RAFFLES GIRLS' PRIMARY SCHOOL
SEMESTRAL ASSESSMENT 1

MATHEMATICS (PAPER 1)
PRIMARY 5

Name:

(

)

Form Class: P5

Banded Math Class: P5
Duration: 50 min

Date: 10 May 2011

Your Score

(Out of 100 marks)
Your Score

(Out of 40 marks)

Parent's Signature

INSTRUCTIONS TO HAMninATFS

1• Do not turn over this page until you are told to do
2. Follow all instructions carefully.

so.

3. Answer ALL questions and show all working clearly.
4. NO calculator is allowed for this paper.
Pagel of 12

SECTION A (20 marks)

Questions 1 to 10 carry 1 mark each. Question 11 to 15 carry 2 marks each. For each question, four options are given. One of them is the correct answer. Make your choice (1, 2, 3 or 4). Shade your answer (1, 2, 3 or 4) on the OAS provided. All diagrams are not drawn to scale.

1.

How many ten-dollar notes make up $201 010?
(1) (2)
(3) (4)

10 20
2 010 20101

2.

What is the product of 83 * 700?
(1) (2) 581 5 810

(3)

58100

(4)

581 000

Page 2 of 12

3. Find the volume of the cuboid shown below.

28 m

(1) (2)

84 m3 140 m3

(3) (4)

168 m3 840 m3

What is the missing number in the box?

•
9
d) 6

2
3

(2)
(3) (4)

8
14 15

->•

k

txpress — as a mixed number.

c

38

(D (2)

3*
4

4

(3)
(4)

94

9!
2

Page 3 of 12

6.

Which of the following figures cannot be tessellated?
(D

(2)

(3)

(4)

(

)

7.

In 43.21, which digit is in the tenths place?
(1) (2) (3) 1 2 3

(4)

4

(

)

Page 4 of 12

8. Express 0.025 as afraction in its lowest term
The answer is
I

(1)

4

(2)

I 8

(3)

1

25

(4)

I

40

9. Which of the following is acommon factor of 6and 27?
d) (2)
(3)
27
2 3

(4)

54

10. Which one of the following when rounded off to the nearest thousand gives 190 000?
185809 189099 189599 (1) (2) (3)

(4)

191 099

Page 5 of 12

11.

What is the area of the shaded triangle?

I cm

cm

(D
(2) (3) (4)

6 cm'

7 cm'

8 cm'
9 cm'

12.

Which of the following figure(s) has/have the line of symmetry drawn correctly? B

(1) (2) (3)

A and B only
B and D only

C and D only A, B and C only

(4)

Page 6 of 12

13' i ofMarys moneyis equal ,0 _L ofPeter.s
Find the ratio of Mary's money to Peter'ss money.
(1)
1:7 1:4
4:7

(2)
(3)

(4)

7:4

"• s^ssssrs'^-r-'-

(1) (2)

36 cm3 216 cm3

(3)
(4)

864 cm3
972 cm3

15. Sa.,y spent | ofher money on books and $58 on shoes lfshehad$27left,howmuChdidthebookscoSt? (1) (2) (3) (4)
$14.50
$21.25 $43.50

$63.75

Page 7 of 12

Questions 16 to 25 carry 1 mark each. Write your answers in the spaces provided. For questions which require units, give your answers in the units stated. All diagrams are not drawn to scale. Answers in fractions or ratio must be expressed in the simplest form.

16. Arrange the numbers in descending order.
513 082, 231058, 213 058, 513 820

Ans:

17.

Fill in the blank.

28.13 = 28+

?

+0.03

Ans:

18.

Find the maximum number of 2-cm cubes that can be cut from the rectangular block given below.

3 cm

2 cm
25 cm

Ans:

Page 8 of 12

19. Given that AB is aline of symmetry, complete the figure below.

20. The figure shown below is astaircase made up of 1-cm cubes What is the volume of the total number of cubes up to the 10th step?
3rd step

2nd step

Is* step

Ans:

cnr

Page 9 of 12

21.

Mrs Tan had a piece ofcloth which was 7-m. She gave 3- m ofthe cloth to her sister. What was the length of the cloth left?

Ans:

m

22

Express 4- as a decimal.
8

Ans:

23. The cost of 9curry puffs is $9.45. What is the cost of 1curry puff?

Ans: $

24. What is the measurement indicated by the arrow below?

\ ' I ' I
Ans:

25. Rod Ais 1mlong. Rod Bis 2 cm long. Find the ratio of the length of Rod Ato the length of Rod B.

Ans:

Page 10 of 12

M

provided for each question and write your answers in the space provided. For questions which require units, give your answers in the units stated. All diagrams are not drawn to scale. Answers in fractions or ratio must be expressed in the simplest form. Questions 26 to 30 carry 2 marks each. Show your working clearly in the space

26. During a Speech Day rehearsal, 12 pupils were standing in a row at equal distances. The distance between the first and fourth pupil was 12m. What was the distance between the first and twelfth pupil?

Ans:

m

27.

Solve the following.

( 55 +65 ) - 100 + 100 +5 x 2 =_?_

Ans:

28

In the working below, A, B, C, D, Eand Fare 2-digit numbers. If Ais 20, Bis the 4th multiple ofA, Cis the 3rd multiple of 11, Dis the volume of a cube with length of 4 units, and Fis the 4th multiple of 11, what is E?

Ans:

Page 11 of 12

29. The capacity ofa rectangular tank is432 m3. The bottom ofthetank measures
6 m by 3 m. It is then filled with some water. The height of the tank is 3 times the height of the water. What is the height of the water?

Ans:

m

30.

Extend the tessellation by drawing 2 more unit shapes.

End of Paper-

© Please check your work carefully ©
Setters: Mr Ho Kal Huat Ms Lee Suan Khim Mr Jonathan Teo

Page 12 of 12

/?

RAFFLES GIRLS' PRIMARY SCHOOL SEMESTRAL ASSESSMENT 1 MATHEMATICS (PAPER 2)
PRIMARY 5

Name:

(

)

Form class: P5

Banded Math Class: P5
Duration: 1 h 40 min

Date: 10 May 2011

Your Score

(Out of 60 marks)
Banded Math
Class

Level

Highest Score Average Score

INSTRUCTIONS TO CANDIDATES

1. Do not turn over this page until you are told to do so.
2. Follow all instructions carefully.

3. Answer ALL questions and show all working clearly.
4. The use of calculator is allowed for this paper.

Page 1 of 11

/r

Questions 1 to 5 carry 2 marks each. Show your working clearlyin the space provided for each question and write your answers in the spaces provided.
Figures are not drawn to scale.

Forquestions which require units, give your answers in the units stated.

(10 marks)

1

The breadth of a rectangle is - of its length.

1

If the perimeter of the rectangle is 120cm, what is the area of the rectangle?

Ans:
2. Write down all the common multiples of 3 and 8 that are smaller than 50.

cm2 [2]

Ans:

[2]

Nicole had $63 at first. She spent $28 of her money. What fraction of her money was left? (Express the answer in its simplest form)

Ans:

[2]

Page 2 of 11

/T

4SESHSF^"-

Ans:

PJ

5.

The

area of the triangle ABC

8 cm

6 cm

Ans:

[2]

Page 3 of 11

For questions 6 to 18, show yourworking clearly in the space provided for each question and write your answers in the spaces provided. Figures are not drawn to scale. The number of marks available is shown in the brackets [ ]at the end of

each question or part-question.
2 machines took 14 minutes to print a magazine. How long would ittake for 7 machines to print a magazine?

(50 marks)

Ans:

[3]

In a library, the ratio of the number of fiction books to the number of reference books was 3:7. After buying 126 fiction books, the ratio of the number of fiction books to the number of reference books was 3:4. How many fiction books were there in the end?

Ans:
Page 4 of 11

[3]

/9

In the figure below, ABCD and BEGH are squares. CDH and BFH are triangles. Find the total shaded areas.

14 cm

20 cm

Ans:

[3]

9.

Alicia had some beads. She gave Bernice half of the beads and 2 more. Then she gave half of the remaining beads and 3 more to Cindy. If Alicia had 9 beads after this, how many beads had Alicia at first?

Ans:

[4]

Page 5 of 11

10.

Mr Lim had some stickers and stamps for his class. The number of stickers

was half as many as the number of stamps. After each pupil in the class had received 3 stickers and 8 stamps from Mr Lim, he had 39 stickers and 2

stamps left. What was the total number of stickers and stamps Mr Lim had at first? Ans:

[4]

11.

A cubical container of edge 8 cm was filled to the brim with water. The water was then poured to a rectangular tank that already had some water in it. The ratio of the volume of the empty cubical container to the volume of water in the rectangular tank was then 4:7. Find the volume of water that was in the rectangular tank at first.

Ans:
Page 6 of 11

[3]

*l

12. Michelle went shopping and spent $225 on awatch. She used - of her remaining money to buy adress.

She was then left with A0f her initial amount of money.
How much money did she have at first?

Ans:

[3]

13' triangle. Find the area ofthe figure. reCtang,es' 2identlca' s^ares and 1 ZlTl^T,S made UP °f5ldentiCa'
•

*

.

34 cm
_ w«

20 cm

i
.—

Ans:

[4]

Page 7 of 11

14.

A basket with 80 apples had a mass of 1320g. The same basket with 60 oranges had a mass of 1850g. If the mass of each orange is 2 times the mass of an apple, find the mass of the empty basket.

Ans:

[4]

5.

Chloe paid $3884.55 for 1 television set, 1 laptop and 3 chairs.
The television set cost $520 more than the laptop.
Each chair cost $899.90 less than the television set.
How much did the television set cost?

Ans:

[4]

Page 8 of 11

2.3

16. Jason formed the following pattern using 1-cm square.

Pattern 1

Pattern 2

Pattern 3

Pattern 4

(a) How many shaded squares are there in pattern 55?
(b) How many squares are there in pattern 250?

Ans: (a)
(b)

[3]

f2]

Page 9 of 11

U.

*-,

In a concert, - of the audience were adults and the rest were children. - of g 4

the adults were men and - of the children were girls. If there were 450 more
8

female than male audience in the concert, how many women were there?

Ans: Page 10 of 11

[5]

%S

18. Andy and Betty saved a fixed amount every day. Betty, who started saving

earlier, saved $4 each day. By the 10th day of Betty's savings, Andy had saved $18. By the 16th dayof Betty's savings, Andy had saved $54.
(a) Find the ratio of Andy's savings to Betty's savings,
(leave your answer in the simplest form)

(b) On which day of Betty's savings will Andy save the same amount as Betty?

Ans: (a)

[2]

(b)

[3]

-End of PaperPlease check your work carefully ©
Setters: Mr Ho Kai Huat Ms Lee Suan Khim Mr Jonathan Teo

Page 11 of 11

RGPS P5 SA1 Mathematics 2011 Answer Key (Paper 1)
Updated: 13 May 2011

Section A (1m each for Q1-10; 2m each for Q11-15)
D 2)
3)

^ery^

4 3
4

6)

1

11)

2

7)
8) 9)
3

12)
13)

1
4

4) 5)

4 4

14) 15)

3 4

10)

3

Section B (1 mark each)
16) 513 820. 513 082, 231 058. 213058

2D 3n
20

17) 0.1 Or equivalent
18)
19)

22)

4.375

12

23)
24)

1.05
3.375

' B

20) 55

25)

50: 1

RGPS P5 Math SAl (2011) Answer Key

Page 1 of 10

Section B (2 marks each) 26) Distance b/w 2 pupils -> 12m - 3
= 4m
Ist Distance b/w 1sl& 12,n pupil -> 4m x 11

(M1)

= 44m

(A1)

27)

60

(A2 - either right or wrong)

28) 20 + 33+1=54 (M1.A1) (A2 if all values indicated in the boxes correctly)
29) 6x3=18
6x3=18

432*18 = 24 24-3 = 8
30)

(M1) (A1)

432 + 3 = 144

144-18 = 8

(M1) (A1)

as
A1 for each correct unit shape drawn

RGPS P5 Math SA1 (2011) Answer Key

Page 2 of 10

RGPS P5 SA1 Mathematics 2010 Answer Key (Paper 2)
2m each: Q1 -Q5

3m each: Q6 - Q8, Q11 - Q12 4m each: Q9 - Q10, Q13 - Q15
5m each: Q16-Q18

1)

120cm -8 = 15cm
15cm x3 = 45cm

(M1)

120-2 = 60 60 + 4=15

15cm x 45cm = 675cm2(A1)
2) 24,48 or: (M1)
(AD

15x45 = 675 cm2

(A2 - either right or wrong)

A2 awarded as long as answers are clearly shown in working
No marks deducted for ransfer errors.

3)

63-28 = 35 (M1)
35 _ 5
63 9

63-28 = 35 (M1)
35 + 7 = 5

28 =4
63 ~ 9
9 45 1-Z =±

(A1)

63 + 7 = 9
5 9

(A1)

9 9~9

(M1.A1)

or:

63 63

28=35

63 63

(M1)

35=5 63 9

(A1)

(No answer mark If $ is

added.)

4)

3x3 = 9

M1 awarded if all 3 lengths are clearly shown in diagram.

6 x 6 = 36
9x9 = 81

(M1 for listing all three steps correctly)
9:6:3 = 3:2:1

(A1)

RGPS P5 MathSA1(2011) Answer Key

Page 3 of 10

rf

5*

Area of triangle ABC ->- x6cm x8cm
= 24 cm2 or: (M1)
(A1)

(Pupil added Point E to form a rectangle)
Area of rectangle = = 12x8 96 cm2

Area of triangle ADC

=

1 x 12 x 8
48 cm2

Area oftriangle ABE

=

!x8x6
2

24 cm2

Area of triangle ABC
6) 2 machines -> 14 min

=

=

96-48-24

24 cm2

(M1)

(A1)

1 machine -> 14 min x 2 = 28 min (M1) 7 machines -> 28 + 7 = 4 min (M1, A1) or: The first M1 is awarded only ifthe time taken for 1 machine is shown.
7) BeforeAfter
F : R F : R

3:7

3:4

* No additional reference books were bought

*(3x4)
12 :

(7x4)
28

*(3x7)
21 :

(4x7)
28

21-12 = 9

9 units -> 126 books

1 unit ->126 books + 9 = 14 books 21 units -»21 x 14 books = 294books or: (M1)

(M1. A1)

Alternative for last step (2nd M1, A1):
14x12 = 168

168+126 = 294

(M1.A1)

(Methods using simultaneous equations and fractions also accepted.)
RGPS P5 Math SA1 (2011) Answer Key Paee 4of 10

Area ofbigger triangle ->- x 20 cm x 20 cm
= 200 cm2

(M1)

Area ofsmaller triangle ->- x 14 cm x 6 cm
= 42 cm2

(M1)

Total shaded areas -> 200 cm2 + 42 cm2
9) Half nf •'-•••wiiiiuy UCCHJS --» romoio;™ u ,_ ^ - •• -•

| I

l

=12 Remaining beads -> 12 +12
= 24

y + ^

(M1)

Half ofbeads at first -> 24 +2
= 26

(M1)
(M1) (A1)

Beads at first -> 26 +26
= 52 or: 9 + 3 = 12

12 +2=14 14x2 =28 12x2 =24 28 +24 =52

(M1) (M1) (M1) (A1)

RGPS P5 Math SA1 (2011) Answer Key
Page 5 of 10

S*

10) stickers 39

stamps

2

stickers

1 unit + 1 = 39
I unit = 38

II units = 11x38 = 418 418 + 39 + 2 = 459 or. (M1) (M1) (M1.A1)

(Full mark given if the students used guess and check method) or: 153 + 306 = 459

.

,

....

38x3 = 114 114 + 39 = 153 38 x 8 = 304 304 + 2 = 306 306-2 = 153
153x3=459

(M1) (M1) (M1) (A1)

11) 8 cm x 8 cm x8cm = 512cnv 512 cm3 +4 = 128 cm3
128cm3x7 = 896cm3

(M1) (M1)
(A1)

896 cm3 - 512 cm3 = 384 cm3 or: 512-4 = 128
128x3=384

(M1)

(M1.A1)

12)

Method 1
— x6= —

jL=I-> 225
15 5

(M1)

15

15

225 x 5 = 1125

(M1.A1)

15

15

225 + 3 = 75

(M1) 75x15 = 1125(M1,A1)
Page 6 of 10

RGPS P5 MathSA1(2011) AnswerKey

13)

Method 1 Length of square -> 5 cm Length of rectangle -> 12 cm

Area of 2 squares -> (5 cm x 5 cm ) x 2
= 50 cm2

(M1)
(M1)

Area of 5 rectangles -> (12 cm x 5 cm ) x 5
= 300 cm2

Area of triangle -> - x 12 cm x 10 cm
= 60 cm2

(M1)

Total area -> 50 cm2 + 300 cm2 + 60 cm2
= 410 cm2
Method 2

(A1)

square -> 5 cm x 5 cm =25 cm2 2 squares -> 25 cm2 x 2 =50 cm2 rectangle -> 12 cm x 5 cm =60 cm2 5 rectangles -> 60 cm2 x 5 =300 cm2

(M1) (M1)

triangle->! x12 cm x10 cm =60 cm2
50 cm2 + 300 cm2 + 60 cm2 = 410 cm2
Method 3

(M1)
(A1)

12 cm x 5 cm =60 cm2

60 cm2x 6 = 360 cm2 5 cm x 5 cm x 2 cm = 50 cm2 360 cm2+ 50 cm2 = 410 cm2
14) Mass Mass Mass Mass

(M2) (M1) (A1)

of 1 orange -> Mass of 2 apples of 60 oranges -> 60 x 2 = Mass of 120 apples of the basket with 120 apples -> 1850 g of basket with 80 apples -> 1320 g

Mass of 40 apples ->1850 g - 1320 g = 530 g Mass of 80 apples -> 530 g x 2
= 1060g

(M1) (M1)
(M1)
(A1)

Mass of empty basket -> 1320 g - 1060 g
= 260g or: 530 + 20 = 26.5
26.5x60 = 1590

1850-1590 = 260 q

(M1) (M1) (M1.A1)

RGPS PS Math SA1 (2011) Answer Key

Page 7 of 10

5?

15)
TV

Laptop
3 chairs

$520

$ 3884.55

$ 899.90

Method 1

$899.90 - $520 = $379.90

$899.90 + $379.90 = $1279.80
$3884.55 - $1279.80 = $2604.75

(M1) (M1)
(M1) (A1)

$2604.70 + 5 = $520.95
$520.95 + $899.90 = $1420.85

Method 2

$899.90 x 3 = $2699.70

$2699.70 + $520 = $3219.70 $3219.70 + $3884.55 = $7104.25

(M1)

(M1)

$7104.25 4-5 = $1420.85

(M1.A1)

or:

(3884.55 + 2699.7) - (520 x 4) = 4504.25
4504.25 + 5 = 900.85

900.85 + 520 = $1420.85

(M1) (M1) (M1.A1)

RGPS P5 Math SA1 (2011) Answer Key

Page 8 of 10

16a) Method 1

(55 + 1 )x (55+ 2) = 3192
3192 + 4=3196
Method 2 59 x 57 = 3363 55x2=110 110 + 57 = 167 3363-167 = 3196
Method 3

(M1) (M1.A1)

(M1) (M1)

' (A1)
(M1)

59 x 57 = 3363 55x3 = 165 165 + 2=167 3363-167 = 3196
Method 4

(M1) (A1)

Listing:
Pattern 5 -> 46 Pattern 6 -> 60 Pattern 7 -> 76

Correct start for frst 3

>

Correct listing

Pattern 54 -> 3084 j
Pattern 55 ->3196

(A1)

16b) Method 1 252 x 254 = 64008 (M1.A1)
Method 2 253 x 253 = 64009

64009-1 = 64008 (M1.A1)

RGPS P5 Math SA1 (2011) Answer Key

Page 9 of 10

l?

17)

- x - = — (men)
6 4 24

5

1

5 ,

x

5 3 15 , , - x - = — (women)
6 4 24

6 X8 = 48 (9,r,S)
- x - = — (boys)
6 8
3

48
33

-

15

+ — = — (females)
48 48

OR

II

(M1)
(M1)

24

16
5

.33 15 , . , 1 = — (male)
48 48

16

33-15 = 18
450-18 = 25 30 x 25 = 750

11-5 = 6
450 - 6 = 75 10x75 = 750

(M1) (M1)
(A1)

18a) 54-18 = 36
36 + 6 = 6 6:4 = 3:2

(M1) (A1)
OR 4x10 = 40

18b)

16x4 = 64 64-54 = 10
10-2 = 5

5+16 = 21

(M1) (M1) (A1)

40-18 = 22 (M1) 22-2 = 11 (M1) 10+11 =21(A1)

OR Listing : Day 10
A B 40 18

11

12

13 52 36
_>

14

15

16 64
54

17

18 72 66
-v

19 76

20 80
78

21

44
24

48 30
"V

56
42

60
48

68 60 v^_ 84
84

72

Correct start for first 3 -> M1

(Either for Day 11-13 or Day 17-19)

Able to show 5 days after Day 16 -> M1
Ans:84(A1)

RGPS P5 Math SA1 (2011) Answer Key

Page 10 of 10