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Operation Research

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Submitted By arunddhutiray
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Cases in Operation Management

Semester 4

PGDBA (Operations)

Page 1

Question-: 1

The “Quality Auto Works” is a manufacturer of auto parts. All the auto parts being manufactured in the industry are required to be phosphated for surface protection. Presently other small units are done this phosphated work. Quality Auto Work is now thinking of installing its own phosphating plant and is interested about knowing about following. (A) Should the install new plant or continue the present practice of subcontracting?

For finding out whether the firm should do the phosphating work by own or it should contract other for the some one, we have to compare both the cost which are as follows.

Annual Cost of subcontracting

Cost of purchase

=6.25x12000x12 =9, 00,000/- Cost of Transportation Total Cost
=1800x12=21600/-
=9, 21,600

Annual cost for installing own phosphating plant:

Installation cost of plant: 2, 80,000x0.2452= 68,656/- Labor cost Benefit to labor Power Raw material : 8000x12 = : 96000x40/100 = : 12,000x0.23x12 = : 12000x0.45x12 = 96,000/-
38,400/-
33,120/-
64,800/-
Total cost of installing
=
3, 00,976/-

According to above calculation installing its own plant will benefit form.

(B) If the phosphating work expected to go up around 30,000Kg, what should the company do?

In this case also both type of cost are to be compared, which are as follows:

Cost of purchase:

6.25x30, 000x12

=2,250,000/- Cost of transportation: 18000x12

Annual cost of installing own plant
=21,600/-

Installation cost of plant: 2, 80,000x0.2452= 68,656/- Labor cost Benefit to labor Power Raw material : 8000x12 = : 96000x40/100 = : 30,000x0.23x12 = : 30,000x0.45x12 = 96,000/-
38,400/-
82,800/-
1, 62,000/- Total cost of installing =

Page 2
4, 47,856/-

According to above calculation the firm should install its own phosphating plant; it will be beneficiary for it. Question-2

Nitneel Industries P Ltd is a firm dealing in different types of operations the firm in interested in knowing about the following.

A) Estimate the requirement of power hacksaw sand manpower for the above mentioned production target. If presently company has four power hacksaws, establish additional requirement.

For finding out the requirement of power hacksaws and manpower according to mentioned production target we have to make some calculation, which is based on the following assumption.

a) The labor efficiency against output standards is @80%. b) The plant utilization against output standard is @75% c) Hour available per month is 200 hrs(25x8hrs)

Part Name/Part No Std Avg. Usage Runnin Capacit No of

No of time per piece
Quant/mont
h hr in month g hrs
80%
y hrs
75%
Fitter reqd hacksaw
Reqd
1 Agro Control Shaft (50.16252.0) 2 Serration Shaft (0.16288.0)
8.46 1250

8.46 1250
176.25 220.3

176.25 220.3
293.7

293.7
1.46 1.1

1.46 1.1 3 Oil Pump Gear (2523.1810.5401/5402)
5.4
4000
360
450
600
3
2.25
4 Helical Oil Pump Gear(312.181.0308.51) 5 Break shaft(2573.4230.7904) 6 Hub(640393) 7 Hex nuts(50.52 5001/A
4.8

5.4

9.6
17.1
6
2000

1000

2500
250
160

90

400
71.5
200

112.6

500
89.3
266.6

150

666.6
119
1.33 1

0.75 0.56

3.33 2.5
0.59 0.44 8 Thread Rolls

Total Requirement
96
30
48
60
80
0.4
12.32
(12)
0.3
9.25
(9)

As 4 power hacksaws are available therefore total fitter & hacksaws will be 12& 5

Page 3

B) The company has received an order for a new item to be produced from bar stock in lots of 2000 nos per month. The standard time required to source of each part of this item is estimated to be 12 minutes. What will be total requirement of machines and manpower use? Should the company accept the order or regret the same considering six power hacksaws being available.

Assumptions remaining the same our purpose can be solved with the help of following calculation.

Required no of item per month Minutes required for one item

Hrs required

Hours required for machining

Hours required by the labor

No of machines required

no of Labor required

= 2000
= 12 min

= 2000x12/60
= 400hrs

= 400/80x100
= 500 hrs

= 500/75x100
= 667 hrs

= 500/200
= 2.5
= 3 appx

= 667/200
= 3.33
= 3appx.

As company is having six hacksaws and only three of them are required, the order should be accepted.

Page 4

Question -3

Summary

Sidharth Chemicals Ltd is an organic chemical plant, in its one of the scheduled activities of the corrective maintenance, the activity is performed 4 times per year and the average down time per occasion and other information are been provided, with the help of it following information are required

A) Draw an arrow diagram.

Page 5

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