Week 2
Exercise One - Geometry Complete the following in your team meeting and be prepared to report your results and discussions to the class:
Complete parts 1–5 from the Group Activity at the end of section 2.3 in Ch. 2 of the text.
Discuss any concept that a team member is having a difficult time understanding.
Examine the importance and applicability of this week’s concepts to each team member and to society in general.
Plan and work on team assignments or projects.
Give a brief update to the class in which you present your team’s solutions from this exercise. Be sure to describe how this exercise applied to the weekly concepts.
Prepare to update your instructor on your team’s progress on Learning Team assignments.

Exercise 1. Directions: Form a group of 2 to 4 people. Select someone to record the group’s responses for this activity. All members of the group should work cooperatively to answer the questions.
If your instructor asks for your results, each member of the group should be prepared to respond.
Exercises 1–5: In this set of exercises you are to use your mathematical problem-solving skills to find the thickness of a piece of aluminum foil without measuring it directly.

Area of a Rectangle The area of a rectangle equals length times width. Find the area of a rectangle with length 12 centimeters and width 11 centimeters. Area of a Rectangle: A=LW L= 12 and W= 11
A= 12 * 11
A = 132 centimeters Volume of a Box The volume of a box equals length times width times height. Find the volume of the box shown, which is 12 centimeters long, 11 centimeters wide, and 5 centimeters high. V = LWH L= 12 centimeter, W= 11 centimeters, and H= 5 centimeters V=12*11*5 V= 660 cc (cubic centimeters) Height of a Box Suppose that a box has a volume of 100 cubic centimeters and that the area of the bottom of the box is 50 square centimeters. Find the height of the box.

Height of a box: V/A=H
Volume: 100 cubic centimeters, Area= 50 square centimeters
H = 100/50 H = 2 centimeters is the height
4. Volume of Aluminum Foil One cubic centimeter of aluminum weighs 2.7 grams. If a piece of aluminum foil weighs 5.4 grams, find the volume of the aluminum foil.

Volume of Aluminum Foil: 2.7 grams=1 cm3 5.4 grams=2 cm3
One cubic centimeter: 1 cm × 1 cm × 1 cm
Grams is a mass (5.4 grams) and cubic centimeters is a volume (the same volume as 1 millimeter) Density= mass/volume 5.4/2.7=2cm3 A cubic centimeter cm3 — the abbreviations cc and ccm, is a commonly used unit of volume extending the derived SI-unit cubic meter, and corresponds to the volume of a cube measuring 1 cm × 1 cm × 1 cm. One cubic centimeter corresponds to a volume of 1⁄1000000 of a cubic meter, or 1⁄1000 of a liter, or one milliliter; thus, 1 cm3 ≡ 1 ml.
5. Thickness of Aluminum Foil A rectangular sheet of aluminum foil is 50 centimeters long and 20 centimeters wide, and weighs 5.4 grams. Find the thickness of the aluminum foil in centimeters.

Volume = 2 Result from question 4
Length = 50, Width = 20, (L * W = 1000)
Thickness = T
Volume = LWT: Example (2 = 50*20*T)
Thickness = V LW
T = V LW
T = 2 = 2 = .002 millimeters thick 50*20 1000
T = .002
Therefore, the thickness is .002 millimeters thick
Exercise Two - Global Warming Complete the following in your team meeting and be prepared to report your results and discussions to the class:
Complete question 6, parts a–e, from the Extended and Discovery Exercises at the end of Ch. 2 of the text.
Discuss any concept that a team member is having a difficult time understanding.
Examine the importance and applicability of this week’s concepts to each team member and to society in general.
Plan and work on team assignments or projects.
Give a brief update to the class in which you present your team’s solutions from this exercise. Be sure to describe how this exercise applied to the weekly concepts.
Prepare to update your instructor on your team’s progress on Learning Team assignments.

Global Warming If the global climate were to warm significantly as a result of the greenhouse effect or other climatic change, the Arctic ice cap would start to melt. This ice cap contains the equivalent of some 680,000 cubic miles of water. More than 200 million people live on land that is less than 3 feet above sea level. In the United States several large cities have low average elevations. Three examples are Boston (14 feet), New Orleans (4 feet), and San Diego (13 feet). In this exercise you are to estimate the rise in sea level if the Arctic ice cap were to melt and to determine whether this event would have a significant impact on people living in coastal areas.

(a) The surface area of a sphere is given by the formula where r is its radius. Although the shape of Earth is not exactly spherical, it has an average radius of 3960 miles. Estimate the surface area of Earth.

A ≈ 4*3.14*39602 A ≈ 4*3.14*15,681,600 A=196,960,896r^2 i
(b) Oceans cover approximately 71% of the total surface area of Earth. How many square miles of Earth’s surface are covered by oceans?

196,960,896 * .71= 139,842,236.16 m2

(c) Approximate the potential rise in sea level by dividing the total volume of the water from the ice cap by the surface area of the oceans. Convert your answer from miles to feet.

We determined the total surface area of the oceans. We must determine the total volume of water in the ice caps 680,000〖cm〗^3 and write those values below. Include the units.

Volume of water in ice caps = 680,000〖cm〗^3
Surface area of oceans =〖 139,842,236.16 m〗^2

Calculate the rise in sea level by dividing the volume of water in the ice caps by the total surface area of the ocean. To convert from kilometers to meters, multiply the result by 1000.

(d) Discuss the implications of your calculation. How would cities such as Boston, New Orleans, and San Diego be affected?

(e) The Antarctic ice cap contains some 6,300,000 cubic miles of water. Estimate how much the sea level would rise if this ice cap melted.