...pages –2– 1. Which processes occur during interphase? I. II. III. A. B. C. D. DNA replication DNA transcription Separation of replicated DNA molecules M02/410/H(1)+ I and II only I and III only II and III only I, II and III 2. What is the ratio of the relative size of a eukaryotic cell, a virus and a prokaryotic cell? Eukaryotic cell A. B. C. D. 100 100 100 1000 Virus 1 10 10 1 Prokaryotic cell 1 10 1 10 3. Which characteristic of water explains its thermal properties? A. B. C. D. Adhesion Surface tension Solvent properties Hydrogen bonding 222-134 –3– 4. Which structures represent a generalised amino acid and glycerol? I. H H N H R C C OH O M02/410/H(1)+ II. H H N H R1 H H C C N C C OH O R2 O III. OH H C H OH C H OH C H H IV. H H C H OH C H H Amino acid A. B. C. D. I II I II Glycerol IV III III IV 222-134 Turn over –4– 5. What is the arrangement of nucleotides in a single DNA strand? S = sugar, P = phosphate group, B = organic base M02/410/H(1)+ S A. P S B P B P B. B B C. P D. S S P B B P S S B S P B S P 6. Which group of three molecules makes up one RNA nucleotide? A. B. C. D. Phosphate, ribose, uracil Phosphorus, ribose, adenine Uracil, deoxyribose, phosphorus Guanosine, deoxyribose, phosphate 7. Which techniques of recombinant DNA technology (genetic engineering) require the use of plasmids? I. II. III. A. B. C. D. Gene...
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...COMMERCIAL BANKS AND NEW CAPITAL REGULATION MAF 202 Prepared By: Simardeep Sran - 211689444 Due: September 12, 2013 Table of Contents 1. Introduction 4 2. Findings 5 3.1. Move from Basel II to Basel III 5 3.2.1. The Global Financial Crisis and Basel II Shortcomings 5 3.2. Basel III 6 3.3.2. Main Features 6 3.3.3. Basel II and Basel III Difference 8 3.3. Implications of Basel III 9 3.4.4. Global Banking System 9 3.4.5. Banking System in Australia 9 3.4.6. Banking System in Japan 10 3. Conclusions 11 4. Reference List 12 1. Introduction The financial system is beyond indispensable in the global economy, with commercial banks playing a vital role as the main form of a financial institution. Within the financial system it is crucial to have regulations and guidelines for financial institutions...
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...economies in the world. P. 660. d. Open economy is an economy that interacts freely with other economies around the world. P. 660. 2. The International Flows of Goods and Capital a. The Flow of Goods: Exports, Imports, and Net Exports i. Exports are goods and services that are produced domestically and sold abroad. P. 660. ii. Imports are goods and services that are produced abroad and sold domestically. P. 660. iii. Net exports are the value of a nation’s exports minus the value of its imports, also called the trade balance. P. 660. iv. Trade balance is the value of a nation’s exports minus the value of its imports, also called net exports. P. 660. v. Trade surplus is an excess of exports over imports. P. 660. vi. Trade deficit is an excess of imports over exports. P. 661. vii. Balanced trade is a situation in which exports equal imports. P. 661. b. Case Study: The Increasing Openness of the U.S. Economy, P. 661. i. Over the last 50 years, both exports and imports as a share of GDP have more than doubled due to improvements in (1) transportation, (2) telecommunications, (3) technological progress and (4) the movement toward freer trade. ii. Figure 1: The Internationalization of the U.S. Economy. P. 661. iii. In the News: The Changing Nature of US Exports, P. 662. c. The Flow of Financial Resources: Net Capital Outflow i. Net Capital Outflow (NCO) is the purchase of foreign assets by domestic residents minus the purchase of domestic assets by foreigners. P. 664. ii. The flow of...
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... Math III – 1 1:00 - 2:20 Math III - 2 I. Objective: * Compare values of the different denominations of coins and bills through P1000 Value: Gratitude II. Subject Matter: Comparing values of the different denominations of coins and bills through P1000 References: BEC PELC – I A. 4. 3. Materials: Philippine money, play money, flashcards, charts III. Procedure: A. Preliminary Activities: 1. Drill: Write greater than, less than or equal to the following a. P50.00 __ P100.00 b. 2 ten peso bills __ P30.50 2. Review: Write the money values in symbols. a. nine hundred fifty pesos and fifty centavos b. seven hundred seventy-eight pesos and twenty five centavos 3. Motivation: Did you also receive Christmas gifts from your godparent? What did you say after you receive such gift? B. Developmental Activities: 1. Presentation: a. Last Christmas Edmar’s godparents gave him P500 P100P100 P50 . Allyssa’s godparents gave her P1 000 Edmar received P750 while Alyssareceived P1000. Let us compare the amounts. Use >, < or =. Which is more, 750 or 1000? Which is less? 2. Guided Practice Compare the following. Write >, < or = 1. P 955 ____ P 595 2. P 1 000 ____ P 100 3. P 99 ____ P59 4. P 678 ____ P 876 ...
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...10. The equation f ( x ) = 0 has only one real root. 4 (i) Show that the root lies between 0 and 2. (ii) Use one application of the ‘halving the interval’ method to find a smaller interval containing the root. (iii) Which end of the smaller interval found in part (ii) is closer to the root? Briefly justify your answer. Consider the equation 4 x 3 + 6 x 2 − x − 30 = 0. One of the roots of this equation is equal to the sum of the other two roots. Find the values of the three roots. 1996 (a) ( x − 2) is a factor of the polynomial P( x ) = 2 x 3 + x + a . Find the value of a. Marks The function f ( x ) = x 3 − ln( x + 1) has one root between 0·5 and 1. (i) (b) Show that the root lies between 0·8 and 0·9. (ii) Hence use the halving-the-interval method to find the value of the root, correct to one decimal place. 1997 (b) A particle is moving in simple harmonic motion. Its displacement x at time t is given by 4 x = 3 sin(2t + 5) . (i) Find the period of the motion. (ii) Find the maximum acceleration of the particle. (iii) (c) Find the speed of the particle when x = 2 . The polynomial P( x ) = x 3 + bx 2 + cx + d has roots 0, 3, and –3. (i) Find b, c, and d. (ii) Without using calculus, sketch the graph of y = P( x ) . (iii) Hence, or otherwise, solve the inequality x2 − 9 all over x > 0. 1998 Let α, β and γ be the roots of the polynomial 2x3 − 14x − 1 = 0. Find αβγ . A particle moves in a straight line and its position...
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...de la serie y los valores de la tendencia determinística, para distintos valores de (que dependen del parámetro c) y para =1. Una vez obtenidos los residuos de la estimación eficiente (es decir, aquella que minimiza la diferencia mencionada), se aplica un test de Dickey-Fuller sin constante o deriva y sin tendencia, por cuanto se trabaja con una serie transformada por precisamente la remoción de la tendencia determinística. EJEMPLO CON DATOS DEL PIB EN EVIEWS UNIT ROOT EN NIVELES CON 11 REZAGOS Null Hypothesis: PIB has a unit root | | Exogenous: Constant | | | Lag length: 4 (Spectral OLS AR based on SIC, maxlag=11) | Sample: 1 89 | | | | Included observations: 89 | | | | | | | | | | | | | | | | | P-Statistic | | | | | | | | | | | Elliott-Rothenberg-Stock test statistic | 2305.703 | Test critical values: | 1% level | | | 1.932400 | | 5% level | | | 3.079200 | | 10% level | | | 4.112800 | | | | | | |...
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... fg ( x ) = ……………. Object f(x)=y ……………… http://mathsmozac.blogspot.com 2 http://sahatmozac.blogspot.com 1.1 Functions Express the relation between the following pairs of sets in the form of arrow diagram, ordered pair and graph. Arrow diagram Ordered pair Graph a ) Set A = Kelantan, Perak , Selangor Set B = Shah Alam , Kota Bharu ,Ipoh Relation: ‘ City of the state in Malaysia ‘ b )Set A = triangle,rectangle, pentagon Set B = 3,4,5 Relation : ‘ Number of Sides’ 1.2 Determine domain , codomain , object, image and range of relation. List down the domain , codomain , objects , images and the range of the following relation . 3 9 2 5 1 4 -2 3 -3 1 Set P Diagram 1 Set Q Domain = ……………………………………… Codomain = ……………………………………… Object =…………………… Image =…………………… Range =…………………......
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...Horst Seibt COMPENDIUM OF CASE STUDIES OF INTERNATIONAL HUMANITARIAN LAW Horst Seibt Legal expert, German Red Cross COMPENDIUM OF CASE STUDIES OF INTERNATIONAL HUMANITARIAN LAW Translated and adapted from German by the International Committee of the Red Cross International Committee of the Red Cross 19 Avenue de la Paix 1202 Geneva, Switzerland T +41 22 734 6001 F +41 22 733 2057 E-mail: icrc.gva@icrc.org www.icrc.org Original German title: Es begann in Solferino ISBN 2-88145-058-X # International Committee of the Red Cross Geneva 1994 FOREWORD The ICRC takes pleasure in presenting this compendium of case studies of International Humanitarian Law (IHL), a collection of some 60 cases in which IHL is applicable, taken from a work entitled Es begann in Solferino by Mr. Horst Seibt, IHL expert, of the German Red Cross. With his kind permission, the ICRC has translated it and adapted it to the general plan of one of its recent publications, Basic Rules of the Geneva Conventions and their Additional Protocols. The analysis of case studies is (if I may be allowed the metaphor) a sort of obstacle race over IHL territory. It is the rider who, on completing his circuit faultlessly, realizes the majesty and beauty of horsemanship. And it is by overcoming all the difficulties of these cases that the importance of IHL, and its applicability to present conditions, will be realized and IHL better understood. The cases are admittedly difficult, but they can be an...
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...PRIVATE EQUITY One of the top ten Investment Bankers and winner of the M&A Atlas Awards – Deal of the Year 2011, ACQ Global Award 2009 for ‘Corporate and M&A Advisory firm of the year-India’ o Co po ate a d & dv so y o t e yea da Multi–dimensional focus, covering all major sectors and industries Current focus with mid market and growing Corporates, while having strong relationships with top business houses in the country E Experienced & S bl M i d Stable Management, l di leading a team of >35 f 35 professionals, 70% of the team averaging 6+ years with Singhi Strong relationship and confidence from existing clients with 60% repeat business and 80% strike rate Live relationship with >250 Corporates, resulting in >800 ve e at o s p w t 50 Co po ates, esu t g 800 completed assignments. CORPORATE RESTRUCTURING DEBT SYNDICATION CORPORATE ADVISORY Global Reach Exclusive Indian Member of “Mergers-Alliance”, a leading international network of independent Investment Banking Firms and Corporate Finance advisory firms offering seamless services on mid-market transactions With the successful closure of more than 90 transactions valued at over Euro 5 billion to its credit Mergers-Alliance is ranked No 19 credit, No. globally by Thomson Financial Table Mergers-Alliance helps us offer clients a global platform, seamless service and enhanced access to global opportunities through a network of 50+ offices across 25 countries with 20 like-minded firms, each having strong presence...
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...product Muffins cookies loaves of bread price 5.5 4.75 5.25 quantity 45000 65000 85000 IV quarter 247500 308750 446250 1002500 price 6 5.25 5.75 quantity 36000 52000 68000 I quarter 216000 273000 391000 880000 price 6 5.25 5.75 quantity 37800 54600 71400 II quarter 226800 286650 410550 924000 price 6 5.25 5.75 quntity 39690 57330 74970 III quarter 238140 300982.5 431077.5 970200 price 6 5.25 5.75 quantity 47628 68796 89964 IV quarter 285768 361179 517293 1164240 price 6 5.25 5.75 3938440 quantity I quarter 41675 250047 0 60197 316031.625 0 78719 452631.375 1018710 product Muffins Cookies loaves of Bread I quarter inventory sales estimation need of production 800 1156 1511 36000 52000 68000 36040 52058 68076 II quarter inventory sales estimation need of production 840 1213 1587 37800 54600 71400 37842 54661 71479 III quarter inventory sales estimation need of production 882 1274 1666 39690 57330 74970 39866 57585 75303 IV quarter inventory sales estimation need of production 1058 1529 1999 47628 68796 89964 47496 68605 89714 I quarter inventory sales estimation of production need 926 1338 1749 41675 60197 78719 41721 60263 78806 inventory 972 1405 1837 II quarter sales estimation 43758 63206 82654 6 5.26 5.75 5557 0 7036 0 10058 22651 muffins usage flour Margarine...
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...Aarhus Universitet, School of Business and Social Sciences Vintereksamen 2014/2015 HD 1. del DATAANALYSE MINIPROJEKT III Opgaveløsere (anfør navn og studienummer): Martin Stentoft Peter Guiltoft Andreas Roar Nemaja Stankovic 201402687 201400077 201207880 201409598 Gruppenummer: 18 Hold (F01/on, F02/to, F03/lø): F03/lø Opgaven udleveres den 4. december 2014 via Blackboard, og besvarelsen afleveres 1) i to eksemplarer (inkl. udfyldt forside) til Institut for Marketing og Organisation, School of Business and Social Sciences, Aarhus Universitet, att. Lisbeth Widahl (bygn. 1326, lokale 217), Bartholins Allé 10, 8000 Aarhus C OG 2) uploades på Blackboard som pdf (med denne udfyldte forside som første side i dokumentet) senest onsdag den 17. december 2014 kl. 12.00. Miniprojekt III Opgave 1: Dataanalyse Gruppenr.: 18 Foretag en kort diskussion af datagrundlaget til opgaven i forhold til de krav, der almindeligvis stilles til stikprøver og deres udvælgelse med henblik på at gennemføre statistiske analyser (herunder også datakvaliteten). - Repræsentativ, dvs. at det kun er en stikprøve af hele populationen, men som skal afspejle populationen, og der skal være samme fordeling i stikprøven som det er i populationen, fx køn. - Simpel tilfældig udvælgelse forventes at sikre repræsentativitet, dvs. at alle enheder i populationen har samme sandsynlighed for at blive udtrukket til stikprøven, ligesom lodder fra en tombola...
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...FACULTY OF BUSINESS AND MANAGEMENT MATHEMATICS FOR MANAGEMENT Question 1: A) 7 A + 10 B = 73 4 53 3 15 2 4 + 101 5 40 1 33 2 2 = 10 35 4221 21 735 14 28 + 10 50 400 10 3030 20 20 = 24 85 8221 31 3765 34 48 B) I. Matrix inverse method: 2x1 + 3x2 + 4x3 = 29 X1 + x2 + 2x3 = 13 3x1 + 2x2 + x3 = 16 1) Matrix form ,A: A =211 312 413121 122 223331 232 133 XX1 X2 X3 b291316 Ax = b ; x = A-1b A-1 =1A - A djoint A 2) Determine ( Row 2 as sample) A = (1) (-1)2+13421 + (1) (-1)2+2 2431 + 2(1)2+32332 = (-1) [(3)(1) – (4)(2)] + (1) [(2)(1)-(4)(3)] + (-2) [(2)(2)-(3)(3)] = (-1)(3-8) + (1)(2-12) + (-2)(4-9) = 5 – 10 + 10 A=5 3) Minor A A11 = 1221 = 1(1) – (2)(2) = 1 – 4 = -3 A12 = 1231 = 1(1) – (2)(3) = 1 – 6 = -5 A13 = 1232 = 1(1) – (1)(3) = 2 – 3 = -1 A21 = 3421 = 3(1) – (4)(2) = 3 – 8 = -5 A22 = 2431 = 2(1) – (4)(3) = 2 – 12 = -10 A23 = 2332 = 2(2) –(3)(3) = 4 – 9 = -5 A31 = 3412 = 3(2) – (4)(1) = 6 – 4 = 2 A33 = 2311 = 2(1) – (3)(1) = 2 – 3 = -1 Minor A = -3-5-1-5-10-520-1 4) Cofactor A = +-3--5+-1--5+-10--5+2-0+-1 = -35-15-10520-1 5) Ad-joint A = [Cofactor A] T = -35-15-10520-1T = -3525-100-15-1 6) Inverse A, A-1 A-1 = 1A – Ad-Joint A = 15-3525-100-15-1 = -3/512/51-20-1/55-1/5 7) Find X1...
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...much of its portfolio should it allocate to the zero-coupon bonds to immunize if there are no other assets funding the plan? → 57.14% 42.86% 35.71% 26.00% Duration of the perpetuity = 1.04/0.04 = 26 years Duration of the zero = 1 years 14 = (wz)(5) + (1 – wz)26; wz = 57.14% Learning Objective: 11-04 Formulate fixed-income immunization strategies for various investment horizons. Multiple Choice Difficulty: 3 Hard award: 1.00 point You own a bond that has a duration of 5 years. Interest rates are currently 6%, but you believe the Fed is about to increase interest rates by 29 basis points. Your predicted price change on this bond is ________. (Select the closest answer.) +1.37% → –1.37% –4.72% +4.72% D* = 5/1.06 = 4.72 ∆P/P = –D*(∆y) = –4.72(0.29%) = –1.37% Learning Objective: 11-02 Compute the duration of bonds; and use duration to measure interest rate sensitivity. Multiple Choice Difficulty: 2 Medium 1 of 13 11/29/2014 1:56 PM Assignment Print View http://ezto.mheducation.com/hm_finance.tpx award: 1.00 point You have purchased a guaranteed investment contract (GIC) from an insurance firm that promises to pay you a 7% compound rate of return per year for 5 years. If you pay $10,000 for the GIC today and receive no interest along the way, you will get __________ in 6 years (to the nearest dollar). $13,500 $14,071 → $14,026 $13,108 (10,000)(1.07)5 = $14,026 Learning Objective: 11-04 Formulate fixed-income immunization strategies...
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...Russell and Bernard W. Taylor III, authors of Operations and Supply Chain Management discussed quality tools and their importance to organizations. The authors conveyed that W. Edwards Deming, along with many other successful individuals who focused on quality, created an immense number of tools to discover the causes of quality issues. Fortunately, the tools are still being implemented by organizations today. The quality methods represent graphical techniques and consist of Pareto Charts, Process Flowcharts, Checksheets, Histograms, Scatter Diagrams, Statistical Process Control Charts, and Cause-and-Effect Diagrams. Russell and Taylor III clearly define the tools and their representation. Pareto Charts are designed for tallying the percentage of defects in which result from different causes to identify major quality issues; Process Flowcharts assist with focusing on where a quality issue may appear during a particular process; Checksheets demonstrate tallies of the number of defects for a list of problems that were discovered in the past; Histograms provide management with a frequency of data that is relevant to the quality problem; Scatter Diagrams identify "a pattern that may cause a quality problem" (Russell & Taylor III, 2014, p. 61); Statistical Process Control Charts consist of upper and lower boundaries. "If the process stays between these limits over time, it is in control and problem does not exist" (Russell & Taylor III, 2014, p. 61); and Cause-and-Effect Diagrams...
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...intersection of the curve y = 1.5n2 – 8.5n + 17 and the line y = 100. Hint to students: From GC, n > 10.79. Hence solution set = {n ℤ+ : n 11}. 1 1 0 4 – x2 dx 1 2+x 1 = [4 ln 2 – x ]0 1 = 4 ( ln 3 – ln 1 ) 1 = 4 ln 3 1 1/2p dx 0 1 – p2x2 1 1 = p 1/2p dx 0 1 2 p2 – x 1 1/2p = p [sin–1 px]0 1 1 = p (sin–1 2 ) 1 1 = p 6 = 4 ln 3 2 p = 3 ln 3 2) 3i) 1 2 1 –n+n+1 n–1 n(n + 1) – 2(n2 – 1) + n(n – 1) = n(n2 – 1) It is helpful to use the GC to do a quick check that the integration has been done correctly. Teaching point: Students sometimes leave out 1 the term p when integrating 1 . To safeguard this, 1 – p2x2 it is advisable to change the integrand into the form 1 before integrating. 2 a – x2 1 2 = n3 – n A = 2. Shown (ii) r=2 r3 – r n 1 1 n 2 = 2 r3 – r r=2 1 1 n 2 1 =2 (r–1–r+r+1) r=2 1 1 2 1 =2 [1–2+3 1 2 1 +2–3+4 1 2 1 +3–4+5 : : : : 2 1 1 +n–2–n–1+n 1 2 1 +n–1–n+n+1] 1 1 1 1 =2[2–n+n+1] (iii) 1 1 As n , n 0 and n + 1 0. 1 the series converges to the value 4 . 4i) f(27) + f(45) = f(23) + f(41) = f(19) + f(37) : : = f(3) + f(1) =5+6 = 11 2 (ii) y 7 Teaching Point: Students should be advised to sketch a clear and properly– labelled graph. 3 –7 –6 –4 –2 (iii) 2 4 6 8...
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