Ethical and Professional Standards The candidate should be able to demonstrate a thorough knowledge of the CFA Institute Code of Ethics and Standards of Professional Conduct, familiarity with the Global Investment Performance Standards, and familiarity with corporate governance issues and risks affecting companies. Study Session 1 Ethical and Professional Standards Reading Assignments 1.* “Code of Ethics and Standards of Professional Conduct” Standards of Practice Handbook, 9th edition
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establishing norms 8 1. Issues related to the reliability of a psychological measure 8 1. Definition 8 2. Measurement error 8 3. The reliability coefficient 9 4. Standard error of measurement 9 5. Types of reliability 10 2.6.1.5.1. Reliability measures of stability 10 - Test-retest reliability - Alternate-form reliability 2.6.1.5.2. Reliability measures
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2nd grade class. {25, 60, 51, 47, 49, 45} Find the mean; median; mode; variance; standard deviation. Solution: This would be a sample from the class mean = 46.166 (=AVERAGE) median = 48 (=MEDIAN) mode does not exist (looking at the data) variance = 134.5667 (=VARIANCE.S) standard deviation =11.60029 (=STDEV.S) 3. If the variance is 846, what is the standard deviation? Solution: standard deviation = square root of variance = sqrt(846) = 29.086 4. If we have the
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654424 | 202400 | | | 3.674528 | 205900 | | | 3.77505 | 322500 | | | 7.123872 | Excel functions: Income Mean: =AVERAGE(Data!G2:G411) Standard Deviation: =STDEV(Data!G2:G411) z-score calculation: =(G2-Sheet2!$B$1)/Sheet2!$B$2 or =(G2-74459.51)/34818.21 c) Age of subscribers approximates normal distribution, and according to empirical rule, 68% of subscribers can be expected to be between ages 26 and 34, 95% of subscribers between ages 22 and 38, and 99% of subscribers
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average of 635 units with a standard deviation of 40. Their lowest production in a day was 494 and highest was 768. They did a 60 day trial run using the new method to determine if indeed it was a more efficient process. See Figure 1 below with the daily results of the 60 day trial: New Method Figure 1 As predicted the new method did start off slow due to the steep learning curve but starting month 2 (last 30 days) the production numbers were higher with a lower standard deviation. See actual
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been made. ------------------------------------------------- All variables appear statistically significant at the 95% level. They have their expected signs. The R bar square value is very high (.99806), as well as the F-stat (22135.4). Normal Distribution T-Test – Confidence Intervals P-Value | Similar to the previous model, the P-values for all 3 variables are 0.000. Since the value is less than 0.005, we reject the null hypothesis Ho and accept H1. The results are also statistically
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Question 1. (a) R²= 4.33% of the variation in the dependent variable RET is explained by the variation of the independent variables: GRI, SAT, TEN, Age, and MBA. We cannot assume from the low R squared that the model is useless because there might be one or more independent variables that are not significant to the dependent variable. Also, we cannot question the fact that the OLS are not accurate just by looking at the low R squared. In the opposite, adding new independent variables do increase
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CURTIN UNIVERSITY OF TECHNOLOGY School of Information Systems End of Semester 1 Examination June 2006 Internal/External Students: Internal and External. All Campuses. Unit Name: Business Statistics 101 Unit Number & Version: 10993 Version 3 Duration: Two hrs preceded by a 10 minute reading period. Supervisor will indicate when answering of exam may begin. If you wish to make notes, please use the back of your exam paper, or on the edge columns. Instructions:
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APPENDIX, T ABLE 2: STANDARD NORMAL DISTRIBUTION TABLE ~ • The eDtries lD this bible g in the areas uDder the IblDdard Dormal c ane from 0 t o:. 0 H, : 0.0 .00 .01 .02 .03 .04 .05 .06 .0000 .0040 .0080 .0120 .0160 .0199 0.1 0.2 0.3 0.4 0.5 .0398 .0793 .1179 .1554 .19lS .0438 .0832 .1217 .1591 .1950 .0478 .0871 .1255 .1628 .1985 .0517 .0910 .1293 .1664 .0557 .0948 .1331 .1700 .2054 0.6 0.7 0
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rate in % based on prices pc Generate / x = log(y) taking logs Generate / dlx = dlog(x) dlx = log(x) – log(x(-1)) Growth rate in continuous time Generate / y = exp(x) exp(x) as command: series x=0 Trend variable (linear): Generate / t = @trend Standard normal distributed realizations: Generate / x = nrnd Lags, lagged variables, taking differences: Generate / x1 = x(-1) x1(t) = x(t-1), Lag 1 of x Generate / dx = d(x) dx(t) = x(t) – x(t-1) = (1-B)x(t) first difference Generate / d2x = d(x,2) d2x(t) =
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