dice. 11 because it shows up twice so 2/36 because there is 36 possible outcomes simplified 1/18. 1 | 2 3 4 5 6 7 2 | 3 4 5 6 7 8 3 | 4 5 6 7 8 9 4 | 5 6 7 8 9 10 5 | 6 7 8 9 10 11 6 | 7 8 9 10 11 12 B . odds or above 9 Answers odd probability on both odds is ½ above 9 is 10/36 C. (4/1)(13/5)=5148*2=10296 for Black Flush. (13/2)(4/2)^2(44/1)+123552 for Two Pair. So black flush.
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leaving Host A. e) The first bit is in the link and has not reached Host B. f) The first bit has reached Host B. g) Want km. Problem 8 a) 20 users can be supported. b) . c) . d) . We use the central limit theorem to approximate this probability. Let be independent random variables such that . “21 or more users” when is a standard normal r.v. Thus “21 or more users”. link: http://www.stat.ufl.edu/~athienit/Tables/Ztable.pdf Problem 10 The first
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Starbucks Queuing Model Inevitably, for those coffee drinkers that don’t have a coffee machine at home, it is a fact of life that you would have to wait in lines at your closest coffee shop to get that glorious cup of Joe. For the one of the most prolific coffee chains, Starbucks, this is a problem that needs to be addressed as customer service is one of the cornerstones of the industry. In order maintain a good customer service, Starbucks must minimize the in-line wait time and the service times
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existing contract specifies that once Company A places the order, no changes are allowed to it. Also, Company B does not accept any returns of unsold inventory, so Company A must dispose excess inventory in the secondary market. 1) What is the probability that Company A’s demand will be more than 40% greater than its forecast? 2) Under this contract, how many units should Company A order to maximize its expected profit? For Questions 3) to 5), assume Company A orders 1,200 units. 3) What are Company
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Will Semsch 17/02/2015 Case Study #1 In offer number one you would receive $1,000,000 now, $200,000 from year 6-15, then 3,000,000 if the product did $100,000,000 in sales, which had a 70% probability. To calculate to present value of 3,000,000 in 15 years you first have to multiply it by the possibility, 0.7 giving you 2,100,000. I then used the equation. 2,100,000* 1/(1.1)^15 giving an answer of $502,723.30. After that I calculated the value of the ordinary annuity from year 6-15 by using
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Returning to the earlier example, there are 3 key points: Why should theoretical price be the market price? This is an important question. If not then there is risk-free money to be made. If C < 50p buy it and hedge to make pro…t. If C > 50p sell it and hedge, make a guaranteed pro…t. Supply and demand should make this price converge to 50p. How do I know to sell 1/2 the stock for hedging (and not another value)? means the amount of stock sold for hedging purposes. The right choice for hedging
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statistically independent, which allows us to sum the individual expected activity times and variance to get an expected project time and variance (Russell & Taylor III, 2014).” I decided to conduct a probabilistic analysis to determine the probability that building a home will be completed within 45 days. This analysis shows that the duration of building one home would be 45.83 days. The Critical Path for this project
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CHAPTER 13 RISK, RETURN, AND THE SECURITY MARKET LINE Answers to Concepts Review and Critical Thinking Questions 1. Some of the risk in holding any asset is unique to the asset in question. By investing in a variety of assets, this unique portion of the total risk can be eliminated at little cost. On the other hand, there are some risks that affect all investments. This portion of the total risk of an asset cannot be costlessly eliminated. In other words, systematic risk can be controlled
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This means that the probability of missingness is not related neither to the recorded variables of the data nor the unobserved variable $Z$ itself. In other words, the behavior of $M_{Z}$ is statistically independent of all remaining variables of the data. For example, if the participants throw a coin to decide if they will answer a question or not, the missing item is MCAR. The independence of $M_{Z}$ from the missing values $Z$ cannot be tested because we do not have access to the values which
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Crutcher Dr. Emeka Dunu, MAT 540 6/3/13 In the JET Copies Case Problem the probability function of time between repairs is the one of the issues and the other is the loss of revenue if they do not purchase the new copier. We were asked to generate a random value for computation of times between breakdowns. Using these random numbers and the linear formula SQRT(R1)*6, which represents the slope and probability function for breakdown intervals, we were able to compute the interval between breakdowns
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