1. What fraction of the days in 2004-2004 failed to meet the targeted daily average hold time of 110 econds? Given that the daily average hold time was normally distributed with a mean of 99.67 and a standard deviation of 24.24, what fraction of days where the call center failed to meet the targeted hold time of 110 seconds would you expect? a) Based on the data in the exhibit 1, the number of days out of target hold time (more than 110 seconds) is 237. And total number of days is 728. Therefore
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Answer of Discussion Questions Q1. Given, The mean daily hold time μ = 99.67 s; Standard Deviation σ = 24.24 s The targeted hold time x = 110 s The fraction of days when hold time exceeded 110 s = P(x>110) = ? Answer: Mean of a distribution (μ) and a data point (x) is related by the following equation: x = μ ± zσ For x > 110 s; [pic] Now, [pic] Value of [pic] is area under normal curve between z = 0 to z = 0.43. Thus it can be seen that fraction of days when call center failed to meet
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One-Sample Tests of Hypothesis LEARNING OBJECTIVES 1 Define a hypothesis. 2 Explain the five-step hypothesis-testing procedure. 3 Define Type I and Type II errors. 4 Define the term test statistic and explain how it is used. 5 Distinguish between a one-tailed and a two-tailed hypothesis. 6 Conduct a test of hypothesis about a population mean. 7 Compute and interpret a p-value. 8 Conduct a test of hypothesis about a population proportion. 10-2 Define a hypothesis. Explain the
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STANINE SCORE - Coined from Standard Nine. - Standard score that separates the normal distribution into 9 symmetrical groups , where there is one-half (1/2) Sd equally distributed fore ach of the groups from 2nd to the 8th while placing the mean at the center of the 5th. DISTRIBUTION OF STANINE SCALE Stanine Percent of Distribution z-score boundaries Performance Distribution 9 4% Above 1.75 Superior 8 7% Above 1.25 to 1.75 Above Average 7 12% Above 0.75 to 1.25 Above Average 6 17% Above
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Chapter 7—Introduction to Sampling Distributions When applicable, selected problems in each section will be done following the appropriate stepby-step procedures outlined in the corresponding sections of the chapter. Other problems will provide key points and the answers to the questions, but all answers can be arrived at using the appropriate steps. Section 7-1 Exercises 7.1. Step 1: The population mean of 125 is given Step 2: Compute the sample mean using Equation 7-3 x = (103 + 123 + 99 +
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Sampling and Sampling Distributions Practice Exam - Solution Instructors: Dr. Samir Safi Mr. Ibrahim Abed SECTION I: MULTIPLE-CHOICE 1. Sampling distributions describe the distribution of a) parameters. b) statistics. c) both parameters and statistics. d) neither parameters nor statistics. 2. The Central Limit Theorem is important in statistics because a) for a large n, it says the population is approximately normal. b) for any population, it says the sampling distribution of the sample mean
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7, 10, 6 Make (a) a frequency table and (b) a frequency polygon. (c) Make a grouped frequency table using intervals of 0-5, 6-10, 11-15, 16-20. Based on the grouped frequency table, (d) make a histogram and (e) describe the general shape of the distribution. 4. Below are the number of minutes it took each of a group of 10-year-olds to do a series of abstract puzzles: 24, 83, 36, 22, 81, 39, 60, 62, 38, 66, 38, 36, 45, 20, 20, 67, 41, 87, 41, 82, 35, 82, 28, 80, 80, 68, 40, 27, 43, 80, 31, 89, 83,
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Applied Econometrics ━━HW3 徐韧锋 Xu Renfeng UID:2012970544 E10.2 a [pic] For the coefficient on the sb_useage term,t=3.30, p-value=0.001, which is smaller than 5%, we can reject the null hypothesis. The estimated coefficient on seat belt useage is positive and statistically significant. One the face of it, this suggests that seat belt useage leads to an increase in the fatality rate.
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C H A P T E R 6 The Normal Distribution Objectives After completing this chapter, you should be able to Outline Introduction 6–1 Normal Distributions 1 2 3 4 5 6 7 Identify distributions as symmetric or skewed. Identify the properties of a normal distribution. Find the area under the standard normal distribution, given various z values. Find probabilities for a normally distributed variable by transforming it into a standard normal variable. Find specific data values for given
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Introduction Sport Obermeyer, Ltd is an American sportswear manufacturer based in Aspen, Colorado. Founded by a creative German emigrant, it is a successful provider of various skiing apparels for all ages. Being successful for over 40 years, Obermeyer had thorough experience in providing high quality clothing in the middle-higher price range. In order to keep its competitive strengths, outsourcing to the Far East started around the early nineties to lower production costs. The product portfolio
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