...QLT1 Task 5 Daycare Cost Analysis A.) Basic information: The Depp family is seeking child care for their 2 year old son Jack. The family needs care for approximately 42-50 hours per week. They have interviewed several care providers and have selected two providers in the vicinity of their employers and now need to decide between: one is family day care home that charges $5 per hour per child and the other is a child care center that charges $200 per week for 40 hours with an additional $10 per hour over 40 hours. Additional factors considered are that both facilities provide lunch and snacks, other facilities did not; as well the center will provide a 25% discount on a second child. Although the Depps have only one child however will be adding to their young family. 1.) Rates: i. Daycare rates: Home care $5/hour ii. Center $200/week for 40 hours + $10/hour over 40 hours 2.) Other expenses iii. Meals included with both facilities iv. Both located within 10 blocks of employer, transportation costs are negligible 3.) Other considerations v. Parents are state employees 37.5 hours per week + 1 hour lunch = 42.5 hours @ employer per week minimum vi. Currently have one child in need of care, but is considering another child in the next 1-2 years vii. Family day care home is 1 employee, no coverage for sick days/vacation; center has multiple staff members to cover...
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...QLT1 Task 5 A. Create a story problem using one of the above real-world scenarios as a basis, including realistic numeric values, by doing the following: 1. Describe the real-world problem. I was looking into phone plans and stumbled upon T-Mobile, and I decided that I needed a cell-phone and took a look at the plans. T-mobile had one plan that was 50 dollars a month and is unlimited talk, text and web, T-Mobile also has a plan for 30 dollars a month for 1,500 talk and text minutes. After you go through your allotted 1,500 talk and text time was up, the cost skyrockets up to 10 cents a minute. 10 cents a minute comes out to 6.00 per hour, I thought in my head. I decided that instead of jumping into a decision about phone plans, that I should first go home and do the math. I wanted to figure out which plan was going to be the most cost effective, and which plan would suite my needs the best. 2. Explain all needs (e.g., financial, non-financial, situational) of the hypothetical consumer. The needs include many different factors: • The first and most important factor how much do you use your phone? The breaking point on the problem today is 200 talk or text above the 1500 minute plan and I will be paying less up front but more on the back end which is no good. If I chose the 1500 minute plan, I will not want to be going over the 1500 minutes as then the cost would go up to 10 cents a minute or 6.00 per hour. • Is this replacing a work or office phone? If...
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...daycares to determine the best option for their 1 year old son. A home-based daycare charges a flat rate of $5 per hour. A center-based daycare charges a fixed rate of $185 per week, providing 40 hours of childcare. Above 40 hours, the center-based daycare then charges a fixed rate of $8 per hour. The couple determines that the driving distance to each daycare is the same, thus driving expenses do not need to be considered. The couple will require 50 hours of childcare per week and are looking for the cheapest daycare, as they are soon expecting their second child. Part B: 1. “y” represents total cost per week in dollars “x” represents hours Home based daycare: y=5x Center based daycare: y=185+8(x-40), x≥40 hours 2. For the home based daycare, they charge a flat rate of $5 per hour. Thus the couple can calculate their cost by multiplying $5 by the number of hours they need for childcare each week. For the center based daycare, the couple can calculate their weekly cost by adding the $185 fixed rate to the cost of any additional hours needed after 40. Thus, if they are going over 40 hours, they would subtract 40 hours from the total number of hours needed and multiply that by the $8 the center charges for each additional hour. 3. y=5x y=185+8(x-40) y=185+8(x-40) 5x=185+8x-320 5x=-135+8x 5x-8x=-135+8x-8x -3x=-135 -3 -3 x=45 y=5x y=5(45) y=225 Thus, both the center based and the home based daycares will charge $225 for 45 hours of...
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...A1) A parent is looking for the best option for daycare for a child. A home-based option charges a flat rate of $10 per hour. A center-based option charges a fixed fee of $332.50 per week for 35 hours and then a fixed rate of $11 per hour for any hour provided over the set amount. Determine which option is most advantageous for the parent based upon the parents’ needs. A2) The parent works a 40 hour work week. Each of the daycare options is a half an hour away from the parent’s office. This means that the child is there for a total of 45 hours a week. The parent has federal holidays (10 holidays in 2014), the day after Thanksgiving, and Christmas Eve off so there will be weeks that the child will not be in daycare for the full week. The parent also receives two weeks of vacation each year. Other situations to consider are that the child and/or parent could get sick or they could take a short vacation and the child will not have to attend the daycare for the full week. A3) If the parent chooses to go with the home-based option, the parent will be charged a flat rate of $10 per hour. This option gives the parent the freedom to either take the child to daycare or to not and only be charged for the hours the child is there. If the child is there for 45 hours a week, the parent will pay $450 for that week; if the child is there for only 20 hours a week, the parent will pay $200 for that week. If the parent chooses to go with the center-based option, the parent will be charged $332...
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...A1 Andrew has just moved to Los Angeles and bought a car and is looking for the best parking option that will allow him to save the most money. There are two parking garages by his work. One charges $40 per month and the other charges 20 cents per hour. Which option will be less costly for him? A2 Since Andrew is new to the area it is necessary that he find the cheapest parking option possible in order to cut down on expenses in the new city as he has just purchased a new car and had high moving costs. A3 Andrew’s two options are the monthly parking garage which charges $40 per month or the hourly parking garage which charges 20 cents per hour. B1 A work day has 8 hours A is the number of days the car will be parked. T will be the total price Monthly parking garage: (A-A)+40=T Hourly parking garage: (0.2 x 8)A=T B2 The monthly parking garage doesn’t charge by the day so having the days at zero just leaves the $40 charge. The hourly parking garage multiplies the rate by 8 hours since there are 8 hours in a work day. That is then multiplied by the total number of days in a month that the car will be parked. B3 We set both equations equal to each other in order to find the solution for the number of days. Set both equations equal to each other (A-A)+40=(0.2 x 8)A Subtract (A-A) 40=(0.2 x 8)A Multiply inside the parentheses (0.2 x 8) 40=(1.6)A Multiply (1.6)A 40=1.6A Divide both sides by 1.6 25=A A=25 days solution We...
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...Task 5 Moving Truck Cost Analysis The Thompsons have lived in Canada all their life but recently Mr. Thompson got a job offer he could not refuse. The new job will require they move to the west coast of the United States. This is going to require they move across the country from New Brunswick, Canada to Seattle, WA. Which is a total of 3200 miles. Although the company Mr. Thompson will be working for will reimburse them for the move, they still have a budget they need to stay under so they can have enough money for hotel stays, stocking the house with food, cleaning supplies etc. when they arrive. They are planning on leaving early and site seeing on the way but still arrive at least two weeks early so they have time to settle in. Arriving early though means there will be a big gap between paychecks so budgeting is very important. They narrowed it down to two companies, Acme Moving which charges $2.00 per mile and Lightening Moving that charges $1500 for the first thousand miles and $2.25 for each mile over 1000. They have to analyze the costs and figure out which one is going to be the best deal. The Equation: Lightening Moving Co. Lightening Moving charges $1500 for the first 1000 miles and then $2.25 for each mile over 1000. Let X = Amount of miles traveled 1500 = the initial cost of the first 1000 miles 3,200 = the total amount of miles traveled $2.25 per mile over 1000 miles therefore; 1500 + 2.25(X-1000) = Cost of moving over 1000 miles 1500 + 2...
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...- The graduate interprets documents and materials containing quantitative information and effectively communicates mathematical arguments and quantitative results. Competency 212.2.4: Applying Technology to Quantitative Problems - The graduate uses appropriate technological tools, including regular and graphing calculators, databases, and/or statistical analysis programs, to solve problems involving computation, graphical information, and informational technology in a wide range of areas. Introduction: Individuals encounter countless situations in day-to-day life that require a strong mathematical foundation in order to make informed decisions. Shown below are four real-world scenarios that one might encounter in day-to-day life. For this task you will choose one of the scenarios below. Each situation requires a mathematical comparison of cost options in order to determine which is best for a consumer (e.g., customer or person). Scenario 1: A parent is looking for the best option for daycare for a child. A home-based option charges a flat rate per hour. A center-based option charges a fixed fee per week for a certain number of hours and then a fixed rate per hour for any hour provided over the set amount. Determine which option is most advantageous for the parent based upon the parents’ needs. Scenario 2: A downtown employee...
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...Task 5 A. Jenny is looking for the best option for daycare for her son. She lives in a small town, so her options are limited to two daycare centers. Option A is a home-based facility which charges $9.00 per hour that the child is at the home. Option B is a center-based facility which charges $150 for the first 20 hours and then charges $10 per hour thereafter. Due to a new promotion, Jenny will be required to work more hours away from home. Which facility will cost less for Jenny to have her son in daycare for a work week (40 hours)? B. I. h = how many hours of child care is needed = 40 f = the flat hourly rate charge t = total amount due for the week Option A: f * h = t a. 9 * 40 = $360 Option B: 150 + f(h-20) = t, for h >=20 b. 150 + 10(40-20) = $350 150 = t, for h < 20 c. 150 = total II. I set the hours to "h", the hourly fee to "f" and the total to "t". a. Option A: This option only has an hourly fee for each hour. The fee is $9 and the amount of hours is 40 so I multiplied the hours by the fee. b. Option B: This option has a flat rate of $150 for the first 20 hours and then an hourly rate of $10 thereafter. For the first equation that refers to over 20 hours, I subtracted 20 hours from the total time, multiplied it by $10, and then added it to $150. For the second equation that refers to any amount less than 20 hours, the total is always going...
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...Quantitative Literacy Numeracy, Algebra, & Geometry - All 5 Tasks http://www.homeworkminutes.com/question/view/41069/QLT1-WGU-Quantitative-Literacy-ALL-5-TASKS This tutorial contains all of the required attachments for the entire QLT1 Quantitative Literacy course at WGU. All of the attachments passed the Taskstream evaluations. Task 1 Solving Algebraic Equations: The attachment contains the graphs for parts A1 (graphing values on a number line), A2 (graphing points on a single coordinate plane), and A3 (graphing functions on spearate coordinate planes). There are six graphs total. Task 2 Solving Algebraic Equations: The attachment pertains to a man shining a laser beam from a third-story window and contains the calculation for part A1, the graph for part A2, the identification of points for part A3, the height for part A4, the explanation for part A4a, the determination for part A5, and the explanation for part A5a. Task 3 Solving Algebraic Equations: The attachment pertains to a person saving money according to a rigid savings schedule and contains the equations for part A1, the solutions to the equations for part A2, the graph for part A3, the determination for part A3a, and the explanation for part A4. Task 4 Constructing Arguments and Reasoning: The attachment contains the logical progression of steps to develop a reasonable and complete geometric proof of isosceles Triangle ABC. Task 5 Solving Algebraic Equations, Applying Probability and Statistics...
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...Mike Henkle QLT1 Task 5 Western Governors University A. Create a story problem using one of the above real-world scenarios as a basis, including realistic numeric values, by doing the following: 1. Describe the real-world problem. I was looking into phone plans and stumbled upon T-Mobile, and I decided that I needed a cell-phone and took a look at the plans. T-mobile had one plan that was 50 dollars a month and is unlimited talk, text and web, T-Mobile also has a plan for 30 dollars a month for 1,500 talk and text minutes. After you go through your allotted 1,500 talk and text time was up, the cost skyrockets up to 10 cents a minute. 10 cents a minute comes out to 6.00 per hour, I thought in my head. I decided that instead of jumping into a decision about phone plans, that I should first go home and do the math. I wanted to figure out which plan was going to be the most cost effective, and which plan would suite my needs the best. 2. Explain all needs (e.g., financial, non-financial, situational) of the hypothetical consumer. The needs include many different factors: • The first and most important factor how much do you use your phone? The breaking point on the problem today is 200 talk or text above the 1500 minute plan and I will be paying less up front but more on the back end which is no good. If I chose the 1500 minute plan, I will not want to be going over the 1500 minutes as then the cost would go up to 10 cents...
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