2
2
1
1
3
3
9
9

104 103 102 101 1000 100 10 1 1
1
30
30
2000
2000
900
900

2931
2931
+ + +

22 21 20 4 2 1 1 1 0 6
6

4 + 2 + 0

21 20

2 0

1 1 2 2 0

24 23 22 21 20

16 8 4 2 1

18
18
1 0 0 1 0

16 + 0 + 0 + 2 + 0

27 26 25 24 23 22 21 20

128 64 32 16 8 4 2 1

1 1 1 0 0 0 1 0

226
226

128 + 64 + 32 + 0 + 0 + 0 + 2 + 0

156 100 100 36 4 4 1 1 0

28 27 26 25 24 23 22 21 20

256 128 64 32 16 8 4 2 1
X x x x x x x x x 156
156
1 0 1 1 0 0 1 0 1 256 + 0 + 64 + 32 + 0 + 0 + 4 + 0 + 1

255 1 1 1 1 1 1 1 0 28 27 26 25 24 23 22 21 20 256 128 64 32 16 8 4 2 1 X x x x x x x x x 255
255
1 0 0 0 0 0 0 0 1 0 + 128 + 64 + 32 + 16 + 8 + 4 + 2 + 0

200 200 72 8 8 8 1 1 1 28 27 26 25 24 23 22 21 20 256 128 64 32 16 8 4 2 1
X X X X X X X X X 0 1 1 0 0 1 0 0 1
200
200

0 + 128 + 64 + 0 + 0 + 8 + 0 + 0 + 1

1. 8 2. 184 3. 46 4. 128 5. I use the division method to convert decimal to binary a. First divide 127 by 2 you get 63 with a remainder of 1 b. Then divide 63 by 2 you get 31 with a remainder of 1 c. Divide 31 by 2 you get 5 with a remainder of 1 d. Divide 5 by 2 you get 2 with a remainder of 1 e. Divide 2 by 2 you get 1 with a remainder of 0 6. With the numbers 102 and 00102 they are equivalent because the zeroes in binary numbers are not counted for they are just blank numbers. Both equations therefore equal two. 7. The first four base five numerals are 0, 5, 10, 15. The available digits in the base five numerals are 1 and 5. 8. It would be more difficult because of the fact that you are changing the convertor to be backwards. It would also be difficult when it comes to the decimal numbers not adding up to what the binary number is.