...Fourier Transform and its applications Jatin Kumar Murray State University Abstract It has been widely recognized that waveforms are an integral part of the various universe phenomenon. Waveforms can be used to represent almost everything in the world. Therefore it is understandable that concepts related to waveforms or signals are extremely important as their applications exist in a broad variety of fields. The processes and ideas related to waveforms play a vital role in different areas of science and technology such as communications, optics, quantum mechanics, aeronautics, image processing to name a few. Even though the physical nature of signals might be completely different in various disciplines, all waveforms follow one fundamental principle; they can be represented by functions of one or more independent variables. This paper would focus on the concept of Fourier Transform, the technique through which signals can be deconstructed and represented as sum of various elementary signals. It briefly describes Linear Time Invariant systems and their response to superimposed signals. Fourier transform has many applications in physics and Engineering. This paper would also cover some of Fourier Transform applications in telecommunication and its impact on society. Introduction Some of the basic signals that exist in the world and are useful in various technology fields are continuous and discrete time...
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...Lab 2: Linear Time-Invariant Systems In this experiment, you will study the output response of linear time-invariant (LTI) systems using MATLAB, and learn how to use MATLAB to implement the convolution sum. You will also investigate the properties of LTI systems. The objective of this experiment is: (1) to study how to compute the output of LTI systems, and (2) to study the properties of discrete-time LTI systems. 1. Introduction to Linear Time-Invariant (LTI) Systems In discrete time, linearity provides the ability to completely characterize a system in terms of its response [pic] to a signal of the form [pic] for all [pic]. If a linear system is also time-invariant, then the responses [pic] will become [pic]. The combination of linearity and time-invariance therefore allows a system to be completely described by its impulse response [pic]. The output of the system [pic] is related to the input [pic] through the convolution sum as follows: [pic] Similarly, the output [pic] of a continuous-time LTI system is related to the input [pic] and the impulse response [pic] through the following convolution integral: [pic] The convolution of discrete-time sequences [pic] and [pic] represented mathematically by the expression given in [pic] can be viewed pictorially as the operation of flipping the time axis of the sequence [pic] and shifting it by [pic] samples, then multiplying [pic] by[pic] and summing the resulting product sequence...
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...Signals and Systems Midterm 10:20a.m. ~ 12:20p.m., May 1, Fri., 2009 Closed book, but open 1 sheet (both sides, 2 pages) of personal notes of A4 size Total score: 120 Total 4 pages in one B4 sheet 1. [12] Suppose x and y denote input and output, respectively, of each of the three systems: System A: y (t ) = x(t + 2) sin(ω t + 2), ω ≠ 0 System B: y[n] = ( − 1 ) ( x[n] + 1) 2 System C: y[n] = ∑ x 2 [k + 1] − x[k ] k =1 n n Answer the following questions for each system and justify your answer. (a) Is the system linear? (b) Is the system time invariant? (c) Is the system causal? (d) Is the system stable? 2. We want to develop an edge detector that is robust against additive noise. Consider a discrete-time (DT) linear time-invariant (LTI) system H 2 with h2 [ n] = h[ n] ∗ h[ n + 1] as its impulse response shown below, where h[ n] = δ [ n] − δ [ n − 1] . (a) [4] Assume there is no noise, i.e., d [n] = 0 and x[n] = p[n] . Sketch the output y[n] of the system assuming the input p[n] to the system is the following signal: (b) [4] Assume the noise is d [ n] = −δ [ n + 1] and the input p[n] remains the same. Sketch the output y[n] of the system. (c) [4] In order to use system H 2 as a part of an edge detector, we would like to add an LTI system H s whose unit impulse response hs [n] is shown below. System H s smoothes out effect of noise on x[n] . The overall system can be represented as below: Sketch the output ys [n] of the system with d [n] and p[n] specified...
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...INSS 370 Final Exam Study Guide Below is a study guide for your final exam. There will be a combination of true/false and multiple choice questions. 1. Who is responsible for prioritizing the product backlog? 2. What does a burn‐down chart show? 3. What are the principles outlined in the Agile Software Development Manifesto? 4. If our highest priority is to satisfy the customer through early and continuous delivery of valuable software, in general, how can we do that? 5. In agile software processes are the highest priorities to satisfy the customer through early and continuous delivery of valuable software? 6. What traits need to exist among the members of an agile software team? 7. In agile development is it more important to build software that meets the customers' needs today than worry about features that might be needed in the future? 8. The ____ phase of the SDLC includes four main activities: requirements modeling, data and process modeling, object modeling, and consideration of development strategies. 9. One of the main activities in the systems analysis phase is ____ modeling, which involves fact‐finding to describe the current system and identification requirements for the new system. 10. How is planning performed on projects that use Agile approaches? 11. Who should be the main judge of the business value (think of the various roles within an agile team)? 12. How should work be allocated and who should allocate the work to the team in an Agile ...
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...Identifying Good or Bad Statements Anit Maharjan HUMN210-H5WW Meghan Roehll Franklin University 4th April, 2013 a. Nobody in the world today is really good. Yes, I have heard of good people, but not really good people. - Good statement. b. The world is not flat. Well, if you look at a map it is: - in what point of view - bad statement. c. I will need an extended period of laborious cogitation to assimilate the missive. This doesn't make any sense - bad statement. d. The number 2 is odd. Are we talking about an even number? I believe your confusion comes from the fact that 2 is a prime number, but it is still even. It is the only even number that is prime – false statement. e. If you believe in evolution, then your ancestors were filthy apes. There are two kinds of people in the world: - one is god prayer and the next is science believer. If you support the statement from the point of scientific theory of evolution by Darwin, then yes our ancestors are filthy apes, whereas if you think form the side of god’s prayer then the statement is false – good statement. f. Some swans are black. In this statement, I am not sure that some swans are black or not, all swans could be black or white – good statement. g. If you are a human, then you are a person. If you are an individual, then you are alive. Human is a person and of course the person becomes an individual and every individual breaths...
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...អាណាចក្រភ្នំ អាណាចក្រភ្នំ គស 50-630 ទីតាំង * ៣០០លី លិចលីនីយ(ជនជាតិចាម) * ៧០០០លី Jenan(តុងកឹង) * ឈូងសមុទ្រធំមួយ * ទន្លេរធំមួយ លិចនឹងពាយព្យគឺសមុទ្រ * ១លី=៥៧៦ម=១៧២៨គម=> 1. កម្ពុជា 2. កម្ពុជាក្រោម 3. ថៃ(ភាគកណ្តាល) រាជវង្សមាន៖ 1. លីវយី(៥០-៦៨) 2. ហ៊ុនទៀន(៦៨) 3. ហ៊ុនប៉ានហួង៖ដែលជាមេទ័ពបានប្រើល្បិចវាយក្រុងទាំង៧នឹងបានដណ្តើមអំណាចពីព្រះ បាទហ៊ុនទៀន 4. ហ៊ុនប៉ានប៉ាង៖ជាកូនហ៊ុនប៉ានហួង 5. ហ្វាន់ជេម៉ាន់៖ជាអ្នកសំលាប់សោយរាជ្យបន្តរឺក៍ហ៊ុនប៉ានប៉ាងផ្ទេរអំណាចអោយ 6. គិនចេង(២២៥)៖ត្រូវជាកូនរបស់របស់ហ្វាន់ជេម៉ាន់ពីព្រោះគាត់បានស្លាប់ពេលវាយ នៅ គិនស៊ីន 7. ហ្វានឆាន(២២៥-២៤៥)៖បានសំលាប់គិនចេងដើម្បីសោយរាជ្យបន្តដែលត្រូវជាក្មួយហ្វាន់ជេម៉ាន់នឹងត្រូវជាបងប្អូនគិនចេង 8. ហ្វានឆាង(២៤៥-២៥០)៖ជាកូនពៅរបស់ហ្វានជេម៉ាន់បានមកសងសឹកនឹងសោយរាជ្យបន្ត 9. ហ្វានស៊ីយ៉ុន(២៥០-២៨៩)៖បានសំលាប់ហ្វានឆាងសោយរាជ្យបន្ត 10. ធៀនឈូឆានតាន(៣៥៧) 11. កៅណ្ឌិន្យ(៣៥៧)៖គាត់មានកូនពីរគឺស្រីឥន្រ្ទវរ្ម័ននឹងស្រេស្ធវរ្ម័ន 12. កៅណ្ឌិន្យជ័យវរ្ម័ន(៤៤២-៥១៤)៖មានបុត្រាពីរគឺគុណវរ្ម័នជាប្អូននឹងរុទ្រវរ្ម័នជាបងក៍ប៉ុន្តែគុណវរ្ម័នជាអ្នកសោយរាជ្យដែលត្រូវជាកូនកុលប្រភាវតីជាមហេសីរីឯរុទ្រវរ្ម័នជាកូនស្នំ។ដោយមិនសុខចិត្តព្រោះខ្លួនជាបងមិនបានសោយរាជ្យក៍ប្រើល្បិចសំលាប់ប្អូនដើម្បី សោយរាជ្យម្តង។ 13. គុណវរ្ម័ន 14. ចេនឡា ចេនឡា រុទ្រវរ្ម័ន(៥១៤-៥៥៦) គស ៥៥០-៨០២ 15. ឥសីកម្ពុស្វយម្ហូវ៖ 16. ស្រុតវរ្ម័ន៖ 17. ស្រស្ធវរ្ម័ន៖ 18. វីរវរ្ម័ន៖ 19. ភវរ្ម័ន(៩០០-៩២២)៖ * ទីតាំងរបស់ចេនឡានៅត្រង់តំបន់បាសាក់តាមដងទន្លេរមេគង្គដែលច្ចុប្បន្ននៅភាគ អាគ្នេយ៍ប្រទេសឡាវ...
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...– – – – • – – • – • • • • – – – – • • • – – – – – – Wood Stick Holder Premium Wood Stick Holder Glow in the Dark Stick Holder Brass Burner Premium Brass Burner Aroma Ring Votive Holder NIPPON KODO INCENSE HERB & EARTH STICKS STICKS Classic STICKS CONES AFRICAN AMERICAN Family Unity – – Rhythm Sensuality Spirituality • • • • Bergamot Cedar • • • Fashion & Style • Number 4 - 100-st Number 6 - 100-st Chamomile Frankincense Jasmine Lavender Orange Patchouli Peppermint Rose Sandalwood Vanilla GONESH DIFFUSER SETS 3 fl.oz. Coconut Lime Mango Peach Sweet Apple Vanilla Cream REFILLS - 6 oz Coconut Lime Mango Peach Sweet Apple Vanilla Cream HOLIDAY TRADITIONS Number 8 - 100-st Number 10 Number 12 Number 14 Variety 1 (6,8,12) - 30 st Variety 2 (2,4,10) - 30 st MORNING STAR STICKS GONESH® EXTRA RICH Amber Apple Cider Jasmine Lavender Sandalwood Christmas Dream (Winter) Nutcracker Dance (Winter) Snowy Sensations (Winter) Holiday Memories (Winter) SCENTED REEDS & OILS REEDS OILS Black Cherry Cedarwood Cherry Blossom Cinnamon Coconut Dragon’s Blood...
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...Mr. Weidenboerner Period 7 Purpose: To explore sensors and use them to knock down a box filled with bean bags without going over the edge of a precipice. Hypothesis: I think that designs with a high point of impact and and sensor placed out in front of the robot will have the best results. Group 2 | Trial | Distance from the Egde | 1 | 28 mm | 2 | 32 mm | 3 | 35 mm | 4 | 22 mm | 5 | fail | Average | 32 mm | Competion | Group | Average | 1 | 23 mm | 2 | 32 mm | 3 | fail | 4 | 7 mm | Program Flow: 1. #Include “Main.h” 2. 3. void main (void) 4. { 5. int limitswitch; 6. 7. // 0 is pressed 8. // 1 is not pressed 9. Wait (5000) 10. while (1==1) 11. { 12. limitswitch = Get DigitalInput (1); 13. if (limitswitch==1) 14. { 15. Set Motor (1.0); 16. Set Motor (10.0); 17. Wait (200) 18. } 19. else 20. } 21. Set Motor (1.-40); 22. Set Motor (10.40); 23. } 24. } 25. } Results: Group 1 cam in second place with an average of 23 mm from 5 trials. Group 2 (my group), came in third place with an average of 32 mm from the edge of the table. Group 3 came in last place with one fail and not having completed the rest of the trials yet. Group 4 came in first place with an average of 7 mm from the edge of the table. Conclusion: I think that...
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...@; do rep=1 to 3; do s1=1 to 3; do s2=1 to 2; input y @@; output; end;end;end; datalines; 1 1 12 13 14 15 23 22 15 16 17 18 24 15 26 25 18 19 20 21 1 2 23 10 23 20 15 33 26 13 26 23 16 12 18 36 29 16 29 26 1 3 21 15 34 23 16 19 24 18 37 26 17 17 19 22 27 21 40 29 2 1 13 18 23 14 18 21 16 21 26 17 19 20 21 24 19 24 29 20 2 2 16 16 13 25 19 21 19 19 16 28 20 18 22 24 22 22 19 31 2 3 17 24 15 17 19 21 20 27 18 20 20 26 22 24 23 30 21 23 ; proc print; run; /* lets consider A and B are random, and of course rep, samoplings ( s1 and s2 ) all are random */ proc glm; class a b rep s1 s2; model y=a b a*b rep(a*b) s1(rep*a*b); random a b a*b rep(a*b) s1(rep*a*b); run; proc varcomp method=type1; class a b rep s1 s2; model y=a b a*b rep(a*b) s1(rep*a*b); run; output: The SAS System 10:46 Wednesday, November 16, 2011 21 Obs a b rep s1 s2 y 1 1 1 1 1 1 12 2 1 1 1 1 2 13 3 1 1 1 2 1 14 4 1 1 1 2 2 15 5 1 1 1 3 1 23 6 1 1 1 3 2 22 7 1 1 2 1 1 15 8 1 1 2 1 2 16 ...
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...To Write a Chemical Formula in OWL Enclose subscripts with underscores _. Enclose superscripts with carats ^. The underscore key is next to the number zero on the keyboard. The carat key is the number six on the keyboard. H_2_O = H2O Cr^3+^ = Cr3+ Combined: SO_4_^2−^ = SO42− Ions Unit Charge Ions Write the number first and then the charge. Do not include the number one in unit charge ions. N^3−^ = N3− Ca^2+^ = Ca2+ Na^+^ = Na+ Cl^−^ = Cl− Using the Chemical Formula Input The chemical formula input box displays the superscripts and subscripts as you enter the formula. There are 3 ways to use the input box. • Keyboard: Use the keyboard to enter underscores and carats on your own. • Buttons after: Enter the formula without underscores or carats, then highlight each superscript and/or subscript, click the appropriate subscript or superscript button, and the underscores or carats will be filled in automatically. • Button during: Use the subscript or superscript buttons to enter the underscores and carats while you type the formula. To Write a Chemical Formula in OWL Enclose subscripts with underscores _. Enclose superscripts with carats ^. The underscore key is next to the number zero on the keyboard. The carat key is the number six on the keyboard. H_2_O = H2O Cr^3+^ = Cr3+ Combined: SO_4_^2−^ = SO42− Ions Unit Charge Ions Write the number first and then the charge. Do not include the number one in unit charge ions. N^3−^ = N3− Ca^2+^ = Ca2+...
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...Grade 5 Math STAAR Student Workbook © Forde-Ferrier, L.L.C. Page 1 Table of Contents STAAR Reporting Category 1: Numbers, Operations, and Quantitative Reasoning TEKS 5.1(A) Read, Write, Compare, and Order Whole Numbers (Supporting) TEKS5.1(B) Read, Write, Compare, and Order Decimals (Supporting) TEKS 5.2(A) Generate Equivalent Fractions (Readiness) TEKS 5.2(B) Generate Mixed Numbers and Improper Fractions (Supporting) TEKS 5.2(C) Comparing Fractions (Readiness) TEKS 5.2(D) Relate Fractions to Decimals (Supporting) TEKS 5.3(A-C) Addition, Subtraction, Multiplication, and Division (Readiness) TEKS 5.3(D) Identify Common Factors of a Set of Whole Numbers (Supporting) TEKS 5.3(E) Addition and Subtraction of Fractions (Supporting) TEKS 5.4(A) Estimation (Supporting) STAAR Reporting Category 2: Patterns, Relationships, and Algebraic Thinking TEKS 5.5(A) Relationship of Data (Readiness) TEKS 5.5(B) Identify Prime and Composite Numbers (Supporting) TEKS 5.6(A) Solution Sentences (Supporting) STAAR Reporting Category 3: Geometry and Spatial Reasoning TEKS 5.7(A) Geometric Properties (Supporting) TEKS 5.8(A and B) Transformations (5.8A Readiness/5.8B Supporting) TEKS 5.9(A) Locate and Name Points on a Coordinate Grid (Supporting) STAAR Reporting Category 4: Measurement TEKS 5.10(A) Perform Simple Conversions (Supporting) TEKS 5.10(B) Formulas for Perimeter, Area, and Volume (Supporting) TEKS 5.10(C) Length, Perimeter, Area, and Volume (Readiness) TEKS 5.11(A) Changes in Temperature...
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...| Bright Lights * Released: August 2000 * Label: Island | 1 | 3 | 2 | 2 | 6 | 3 | 10 | 1 | * UK: 3xPlatinum * AUS: Platinum * GER: Platinum * SWI: Platinum * FRA: Gold * NZ: Platinum * IRE: Platinum | 2001 | Dangerously In Love * Released: October 2001 * Label: Island | 1 | 1 | 1 | 1 | 3 | 1 | 6 | 1 | * UK: 4xPlatinum * AUS: Platinum * GER: Platinum * SWI: Platinum * FRA: Platinum * NZ: Platinum * AUT: Gold * IRE: Platinum | 2003 | All Night Long * Released: August 2003 * Label: Island | 1 | 6 | 5 | 5 | 10 | 6 | 14 | 1 | * UK: 2xPlatinum * AUS: Gold * GER: Gold * SWI: Gold * NZ: Gold * IRE: Platinum | 2004 | Troublemaker * Released: October 2004 * Label: Island | 3 | 12 | 10 | 10 | 14 | 12 | 18 | 3 | * UK: Platinum * IRE: Platinum | Year | Song | Peak chart positions | Sold | Album | | | UK | AUS | GER | SWI | FRA | NZ | AUT | IRE | | | 2000 | | 2 | 12 | 10 | 10 | 14 | 12 | 16 | 2 | * UK: Gold * AUS: Gold * NZ: Gold | | | | 1 | 6 | 4 | 4 | 8 | 6 | 10 | 1 | * UK: Platinum * AUS: Platinum * GER: Gold * SWI: Gold * NZ: Platinum | | 2001 | | 8 | 24 | 22 | 22 | 26 | 24 | 28 | 8 | * UK: Gold | | | | 12 | - | - | - | - | - | - | 12 | | | | | 1 | 8 | 6 | 6 | 10 | 8 | 12 | 1 | * UK: Platinum * AUS: Platinum * GER: Gold * SWI: Gold * NZ: Platinum | | 2002 | | 1 | 4 | 3 | 3 | 6 | 4 | 8 | 1 | * UK: Platinum * AUS: Platinum * GER: Gold * SWI:...
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...Choices and Consequences The Number 1 choice is Jerry, the father, offers the best utilitarianism of hope and use of his life to help his children and family and the best longevity of life given he has essentially been healthy except for the damage done to his heart from the Steroids some 20 to 30 years earlier. His wife and children play no part in the decision in him getting the heart. It all has to do with his health, and ability to live a life after he receives it. And also some other facts which should be considered like life expectancy, importance, age etc. when deciding on whom to donate the heart to. He’s cause for damage to the heart was the steroids, of which he was unaware of the consequences of taking the steroids at the time he took so there wasn’t any sort of health irresponsibility known otherwise. His chances to live 10-15 more years are very high so it’s one point investing in him. He has a family to take care of, wife and the 3 kids who he has to support till they are on their feet and so forth. He also has been a good supporting father as he’s already being supporting their dreams career wise and the future. So my first choice with all confidence would be Jerry. The number 2 choice is Ozzie because as LONG as he does not get back on his old ways HE does hold out some hope on society as a whole as long he does NOT revert back and does good in society by helping out and he no longer does any drugs - he really can have a useful and a prosperous and productive...
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...MON TUE MAR WED THU FRI SAT SUN MON TUE APR WED THU FRI SAT 1 2 3 4 5 6 8 9 10 11 12 13 15 16 17 18 19 20 22 23 24 25 26 27 29 30 31 2012 SUN MON TUE 7 14 21 28 5 6 7 12 13 14 19 20 21 26 27 28 SUN MON TUE 1 2 3 8 9 10 15 16 17 22 23 24 29 JUNE WED THU FRI 4 11 18 25 4 5 6 7 11 12 13 14 18 19 20 21 25 26 27 28 SUN MON TUE 1 2 3 8 9 10 15 16 17 22 23 24 29 30 31 FRI SAT 1 2 3 4 5 6 8 9 10 11 12 13 15 16 17 18 19 20 22 23 24 25 26 27 29 30 AUG SUN MON TUE WED THU FRI 7 14 21 28 MAY WED THU FRI SAT JULY SAT WED THU SAT 6 7 13 14 20 21 27 28 2012 1 2 3 4 5 8 9 10 11 12 15 16 17 18 19 22 23 24 25 26 29 30 31 SEPT WED THU FRI SAT 3 4 5 6 7 10 11 12 13 14 17 18 19 20 21 24 25 26 27 28 OCT SUN MON TUE WED THU 1 8 15 22 29 FRI 2 9 16 23 30 SAT 1 2 3 4 5 6 8 9 10 11 12 13 15 16 17 18 19 20 22 23 24 25 26 27 29 30 31 NOV SUN MON TUE WED THU FRI 7 14 21 28 5 6 7 12 13 14 19 20 21 26 27 28 SUN MON TUE 1 2 3 8 9 10 15 16 17 22 23 24 29 30 31 DEC WED THU FRI 4 11 18 25 SUN MON TUE SAT SAT 2 3 4 5 6 7 9 10 11 12 13 14 16 17 18 19 20 21 23 24 25 26 27 28 30 1 8 15 22 29 7 14 21 28 1 2 3 4 5 6 8 9 10 11 12 13 15 16 17 18 19 20 22 23 24 25 26 27 29 30 31 4 5 6 7 11 12 13 14 18 19 20 21 25 26 27 28 1 2 3 8 9 10 15 16 17 22 23 24 29 30 2 9 16 23 30 3 4 5 6 7 10 11 12 13 14 17 18 19 20 21 24 25 26 27 28 31 1 8 15 22 29...
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...ENGLISH TO SPANISH 1.CONFIDENCE CONFIANZA 2. OPTIMISM OPTIMISMO 3. INTEREST INTERÉS 4. SERIOUSNESS SERIEDAD 5. CHEERFUL ALEGRE 6. GRATEFUL AGRADECIDO 7. SUPERIORITY SUPERIORIDAD 8. CONDESCENDING CONDESCENDIENTE 9. OPENNESS APERTURA 10. AUTHORITY AUTORIDAD 11. SINCERITY SINCERIDAD 12. TRUSTING CONFIAR 13. LOVING AMANDO 14. SATISFACTION SATISFACCIÓN 15. HOSTILITY HOSTILIDAD 16. CONSIDERATE CONSIDERADO 17. CAUTIOUS CUIDADO 18. CONSCIENTIOUSNESS ESCRUPULOSIDAD 19. INSOLENT INSOLENTE 20. SUSPICIOUS SOSPECHOSO 21. TOLERANT ...
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