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Hejsa

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Submitted By frederiknis
Words 312
Pages 2
Aflevering – Ensvinklede trekanter
Opgave 1
a) Bestem flagstangens højde.

Opgave 2

a) Beregn de resterende sider.
Ved at finde forstørrelsesfaktoren kan jeg beregne de resterende sider.

Jeg får af vide at min mindste side i den ukendte trekant er 18. Og da den mindste side er 12, må 12 altså være forstørret til 18. Så kan jeg sige 18/12 = 1,5 og dermed har jeg fundet ud af at min forstørrelsesfaktor er 1,5

a = 12*1,5 = 18

b = 18*1,5 = 27

c = 27*1,5 = 40,5

Opgave 3

a)
For at finde ud af hvor meget længere skyggen er, skal jeg finde forstørrelsesfaktoren.
Det gør jeg ved at sige 16/12. Det giver 1,33 og dermed har vi vores forstørrelsesfaktor.

Vi har fundet den første, så for at finde den næste gør vi sådan:

20*1,33=26,67

Altså kaster det 16 meter høje hus, 26,67 meter skygge.

Opgave 4

7)
5p-2q-r+3p-q+2r=5p-10q-5r+3p-3q+6r=2p-13q+1r

8)
2a+2b+a-b=2a+4b+a-b=3a+5b

9)
4c-d-3c+2d=4c-4d-3c+6d=7c-2d

10)
4a+5b+73a+b=4a+20b+21a+7b=25a+27b

Opgave 5

a)
3(x-1)=6
3x-3=6
3x=3+6

3x3=93

x=3

b)
3-2x=4x
3=4x+3x
3=6x

36=6x6

0,5=x

c)
2(1-2x)+5x=7
2-4x+5x=7
-4x+5x=7-2
x=5

d)
-0,52x-4=2
-x+2=2
-x=2-2
Jeg ændrer nu fortegnet på begge, da x skal være positiv

x=2+2 x=4 Opgave 6

a) Eftersom at F1 er opadgående må den jo være positiv

b) Da F2 er nedadgående må den være negativ

c) F3 er konstant og er derfor hverken negativ eller positiv

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