorithm: |
| | |check_cx: |
| | |if CX 0 then |
| | |������ do following chain instruction |
| | |������ CX = CX - 1 |
| | |������ go back to check_cx |
| | |else |
| | |������ exit from REP cycle |
|REPE |chain instruction |Repeat following CMPSB, CMPSW, SCASB, SCASW |
| | |instructions while ZF = 1 (result is Equal), |
| | |maximum CX times. |
| | |Algorithm: |
| | |check_cx: |
| | |if CX 0 then |
| | |������ do following chain instruction |
| | |������ CX = CX - 1 |
| | |������ if ZF = 1 then: |
| | |������ go back to check_cx |
| | |else |
| | |������ exit from REPE cycle |
| | |else |
| | |������ exit from REPE cycle |
|REPNE |chain instruction |Repeat following CMPSB, CMPSW, SCASB, SCASW |
| | |instructions while ZF = 0 (result is Not Equal), |
| | |maximum CX times. |
| | |Algorithm: |
| | |check_cx: |
| | |if CX 0 then |
| | |������ do following chain instruction |
| | |������ CX = CX - 1 |
| | |������ if ZF = 0 then: |
| | |������ go back to check_cx |
| | |else |
| | |������ exit from REPNE cycle |
| | |else |
| | |������ exit from REPNE cycle |
|REPNZ |chain instruction |Repeat following CMPSB, CMPSW, SCASB, SCASW |
| | |instructions while ZF = 0 (result is Not Zero), |
| | |maximum CX times. |
| | |Algorithm: |
| | |check_cx: |
| | |if CX 0 then |
| | |������ do following chain instruction |
| | |������ CX = CX - 1 |
| | |������ if ZF = 0 then: |
| | |������ go back to check_cx |
| | |else |
| | |������ exit from REPNZ cycle |
| | |else |
| | |������ exit from REPNZ cycle |
|REPZ |chain instruction |Repeat following CMPSB, CMPSW, SCASB, SCASW |
| | |instructions while ZF = 1 (result is Zero), |
| | |maximum CX times. |
| | |Algorithm: |
| | |check_cx: |
| | |if CX 0 then |
| | |������ do following chain instruction |
| | |������ CX = CX - 1 |
| | |������ if ZF = 1 then: |
| | |������ go back to check_cx |
| | |else |
| | |������ exit from REPZ cycle |
| | |else |
| | |������ exit from REPZ cycle |
|RET |No operands |Return from near procedure. |
| |or even immediate |Algorithm: |
| | |������ Pop from stack: |
| | |������ IP |
| | |������ if immediate operand is present: |
| | |SP = SP + operand |
| | |Example: |
| | |ORG 100h ; for COM file. |
| | |CALL p1 |
| | |ADD AX, 1 |
| | |RET ; return to OS. |
| | |p1 PROC ; procedure declaration. |
| | |MOV AX, 1234h |
| | |RET ; return to caller. |
| | |p1 ENDP |
|RETF |No operands |Return from Far procedure. |
| |or even immediate |Algorithm: |
| | |������ Pop from stack: |
| | |������ IP |
| | |������ CS |
| | |������ if immediate operand is present: |
| | |SP = SP + operand |
|ROL |memory, immediate |Rotate operand1 left. The number of rotates is set |
| |REG, immediate |by operand2. |
| |memory, CL |Algorithm: |
| |REG, CL |shift all bits left, the bit that goes |
| | |off is set to CF and the same bit is |
| | |inserted to the right-most position. |
| | |Example: |
| | |MOV AL, 1Ch ; AL = 00011100b |
| | |ROL AL, 1 ; AL = 00111000b, CF=0. |
| | |RET |
|ROR |memory, immediate |Rotate operand1 right. The number of rotates is |
| |REG, immediate |set by operand2. |
| |memory, CL |Algorithm: |
| |REG, CL |shift all bits right, the bit that |
| | |goes off is set to CF and the same bit |
| | |is inserted to the left-most position. |
| | |Example: |
| | |MOV AL, 1Ch ; AL = 00011100b |
| | |ROR AL, 1 ; AL = 00001110b, CF=0. |
| | |RET |
|SAHF |No operands |Store AH register into low 8 bits of Flags register. |
| | |Algorithm: |
| | |flags register = AH |
| | |AH bit: 7 6 5 4 3 2 1 0 |
| | |[SF] [ZF] [0] [AF] [0] [PF] [1] [CF] |
| | |bits 1, 3, 5 are reserved. |
|SAL |memory, immediate |Shift Arithmetic operand1 Left. The number of |
| |REG, immediate |shifts is set by operand2. |
| |memory, CL |Algorithm: |
| |REG, CL |������ Shift all bits left, the bit that goes |
| | |off is set to CF. |
| | |������ Zero bit is inserted to the right-most |
| | |position. |
| | |Example: |
| | |MOV AL, 0E0h ; AL = 11100000b |
| | |SAL AL, 1 ; AL = 11000000b, CF=1. |
| | |RET |
|SAR |memory, immediate |Shift Arithmetic operand1 Right. The number of |
| |REG, immediate |shifts is set by operand2. |
| |memory, CL |Algorithm: |
| |REG, CL |������ Shift all bits right, the bit that |
| | |goes off is set to CF. |
| | |������ The sign bit that is inserted to the |
| | |left-most position has the same value |
| | |as before shift. |
| | |Example: |
| | |MOV AL, 0E0h ; AL = 11100000b |
| | |SAR AL, 1 ; AL = 11110000b, CF=0. |
| | |MOV BL, 4Ch ; BL = 01001100b |
| | |SAR BL, 1 ; BL = 00100110b, CF=0. |
| | |RET |
|SBB |REG, memory |Subtract with Borrow. |
| |memory, REG |Algorithm: |
| |REG, REG |operand1 = operand1 - operand2 - CF |
| |memory, immediate |Example: |
| |REG, immediate |STC |
| | |MOV AL, 5 |
| | |SBB AL, 3 ; AL = 5 - 3 - 1 = 1 |
| | |RET |
|SCASB |No operands |Compare bytes: AL from ES:[DI]. |
| | |Algorithm: |
| | |������ AL - ES:[DI] |
| | |������ set flags according to result: |
| | |OF, SF, ZF, AF, PF, CF |
| | |������ if DF = 0 then |
| | |������ DI = DI + 1 |
| | |else |
| | |������ DI = DI - 1 |
|SCASW |No operands |Compare words: AX from ES:[DI]. |
| | |Algorithm: |
| | |������ AX - ES:[DI] |
| | |������ set flags according to result: |
| | |OF, SF, ZF, AF, PF, CF |
| | |������ if DF = 0 then |
| | |������ DI = DI + 2 |
| | |else |
| | |������ DI = DI - 2 |
|SHL |memory, immediate |Shift operand1 Left. The number of shifts is set |
| |REG, immediate |by operand2. |
| |memory, CL |Algorithm: |
| |REG, CL |������ Shift all bits left, the bit that goes |
| | |off is set to CF. |
| | |������ Zero bit is inserted to the right-most |
| | |position. |
| | |Example: |
| | |MOV AL, 11100000b |
| | |SHL AL, 1 ; AL = 11000000b, CF=1. |
| | |RET |
|SHR |memory, immediate |Shift operand1 Right. The number of shifts is set |
| |REG, immediate |by operand2. |
| |memory, CL |Algorithm: |
| |REG, CL |������ Shift all bits right, the bit that |
| | |goes off is set to CF. |
| | |������ Zero bit is inserted to the left-most |
| | |position. |
| | |Example: |
| | |MOV AL, 00000111b |
| | |SHR AL, 1 ; AL = 00000011b, CF=1. |
| | |RET |
|STC |No operands |Set Carry flag. |
| | |Algorithm: |
| | |CF = 1 |
|STD |No operands |Set Direction flag. SI and DI will be decremented |
| | |by chain instructions: CMPSB, CMPSW, LODSB, |
| | |LODSW, MOVSB, MOVSW, STOSB, STOSW. |
| | |Algorithm: |
| | |DF = 1 |
|STI |No operands |Set Interrupt enable flag. This enables hardware |
| | |interrupts. |
| | |Algorithm: |
| | |IF = 1 |
|STOSB |No operands |Store byte in AL into ES:[DI]. Update DI. |
| | |Algorithm: |
| | |������ ES:[DI] = AL |
| | |������ if DF = 0 then |
| | |������ DI = DI + 1 |
| | |else |
| | |������ DI = DI - 1 |
| | |Example: |
| | |ORG 100h |
| | |LEA DI, a1 |
| | |MOV AL, 12h |
| | |MOV CX, 5 |
| | |REP STOSB |
| | |RET |
| | |a1 DB 5 dup(0) |
|STOSW |No operands |Store word in AX into ES:[DI]. Update DI. |
| | |Algorithm: |
| | |������ ES:[DI] = AX |
| | |������ if DF = 0 then |
| | |������ DI = DI + 2 |
| | |else |
| | |������ DI = DI - 2 |
| | |Example: |
| | |ORG 100h |
| | |LEA DI, a1 |
| | |MOV AX, 1234h |
| | |MOV CX, 5 |
| | |REP STOSW |
| | |RET |
| | |a1 DW 5 dup(0) |
|SUB |REG, memory |Subtract. |
| |memory, REG |Algorithm: |
| |REG, REG |operand1 = operand1 - operand2 |
| |memory, immediate |Example: |
| |REG, immediate |MOV AL, 5 |
| | |SUB AL, 1 ; AL = 4 |
| | |RET |
|TEST |REG, memory |Logical AND between all bits of two operands for |
| |memory, REG |flags only. These flags are effected: ZF, SF, PF. |
| |REG, REG |Result is not stored anywhere. |
| |memory, immediate |These rules apply: |
| |REG, immediate |1 AND 1 = 1 |
| | |1 AND 0 = 0 |
| | |0 AND 1 = 0 |
| | |0 AND 0 = 0 |
| | |Example: |
| | |MOV AL, 00000101b |
| | |TEST AL, 1 ; ZF = 0. |
| | |TEST AL, 10b ; ZF = 1. |
| | |RET |
|XCHG |REG, memory |Exchange values of two operands. |
| |memory, REG |Algorithm: |
| |REG, REG |operand1 < - > operand2 |
| | |Example: |
| | |MOV AL, 5 |
| | |MOV AH, 2 |
| | |XCHG AL, AH ; AL = 2, AH = 5 |
| | |XCHG AL, AH ; AL = 5, AH = 2 |
| | |RET |
|XLATB |No operands |Translate byte from table. |
| | |Copy value of memory byte at |
| | |DS:[BX + unsigned AL] to AL register. |
| | |Algorithm: |
| | |AL = DS:[BX + unsigned AL] |
| | |Example: |
| | |ORG 100h |
| | |LEA BX, dat |
| | |MOV AL, 2 |
| | |XLATB ; AL = 33h |
| | |RET |
|XOR |REG, memory |Logical XOR (Exclusive OR) between all bits of |
| |memory, REG |two operands. Result is stored in first operand. |
| |REG, REG |These rules apply: |
| |memory, immediate |1 XOR 1 = 0 |
| |REG, immediate |1 XOR 0 = 1 |
| | |0 XOR 1 = 1 |
| | |0 XOR 0 = 0 |
| | |Example: |
| | |MOV AL, 00000111b |
| | |XOR AL, 00000010b ; AL = 00000101b |
| | |RET |

Similar Documents

Free Essay

Asdsad

...Introduction Antitrust laws are essentially a series of highly interpretable and ever-changing guidelines meant to encourage stable competition between businesses; in essence they are laws to protect against anti-competitive monopolists and conspiracies. What is US antitrust law? US antitrust law is essentially competition law. The term “antitrust” refers to the colossal trusts which were set up in the US in the late 1800s to control entire markets for petroleum, transport, banking, rail and other industry sectors. However, these trusts undermined free market economics by restricting competition, and the US antitrust laws were enacted to redress this issue. Consequently it is fair to say that defending the right of businesses to compete is the true purpose of antitrust law. An anticompetitive practice that is harmful to a business or its customers will find no antitrust law protection. The antitrust laws come only into effect when competitors collude with one another to undermine legitimate competition; or one of more competitors attempt to exclude another competitor to create or preserve a monopoly on their position; or if a proposed merger, acquisition or exclusive supplier agreement threatens to reduce competition in an unacceptable manner. In each of these instances there is a threat that the predatory corporate could increase prices without this having an effect on demand since the consumer has no-one else to purchase the goods from. This, in effect, distorts competition...

Words: 570 - Pages: 3

Premium Essay

Asdsad

...JAN MAVERICH G. GARCIA BSHRM 2Y1-8 10/11/14 FRIENDSHIP AND IMPORTANCE ROLE THAT IT PLAYS IN OUR LIVES Good morning to the honourable professors, classmates and my fellow friends. I standing here to deliver a speech about FRIENDSHIP and THE IMPORTANT ROLE THAT IT PLAYS IN OUR LIVES. Firstly, let me ask all of you, WHAT IS FRIENDSHIP? …. well, friendship consists of true friends that can make you laugh when skies are the darkest, true friends that will even hurt you only if it’s for your own good, friends that protect you under any circumstances and friends that will make you feel like you’re on the top of the world when you’re feeling crushed to the ground. My fellow audiences, Have you ever noticed that when a friend is happy you find yourself happy too, even it has nothing to do with you? A true friend is like a mirror. Do you know why? It’s because they reflect you. When I say that, I mean by emotionally, spiritually and many more. When you’re happy, they’re happy and when you’re sad, they’re feeling pretty much the same way you’re feeling too. People today, in this new era of technology and mordancy have lost sight of what a true friendship is. Friends do not have to be exactly the same, I mean, come on, friends do have similarities but they also have their differences. The key to opening up the world of friendship is not just to focus on the similarities but to accept each other’s faults because true friends do not judge each other. Friends love...

Words: 371 - Pages: 2

Free Essay

Asdsad

...Task 4: Aim to sell the products and maximize the profits, Truong Thanh Furniture Corporation (TTFC) has to determine the target market. There are two major types of market including Business- to- Business (B2B) and Business- to- Customer (B2C). The terms B2B and B2C were developed to make a major choice whether they sell to consumers or others businesses that need products or corporate to manufacture or distribute. B2B refers to the potential market being a business and the primary activities are business-to-business sales. In the contrast, the term B2C refers to a business-to-consumer sales situation. | Business to Business (B2B)B2B refers to business model in which trading and exchanging directly between businesses. Transactions with other companies usually occur as manufacturers selling to distributors and wholesalers selling to retailers.Pricing is based on the quantity of order and is often negotiable. | Business to Customer (B2C)B2C is included commercial transactions over the Internet between businesses and customers, in which customers of this type is that individuals purchase. This type applies to any business or organization to sell their products or services to customers for personal needs. | Target customer | Customers of B2B transactions are companies, while B2C customer are individuals. Considering the letter C in B2C is the final consumer (end-user). This also means that C refers to companies, which buy products to use.Overall, B2B transactions are more...

Words: 1726 - Pages: 7

Free Essay

Asdsads

...Sdasdasdsadasd sad ssds d asd asd sad fw qewq e we wqe we ewe Sdasdasdsadasd sad ssds d asd asd sad fw qewq e we wqe we ewe Sdasdasdsadasd sad ssds d asd asd sad fw qewq e we wqe we ewe Sdasdasdsadasd sad ssds d asd asd sad fw qewq e we wqe we ewe Sdasdasdsadasd sad ssds d asd asd sad fw qewq e we wqe we ewe Sdasdasdsadasd sad ssds d asd asd sad fw qewq e we wqe we ewe Sdasdasdsadasd sad ssds d asd asd sad fw qewq e we wqe we ewe Sdasdasdsadasd sad ssds d asd asd sad fw qewq e we wqe we ewe Sdasdasdsadasd sad ssds d asd asd sad fw qewq e we wqe we ewe Sdasdasdsadasd sad ssds d asd asd sad fw qewq e we wqe we ewe Sdasdasdsadasd sad ssds d asd asd sad fw qewq e we wqe we ewe Sdasdasdsadasd sad ssds d asd asd sad fw qewq e we wqe we ewe Sdasdasdsadasd sad ssds d asd asd sad fw qewq e we wqe we ewe Sdasdasdsadasd sad ssds d asd asd sad fw qewq e we wqe we ewe Sdasdasdsadasd sad ssds d asd asd sad fw qewq e we wqe we ewe Sdasdasdsadasd sad ssds d asd asd sad fw qewq e we wqe we ewe Sdasdasdsadasd sad ssds d asd asd sad fw qewq e we wqe we ewe Sdasdasdsadasd sad ssds d asd asd sad fw qewq e we wqe we ewe Sdasdasdsadasd sad ssds d asd asd sad fw qewq e we wqe we ewe Sdasdasdsadasd sad ssds d asd asd sad fw qewq e we wqe we ewe Sdasdasdsadasd sad ssds d asd asd sad fw qewq e we wqe we ewe Sdasdasdsadasd sad ssds d asd asd sad fw qewq e we wqe we ewe Sdasdasdsadasd sad ssds d asd asd sad fw qewq e we wqe we ewe Sdasdasdsadasd sad ssds d asd...

Words: 574 - Pages: 3

Free Essay

Test

...sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd as dsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd asdsad sadsaD SAd...

Words: 60215 - Pages: 241

Free Essay

Blah

...Bhjshdja sdada asdsad asdsada asdadsa asdsad sadas asd asd sada ere werewr rwerwer wer4tu yytuity Bhjshdja sdada asdsad asdsada asdadsa asdsad sadas asd asd sada ere werewr rwerwer wer4tu yytuity Bhjshdja sdada asdsad asdsada asdadsa asdsad sadas asd asd sada ere werewr rwerwer wer4tu yytuity Bhjshdja sdada asdsad asdsada asdadsa asdsad sadas asd asd sada ere werewr rwerwer wer4tu yytuity Bhjshdja sdada asdsad asdsada asdadsa asdsad sadas asd asd sada ere werewr rwerwer wer4tu yytuity Bhjshdja sdada asdsad asdsada asdadsa asdsad sadas asd asd sada ere werewr rwerwer wer4tu yytuity Bhjshdja sdada asdsad asdsada asdadsa asdsad sadas asd asd sada ere werewr rwerwer wer4tu yytuity Bhjshdja sdada asdsad asdsada asdadsa asdsad sadas asd asd sada ere werewr rwerwer wer4tu yytuity Bhjshdja sdada asdsad asdsada asdadsa asdsad sadas asd asd sada ere werewr rwerwer wer4tu yytuity Bhjshdja sdada asdsad asdsada asdadsa asdsad sadas asd asd sada ere werewr rwerwer wer4tu yytuity Bhjshdja sdada asdsad asdsada asdadsa asdsad sadas asd asd sada ere werewr rwerwer wer4tu yytuity v Bhjshdja sdada asdsad asdsada asdadsa asdsad sadas asd asd sada ere werewr rwerwer wer4tu yytuity Bhjshdja sdada asdsad asdsada asdadsa asdsad sadas asd asd sada ere werewr rwerwer wer4tu yytuity Bhjshdja sdada asdsad asdsada asdadsa asdsad sadas asd asd sada ere werewr rwerwer wer4tu yytuity Bhjshdja sdada asdsad asdsada asdadsa asdsad sadas asd asd sada ere werewr rwerwer wer4tu...

Words: 406 - Pages: 2

Free Essay

Yes Itis

...Asasdasdasd Asdd A Adsa Sd Asdadasdas Asasdasd Asasd Asdasdasdasas Dsadad adasdas asd asd asdasd a adasdsadas ass a sad asdsa d as dsa d asd asd ad e r f dsfd dfdfasde sd sdsadf dgfsdfdf sdf df asdfdfd df df dsf dsf sad add sad asd asdd sad asa dsas dasd assd asad ads asad sad asad sad sad asd sd ad asd asd asd asda ad asd ad asd asdsdasd ad adadasd ads adasdaasd asd asdsad sad sad sad sad sd asd sad sad sad asd asd Sssssssssssssssssssssssssssssdada Ad Ad A Da A Ds Da D Ada Da Sda Sda Sda Sda Sd Asd Asd Asd Asd Asd Asd Sad Asd Asd Asd Ad Asd As Dasd As Das Da Da Sda Sd Asd Sad Sad Asdasdsada Ad Asd Ad Adasd Asd Asd Asd Asd Asd Dasdasdasd Asasdasdasd Asdd A Adsa Sd Asdadasdas Asasdasd Asasd Asdasdasdasas Dsadad adasdas asd asd asdasd a adasdsadas ass a sad asdsa d as dsa d asd asd ad e r f dsfd dfdfasde sd sdsadf dgfsdfdf sdf df asdfdfd df df dsf dsf sad add sad asd asdd sad asa dsas dasd assd asad ads asad sad asad sad sad asd sd ad asd asd asd asda ad asd ad asd asdsdasd ad adadasd ads adasdaasd asd asdsad sad sad sad sad sd asd sad sad sad asd...

Words: 275 - Pages: 2

Free Essay

Nothing

...Dasdasdas dasd dasda dsada das dasd sadas dasd asdasd adas gghg hg g g g dsada s asd as dasd asd asd asd a dasd asd asd asd asd a dasd asd as das as dasd asd asd asdsa das das das asd as das dasdasd asd asd asd asd as das dasd asd asdas sa dasd asd asd asd as dasd as das dasd asd as das dasd asd asd asd as das dasd asdasd asd asd as dasd as dasdasd asd asdsad asd asdas das dasd asd asdas das das das das dasd dsadasdadasda adsas das das das das dasd asdjasjd asj dajsd jasdj asj dasjd jasdj asjd asjd ashdghags dhagsdh gashg dasg dagsd gashdg hasg dhas gdjasg dhjags dhags dhgashdg hags dhasgd hasgd hgas dhgashdg dsaj gdjhasgd hasgd hjasgdh asdg asgd hasgd hasg dhagshd ghas dhsaj dasjdg ahsg dhash dashg dahsg dhas dhash dgahsg dhagsh dgash dhsagd hags hdash dahsgd ahsgd hashg dhas gdhas dhas das das dasd asd asdasd as dasd wq e sadasd wq dasd asd qwd asdasd qw easd aseqw sadqwe asd aseqw dsad qw as dqwe sdasdqw sdsdas das das das dasd asd asd sa dasdasdasda das das dasd asd as dasdasid uhywu duq dyqgd yqgd yqg dyq y dqyd gqdqydg yqdgqy dqg dqydgyqdqg dyqdgyqdg as as das das dasd asdhgash dgashdghasg ha a hg ahgd has dg ghasdg hasdg hasgd hags dh gashdg ashgdha gdhag hsadg ashdg ahsdg hasgd has dashdg ahsd hasgd has hdgahg ahsg dhgas hagda sda asd asd as...

Words: 251 - Pages: 2

Premium Essay

Analysis: Five Tips To Get Organized At Work

...Sherrie Bourg Carter writes “keep a notebook close by” (ASDSAD). By having a notebook it allows you to jot down notes rather than having to remember things that someone tells you. People are not going to remember everything off the top of their head. Writing them thoughts down will help keep people on track. Notes will also help you remember things that still have to get done. In the article it states “labeling not only helps you stay better organized, it also helps others function more independently in your workspace” (SDFDSFDS). Labeling file folders is another thing that helps someone stay organized because it allows you to organize the file folders alphabetically, or by date. This way when your boss asks for a file folder you can easily reach in and grab the one that you are looking for....

Words: 768 - Pages: 4