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Precipitation Lab 1

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Precipitation Lab
Purpose:
1. Identify the ions present in various aqueous solutions.
2. Combine solutions and identify the reactions that form precipitates.
3. Write balanced molecular equation, complete ionic equation, and a net ionic equation for each precipitation reaction.

Materials:
• Small test tubes
• Various solutions
Procedure:
1. Add 10-15 drops of the each reactant to a test tube.
2. Observe the results when the two solutions are combined in the test tube.
3. Record your observations for when the two solutions are mixed together and draw and label the contents of the test tube.
4. If no precipitate (ppt) is detected, write NR or no reaction.
5. Clean your test tubes when finished

Reaction #1: barium chloride + sodium sulfate 
Observations:

Balanced molecular equation: BaCl2(aq)¬ + Na2SO¬4(aq)  BaSO4(s)¬ + 2NaCl(aq)
Complete ionic equation: Ba2+ + 2Cl- + 2Na+ + SO42-  BaSO4(s)¬ + 2Na+ + 2Cl-
Net ionic equation: Ba2+ + SO42-  BaSO4(s)¬
Name of product that makes the reaction occur: Barium sulfate

Reaction #2: sodium carbonate + silver nitrate 
Observations:

Balanced molecular equation: Na2CO3(aq) + 2AgNO3(aq)  2NaNO3(aq) + Ag2CO3(s)
Complete ionic equation: 2Na+ + CO32- + 2Ag+ + 2NO3-  2Na+ + 2NO3- + Ag2CO3(s)
Net ionic equation: CO32- + 2Ag+  Ag2CO3(s)
Name of product that makes the reaction occur: silver carbonate
Reaction #3:
Barium chloride + lead (II) nitrate 
Observations:

Balanced molecular equation: BaCl2(aq) + Pb(NO3)¬2(aq)  Ba(NO3)¬2(aq) + PbCl2(s)
Complete ionic equation: Ba2+ + 2Cl- + Pb2+ + 2NO3-  Ba2+ + 2NO3- + PbCl2(s)
Net ionic equation: 2Cl- + Pb2+  PbCl2(s)
Name of product that makes the reaction occur: lead (II) chloride

Reaction #4: cadmium chloride + sodium sulfide 
Observations:

Balanced molecular equation: CdCl2(aq) + Na2S(aq)  CdS(s) + 2NaCl(aq)
Complete ionic equation: Cd2+ + 2Cl- + 2Na+ + S2-  CdS(s) + 2Na+ + 2Cl-
Net ionic equation: Cd2+ + S2-  CdS(s)
Name of product that makes the reaction occur: cadmium sulfide
Reaction #5: barium chloride + silver nitrate 
Observations:

Balanced molecular equation:
BaCl2(aq) + 2AgNO3(aq)  Ba(NO3)¬2(aq) + 2AgCl(s)
Complete ionic equation: Ba2+ + 2Cl- + 2Ag+ + 2NO3-  Ba2+ + 2NO3- + 2AgCl(s)
Net ionic equation: Cl- + Ag+  AgCl(s)
Name of product that makes the reaction occur: silver chloride

Reaction #6: copper (II) chloride + sodium carbonate 
Observations:

Balanced molecular equation: CuCl¬2(aq) + Na2CO3(aq)  CuCO¬¬¬3(s) + 2NaCl(aq)
Complete ionic equation: Cu2+ + 2Cl- + 2Na+ + CO32-  CuCO3(s) ¬ + 2Na+ + 2Cl-
Net ionic equation: Cu2+ + CO32-  CuCO3(s)
Name of product that makes the reaction occur: copper (II) carbonate
Reaction #7:
Iron (III) chloride + sodium hydroxide 
Observations:

Balanced molecular equation: FeCl3(aq) + 3NaOH(aq)  Fe(OH)¬¬3(s) + 3NaCl(aq)
Complete ionic equation: Fe3+ + 3Cl- + 3Na+ + 3OH-  Fe(OH)3(s) + 3Na+ + 3Cl-
Net ionic equation: Fe3+ + 3OH-  Fe(OH)3(s)
Name of product that makes the reaction occur: iron (III) hydroxide

Reaction #8:
Ammonium chloride + sodium hydroxide 
Observations:

Balanced molecular equation:
NH4Cl(aq) + NaOH(aq)  NH4OH(aq) + NaCl(aq)
Complete ionic equation:
N.R.
Net ionic equation:
N.R.
Name of product that makes the reaction occur: N.R.
Reaction #9: barium chloride + sulfuric acid 
Observations:

Balanced molecular equation: BaCl2(aq) + H2SO4(aq)  BaSO4(s) + 2HCl(aq)
Complete ionic equation: Ba2+ + 2Cl- + 2H+ + SO42-  BaSO4(s) + 2H+ + 2Cl-
Net ionic equation: Ba2+ + SO42-  BaSO4(s)
Name of product that makes the reaction occur: barium sulfate

Reaction #10: barium nitrate + sodium sulfate 
Observations:

Balanced molecular equation: Ba(NO3)2(aq) + Na2SO4(aq)  BaSO4(s) + 2NaNO3(aq)
Complete ionic equation: Ba2+ + 2NO3- + 2Na+ + SO42-  BaSO4(s) + 2Na+ + 2NO3-
Net ionic equation: Ba2+ + SO42-  BaSO4(s)
Name of product that makes the reaction occur: barium sulfate
Reaction #11: barium chloride + sodium hydroxide 
Observations:

Balanced molecular equation: BaCl2(aq) + 2NaOH(aq)  Ba(OH)¬2(s) + 2NaCl(aq)
Complete ionic equation: Ba2+ + 2Cl- + 2Na+ + 2OH-  Ba(OH)2(s) + 2Na+ + 2Cl-

Net ionic equation: Ba2+ + 2OH-  Ba(OH)2(s)
Name of product that makes the reaction occur: barium hydroxide

Reaction #12: lead (II) nitrate + potassium iodide 
Observations:

Balanced molecular equation: Pb(NO3)2(aq) + 2KI(aq)  PbI¬2(s) + 2KNO3(aq)
Complete ionic equation: Pb2+ + 2NO3- + 2K+ + 2I-  PbI2(s) + 2K+ + 2NO3-
Net ionic equation: Pb2+ + 2I-  PbI2(s)
Name of product that makes the reaction occur: lead (II) iodide

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