The Situation
You are playing Texas Hold’em against one other opponent.
• Your two down cards are 6 of (diamonds) & 7 of (diamonds).
• The first three cards to come up are 3 of (diamonds), 4♣ 9♠.
• The next card to come up is 10 of (diamonds).
You and your opponent have both already bet $24,000 into the pot each. Your opponent now adds $10,000 to the pot. You only have $10,000 left in total.
While you consider what to do, your opponent, in an effort to rattle you, reveals his down cards. They are 10♣ 10♠.
The Problem
Should you call his bet by tossing the rest of your money into the pot, or should you fold and give up the pot to your opponent?

Remember your opponent has at least a pair of 10s. What cards could come up to make your hand better? What could come up to make your opponent’s hand better? Is there any way you could tie each other? Also look at the expected value of the game. If you fold, you are assured a loss of $24,000. Make sure this fact is used in your analysis.

I would simply solve my problem by going all in and betting the $10,000.00 that I have left. I would be a winner should the next card be an eight (8) because a straight which is five (5) cards in a row (in this case 6, 7, 8, 9, and 10) beats a 3 of a kind (my opponent’s three 10’s). Another reason I would not fold is because if the next card that comes up is a diamond I would also be a winner. I would then have a flush (which is five cards of the same suit), which wouls also beat my opponents three (3) of a kind. My opponent could perhaps beat my flush if the ten (10) of diamonds was not down yet because even if the ten (10) would give me a flush (with the diamonds) my opponents four (4) of a kind (should he get his four tens) would still beat it. However, since the ten (10) of diamonds is already down then any diamond card will give me a winning hand. My opponent would win if any other card is drawn simply because he already has a three (3) of a kind. Since only thirteen of the remaining fourty-four cards in the deck could possibly be winners for me, eight (8) that would give me a straight (four 8's and four 5's) and nine (9) that would give me a flush. Only two (2) of them were already counted, and two (2) of them would give my opponent a full house (the four of diamond and the nine of diamond). With that said, if I were playing with my own money I would take my $10,000.00 and go home. Since this is only hypothetical, I would take a chance on the win.