to the Dow and Schulman that had the least profits. In 2010, the three companies continued to earn profit but with a weaker momentum. Expected rate of return In order to estimate the rate of return for the following year, I have estimated the probability of having strong, normal, and weak demand. Since I believe that the market characteristics have somehow changed after the financial crises, I’ve based my estimates for the rate of return on the last 10 years with some adjustments to make it more
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had implemented the strategy I would have had lesser money, as the value of blue asset is very less than the red ones and ones with more red assets would benefit more. Frankly I didn’t have any estimate of what each asset would value at. The probability for each number is equal and hence prediction is difficult. Then in game 2 most of the people might have had the thought of increasing the red assets but I thought the value might drop and blue might weigh more. With this view I did not sell
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Weekly Study Plan for AFE134: Business Statistics SP1 2015 | | |Week
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Credibility Theory Lecture Solutions – Week 1 1.1 Let A be the event that a student is an actuarial student. C be the event that a student is a Credibility Theory student. P(C) = 0.02 ⇒ P( C ) = 0.98 P(A | C) = 0.98 P(A | C ) = 0.07 P( A | C ) P(C ) P ( A | C ) P(C ) + P( A | C ) P(C ) P (C | A) = = 0.98 × 0.02 0.98 × 0.02 + 0.07 × 0.98 = 0.0196 0.0882 = 0.2222 = 22% 1.2 Let A1 = “The science department is a heavy polluter”. A2 = “The science
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2. The continuous random variable X is uniformly distributed over the interval [–1, 4]. Find (a) P(X < 2.7), (1) (b) E(X), (2) (c) Var (X). (2) 3. Brad planted 25 seeds in his greenhouse. He has read in a gardening book that the probability of one of these seeds
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1) Mean: The mean of a set of numbers is the average. The mean is calculated by finding the sum of all the values and dividing by the number of values. 11+12+12+13+14+16+18+19+20 = 135 There are 9 numbers in the series, so the mean is: Mean = 135/9 = 15 Median: The median of a series of numbers is the number that appears in the middle of the list when arranged from smallest to largest. For a list with an odd number of members, the way to find the middle number is to take the number of members
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that it broke down. As discovered, the average time for repair was between one and four days. In order to calculate the average, a probability distribution was developed using Microsoft Excel. From there, the cumulative probability was obtained by adding the probability, P(x), from the previously itemized probabilities where the cumulative summation of a probability is always equal to one (1) or 100%. A random number formula, =RAND(), was plugged into the Microsoft Excel desired cell, in this situation
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exploring data through different numerical measures. | To provide a progressive and structured framework to graduates that enables them in developing and applying knowledge set of critical and ethical evaluation. | 3 | To know and understand probability and its different rules. | To craft graduates’ expertise in order to increase their resourcefulness. | 4 | To
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1 Mathematics for Management Concept Summary Algebra Solving Linear Equations in One Variable Manipulate the equation using Rule 1 so that all the terms involving the variable (call it x) are on one side of the equation and all constants are on the other side. Then use Rule 2 to solve for x. Rule 1: Adding the same quantity to both sides of an equation does not change the set of solutions to that equation. Rule 2: Multiplying or dividing both sides of an equation by the same nonzero number
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What is the probability that three of the trainees will still be employed at the end of 9 months? A) 0.0415 B) 0.0446 C) 0.0146 D) 0.0012 2) What is the probability that at least two of the trainees will still be employed at the end of 9 months? A) 0.9841 B) 0.0159 C) 0.1143 D) 0.0984 THE NEXT QUESTIONS ARE BASED ON THE FOLLOWING INFORMATION: A basketball player makes 80 percent of his free throws during the regular season. Consider his next 8 free throws. 3) What is the probability that he will
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