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Submitted By wrightlaura
Words 1867
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3-1
A.
1. 3 YEARS 1837.56 1500X (1+.07) third power = 1837.56 2. 6 YEARS 2251.09 1500x(1.07)sixth power=2251.09 3. 9 YEARS 2757.68 1500(1.07) ninth power=2757.68
B.
1. 1st year 105, 2nd year 112.35, 3rd year 120.21 for a total of 337.56
For the first year you have 1500 x .07 which equals 105. and the .07 in all the equations below is because it is 7% interest.
1500 X .07= 105
Since it is compound interest then for year two I add the 105 to 1500 which equals 1605.
105+1500=1605
Then you must calculate the interest for year two you multiply 1605 by .07 which equals 112.35
1605 X .07 = 112.35 and again it is compound interest so you add the 112.35 to 1605 which equals 1717.35
112.35 + 1605= 1717.35 so then I calculated the interest for year three 1717.35x .07=120.21 So since the question what interest for all three years I add
105 + 112.35 + 120.21= 337.56

2. 4th year 128.63, 5th year 137.63, 6th year 147.26 for a total of 413.52
So since we are in the fourth year we start with 1717.35 plus the interest 120.21 from year three which gives a total of 1837.56.
1717.35 + 120.21=1837.56
To calculate that interest for that you would take 1837.56 x .07=128.6292.
Of course I am going to round up to 128.63.
So for the fifth year I add 128.63 to 1837.56 which equals 1966.19
128 + 1837.56=1966.19
Then to calculate that interest I take 1966.19 and multiply it by .07
1966.19 x .07=137.63
Then for the sixth year I add 137.63 to 1966.19 which equals 2103.82
137.63 + 1966.19=2103.82
Then I calculate the interest for year six 2103.82 x .07= 147.2674
So I add all three interests 128.63 + 137.63 + 147.26 = 413.52

3. 7th year 157.57, 8th year 168.60, 9th year 180.40 for a total of 506.57
So now at year seven we would take year six start plus interest earned
2103.82 + 147.26 =2251.08
Then to calculate the

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