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Chemical Reaction Lab

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Analysis of a Chemical Reaction

Procedure Questions:

What do you observe?
We observed a white, chalky precipitate forming in the limewater test tube.

What does this result indicate?
This result indicates that carbon dioxide gas was formed by heating the test tube of NaHCO3.

What did you observe in the test tube that you heated?
We observed the condensation of water vapour on the mouth of the heated test tube.

What does this indicate?
This result indicates that water molecules were formed during the reaction.

Based on these two qualitative observations which of the four possible reactions can be rules out?
Synthesis can be ruled out due to the formation of multiple products from a single substance. Single displacement can be ruled out because the products were both compounds formed from a single substance. Double displacement can be ruled out because there was only one reactant. Lastly, combustion can be ruled out because the reactant did not require …show more content…
What are the values of these ratios?

NaHCO3 (s) ➡ NaOH(s) + CO2 (g)
Ratio: 84.0/40.0 = 2.1
2NaHCO3 (s) ➡ Na2CO3 (s) + CO2 (g) + H2O(g)
Ratio: 168.0/105.9 = 1.6
2NaHCO3 (s) ➡ Na2O (s) + 2CO2 (g) + H2O(g)
Ratio: 168.0/61.9 = 2.7
4NaHCO3 (s) ➡ 2Na2C2O4 (s) + O2 (g) + 2H2O(g)
Ratio: 336.0/268.0 = 1.3

Which of these ratios agrees with the experimentally determined ratio?
The ratio of 1.6 in the second equation agrees most with the experimentally determined ratio of 1.4. Even though the ratio of 1.3 in the fourth equation is also close to the experimentally determined ratio, it is not possible for there to be more product in the experimental yield than in the theoretical yield, assuming all the gas products escapes. I know this because matter can not be created nor destroyed as explained in the law of conservation of mass.

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