...Answers: Cash Receipt. Answers: Cash Receipt. 1. Samantha is the acting business manager executive officer – accountant of the school. 2. Main function is to report to the ball of trustees and auditor etc... 3. 3 Business is done by internet banking = Liz and Mii, and over the counter and by EFTPOS. 4. Electronic – EFTPOS/Direct credit – internet banking/Cash Register 5. Electronic is safer and people can’t take it easily – Proof – Direct Credit. 6. Electronic it’s safer/credit cards aren’t safe. 7. Every day the till will recode everything. EFTPOS machine, both equals the cash received. 8. Received a receipt = Ticket etc…Cash is very easy to abuse. 9. Till tape = EFTPOS report we do cash accountant = banking and print out every day. 10. Separate the job of banking, one person entering system; two people count the money and one person entering. 11. Access is very limited, stored in a lock box inside the safe. Two people can access and one person has to key the box. Cash payment Cash payment 1. Twenty month creditor/manual payments = Tracy. 2. We must have a purchase order. Tax invoice – special stamp = area budget holder must have an invoice = glued = verified by principal. 3. They don’t do cash payment, electronic payments and Petty cash is under $40.Incorrect source documents do not received payment and verifying process = into system: cheque done again = a lot of stage it must pass through. 4. Cash is...
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...|Objective |To achieve a challenging position in any discipline and contribute to the competitive advancement and | | |growth of my employer. | |Educational Qualification with|2014 Newton Hills University, Commonwealth Dominica,MBA in Logistics & Supply--- in View | |Dates |2009 Lagos School of Travel & Tourism, Advance Diploma in Air Ticketing & Reservation/Customer Care | | |2008 Olabisi Onabanjo University ,Ogun State, B.A. Mass Communication. | | |2002 Kefe Academy, Warri (SSCE- Senior Secondary Certificate Examination) | |Computer...
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...Ottoman Empire. It was founded in 1301 A.D. by Osman the First and ended on the seventeenth of November 1922 A.D. with the abolishment of the sultanate. There were many rulers during the six hundred and twenty one years of the empire. But there was only one that was considered Magnificent, and that is Suleiman the First. Suleiman the Magnificent was born on the twenty seventh of April in the year 1496 A.D. in modern day Trebizond, Turkey. He is the only son of Sultan Selim I and Crimean Tatar princess Hasfa. When he turned seven years old, Suleiman was sent to study history, literature, military tactics, science, and theology in the schools of Topkapı Palace in Constantinople. There he studied until he was appointed governor of the city Kefe, modern day Fedsiya, then of Manisa. In the years 1514- 1515 A.D., Suleiman acted as regent of the empire as his father, Selim I, led a military campaign against present day Iran. He then oversaw the defense of Edirne in the year 1516-1517 A.D. while his father was campaigning against the Mamluks in Egypt and Syria. Before Suleiman succeeded the throne, he had a better education and more military experience than any other European...
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...Solutions to Physics: Principles with Applications, 5/E, Giancoli Chapter 17 CHAPTER 17 1. We find the work done by an external agent from the work-energy principle: W = ®KE + ®PE = 0 + q(Vb – Va) = (– 8.6 × 10–6 C)(+ 75 V – 0)= – 6.5 × 10–4 J (done by the field). 2. We find the work done by an external agent from the work-energy principle: W = ®KE + ®PE = 0 + q(Vb – Va) – 2.40 × 10–17 J (done by the field); = (1.60 × 10–19 C)[(– 50 V) – (+ 100 V)] = W = q(Vb – Va) – 150 eV. = (+ 1 e)[(– 50 V) – (+ 100 V)] = 3. Because the total energy of the electron is conserved, we have ®KE + ®PE = 0, or ®KE = – q(VB – VA) = – (– 1.60 × 10–19 C)(21,000 V) = 3.4 × 10–15 J; 21 keV. ®KE = – (– 1 e)(21,000 V) = 4. Because the total energy of the electron is conserved, we have ®KE + ®PE = 0; ®KE + q(VB – VA) = 0; 3.45 × 10–15 J + (– 1.60 × 10–19 C)(VB – VA); which gives VB – VA = Plate B is at the higher potential. 2.16 × 103 V. 5. For the uniform electric field between two large, parallel plates, we have 4.2 × 104 V/m. E = ®V/d = (220 V)/(5.2 × 10–3 m) = 6. For the uniform electric field between two large, parallel plates, we have E = ®V/d; 640 V/m = ®V/(11.0 × 10–3 m), which gives ®V = 7.04 V. 7. Because the total energy of the helium nucleus is conserved, we have ®KE + ®PE = 0; ®KE + q(VB – VA) = 0; 65.0 keV + (+ 2e)(VB – VA); which gives VB – VA = – 32.5 kV. 8. For the uniform electric field between two large, parallel plates, we have E = ®V/d;...
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