...Exercise 1 – Find the first derivative and the second derivative of the following functions Answer: Applying constant function and power function rule (A) Y = 3 + 10X + 5X2 dY/dX = 0 + 1.10.X1-1 +2.5.X2-1 dY/dX = 10 + 10X d2Y/ dX2 = 0 + 1.10.X1-1 d2Y/ dX2 = 10 (B) Y = 2X (4 + X3 ) Y = 8X + 2X4 dY/dX = 1.8.X1-1 + 4.2.X4-1 dY/dX = 8 + 8X3 d2Y/ dX2 = 0 + 3.8.X3-1 d2Y/ dX2 = 24X2 (C) Y = 3 /X2 Y = 3X-2 dY/dX = -2.3.X-2-1 dY/dX = -6X-3 dY/dX = -6/X3 d2Y/ dX2 = -3.-6X-3-1 d2Y/ dX2 = 18X-4 d2Y/ dX2 = 18/X4 (D) Y = 18T – 2T2 dY/dT = 1.18.T1-1 – 2.2.T2-1 dY/dT = 18 – 4T d2Y/ dT2 = 0 – 1.4.T1-1 d2Y/ dT2 = - 4 Exercise 2 - Find the partial Derivative of Y with respect to X Answer (A) Y = 10 + 3Z + 2X ∂Y/∂X = 0 + 0 + 1.2.X1-1 ∂Y/∂X = 2 (B) Y= 18Z + X2 + Z.X ∂Y/∂X = 0 + 2.1.X2-1 + Z ∂Y/∂X = 2X + Z Application - The nursing home industry is growing rapidly because the aging of American population. According to the study of an economist, the average cost per patient day of a nursing home can be approximated by C = A – 0.16B + 0.002B2 Where, B is the nursing home’s number of patient days per year ( in thousands) and A is the number that depends on the location and other factors but not on B. Based on the information , how big must a nursing home be ( in terms of patient – days) to minimize the cost per patient day ? Answer – C= ƒ (A, B) Where C is Avg. Cost per patient day A is variable depends on location and other factors ...
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...MATH 364A: Ordinary Differential Equations (Midterm 1) Name: Student ID: Signature: Question 1 (40 points) Solve the following initial value problems. (a) y + t3 y = t3 y(0) = 0. (b) y = − (1+x) y y(−1) = 1. Question 2 (40 points) Solve the second-order initial value problem 2y − 3y − 5y = 0 y(0) = 0 2 y (0) = 1. Question 3 (40 points) For each equation below, first determine whether the equation is exact or not exact. If the equation is exact, find the solution. (a) cos(y) + (2y − x sin(y)) dy = 0. dx (b) 3xy 2 + (y 3 + 3x2 ) 3 dy = 0. dx Question 4 (40 points) Consider the following first-order differential equation y = (y 2 − 1)(4 − y 2 ). Find all critical (equilibrium) solutions and classify their stability. 4 Question 5 (40 points) (True/False) In each of the following, determine whether the given function solves the given differential equation or initial value problem. (a) If k > 0 denotes any real constant, then the function y(t) = e−kt solves the initial value problem y = −ky y(0) = 1. (b) The function y(t) = (1 − t)−1 = 1/(1 − t) solves the initial value problem y = y2 y(0) = 1. (c) The function y(t) = e2t solves the second-order initial value problem y = 2y y(0) = 1 y (0) = 2. (d) Any function y(x) defined by the implicit equation x4 + 2x2 y 2 + y 4 = C solves the differential equation x3 + xy 2 + (x2 y + y 3 )y = 0. 5 Question 6 (Extra Credit, 10 points) An object with mass...
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...CLASSIFICATION OF FIRST ORDER DIFFERENTIAL EQUATIONS SUPPLIMENTARY PROBLEMS 1. Write the given equation in standard form 3.16. exy'-x=y' solution exy'-x=y' =exy'-y'=x ex-1y'=x y'=xex-1 ANS 3.25 dy+dx=0 Solution. dy+dx=0 dydx+1=0 y'=-1 2. The differential equations are given in both standard and differential form. Determine whether the equation in standard form are homogeneous and/or linear, if not linear, whether they are Bernoulli: determine whether the equations in differential form as given are separable and/or exact. 3.28 y'=xy+1: xy+1dx-dy=0 Solution. y'=xy+1 = y'-xy=1 this is in the form y'+pxy=qx for px=-x , qx1 thus this is linear next xy+1dx-dy=0 is not separable si9nce the variables cannot be separeted. To check for exactness take Mx=xy+1 and Nx=-1 for an exact equation, ∂M∂y=∂N∂x ∂M∂y=x and ∂n∂y=0 thus ∂M∂y≠∂N∂x so it is not exact 3.30 y'=x2y2: -x2dx+y2dy=0 Solution. y'=x2y2 =≫ y'+0y=x21y2 The equation is of the form y'+pxy=qxyn where px=0, qx=x2 and n=-2 so it is a Bernoulli equation NEXT For -x2dx+y2dy=0 it is separable since the variables are separated. To check for exactness take Mx=-x2 and Ny=y2 thus ∂M∂y=0 and ∂N∂x=0 hence its EXACT. 3.35 y'=2xy+x: 2xye-x2+xe-x2dx-e-x2dy=0 Solution. For y'=2xy+x =≫y'-2xy=x This is in the form y'+pxy=qx for px=-2x and qx=x Thus it’s a linear equation NEXT 2xye-x2+xe-x2dx-e-x2dy=0 this is not separable since the variables...
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...Engineering and Science subjects. Here our intention is to make the students acquainted with the concept of basic topics from Mathematics, which they need to pursue their Engineering degree in different disciplines. Course Contents: Module I: Differential Calculus Successive differentiation, Leibnitz’s theorem (without proof), Mean value theorem, Taylor’s theorem (proof), Remainder terms, Asymptote & Curvature, Partial derivatives, Chain rule, Differentiation of Implicit functions, Exact differentials, Tangents and Normals, Maxima, Approximations, Differentiation under integral sign, Jacobians and transformations of coordinates. Module II: Integral Calculus Fundamental theorems, Reduction formulae, Properties of definite integrals, Applications to length, area, volume, surface of revolution, improper integrals, Multiple Integrals-Double integrals, Applications to areas, volumes. Module III: Ordinary Differential Equations Formation of ODEs, Definition of order, degree & solutions, ODE of first order : Method of separation of variables, homogeneous and non homogeneous equations, Exactness & integrating factors, Linear equations & Bernoulli equations, General linear ODE of nth order, Solution of homogeneous equations, Operator method, Method of undetermined coefficients, Solution of simple simultaneous ODE. Module IV: Vector Calculus Scalar and Vector Field, Derivative of a Vector, Gradient, Directional...
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...REMOVED FROM THE EXAMINATION ROOM Electronic calculators may be used provided that they cannot store text. 1 of 3 P.T.O. 2 of 3 ECON60081 SECTION A Answer ALL Questions. Each question carries equal weight. Question 1. Consider the problem Ax = b where ⎛ ⎞ ⎞ ⎛ ⎛ ⎞ 2 1 3 1 1 A = ⎝ 3 2 5 ⎠ x = ⎝ 2 ⎠ b = ⎝ 3 ⎠ 1 1 2 3 2 Determine the degrees of freedom and the number of redundant equations of this system. Further, determine the solution(s) if solutions exists. [10 marks] Question 2. Give formal definitions for the following: (a) a convex function, (b) a strictly con vex set, (c) a differentiable function. Further, give an example of a concave function that is not differentiable. [10 marks] Question 3. Find the solution of the following differential equation = 1 + 3 − 2 ˙ where (0) = 5. [10 marks] Question 4. Find the general solution of the following second order differential equation + 4 + 10 = ¨ ˙ [10 marks] Question 5. Consider the following system of nonlinear difference equations ½ 1+1 = 31 − 2 2 2+1 = 2 + 1 Find the equilibria and classify them as sink, source or saddle. [10 marks] Continued 3 of 3 ECON60081 SECTION B Answer ALL Questions. Question 6. Assume ≥ 4. For −1 and −1, solve the utility maximization problem (a) max ( ) = 1 ln(1 + ) + 1 ln(1 + ) subject to the constraint 2 + 3 = .[15 marks] 2 4 (b) Let (∗ () ∗...
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...deterministic or probabilistic decision models. As deterministic models, decisions to bring good final outcomes. A deterministic model is “you get what you expect” risk-free model, which determines the outcome. It also depends on the influence of the uncontrollable the factors that determine the outcome of a decision and the information the decision-maker input as a predicting factor (Arsham, 1996). According to Schrodt (2004), deterministic models was widely used in the early 18th century to study physical processes to develop differential equations by many mathematicians. These differential equation allow values of a variable as function of its value at any point in time and as a common form of the deterministic concept. The differential equations apply to a variety of astronomical and mechanical phenomena and have produced crucial scientific literature (Schrodt, 2004). The model is important in astronomical and mechanical phenomena because of the finite equations...
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...Syllabus Cambridge International A Level Further Mathematics Syllabus code 9231 For examination in June and November 2013 Contents Cambridge A Level Further Mathematics Syllabus code 9231 1. Introduction ..................................................................................... 2 1.1 1.2 1.3 1.4 Why choose Cambridge? Why choose Cambridge International A Level Further Mathematics? Cambridge Advanced International Certificate of Education (AICE) How can I find out more? 2. Assessment at a glance .................................................................. 5 3. Syllabus aims and objectives ........................................................... 7 4. Curriculum content .......................................................................... 8 4.1 Paper 1 4.2 Paper 2 5. Mathematical notation................................................................... 17 6. Resource list .................................................................................. 22 7 Additional information.................................................................... 26 . 7 .1 7 .2 7 .3 7 .4 7 .5 7 .6 Guided learning hours Recommended prior learning Progression Component codes Grading and reporting Resources Cambridge A Level Further Mathematics 9231. Examination in June and November 2013. © UCLES 2010 1. Introduction 1.1 Why choose Cambridge? University of Cambridge International Examinations (CIE) is the world’s largest provider of international...
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...Beams in this chapter, we describe methods for determining the equation of the deflection curve of beams and finding deflection and slope at specific points along the axis of the beam 9.2 Differential Equations of the Deflection Curve consider a cantilever beam with a concentrated load acting upward at the free end the deflection in the y v is the displacement direction of the axis the angle of rotation (also called slope) is the angle between the x axis and the tangent to the deflection curve point m1 is located at distance x point m2 is located at distance x + dx slope at slope at m1 m2 is is +d denote O' the center of curvature and the radius of curvature, then d = ds is and the curvature 1 = 1 C = d C ds the sign convention is pictured in figure slope of the deflection curve dv C dx for = tan or ds j dx d C dx d C = dx = cos j 1 and d 2v CC dx2 = dv tan-1 C dx tan dv C dx j , then small = 1 C = 1 C = = if the materials of the beam is linear elastic = 1 C = M C EI [chapter 5] then the differential equation of the deflection curve is obtained d C dx d2v = CC dx2 = M C EI and v dV CC dx d 4v CC dx4 = -q q -C EI it can be integrated to find ∵ dM CC dx d 3v CC dx3 = V then V = C EI = 2 sign conventions for M, V and q are shown the above equations can be written in a simple form EIv" = M EIv"' = V EIv"" = -q this equations are valid only when Hooke's law applies and when the slope and the...
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...Lab 0: MATLAB and ODE Solvers | ME 4173 Robot Kinematics | | | | Introduction The following report will display the results and conclusions of an experiment to simulate the output of an inverse pendulum system in MATLAB. The objectives of this experiment were to review MATLAB programming and using MATLAB to simulate ODEs and systems. Objectives * Examine the basics of MATLAB * Use MATLAB to simulate a system * Use ODE solvers to numerically integrate the system over a set time period Apparatus The apparatus used in this experiment was MATLAB. It was used to provide a simulation environment to analyze the inverse pendulum’s motion. Experiments and Results There were six components of this experiment. This experiment was mostly familiarizing with MATLAB. All code used is illustrated in the Appendix – Code. The first part consisted of learning commands within the MATLAB environment. It was a brief overview of how commands work in MATLAB. There was no code used in the part of the experiment. The second part of the experiment examined how arrays were created and used in MATLAB. The first step was to create a matrix. This matrix was then subjected to various commands including eye( ), zeroes( ), and ones( ). Indexing was also used to access various parts of the matrix. Matrix operations such as transpose, inverse, size and length were also shown. Part three of the experiment explained how a script was created and what it was...
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...entrepreneur. Accordingly, I have been interested in business courses and I decide to take financial related courses, especially Actuarial Studies as the direction of my master’s study. I have been interested in numbers since I was a high school student. I felt satisfied even though I had to contribute more than one hour to solve a mathematic problem. I often spent time to think about other methods to solve mathematic problems that my teacher had provided answers. My enthusiasm about mathematics was inspired again when I began my college study. I took some basic mathematics concepts, such as limit, series, calculus and differential coefficient. I also learned some basic theories and the application of related concepts, such as differential coefficient of function of one variable, calculus, partial derivative of function of many variables, differential equation, and Taylor's formula, intermediate value theorem and infinite series which help me to know the nature of function, and the independent vector algebra and space analytic geometry. To be honest, I even made more efforts in the study of mathematics than that in my academic courses. Therefore, I believe that my mathematics achievements are pretty competitive in pursuing Master of Actuarial Studies. I took multi-directed development when I was in college since I believe that enhancing my learning and surviving ability accounts even...
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... What is called as the setting device? 15. What is called as a function chart and of what it consists? 16. In what difference of a signal from physical size? 17. In what an essence of a principle of the opened management? 18. In what an essence of a principle of indemnification? 19. In what an essence of a principle of feedback? 20. List merits and demerits of principles of management? 21. What special case of management is called as regulation? 22. In what difference of systems of direct and indirect regulation? 23. List and give the short characteristic of principal views CS? 24. What is called as static mode CS? 25. What is called as static characteristics CS? 26. What is called as the equation of statics CS? 27. What difference from strengthening factor is called in transfer factor, in what? 28. In what difference of nonlinear links from the linear? 29. How to construct the static characteristic of several links? 30. In what difference of astatic links from the static? 31. In what difference of astatic regulation from the static? 32. How to make static CS astatic? 33. What is called as a static error of a regulator how it to reduce? 34. What is called statizm of CS? 35....
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...COORDINATE GEOMETRY. EQUATION OF A STRAIGHT LINE SOLVED EXAMPLES. 1. ( ) ( Solution. ( Now, using the formula ) we have: ( ( ). ) . . ( 2. ) Solution. ( ) ( ) ( ( ) ), ( ) ) ( ) ( ) Solution. ( ) ( ) ( ) ( ) EQUATION OF A CIRCLE. The general equation of a circle is of the form .Where (– √ is the centre of the circle and the radius is: Finding the equation of a circle of a circle given its radius and centre Let ( ) be any point on a circle whose centre is ( circle is given by : ( ) ( ) ) and ( r ( ( ) ) ) 0 If the centre is at the origin ( ( ) ( ) ) then the equation becomes: ‘ the equation of a ) Solved Examples. 1. Find the equation of the circle with centre ( ) and radius Solution. Using ( ) ( , ( ( )- ) we have, ) ( ) ( ) 2. Find the equation of a circle with centre ( ) which passes through the point( Solution. ( ) ( ( ) ) ( ) √ ( ) ( ( ) ( , ) ) (√ ) 3. Find the centre and radius of the circle Solution. ( ) Comparing (1) with the general equation of a circle The radius of the circle is: √ The centre is ( √ √ ) ( ) ) EXERCISE. 1. Find the centre and radius of the circle 2. Find the centre and radius of the circle 3. Find the equation of the circle which passes...
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...transformation called the Laplace transform. It is very effective in the study of initial value problem involving linear differential equation with constant coefficient. Laplace transform was first introduced by a French mathematician called Pierre Simon Marquis de Laplace about 1780’s. This method associated with the isolation of the original problem that is function ƒ(t) of a real variable and some function ƒ(s) of a complex variable so that the ordinary differential equation for the function ƒ(t) is transformed into an algebraic equation for ƒ(s) which in most cases can readily be solved. The solution of the original differential equation can be arrived at by obtaining the inverse transformation. The transformation and its inverse can be derived by consulting already prepared table of transform. This method is particularly useful in the solution of differential equation and has more application in various fields of technology e.g. electrical network, mechanical vibrations, structural problems, control systems. Meanwhile in this research work, I shall look into the Laplace transform, the properties of the Laplace transform and the use of this technique in solving delay differential equation will be looked into. 1.2 Statement of the Problem There are so many engineering and other related problems that can be expressed in the form of ordinary differential equations. But such problems cannot easily be solved using the elementary method of solution. In such cases, the Laplace transform...
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...Diese Form der Algebra beschäftigt sich mit mathematischen Aussagen und ihren Verknüpfungen. Dabei gelten Aussagen als mathematisch, wenn sie klar als wahr (w) bzw. falsch (f) zu bezeichnen sind. Wahre Aussagen werden durch einer "1" dargestellt, falsche durch eine "0". Beispiel: Eine mathematische Aussage wäre: 1. Innsbruck liegt in Tirol. (wahre Aussage) 2. Das Münchner Gymnasium hat 10000 Schüler. (falsche Aussage) Dagegen aber keine mathematische Aussage wäre: 1. Schule ist toll. 2. Mathematik macht Spaß. Mit bestimmten Verknüpfungen können mehrere mathematische Aussagen verbunden werden. Diese wären dann: 1. Und ( ) 2. Oder ( ) 3. Nicht ( ) Die Fach-Bezeichnung für die Nicht-Verknüpfung ist Negation, für die Und-Verknüpfung Konjunktion und für die Oder-Verknüpfung Disjunktion. Während und zwei Aussagen Verknüpfen bezieht sich nur auf eine einzelne Aussage oder das "Ergebnis" mehrer Aussagen. Dabei wird dieses Ergebnis folgendermaßen ermittelt: • Eine wahre und eine falsche Aussage durch "Und" verknüpft ergeben eine falsche Aussage. • Zwei wahre Aussagen durch "Und" verknüpft ergeben eine wahre Aussage. • Zwei falsche Aussagen durch "Und" verknüpft ergeben eine falsche Aussage. Beispiele dazu wären: 1. Innsbruck liegt in Tirol (w) und ( ) das Münchner Gymnasium hat 10000 Schüler (f), ist insgesamt eine falsche Aussage. 2. Österreich liegt in Europa (w) und ( ) hat eine Grenze zu Deutschland (w), ist eine wahre...
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...Finance and Economics, University of Ulm in Partial Fulfillment of the Requirement for a Masters Degree in Finance Master of Science University of Ulm Ulm, Germany 5th July 2012 DECLARATION We hereby confirm that the seminar thesis is our own work and that we have used only the stated literature and other means. Ahmed Mahmoud _______________ Harris Rahim _______________ Hudson Joel Division of the Seminar Thesis Division of the seminar thesis is done as follows: Ahmed Mahmoud has done chapter 1 and 2, Harris Rahim has done chapter 3, Hudson Joel has done chapter 4. Content Chapter 1- Introduction 5 1.1 The payoff 6 Chapter 2: Partial Differential Equations 8 2.1 The Black Scholes Model 8 2.2 Reduction to a One-Dimensional Equation 9 Chapter 3- A valuation model for an Average Value (AV) option 11 Chapter 4- Program 15 4.1 Geometric average price call 15 4.2 Geometric average price put 17 References 20 Chapter 1- Introduction Asian option is one type of options where the payoff is determined by the average underlying stock price over a period of time. This differs from the usual European and American options where the payoff depends on the price of the underlying instrument at exercise. Therefore, the Asian options are one of the forms of exotic options. Asian options have a lower volatility and hence rendering them cheaper relative to their European counterparts. They were originally used in 1987 when...
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