...INTRO: Not many training breakthroughs attract attention unless they produce unbelievable results. Wouldn’t you all agree?? Well I’m here to tell you that Interval Training is one of those methods. Today I will talk about what IT is, some of the great benefits and finally, how to get started, in hopes that you will want to try IT as part of your fitness plan and healthy lifestyle or at least arouse your curiosity about this training method. TOPIC 1: What is Interval Training? Interval training has been shown to be THE most effective cardiovascular training method for improving cardiovascular endurance, sport-specific performance, boosting metabolic rate, and best of all, burning fat! It is a form of cardio-respiratory Training involving a combination of high intensity work and low intensity work OR rest in repeated successions. In other words, a high intensity activity is followed by a low intensity one, or by rest, allowing the body to recover its energy systems faster for the next high intensity activity. This also allows the body to…. TOPIC 2: Benefits of Interval Training Interval training is awesome for fat burning and aerobic conditioning but let’s have a look at 3 more benefits and reasons to use interval training for your cardio workouts. (1) IT Has a wide variety of programs and methods. Because of its versatility, IT offers 1000s of different program variations. This is especially great for those looking for variety and change. Almost all aerobic exercises...
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...to obtain a point estimate of the mean overpayment. The estimated mean is then extrapolated to the overpayment amount to the population of all 1,000 claims. http://pages.wustl.edu/montgomery/lecture-7 Point Estimate vs. Interval Estimate To estimate population parameters, statisticians use sample statistics. For example, we use sample means to estimate population means and we use sample proportions to estimate population proportions. An estimate of a population parameter can be expressed in one of two ways: * Point estimate. A point estimate of a population parameter is a single value of a statistic. For example, the sample mean x is a point estimate of the population mean μ. In the same way, a sample proportion p is a point estimate of the population proportion P. * Interval estimate. An interval estimate is defined by two numbers, and the population parameter is said to lie between those two numbers. For example, a < x < b represents an interval estimate of the population mean μ. It expresses that the population mean is greater than a but less than b. Confidence Intervals To express the precision and uncertainty that are associated with a particular sampling method statisticians use a confidence interval. A confidence interval consists of three parts: * A confidence level. * A...
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...Inequalities This assignment involves the use of inequalities in mathematical equations. The formula for finding Body Mass Index (BMI) is BMI =703W/H^2. In this formula W = weight in pounds In this formula H = height in inches. For this assignment four intervals based on our own personal heights must be calculated. I am 6 feet 4 inches tall. My height in inches (or H) equals 76. These intervals include inequalities that are categorized as between or compound inequalities. One interval in this assignment will be a regular inequality. Wherever “BMI” appears in the inequalities, we will exchange the formula and solve the inequality for W to find the weight ranges that fit each category for my height. The first interval calculates those who might have a longer than average life span. The compound inequality for this follows: 17<bmi<22 17<703W/76^2<22 17<703W/5776<22 17*5776<703W<22*5776 98192<703W<127072 (Dividing all by 703) 139.6756<w<180.7567 140<w<181 People with a height of 76 inches may have a longer lifespan if they weigh between 140 and 181 pounds (after rounding up). Now we will do something a little different from the previous problem. Below we will solve the 2nd inequality for the formula for W prior to entering the different values to find W. 23<703W/H^2<25 23H^2<703W<25H^2 Divide all by 703 23H^2/703<w Square H for insertion (76*76) = 5776 23(5776)/703<w 132848/703<w 188.9729<w<205...
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...MATH 012 Midterm Exam Click Link Below To Buy: http://hwaid.com/shop/math-012-midterm-exam/ Math 012 Midterm Exam Name________________________________ Instructions: • The exam is worth 75 points. There are 15 questions, each worth 5 points. Your score on the exam will be converted to a percentage and posted in your assignment folder with comments. • This exam is open book and open notes, and you may take as long as you like on it provided that you submit the exam no later than the due date posted in our course schedule of the syllabus. You may refer to your textbook, notes, and online classroom materials, but you may not consult anyone. • You must show all of your work to receive full credit. If a problem does not seem to require work, write a sentence or two to justify your answer. • Please type your work in your copy of the exam, or if you prefer, create a document containing your work. Scanned work is also acceptable. Be sure to include your name in the document. Review instructions for submitting your exam in the Exams Module. • If you have any questions, please contact me by e-mail (mary.dereshiwsky@umuc.edu). At the end of your exam you must include the following dated statement with your name typed in lieu of a signature. Without this signed statement you will receive a zero. I have completed this exam myself, working independently and not consulting anyone except the instructor. I have neither given nor received help...
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...Distribute the 6 and the 3 * 6x-6+4= 21x+3 Step two: Combine like terms * 6x-2= 21x+3 Step three: Move smaller variable to one side and subtract * -2= 15x+3 Step four: Move the three to the other side * -5= 15x Step five: Divide by 15 * -5/15= x Step six: ALWAYS simplify * -1/3= x * Example 3: 7x/9-12= x Step one: Multiply each side by 9 * 7x-108=9x Step two: Add 108 to both sides * 7x= 9x+108 Step three: Subtract 9x from both sides * -2x=108 Step four: Divide by negative 2 to find what “X” is * X= -54 Solve and graph the inequality. Write the solution set in interval notation. * Example 1: 7x-9 > 6x-12 Step one: Move the smallest variable to one side and subtract * X-9 > -12 Step two: Move the constant term to other side and add * X > -3 Step three: Write in interval notation * [-3, infinity) Step four: Graph * Example 2: 2x+8 > 10x-14 Step one: Subtract 8 from both sides * 2x > 10x-22 Step two: Subtract 10x from both sides * -8x > -22 Step three: Multiply both sides by -1 (reverse inequality) * 8x < 22 Step four: Divide both sides by 8 * X < 11/4 * Example 3: 7x < 49 Step one: divide both sides by 7 to find out what “X” is * X <49 Step two: Graph Solving the equation * Example 1: | 3x-4 / 8x+5| = 3 Step one: Get rid of the absolute value sign by rule 2 (|x|>c x>c or x c-c) * 3x-4/8x+5 = -3 Step...
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...The formula x = y means that x and y are the same. (2) The formula C = 5 (F − 32) represents the relationship between temperatures in 9 degrees Fahrenheit F and Celsius C. A formula is called solved for one of its variables if that variable is isolated on one side of the equals sign in the equation. Not all formulas can be solved for all of their variables. Example 1.2. The formula we wrote relating Fahrenheit and Celsius temperatures is solved for the variable representing degrees in Celsius C. We solve it for degrees in Fahrenheit F : 5 C = (F − 32) 9 9 C = F − 32 5 9 C + 32 = F 5 Written in the normal way (with the solved variable on the left-hand side) our solution is 9 F = C + 32 5 2. Solving Linear Inequalities 2.1. Inequalities and Interval Notation. An inequality is an expression representing the way that variables or numbers are not equal. We will learn to simplify expressions which describe how a variable is less or greater than another. In mathematical notation for fixed real numbers a, the inequality x < a represents all numbers less than a; we can write this equivalently a > x. The inequality x > a represents all numbers greater than a. The previous inequalities are called strict, since we are not allowed to take x = a. If we can take x = a, the inequalities are written x ≤ a or x ≥ a. The solution set of an inequality can be written in set-builder notation: for example, the real numbers greater than or equal to a can be written as {x : x > a} When the upper bound on...
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...on inequalities. I never knew that there were calculations for body mass index until now. Below, I have worked out calculations according to my height that let me know which weight(s) is healthy for me. In addition, I will also work calculations in between as well as the calculations that show which level of weight(s) that I need to stay away from, if I wish to extend my years here. According to page 151 in our textbook, we were given the formula for Body Mass Index or BMI as stated below: BMI= 703W H2 Next, we were asked to calculate the four intervals based on our own individual heights. My height is 72.23 inches. The various intervals include three compound between inequalities and one average inequality. Whenever BMI shows up in the inequalities I will substitute the formula and solve the inequality for W to point out the weight ranges that fit each category for my specified height. As documented, the first interval shows those who might have a longer life span than average. The compound inequality for this is: 17<BMI<22 17<703W<22 This is referred to as an equivalent inequality. H2 17<703W<22 Here H2 has been replaced by my actual height in inches. 72.232 17<703W <22 During the next step, I will multiply all three terms by the denominator. 5217.1729 17(5217.1729)<703W(5217.1729<22(5217.1729) In this step, cancelling is done. 5217.1729 88691.939<703W<114777.8 The multiplications...
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...Indian Institute of Management Bangalore PGP 2009-10 Quantitative Methods I Mid Term Examination Time: 2 hours 30 minutes Name:____________________________ Maximum Marks: 50 Roll. No.________________ Section____ Question No. | 1 | 2 | 3 | 4 | 5 | Total | Maximum Marks | 3+2+2+2+4=13 | 2+3+4=9 | 2+2*1+2*1.5+4=11 | 3+6+2=11 | 3+3=6 | 50 | Student’s Score | | | | | | | Instructions: This is an open-book (1 text-book), open note exam; however you are not allowed to share material with other students. Use of calculator is permitted, but not computer (laptop). Please do not seek any clarifications. To get any credit, you must * circle/clearly indicate your final answer (in the space, whenever provided); * answer all questions in the space provided, * State any assumptions that you make. Assumptions made should be reasonable. * Show calculations and provide reasons to support your answers. Do not attach any additional sheets; use the back sides, if necessary. 1. A highway restaurant is trying to plan its capacity. It finds that on average during the peak lunch hour, which is between 1pm and 2 pm, vehicles arrive at a rate of 1 vehicle per 6 minutes. (Each vehicle on average has four customers, and they can all sit on one table.) To avoid incurring a loss on a particular day, there should be at least 6 vehicles arriving during the peak lunch hour period. (a) What is the probability of the restaurant incurring...
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... in set notation? D. R(-∞,0] 3. y=400x+80 – what is its Range E. D:{x/x≥-3} in interval notation? F. D(-∞,1/2)U(1/2,∞) 4. y=-6x-8 – what is its Range G. R[0,∞) in interval notation? H. R:{y/y≤0} 5. y=/18x+6/+5 – what is its Domain N. D[5,∞) in interval notation? O. R:{y/y≥0} 6. y=5x+82x-8 – what is its Range R. D:{x/x≤1} in interval notation? S. D(-∞,1/6)U(1/6,∞) 7. y=2-2x – what is its Domain T. D:{x/xER} in set notation? U. (-∞,∞) 8. y=6x+2 – what is its Domain V. D:{x/x≥1} in set notation? Y. D:{x/x≥-1/3} 9. y=3x-26x+1 – what is its Domain in interval notation? 10. y=2x-2 – what is its Domain in set notation? 11. y=4+x2x-3 – what is its Range in interval notation? 12. y=6x-8 – what is its Range in interval notation? 13. y=x+1...
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...Inequalities According to our textbook located on page 151 (Dugopolski, M. (2012) the formula for Body Mass Index (BMI) is: BMI = 703W H^2 Now, W is equal to an individual’s weight in pounds and H is equal to the height in inches. The height I will be using in the following problems is 70 inches. The stated intervals combine three compound between inequalities, and one “ordinary,” inequality. For the Body Mass Index (BMI) will be used in inequalities; for this formula they will also be supplemented to solve the inequality for W, that will define the ranges of weight that are particular for the height being utilized. Our first interval indicates which individual might have a longer life span then average. The compound interval that will be used is: 17 < BMI < 22 17 < 703W < 22 Equivalent inequality will be replacing BMI in the formula. H^2 17 < 703W < 22 (70)^2 I have replaced H^2 with my height in inches. 17 < 703W < 22 4900 We square the denominator and then multiply it by each numerator. In this case it will be 17, 703W, and 22. 17(4900)<703W(4900)<22(4900) It has now been cancelled. 49000 83300<703W<107800 Carry out the multiplication 83300<703W<107800 The terms are then divided by 703 in order to isolate W. 703 703 703 118.5<W<153.3 Those with the height of 70 inches may indeed have a longer than average...
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...Algebra 2 Honors Name ________________________________________ Test #1 1st 9-weeks September 2, 2011 SHOW ALL WORK to ensure maximum credit. Each question is worth 10 points for a total of 100 points possible. Extra credit is awarded for dressing up. 1. Write the solutions represented below in interval notation. A.) [pic] B.) [pic] 2. Use the tax formula [pic] A.) Solve for I. B.) What is the income, I, when the Tax value, T, is $184? 3. The M&M’s company makes individual bags of M&M’s for sale. In production, the company allows between 20 and 26 m&m’s, including 20 and 26. Write an absolute value inequality describing the acceptable number of m&m’s in each bag. EXPLAIN your reasoning. 4. Solve and graph the solution. [pic] 5. Solve and graph the solution. [pic] 6. Solve. [pic] 7. Solve. [pic] 8. True or False. If false, EXPLAIN why it is false. A.) An absolute value equation always has two solutions. B.) 3 is a solution to the absolute value inequality [pic] C.) 8 is a solution to the compound inequality x < 10 AND x > 0. 9. Solve for w. [pic] 10. You plant a 1.5 foot tall sawtooth oak that grows 3.5 feet per year. You want to know how many years it would take for the tree to outgrow your 20 foot roof. A.) Write an inequality that defines x as the number of years of growth. B.) Determine the number of years, to nearest hundredth, it...
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...CASES ANALYSIS OUTLINE STEPS If all of the objectives of the case analysis method are to be realized, an organizational structure for the compilation, analysis, and presentation of case analyses should also be considered. Without this structure, integral parts of the case analysis may be ignored, and the multi-purpose nature of the course defeated. Such a structure would provide the inclusion of the following: 1. Statement of the major problem – the essence of the case, the point beyond which one can no longer find a broader, more pervasive or underlying issue. 2. Outline of minor problems – with facts and reasons. A hierarchical order of importance for the sequencing of these minor problems will be discussed following these steps. 3. Existing major policy issues – if any. This section will develop the ability to discriminate between goals, strategies, polices, programs, procedures, and rules by requiring a delineation of those policy issues which require formulation, administration, or revision. 4. Major rejected alternative solutions – with facts and reasons. This insures an adequate search for alternatives, as opposed to superficial analyses that lead to 5. Recommended solutions – with reasons. These solutions should embrace and resolve all major and minor problems delineated in steps 1 and 2. 6. Policy recommendations: This step will require the completion of the goals cited in step number 3. 7. Programmed implementation of recommendations...
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...Case Study 2, Under Armour’s Strategy Under Armour is an emerging company in the sports apparel industry whose mission is to “Make all athletes better through passion, science and the relentless pursuit of innovation”. Under Armour was a disruptive innovator in the sports apparel industry by creating sports apparel using synthetic materials as an alternative to natural fibers, such as cotton. This important change in material resulted in a “shirt that provided compression and wicked perspiration off your skin rather than absorb it…that worked with your body to regulate temperature and enhance performance”. This promise to increase athletic performance differentiated it from competing sports apparel companies, but rivals have since implemented synthetic materials into their product lines. This case study seeks to analyze Under Armour’s history, resources, capabilities, and core competencies, business and corporate-level strategies, as well as the general environment and competitive landscape. After careful inspection of these varying areas, the factors contributing to Under Armour’s current success and future challenges will become clearer. The conception for Under Armour began over a year ago when CEO Kevin Plank played on the University of Maryland football team. Frustrated with having to repeatedly change his cotton shirt during practice, he envisioned a shirt whose materials allowed the perspiration to dry quickly, causing the athlete to be quicker, faster, and stronger...
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...pts) We will be constructing confidence intervals for the proportion of each color as well as the mean number of candies per bag. You will use the methods of 6.3 for the proportions and 6.1 for the mean. For the Bonus, you will use the sample size formula on page 338. You can use StatCrunch to assist with the calculations. A link for StatCrunch can be found under Tools for Success in Course Home. Here is also a link: http://statcrunch.pearsoncmg.com/statcrunch/larson_les4e/dataset/index.html. You can also find additional help on both confidence intervals and StatCrunch in the Online Math Workshop under Tab: “MAT300 Archived Workshops”. Specifically you will be looking for Confidence Intervals and Using Technology – CI. Submit your answers in Excel, Word or pdf format. Submit your file through the M&M® project link in the weekly course content. If calculating by hand, be sure to keep at least 4-6 decimal places for the sample proportions to eliminate large rounding errors. Answers 3 pts. Construct a 95% Confidence Interval for the proportion of blue M&Ms® candies. 95% Confidence Interval for proportion is given by [pic] where p = x/n = 810/4049 = 0.200049395, [pic]= 1.959963985, n = 4049 Therefore, CI is given by, [pic] = (0.187727588, 0.212371202) Thus with 95% confidence we can claim that the proportion of blue M&Ms® candies is within (18.77%, 21.24%). Details |Confidence Interval Estimate for Proportion ...
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...Statistics 4/29/15 Homework Question 1 – What is the essence of the confidence interval? Analyze the relationship between the confidence interval and central limit theorem. Question 2 – Explain the essence of Hypothesis testing. How related are null hypothesis and Alternative Hypothesis. How do you apply confidence interval in hypothesis testing? Question 3 – Explain the difference between T distribution and Z distribution. When and how do we use T distribution? What is the meaning of the number of degrees of freedom? Left Tail, right tail, 2 tail test: Try to understand the idea of hypothesis testing! Understand how all are participating. The confidence interval is used by statisticians to express the degree of uncertainty associated with a statistic. It is an interval estimate combined with a probability statement. For example, an interval estimate may be described as 95% confidence interval. This means that if we used the same sampling method to select different samples and we computed an interval estimate for each sample, we would expect the true population range to fall within the interval estimates 95% of the time. Confidence intervals indicate the precision of the estimate and the uncertainty of the estimate. The Central Limit Theorem allows us to define an interval within the sample’s expected range. If samples are drawn from a normal population or if the sample is large enough that xbar is approximately normal by the central limit theorem and standard deviation...
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