...Momentum and Energy in 2D Name__________________________________________ Date ________ Explosions: Conservation of Momentum: Note: If particles are not emitted at 900 Then must use Law of Sines: P1 / sin(1800-((1 + (2)) = P2 / sin(3 = P3 / sin(2 Or Law of Cosines P32 = P22 + P12 - 2P1P2cos(2 P22 = P32 + P12 - 2P3P1cos(3 P12 = P32 + P22 - 2P3P2cos(1800-((1 + (2)) Collisions: Conservation of Momentum: Examples: An unstable nucleus of mass 17 x 10-27 kg, initially at rest, disintegrates into three particles. One of the particles, of mass 5.0 x 10-27 kg, moves along the positive y-axis with a speed of 6.0 x 106 m/s. Another particle of mass 8.4 x 10-27 kg, moves along the positive x-axis with a speed of 4.0 x 106 m/s. Determine the third particle’s speed and direction of motion. (Assume that mass is conserved) Write down what you know mnucl = 17 x 10-27 kg m1 = 5.0 x 10-27 kg m2 = 8.4 x 10-27 kg m3 = mnucl – (m1 + m2) = 17 x 10-27 kg – (5.0 x 10-27 kg + 8.4 x 10-27 kg) = 3.6 x 10-27 kg vnuci = 0 m/s v1 = 6.0 x 106 m/s @ y-axis v2 = 4.0 x 106 m/s @ x-axis v3 = ? Draw a vector diagram of the momentum Solve for the momentum of the third particle and then find its velocity Right angled triangle so use Pythagorean Theorem P12 + P22 = P32 therefore:...
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...P A R T I Discovering Momentum 1 1 The Power of Momentum Where’s the Impetus? Momentum. Most businesses get it at some point: the impression that everything they undertake succeeds effortlessly, as if they’re being carried along by a tailwind that increases their efficiency and propels them on to exceptional growth.1 Some hold on to it. Most don’t. Slowly, imperceptibly, the tailwind turns around and the momentum disappears, without anyone quite realizing what has happened. The company is still growing, but not as strongly as before, not as efficiently. Everyone’s maxing out, but it seems like there’s molasses in the works. Sound familiar? Sooner or later, it hits you in the face. Imagine you are meeting up with a senior analyst whose opinion counts with some of your company’s biggest investors. You think you’re on safe ground—after all, your company is doing better than the competition. But the analyst is in full gimlet-eyed, illusion-killing mode. “That’s nothing to crow about,” she says. “Yeah, you’ve got reasonable growth, but it’s nothing exceptional. You’re a safe bet, nothing more. Okay, I might tell my mom to buy, but 3 The Momentum Effect then she’s happy with inflation plus one. The way we see it, you’re really grinding it out. We reckon the strain’s getting harder, too. There’s no impetus—no momentum.” Words like that can really take the gloss off a day. The next time you gather your team, you don’t congratulate them on beating their targets—you...
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...My definition of momentum is Tenacity, force, and admiration. My current job is not secure. Despite, the fact that I have been working in broadcast news as a video editor for the past eleven years, receiving my masters in Media Design can start developing my strategy for career change. I have been searching for ways to maximize my talent and skill set to keep me current with technology. Technology changes so rapidly that if you don't keep up with it, it will pass you by. In my current career you can edit on the same editing software for many years, while there are newer versions and updates available, but your company with not provide them to keep their cost down. So when you get to that point you have to ask yourself stay and move forward with current times. When you get to the point of losing you competitive advantage it’s time for higher learner. A fresh new look at you career and the possibility for change. Continuing my education will keep me marketable, obtainable and in high demand. I am responsible for my own learning. I am responsible for obtaining the skill set to obtain the pay scale I truly deserve. No one is more responsible for my professional development, only me. I want to effective in my profession. I want to be on the for front of all technology. I have finally accepted that change is constant; change is receiving my Master’s in Media Design from Full Sail...
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...Collisions and Conservation of Momentum Go to http://phet.colorado.edu/en/simulation/collision-lab and click on Run Now. 1. In the green box on the right side of the screen, select the following settings: 1 dimension, velocity vectors ON, momentum vectors ON, reflecting borders ON, momenta diagram ON, elasticity 0%. Look at the red and green balls on the screen and the vectors that represent their motion. a. Which ball has the greater velocity? The red ball has the greater velocity b. Which has the greater momentum? The green ball has more momentum 2. Explain why the green ball has more momentum but less velocity than the red ball (HINT: what is the definition of momentum?). The green ball has more momentum and less velocity because momentum depends solely on mass and velocity. Momentum = Mass(Velocity) Thus, since the green ball has a greater mass than the red ball, the green ball’s mass times its velocity is more than the red ball’s mass times its velocity. 3. Push “play” and let the balls collide. After they collide and you see the vectors change, click “pause”. Click “rewind” and watch the momenta box during the collision. Watch it more than once if needed by using “play”, “rewind”, and “pause”. Zoom in on the vectors in the momenta box with the control on the right of the box to make it easier to see if necessary. a. What happens to the momentum of the red ball after the collision? The momentum of the red ball decreases...
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...Conservation of Momentum Partial Lab Report Results Summary Elastic Collision Initial Momentum = .414 N | Initial Momentum = 0 N | Initial Kinetic Energy = .084 J | Initial KE = 0 J | V1’ = .0596 m/s | V2’ = .462 m/s | Final Momentum = .061 N | Final Momentum = .354 N | Final KE = .00182 J | Final KE = 0.082 J | Inelastic Collision Initial Momentum = n/a | Initial Momentum = n/a | Initial Kinetic Energy = n/a | Initial KE = n/a | V1’ = n/a | V2’ = n/a | Final Momentum = n/a | Final Momentum = n/a | Final KE = n/a | Final KE = n/a | Discussion For the first part of our lab we were able to successfully show that both kinetic energy and momentum were conserved during the collision. As stated in the lab procedure, we kept one mass heavier than the other and made the heavier object collide with the lighter object at rest. Looking back, there wasn’t too much difference between the sizes of the mass. There was only a 300 gram difference in the system and that may have helped in keeping the collision elastic. The speed was recorded as .404 m/s and that also may have helped in causing the object at rest to bounce off the moving object. We were not able to complete the inelastic collision part of the lab because we were not able to make the objects stick together. We were not sure if the plane the objects were set on was level and this may have caused the objects to keep bouncing away from each other. We also kept the weight and velocity (roughly) the same...
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...A collision occurs when two objects collide together creating an external force that is either zero or smaller. The goals of this lab were to find out what happens to the linear momentum and kinetic energy of different objects when they collide. Also, what happens to the momentum and kinetic energy in a completely inelastic collision and perfectly elastic collision? For completely inelastic collision the linear momentum should be conserved, but the kinetic energy should not be conserved. On the other hand, the linear momentum and the kinetic energy should both be conserved during perfectly elastic collision. Kf / Ko should equal one for perfectly elastic collision and, it should equal the mass of 1 divided by the sum of the mass 1 and 2 for...
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...[Document subtitle] March 29, 2016 Engineering Physics 150 March 29, 2016 Engineering Physics 150 Objectives: The objectives of this laboratory experiment is to investigate the velocities and momentm of two carts before and after various types of collisions. Theory: * When objects collide and assuming there are no external forces are acting on the colliding objects, the principle of the conservation of momentum always holds. * For a two-object collision, momentum conservation is stated mathematically by the equation: * PTotali =PTotalf * m1v1i+m2v2i=m1v1f+m2v2f * When working with a complete inelastic collision, the two objects stick together after the collision, and the momentum conservation equation becomes: * PTotali =PTotalf * m1v1i+m2v2i=(m1+m2)vf * During this experiment, photogates will measure the motion of two carts before and after elastic collision. The cart masses can be measured by using a simple mass scale. * Then, total momentum of the two carts before collision will be compared to the total momentum of the two carts after collision. Equipment: 850 Universal | Dynamic Track | Two dynamic carts | Two picket fences | Mounting brackets | Mass Balance | Mass Bar | Two Photogates | Data: Part A – Elastic Collision with approx. equal masses: Trial | V1 i (m/s) | V2 i (m/s) | V1 f (m/s) | V2 f (m/s) | 1 | .310 | 0 | 0 | .287 | 2 | .468 | 0 | 0 | .439 | 3 | .486 | 0 | 0 | .435 | 4 | .274 | 0...
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...started and ended were equivalent - indicating that there was conservation of speed, in addition to the complete transfer of velocity. However, in the different-mass elastic collisions, the transfer of the speed of the cart was not complete, but instead, the lighter cart moved quicker than the heavier cart. This shows us that although force may be the same, the transfer of momentum shows us why the lighter cart moves more quickly than the slower. Throughout our previous unit, we described the constant velocity of objects in motion. That laid the basis for this next unit, where we will be studying why and how the object moves the way it does, specifically the "push" or "pull" of force. The heavier cart in a same-direction elastic collision seems to push the lighter cart, which causes an increase in speed for the lighter cart. Although we may have brushed on the surface of movement, this unit will pave the path for further investigation on velocity as well as momentum. According to today's lab, it is possible to measure the mass of the carts and then multiple the mass by the velocity to determine momentum. These two things will be related to almost everything that we will be doing in physics, as how can we study how things move if we don't know how they're...
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...No. Information on Every Subject 1. Unit Name: Physics I 2. Code: FHSP1014 3. Classification: Major 4. Credit Value: 4 5. Trimester/Year Offered: 1/1 6. Pre-requisite (if any): No 7. Mode of Delivery: Lecture, Tutorial, Practical 8. Assessment System and Breakdown of Marks: Continuous assessment: 50% - Theoretical Assessment (Tests/Quizzes/Case Studies) (30%) - Practical Assessment (Lab reports/Lab tests) (20%) Final Examination 9. 10. 50% Academic Staff Teaching Unit: Objective of Unit: The aims of this course are to enable students to: • appreciate the important role of physics in biology. • elucidate the basic principles in introductory physics enveloping mechanics, motion, properties of matter and heat. • resolve and interpret quantitative and qualitative problems in an analytical manner. • acquire an overall perspective of the inter-relationship between the various topics covered and their applications to the real world. • acquire laboratory skills including the proper handling and use of laboratory apparatus and materials. 11. Learning Outcome of Unit: At the end of the course, students will be able to: 1. Identify and practice the use of units and dimensional analysis, uncertainty significant figures and vectors analysis. 2. Apply and solve problems related to translational and rotational kinematics and dynamics in one and two dimensions. 3. Apply and solve problems related to the...
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...Collisions and Conservation of Momentum Visit the website http://phet.colorado.edu/en/simulation/collision-lab & complete the following: 1. In the green box on the right side of the screen, select the following settings: 1 dimension, velocity vectors ON, momentum vectors ON, reflecting borders ON, momenta diagram ON, elasticity 0%. Look at the red and green balls on the screen and the vectors that represent their motion. a. Which ball has the greater velocity? b. Which has the greater momentum? 2. Explain why the green ball has more momentum but less velocity than the red ball (HINT: what is the definition of momentum?). 3. Push “play” and let the balls collide. After they collide and you see the vectors change, click “pause”. Click “rewind” and watch the momenta box during the collision. Watch it more than once if needed by using “play”, “rewind”, and “pause”. Zoom in on the vectors in the momenta box with the control on the right of the box to make it easier to see if necessary. a. What happens to the momentum of the red ball after the collision? b. What about the green ball? c. What about the total momentum of both the red and green ball? 4. Change the mass of the red ball to match that of the green ball. a. Which ball has greater momentum now? b. How has the total momentum changed? c. Predict what will happen to the motion of the balls after they collide. 5...
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...One copy of the lab report Physics 1030L/ Section 2 Conservation of Momentum Lab performed: 2/18/13 Report submitted: 2/20/13 Sample Calculations Results The magnitudes of the masses for the gliders before the collision were: mass XA1 is equal to 0.107m, and mass XB1 is equal to 0.101m. The magnitudes after the collision of the masses were: mass XA2 equal to 0.0890m, and mass XB2 equal to 0.0820m. The momentum of the masses before collision were: mass PA1 equal to 0.3737 (kg m/s), and mass PB1 equal to 0.3551(kg m/s). The momentum after collision of the masses were: PA2 equal to 0.3109 (kg m/s), and mass PB2 equal to 0.2886 (kg m/s). When considering the direction of the vectors the area of uncertainty is small when considering the area of both parallelograms of uncertainty, because the overlapping of the parallelograms is only a small portion of each. The momentum was partially conserved within the error range of the parallelograms, or the portion where they overlap. Conclusions 1. It is necessary that they glide on a cushion of air, so that they can avoid any friction which would slow down their movement and could possibly keep them from colliding. The friction would differ for each mass, and would change all the predicted values. If the masses were not on an air cushion, it is impossible to predict that the two masses would ever collide because of the differing frictions for each mass. 2.If the masses were...
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...the net force on an object is equal to the rate of change (that is, the derivative) of its linear momentum pin an inertial reference frame: The second law can also be stated in terms of an object's acceleration. Since the law is valid only for constant-mass systems,[16][17][18] the mass can be taken outside the differentiation operator by the constant factor rule in differentiation. Thus, where F is the net force applied, m is the mass of the body, and a is the body's acceleration. Thus, the net force applied to a body produces a proportional acceleration. In other words, if a body is accelerating, then there is a force on it. Consistent with the first law, the time derivative of the momentum is non-zero when the momentum changes direction, even if there is no change in its magnitude; such is the case with uniform circular motion. The relationship also implies the conservation of momentum: when the net force on the body is zero, the momentum of the body is constant. Any net force is equal to the rate of change of the momentum. Any mass that is gained or lost by the system will cause a change in momentum that is not the result of an external force. A different equation is necessary for variable-mass systems (seebelow). Newton's second law requires modification if the effects of special relativity are to be taken into account, because at high speeds the approximation that momentum is the product of rest mass and velocity is not accurate. Isang tao, munting taong kaharia’y nasa bukid...
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...Introduction When an object collides with another, momentum is conserved, but kinetic energy is not. This experiment was designed to find if the coefficient of restitution, e, changes for high-velocity collisions. At low velocities colliding objects will tend to maintain their shape, size and elasticity, so e is likely to be constant over a range. However, at high velocities colliding objects may change their physical properties and therefore a change (probably a reduction) in e may be observed. A small reduction in e was observed, but this was probably accounted for by air resistance and not a change in the material. Theory When a collision occurs, total momentum is conserved, but kinetic energy is not. When a ball, for example, bounces off the floor, it loses a little momentum to the Earth so the total momentum of the system is unchanged. Its KE, given by the formula [pic], assuming it was dropped from rest, will reduce and it will bounce to a height lower than its original height, as shown in diagram 1: Diagram 1: ‘H’ is drop height and ‘h’ is bounce height. The coefficient of restitution is the ratio of the difference in the initial speed and the final speed: (i) is the general formula for e, (ii) is when distances are measured on a drop (one object is stationary), and (iii) is when velocities are measured and one of the objects is stationary. Equation (ii) will be used here. Method Apparatus: Rubber ball, camera, floor...
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...spring bumper which is made of steel, which is considered to be a very elastic material. In reality no collision is elastic as kinetic energy is converted to other forms of energy such as thermal energy, sound energy. Within this investigation, the air coming from the platform prevents energy loss due to thermal energy; however it also introduces air resistance which will prevent kinetic energy and momentum from being conserved. The percentage of the kinetic energy lost is 55 %, as the kinetic energy before the collision was 0.017 J, and the kinetic energy after the collision was 0.008 J, which is high for a supposedly elastic...
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...relations, the kinematic equations; 2) using the principles of conservation of energy and momentum. In this paper, we aim to validate the law of conservation of momentum. We do so by comparing results from two experiments conducted with a single ballistic launcher/pendulum apparatus. Hypothesis: The initial velocity of a ballistic pendulum can be determined using the law of conservation of momentum. Momentum should be conserved, based on the law of conservation of energy. If momentum is conserved, the velocity found using the law of conservation of momentum equation should equal the velocity found using projectile motion. Due to the law of conservation of momentum, the total momentum before the pendulum is swung equals the net momentum after the pendulum is swung. Introduction/Purpose The ballistic pendulum is a device where a ball is shot into and captured by a pendulum. The pendulum is initially at rest but acquires energy from the collision with the ball. Using conservation of energy it is possible to find the initial velocity of the ball. In this ball-pendulum system we cannot use the conservation of mechanical energy to relate the quantities because energy is transferred from mechanical to nonconservative forces. In the absence of external forces, the momentum of the system does not change no matter how complicated the collision. The initial momentum is always equal to the final momentum. Figure 1: Experimental Setup for Part 1 In the first part of the experiment, the...
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