...Корпорация Sure Cut Shears, Inc 28-го апреля 2006 года Майкл Стюарт, глава кредитного бюро Гудзонского Национального банка в Нью-Йорке, просматривал кредитное досье корпорации Sure Cut Shears,Inc готовясь к деловому обеду с президентом и вице-президентом по финансам этой компании. Дэвид Фишер, вице-президент по финансам компании SureCut Shears, Inc недавно поставил его в известность о том, что компания не сможет своевременно погасить свой просроченный заем, как ожидалось прежде. Размышляя, стоит ли еще раз продлить неуплаченный заем в 1,2 миллиона долларов (см. приложение 4), мистер Стюарт решил заглянуть в офис компании, когда будет поблизости от Саванны, штат Джорджия, где были расположено главное здание SureCut Shears Inc и обсудить с руководством в состояние дел компании,. SureCut Shears изготовляла миниатюрные домашние и большие промышленные ножницы. Ее качественная продукция распространялась через систему оптовой торговли по специализированным магазинам, парикмахерским и супермаркетам, расположенным по всей стране. Дешевые продукты продавались напрямую в сети универсальных магазинов. Несмотря на жестокую конкуренцию, SureCut Shears Inc получала прибыль, начиная с 1988 года. Объемы продаж и прибыль ежегодно росли. Гудзонский Национальный Банк обслуживал корпорацию SureCut Shears с начала 2005 года. После нескольких безуспешных звонков, мистер Стюарт в конце концов убедил членов правления SureCut Shears, что сотрудничество с таким...
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...MATA KULIAH MANAJEMEN TRESURI STUDI KASUS “SURECUT SHEARS, Inc” Disusun Oleh: FEBRIANTI K. - 1106112624 JUANITO GUNAWAN – 1106113141 MUHAMMAD HARTADI - 1106113570 PATRON M. HARA – 1106113892 MAGISTER MANAJEMEN UNIVERSITAS INDONESIA JAKARTA 2012 LATAR BELAKANG SureCut Shears adalah perusahaan manufaktur di Amerika Serikat yang memproduksi gunting dan alat potong untuk keperluan rumah tangga maupun keperluan industri. Saluran distribusi SureCut Shears dilakukan melalui pedagang khusus dan toko swalayan. Sejak tahun 1958, dalam perjalanan bisnisnya SureCut Shears selalu menghasilkan profit meskipun dalam kondisi persaingan yang ketat. Bisnis SureCut Shears adalah bisnis musiman yang memiliki siklus puncak dan siklus jatuh. Untuk mengantisipasi siklus bisnis seperti ini perlu upaya SureCut Shears dalam mengatur seluruh pola produksi bisnisnya terutama dalam hal pendanaan. Pada kondisi permintaan tinggi SureCut Shears akan membutuhkan dana untuk ekspansi kapasitas produksinya. Sehingga pada bulan Juni 1995, SureCut Shears menyusun proposal untuk melakukan pinjaman kepada Hudson National Bank senilai $3,5 juta dengan perkiraan akan terbayar lunas pada bulan Desember 1995. Selanjutnya Hudson National Bank menyetujui pinjaman tersebut didasarkan pada laporan Proforma Income Statement dan Balance Sheet SureCut Shears yang dinilainya cukup optimis. Hudson National Bank juga memberikan tambahan kredit kepada SureCut Shears pada bulan September 1995 sebesar $350.000. Namun...
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... was reviewing the credit file of SureCut Shears, Inc. in preparation for a luncheonmeeting with the company’s president and treasurer. David Fischer, treasurer of SureCut Shears,had recently informed Mr. Stewart that the company would be unable to liquidate its outstandingseasonal loan as initially anticipated. While agreeing to extend the outstanding $1.14 millionloan, Mr. Stewart had suggested that he would like to stop by and discuss the company’s recentprogress when he was next in the vicinity of Savannah, Georgia, where SureCut Shears’s homeplant and offices were located.SureCut Shears manufactured a complete line of household scissors and industrial shears.Its qua1ity lines were distributed through wholesalers to specialty, hardware, and departmentstores located throughout the country. Cheaper products were sold directly to large varietychains. Although competition was severe, particularly from overseas companies, SureCut Shearshad made profits in every year since 1958. Sales and profits had grown fairly steadily, if notdramatically, throughout the period.Hudson National Bank had been soliciting the SureCut Shears account for several yearsprior to early 1995. After several unsuccessful calls, Mr. Stewart finally convinced the officers of SureCut Shears that association with a large New York bank offered several advantages not to befound with local banks. He was particularly pleased with the success of his efforts, becauseSureCut Shears historically held fairly sizable deposit...
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...Italy Italy | Tips to know: * Know the requirements for travel * You will need a current passport that has been valid for at least 3 months. * You cannot enter or exit the country with more than 10,000 euros * Medical Needs * Make sure you are up to date on your vaccines schedule prior to traveling. Depending on area and length of stay more vaccinations maybe required. * If your insurance policy does not cover you abroad, consider purchasing a short-term policy that does. * Pack enough medication for your entire trip and you may need a note from your doctor to carry your medication on the plane. * Never eat uncooked meat, eggs or drink water that is not bottled, including ice cubes. * Safety and Security * Keep ID and vital documents on you at all times. * Monitor via the State Department about any unrest in the country. [Event Description Heading][To replace any tip text with your own, just click it and start typing. To replace the photo or logo with your own, right-click it and then click Change Picture. To try out different looks for this flyer, on the Design tab, check out the Themes, Colors, and Fonts galleries.] | | | | Due to earthquake fault lines and active volcano’s in Italy:It is wise to prepare with an emergency preparation plan through FEMA. For security, be mindful of your surroundings. Learn about laws and customs.Illness’s more common in Italy:Travelers' diarrheaCholeraEscherichia coli diarrheaHepatitis ATyphoid...
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...deformation affects rocks – by translation, rotation, distortion Strain • Change in shape • elastic strain (reversible change) • Permanent strain – brittle & ductile deformation (non-reversible) • Cause of deformation – stress – force acting on a rock – often a large scale tectonic origin. Stress is force per unit area. Think of the non-metric measure PSI – (pounds per square inch) Stress • Compression – squeezing, shortening or contraction, or pushing together. Think continental collision – Himalayas formation. • Extension – tension, stretching, pulling apart. Tends to thin the crust – think the Taupo Volcanic zone which is extending at 7 mm a year. The lithosphere is thin allowing magma to reach the surface. • Shear – sliding past, strike-slip. Blocks of rock slide past each other – the surface is neither thickened or thinned. Think the Alpine Fault. Deformation structures (brittle) – for these, need to be able to draw a diagram. • Normal fault. Due to extension. • Reverse fault (> 35 degrees) – due to compression • Thrust fault (< 35 degrees) – compression on a shallow-dipping fault plane. • Strike-slip fault (Waiarapa fault) – recognising left lateral, right lateral. The ages and displacements (horizontal nad vertical) indicate the amount of movement on the fault plane, during one...
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...Name: Kevin Lundstrom Class: Monday Group: 3 Lab Partners: Rusty Flocken Oliver Beres Torsion Introduction The purpose of this experiment was to ultimately determine the shear modulus, 0.2% offset shear yield point, and ultimate shear strength of two different materials: aluminum and brass. This was accomplished using a torsion test machine connected to a computer that recorded the torsion data. After determining these three material properties, the measured experimental values could be compared to published data to determine the accuracy of the test. Experimental Procedure In this experiment the specimens underwent torsion by means of a torsion test machine. This machine consisted of two drill chucks: one was attached to a rotating chain-driven wheel, and the other was held stationary. A potentiometer was used to determine the number of revolutions the rotating wheel had undergone. Strain gauges were attached to the stationary drill chuck. LabVIEW was used to measure and record the data from the potentiometer as well as the strain gauges. Each sample was measured until it failed. The length of each specimen as well as the diameter was recorded in order to perform calculations. Also, the diameter of the potentiometer as well as the drill chuck, as well as the minimum and maximum resistance of the potentiometer was recorded for calculations. Results/Discussion The recorded measurements are shown in the table below. These were necessary to perform the...
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...preferred to adjust the shear stress and shear rate relationship of the specimens at 25°C and 70°C and test results are evaluated with the plotted flow and viscosity curves. Then, samples are categorized due to their time dependence or shear stress dependence. 1. INTRODUCTION A Newtonian fluid is a fluid whose stress versus rate of strain curve is linear and passes through the origin. The constant of proportionality is known as the viscosity. A simple equation to describe Newtonian fluid behavior is (1) Where; τ is the shear stress exerted by the fluid [Pa] μ is the fluid viscosity - a constant of proportionality [Pa·s] is the velocity gradient perpendicular to the direction of shear [s−1] For a Newtonian fluid, the viscosity depends only on temperature and pressure (and also the chemical composition of the fluid if the fluid is not a pure substance), not on the forces acting upon it. Water is a typical Newtonian fluid. In a Non-Newtonian fluid, the relation between the shear stress and the strain rate is nonlinear. Therefore a constant coefficient of viscosity cannot be defined and they can even be shear –stress dependent or time-dependent. Shear stress dependent materials are divided into two groups. In shear thickening materials, the viscosity increases with increased shear rate. These materials are categorized as dilatant materials such as sand in water. In shear thinning materials, the viscosity decreases with increased shear rate. These materials...
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...address prevention of anchorage and shear failure in this region during severe earthquake shaking. In view of these limitations, this paper proposes new provisions for inclusion in IS 13920 : 1993. The paper also gives a clause-by-clause commentary on these recommended provisions and includes one solved example to illustrate the same. Keywords: Beam-column joints, wide beam, strong-column weakbeam, shear design. Beam-column joint is an important component of a reinforced concrete moment resisting frame and should be designed and detailed properly, especially when the frame is subjected to earthquake loading. Failure of beam-column joints during earthquakes is governed by bond and shear failure mechanism which are brittle in nature1. Therefore, current international codes give high importance to provide adequate anchorage to longitudinal bars and confinement of core concrete in resisting shear2. A review of the behaviour and design of different types of beam-column joints in reinforced concrete moment resisting frame under seismic loading illustrates that design and detailing provisions for the joints in the current Indian seismic code, IS 13920 : 1993 are not adequate to ensure prevention of such brittle failure3,4,5. Since joints are subjected to large shear force during earthquake, shear strength in this region should be adequate to carry this large amount of shear force. Therefore, the current code needs to be upgraded to incorporate shear design provisions of beam-column joints...
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...Purdue University Calumet College of Technology Department of Mechanical Engineering Technology MET 21100 – Strength of Materials Torsion Lab Experiment Performed: 4/3/14 Report Due Date: 4/17/14 Report Submitted: 4/17/14 Joshua Deakin Prepared for Aaron Kolb Introduction: In the designing of buildings and structures, torsion, or torque could be applied to certain members. Most times, torsion is found at almost all times in a vehicle, on each axle, the driveshaft, and many others parts in a vehicle. These members all need to withstand the angular moment or load that is acted on it. You do not want to step on the gas, and your driveshaft or axles snapping. You wouldn’t be going anywhere anytime soon. The torsion test primarily measures, at a certain moment or load, how much the bar or specimen is twisting and at what angle. This test can also be done in reverse order measuring the angle first, and recording the torque on the test material. The testing of a “torque-angle” graph can be somewhat similar to a “stress-strain” curve. There are a few different types of torsion tests * Torsion only: applying only a torque (what we had done) * Axial-torsion: Applying and axial, as in tension or compression, and a torsion force to the specimen * Failure: applying the load until the specimen fails, which includes a physical break, kink or other defect in the specimen * Proof: In this test, you apply a torsion and hold that force for an extended period...
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...Chap 1 : Stress Learning Outcomes: At the end of this chapter, students should be able to: • Determine the internal resultant loadings by applying methods of sections and equations of equilibrium • Determine the average normal and average shear stresses in loaded members • Produce a safe design by incorporating the concepts of allowable stresses and factors of safety SK/Chap1/1 Chap 1 : Stress Course Outcomes Addressed CO1: Analyze the stress-strain relationship in various structural members subjected to single loadings; axial load, torsion, bending and shear load; CO4: Design for dimension and strength of structural members subjected to various external loads, determine their deformation, and select the suitable material for a specific engineering application. SK/Chap1/2 Chap 1 : Stress 1.1 Introduction • intensity of the internal forces distributed over a given section (area) • basic units: N/m2 or pascal psi (pounds per square inch) • prefixes used for units : kilo, k (103) mega, M (106) giga, G (109) SK/Chap1/3 Chap 1 : Stress • Normal Stress – Force per unit area acting normal to A Fz z lim A 0 A • Shear Stress – Force per unit area acting tangent to A Fx zx lim A 0 A Fy zy lim A0 A SK/Chap1/4 Chap 1 : Stress 1.2 Average Normal Stress P A where = average normal stress P = internal resultant normal force A = cross-sectional area SK/Chap1/5 Chap 1 : Stress Example 1 ...
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...10-5 m3 For hollow shaft of outer diameter 12mm, inner diameter 6mm, Experimental % change in torsional stiffness, = (261.09 – 264.63) / 264.63 x 100% = -1.3377 % Theoretical % change in torsional stiffness, = - (0.006 / 0.012)4 x 100% = -6.25 % % change in volume, Vh = = 8.483 x 10-6 m3 = (8.483 x 10-6 - 1.131 x 10-5) / (1.131 x 10-5) x 100% = -25.00 % Theoretical % change in maximum shear stress, = [12 / (124 – 64) – 1/123] / (1/123) x 100% = 6.67 % Table 3: Strength and stiffness of hollow and solid shafts having the same volume For solid shaft of diameter 7.93mm and hollow shaft of outer diameter 12mm, inner diameter 9mm, Experimental % change in torsional stiffness, = (240.17 – 119.57) / 119.57 x 100% = 100.86 % Theoretical % change in torsional stiffness, = 2 x [1-(7.93/12)2] / (7.93/12)2 x 100% = 257.98 % Theoretical % change in maximum shear stress, = [12 / (124 – 94) – 1/7.933] / (1/7.933) x 100% = -57.78 % Table 1: Experimental data for solid and hollow shafts Angular Displacements Torque (Nm) for...
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...in 2 or pascal (Pa) strain – the resulting deformation. Hooke’s Law: stress elastic mod ulus strain 3 Types of Stress tensile or compressive stress – changes the length of a strained body. tensile stress bulk stress – changes the volume of a strained body. bulk stress shear stress – opposite forces act at different points in the body. shear stress Tensile and Compressive Stress Consider a body of initial length lo acted upon by a tensile or compressive force of F. F stress A l strain lo Young’s Modulus (Y) F stress A Y strain l l o Flo Y Al Example 1 Bulk Stress When uniform pressure p acts on a body, the volume of the body decreases. F pressure stress A V strain Vo F stress A B strain V V o Bulk Modulus (B) p B V V o B p V Vo Example 2 Shear Stress and Strain When equal and opposite forces act tangent to the opposite sides of a body, a shear strain is produced. F// stress A x strain h x h x tan h Shear Modulus (S) F// h S Ax F// S A tan Example 3 F// = 9.0 x 105 N A = 5.0 x 1-4 m2 F Ssteel = 7.5 x 1010 Pa a ) s. strain s. stress F// 2.4 x10 2 S AS F b) x (h)( s.strain) 2.4 x10 3 m F F Example 4 Example 5...
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...concentrated and uniformly distributed loads. 5. Apply different formulae to analyze stresses in struts and columns subjected to axial loads. 7 Outline syllabus 7.01 MEC211.A Unit A Simple stresses and strains 7.02 MEC211.A1 Unit A Topic 1 Concept of stress and strain, St. Venant’s principle, Stress and strain diagram, Hooke’s law, Young’s modulus (E), Modulus of Rigidity(G), Bulk modulus(K), Poisson ratio. 7.03 MEC211.A2 Unit A Topic 2 Stress and elongation in a bar due to its self – weight, Elongation in case of a Taper rod, Stress in Varying cross-section and Load, Stress produced in compoundbars subjected to axial loading,Factor of safety. 7.04 MEC211.A3 Unit A Topic 3 Thermal stress and strain calculations,Shear stresses and shear strain, Complementary shear stress 7.05 MEC211.B Unit B Compound stress and strains, Thin Cylinder...
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...Introduction The MecE 360 Shaft Design Project consists of designing a gear shaft within specified limits and given angular velocity and power for a certain application of the group`s choosing. This preliminary report will cover the preliminary geometry of the shaft as well as the calculations and information used to obtain this geometry. The members Group 19 have designed a preliminary shaft to be operated at an input angular velocity of ω = 554 rpm and an input power of P = 20KW to be used for . The limits of this project are given by the four different sized gears that are attached to the shaft as well as the module in the normal plane of 4mm and a pressure angle in the normal plane of 0.35-rad (See Appendix C1). The shaft’s linear deflection is not to exceed 0.05mm and the angular deflection is not to exceed 0.03 degrees at the bearings. All gears and bearings were labeled to avoid confusion and ease of calculations (See Appendix A: Figure 1). Discussion Assumptions were made prior to the design of the shaft. Group 19 had assumed the shaft and the gears to be frictionless and all four gears are to be made of the same material, a variation of steel. a) Speed Ratio By looking at the whole gear-shaft assembly, the input and the output of speed or power was determined (See Appendix A: Figure 1). The speed ratio between the two shafts can be determined, in this case, by using the diameters of the four gears given. First, the number of...
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...Simple Stresses Simple stresses are expressed as the ratio of the applied force divided by the resisting area or σ = Force / Area. It is the expression of force per unit area to structural members that are subjected to external forces and/or induced forces. Stress is the lead to accurately describe and predict the elastic deformation of a body. Simple stress can be classified as normal stress, shear stress, and bearing stress. Normal stress develops when a force is applied perpendicular to the cross-sectional area of the material. If the force is going to pull the material, the stress is said to be tensile stress and compressive stress develops when the material is being compressed by two opposing forces. Shear stress is developed if the applied force is parallel to the resisting area. Example is the bolt that holds the tension rod in its anchor. Another condition of shearing is when we twist a bar along its longitudinal axis. This type of shearing is called torsion and covered in Chapter 3. Another type of simple stress is the bearing stress, it is the contact pressure between two bodies. Suspension bridges are good example of structures that carry these stresses. The weight of the vehicle is carried by the bridge deck and passes the force to the stringers (vertical cables), which in turn, supported by the main suspension cables. The suspension cables then transferred the force into bridge towers. Normal Stress Stress Stress is the expression of force applied to a unit...
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