Jane Doe
02/10/2014
QAT1 309.3.2-01-06 A. See table 1.1 attachment B. 1. Expected time to complete: * a= the optimistic completion time estimate * b= the pessimistic completion time estimate * m= the most likely completion time estimate
The activities mean completion time is: t= (a+4m+b)/6 * Task A. (2+12+4)/6=3 * Task B. (5+24+13)/6=7 * Task C. (3+16+8)/6=4.5 * Task D. (10+44+15)/6=11.5 * Task E. (4+20+6)/6=5 * Task F. (8+40+12)/6=10 * Task G. (4+24+11)/6=6.5 * Task H. (8+40+18)/6=11 * Task I. (3+24+12)/6=6.5 * Task J. (2+12+7)/6=3.5

a. The activities completion time variance is: ²= ((b-a)/6)²

* Task A. ((4-2)/6)²=0.10 * Task B. ((13-5)/6)²=1.76 * Task C. ((8-3)/6)²=0.68 * Task D. ((15-10)/6)²=0.68 * Task E. ((6-4)/6)²=0.10 * Task F. ((12-8)/6)²=0.43 * Task G. ((11-4)/6)²=1.34 * Task H. ((18-8)/6)²=2.75 * Task I. ((12-3)/6)²=2.25 * Task J. ((7-2)/6)²=0.68
2.
See Network Diagram attachment
3.
a. Expected duration of the entire project: 33.5 weeks b. Slack for project task A: LS-ES=slack time = 6.5-0= 6 c. Slack for project task H: LS-ES=slack time= 19-18.5= 0.5 weeks d. The week project task F. is scheduled to start: Task F begins when Task B ends, which= week 7 e. The week project task I. is scheduled to finish: Task J. LS= task I. LF time=week 30

4. Probability that the project will be done in 34 weeks: ²=²b+²d+²h+²j= ²=1.76+.43+1.34+2.25+.68=6.42
Project standard deviation: 6.42=2.53
Project completion times: Z=Due date-expected date of completionσT = 34 weeks-33.5 weeks2.53 = 0.19 weeks
Z- Value of 0.19= P (z≤.19) = 0.57535

B. 1. Maximum reduction in time: normal weeks-crash weeks=maximum reduction in time * Task A: 3 weeks-2 weeks= 1 week * Task B: 7 weeks-5 weeks= 2 weeks * Task C: 4.5 weeks-3