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Pt1420 Unit 4

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1. A common food is found to contain .00125% iron. The serving size is 87.0 grams. How many milligrams of iron is in one serving? (Note the change from grams to milligrams!) To solve this problem, the first thing I did was to read through it several times to determine what it is asking. My interpretation was that I needed to find the grams of iron in this food and then convert it to milligrams. To do this, the first thing I did was to convert 0.00125% of iron to a decimal by moving the decimal point two places to the right which gave me a decimal of 0.0000125. I then multiplied 0.0000125 by 87.0 grams to find the percent of iron in a serving of food. I plugged 0.0000125 x 87.0 into a calculator and got the answer of 0.0010875 which means …show more content…
The number sentence I created was 87.0 • 0.0000125 • 1,000= x. In this number sentence, x stands for the unknown which is the milligrams of iron in a serving. Following the order of operations 8.7 and 0.0000125 are multiplied to find the grams of iron in a serving, and then that product is multiplied by 1,000 to convert to milligrams. When I solved the problem using the number sentence I again got the answer of 1.0875 milligrams. I also plugged my number sentence into Wolfram Alpha, and its answer agreed with mine as it said that x was equal to …show more content…
I understood how to represent the glass and cans in the problem but was unsure of how to write an expression for the newspapers. It took a fair amount of experimenting with different expressions before I landed on a logical number sentence. Once I had established my number sentence, it was easy to solve the rest of the problem. I believe that my final answer is correct because when I plug five hundred in for x, all of my expressions add up to equal four thousand five- hundred

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