...P03: Acceleration on an Incline (Acceleration Sensor) |Concept |DataStudio |ScienceWorkshop (Mac) |ScienceWorkshop (Win) | |Linear motion |P03 Acceleration.ds |(See end of activity) |(See end of activity) | |Equipment Needed |Qty |Equipment Needed |Qty | |Acceleration Sensor (CI-6558) |1 |Dynamics Cart (inc. w/ Track) |1 | |Angle Indicator (inc. w/ Track) |1 |Meter stick |1 | |Base and Support Rod (ME-9355) |1 |1.2 m Track System (ME-9429A) |1 | What Do You Think? When a sled accelerates down a snow-covered hill, on what does its acceleration depend? You may want to consider the height of the hill, the slope of the hill and the mass of the sled. How does its acceleration depend on the variable(s) you selected? Take time to answer the ‘What Do You Think?’ question(s) in the Lab Report section. Background A cart on an incline will roll down the incline as it is pulled by gravity. The direction of the acceleration due to gravity is straight down as shown in the diagram. The component of the acceleration due to...
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...Acceleration Due to Gravity Introduction In this lab you will measure the acceleration due to gravity near the earth’s surface with two experiments: first, by determining the time for a steel ball to fall a known vertical distance (free fall), and then second, by measuring the velocity of a cart at various points as it glides down a slightly inclined and nearly frictionless air track (slow fall). Equipment Part 1: Free-Fall • Free-fall apparatus (steel plate, drop mechanism) • Electronic Timer • Steel Ball Part 2: Slow-Fall • Air Track • Electronic Timer (may be different brand/model than in Part 1) • Gliding Car • Laser Photogate Background: Free Fall Acceleration Under the constant acceleration of gravity near the Earth’s surface, g, the vertical position, y, of a falling object is related to the time it has fallen by 1 y = y 0 + v 0 t " gt 2 2 where y0 and v0 are the initial position and velocity, respectively. The distance fallen after a time, t, has elapsed is: ! 1 y 0 " y = gt 2 " v 0 t 2 If you release the object from rest, v0 = 0, the equation simplifies to ! y0 " y = 1 2 gt 2 By varying the distance the ball drops and measuring the corresponding transit times, we can determine the acceleration of gravity from a best fit line to a linear graph of the experimental data. ! ! Procedure: Free-Fall Acceleration A diagram of the experimental apparatus is shown in Figure 1. When the ball loses contact with the release mechanism, the timer starts counting. It stops...
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...Question 5 | | 1 / 1 point | In the figure shown, the coefficient of kinetic friction between the block and the incline is 0.40. What is the magnitude of the acceleration of the suspended block as it falls? Disregard any pulley mass or friction in the pulley. Question options: | 1) | 3.4 m/s2 | | | 2) | 3.7 m/s2 | | | 3) | 4.2 m/s2 | | | 4) | 3.9 m/s2 | | | 5) | 5.4 m/s2 | | Question 34 | | 1 / 1 point | A 4.0-kg block slides down a 35 incline at a constant speed when a 16-N force is applied acting up and parallel to the incline. What is the coefficient of kinetic friction between the block and the surface of the incline? Question options: | 1) | 0.20 | | | 2) | 0.23 | | | 3) | 0.26 | | | 4) | 0.33 | | | 5) | 0.41 | | Question 35 | | 1 / 1 point | A 1.0-kg block is pushed up a rough 22 inclined plane by a force of 7.0 N acting parallel to the incline. The acceleration of the block is 1.4 m/s2 up the incline. Determine the magnitude of the force of friction acting on the block. Question options: | 1) | 1.9 N | | | 2) | 2.2 N | | | 3) | 1.3 N | | | 4) | 1.6 N | | | 5) | 3.3 N | | Question 40 | | 1 / 1 point | A 2.0-kg object has a velocity of 4.0i m/s at t = 0. A constant resultant force of (2.0i + 4.0j) N then acts on the object for 3.0 s. What is the magnitude of the object's velocity at the end of the 3.0-s interval? Question options: | 1) | 9.2...
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...When a 1.00 kg bird lands on the telephone wire midway between the poles, the wire sags 0.200 m. Draw a free-body diagram of the bird. How much tension does the bird produce in the wire? Ignore the weight of the wire. [614 N] 2. A 40 kg crate rests on a horizontal floor, and a 75 kg person is standing on the crate. Determine the magnitude of the normal force that (a) the floor exerts on the crate and (b) the crate exerts on the person. [(a) 1.13 x 103 N, (b) 735 N] 3. A worker stands still on a roof sloped at an angle of 45° above the horizontal. He is prevented from slipping by a static frictional force of 450 N. Find the mass of the worker. [85 kg] 4. A 4.0-kg bucket of water is raised from a well by a rope. If the upward acceleration of the bucket is 5.0 m/s2, find the force exerted by the rope on the bucket. [59 N] 5. A block is pressed against a vertical wall by a force [pic], as the drawing shows. This force can either push the block upward at a constant velocity or allow it to slide downward at a constant velocity. The magnitude of the force is different in the two cases, while the directional angle ( is the same. Kinetic friction exists...
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...00 kg bird lands on the telephone wire midway between the poles, the wire sags 0.200 m. Draw a free-body diagram of the bird. How much tension does the bird produce in the wire? Ignore the weight of the wire. [614 N] 2. A 40 kg crate rests on a horizontal floor, and a 75 kg person is standing on the crate. Determine the magnitude of the normal force that (a) the floor exerts on the crate and (b) the crate exerts on the person. [(a) 1.13 x 103 N, (b) 735 N] 3. A worker stands still on a roof sloped at an angle of 45° above the horizontal. He is prevented from slipping by a static frictional force of 450 N. Find the mass of the worker. [85 kg] 4. A 4.0-kg bucket of water is raised from a well by a rope. If the upward acceleration of the bucket is 5.0 m/s2, find the force exerted by the rope on the bucket. [59 N] 5. A block is pressed against a vertical wall by a force [pic], as the drawing shows. This force can either push the block upward at a constant velocity or allow it to slide downward at a constant velocity. The magnitude of the force is different in the two cases, while the directional angle ( is the same. Kinetic...
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...greatest.| A)|1, 2, 3| B)|2, 1, 3| C)|2, 3, 1| D)|1, 3, 2| E)|3, 2, 1| 3.|A heavy wooden block is dragged by a force ¢ along a rough steel plate, as shown below for two cases. The magnitude of the applied force ¢ is the same for both cases. The normal force in (ii), as compared with the normal force in (i) is:| A)|the same| B)|greater| C)|less| D)|less for some angles of the incline and greater for others| E)|less or greater, depending on the magnitude of the applied force ¢.| 4.|A 6-kg object is moving south. A net force of 12 N north on it result in the object having an acceleration of: | A)|2 m/s2, north | B)|2 m/s2, south | C)|6 m/s2, north | D)|18 m/s2, north | E)|18 m/s2, south | 5.|A 9000 N automobile is pushed along a level road by four students who apply a total forward force of 500 N. Neglecting friction, the acceleration of the automobile is: | A)|0.055m/s2| B)|0.54 m/s2| C)|1.8 m/s2| D)| 9.8 m/s2| E)|18 m/s2| 6.|A 25-kg crate is pushed across a frictionless horizontal floor with a force of 20 N, directed 20° below the horizontal. The acceleration of the crate is: | A)|0.27 m/s2| B)|0.75 m/s2| C)|0.80 m/s2| D)|170 m/s2| E)|470 m/s2| 7.|Two forces are applied to a 5.0-kg crate; one is 6.0 N to the north and the...
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... The beginning of the ride starts with an exhilarating acceleration up the first incline....
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...Experiment #6-FREE FALL FALLING BODIES OBJECTIVES: 1.To describe how the velocity and acceleration of an object change over time when falling under the influence of gravity and to explain why such changes are observed. 2. To determine gravitational acceleration by studying the velocity of a falling object as a function of time. INTRODUCTION: Everything on Earth is under the influence of it’s gravitational field keeping us from jumping of respected measure high.Along with this things that are on Earth,there are objects that are soon to be on Earth’s surface,falling objects have certain interactions with Earth’s gravity.Air resistance is a factor of free-falling objects.Since Earth has an atmosphere,the speed of which objects fall at are not constant. While you are falling, you will probably feel as if you are floating—or not even moving at all. Falling is relational—if there is nothing to fall toward, you may not even be aware that you’re falling. If there is no ground, gravity might be low and you’ll feel weightless. Objects will stay suspended if you let go of them. Whole societies around you may be falling just as you are. And it may actually feel like perfect stasis—as if history and time have ended and you can’t even remember that time ever moved forward. A free falling object is an object that is falling under the sole influence of gravity. Any object that is being acted upon only by the force of gravity is said to be in a state of free fall. ...
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...a horse that gallops a distance of 15 km in a time of 30 min is: Average speed = 15 km/30 min = 15 km/0.5 h = 30 km/h 5. Speed is the distance covered per unit of time. Acceleration is the rate in which an object changes its velocity. 6. If a car is moving at 90 km/h and it rounds a corner, also at 90 km/h, it does maintain a constant speed but not a constant velocity. The velocity never changed, only the direction it’s traveling. 7. Velocity is change in displacement, change in position over a period of time, while Acceleration is change in velocity over a time period. 8. The acceleration of a car that increases its velocity from 0, to 100 km/h in 10s is 10km/h*s 9. The acceleration of a car that maintains a constant velocity of 100 km/h for 10s is 0 km/h*s. Some of my classmates get this question wrong but the last question right because they fail to read the question. In the last question there was a change in velocity. However in this question there was no change in velocity. 10. We are most aware of moving in a vehicle when the vehicle is accelerating because gravity will push us back into the seat. 11. The relationship Galileo discover about a ball's acceleration and the steepness of an incline is the steeper the incline the faster the balls accelerate. Free fall acceleration occurs when the plane is vertical. 12. The velocity acquired by a freely...
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...1) The following problems are representative of the type problems that will be on the 1st semester exam. Exam will cover Chapters 1 - 5. 2) Please solve/answer each of these - pay particular attention to the “type” solution required for each one. 3) You will not be given ANY additional material - any and all equations and/or constants that YOU think you will need must be placed on either a 3x5 or 5x8 index card. This card must be submitted to me during the exam review days and approved by me. The “approved/signed” cards may be used during the exam. 4) YOU MUST HAVE YOUR CARD, CALCULATOR and PENCILS WITH YOU WHEN THE BELL RINGS TO START THE PERIOD. YOU WILL NOT BE PERMITTED TO GO GET ANYTHING AND/OR BORROW ANYTHING FROM ANYONE!!!! 1. One year is about ____ seconds while one day is exactly ____ seconds. a) | 3.16 x 107, 86 400 | b) | 5.26 x 105, 86 400 | c) | 3.16 x 107, 8 640 | d) | 1.04 x 106, 36 000 | 2. The proton contains which of the following combination of quarks? a) | two up quarks and one down quark | b) | one up quark and two down quarks | c) | one top quark and two bottom quarks | d) | two top quarks and one bottom quark | 3. On planet Z, the standard unit of length is the foose. Ann the Astronaut is 5.90 feet tall on earth. She lands on planet Z and is measured to be 94 foosi tall. Her partner Rachael is 88 foosi tall. How tall is Rachael on Earth? a) | 5.2 feet | b) | 5.5 feet | c) | 5.8 feet | d) | 6.3 feet | 4....
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...Roller coasters work by a lot of supports and machinary. Roller coasters also work by tracks, that is what makes a roller coaster what it is. Roller coasters are made for fun and it is hard work to make one. It gets built by good machinary, supports and much more. You need good workers to make a roller coaster or else it will either fall down or the riders will be in huge risk. There is only 1 way to make a roller coaster work and that is for a machine to carry the coaster up and then the rest is up to the inclines and declines in the roller coaster. There is another way and that is rapid changes in the speed and directions that is made. After you are carried up a incline by the machine there can not be big inclines for the rest of the ride or else the coaster can stop in the...
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...Regions, Force Diagrams, Description Correlation of Position, Velocity, and Acceleration Graphs Instructions to Recreate Graph 3 Analysis of Newton’s 3 Laws of Motion Part 2: Scenario C Graph, Force Diagrams, Regions Explanation of Graph Self-Assessment Summary Report on Motion PHS 100 Lab 552 26 March 2013 Region 1: The fan cart is at a constant position. As you can see, the fan cart is set at a constant position of 2.0 meters away from the motion detector. Velocity and acceleration are zero as the cart is not moving. Region 2: A change in motion is occurring. As the cart begins to move, the position of the cart moves closer to the detector. Velocity and acceleration are at a negative slope because the direction is changed from no movement to movement. Region 3: The fan cart is moving at a constant speed and direction towards the detector. Slope for velocity becomes positive as the speed is now greater than zero. Acceleration is constant. Region 4: The fan cart has now moved to a closer position to the motion detector. Velocity and Acceleration is at zero because there is no movement. Regions of Graph 3: Region 1- The fan cart is at a constant position as it is not moving. Since the position is just less than 2 meters away from the detector, we know the fan cart is not directly in front of the motion detector. There is no acceleration. Region 2- The fan cart begins to gradually accelerate towards the motion detector...
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...Acceleration vs. Time * On the first graph, the man walks slowly to the house from the origin. On the Position-Time graph, the line is a positive consistent rise. This is because his position is going in a positive direction as well as the time is going in a consistent positive direction. On the Velocity-Time graph, the line is straight across at 2 m/s because the velocity does not change because of the consistent speed of the man walking to the house. Since the velocity is constant the acceleration is zero. On the Acceleration-Time graph, the line is flat and straight across at the 0 m/s line because the man does not accelerate. He just walks at a consistent pace to the house. This is called constant speed because there is no variation in his speed. * On the second example, the man is sleeping then wakes up and runs toward the house constantly speeding up as he goes. On the Position-Time graph, there is a positive upward curved line. This is because both are moving in a positive direction but because he is running, the position is rising faster than the time. This upward curve indicates an increase in velocity. On the Velocity-time graph, the line is a straight consistent rise. This is caused because the man is running so the velocity is rising throughout the graph, as is the position. A positive slope indicates a changing velocity which is a positive acceleration. On the Acceleration-Time graph, the line constantly rising because the man is running, constantly speeding...
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...NAME: _______________________ PHYSICS 2110 – EXAMINATION 3 FALL SEMESTER 2012 DIRECTIONS: Show your work for each of the problems numbered 1-4. Credit will NOT be given to correct answers without the appropriate work shown. Do NOT turn in additional pages, all work to be graded must be on these exam pages. Do NOT detach any of these exam pages. Be sure to clearly indicate your answers by CIRCLING them. Work need not be shown for the multiple choice problems. There is only one correct answer to each multiple choice question. The exam MUST be turned in at the end of the exam period. Late exams will NOT be graded. 1. Two spheres of mass 5 kg and 11 kg undergo an elastic collision as shown in the accompanying diagram. a) Write an equation for the conservation of momentum for this collision, substitute in the appropriate numbers and simplify. ( 5 points ) b) Calculate the total kinetic energy of the system before the collision. ( 5 points ) c) Determine the velocities of the two spheres after the collision. ( 5 points ) e) Calculate the total kinetic energy of the system after the collision. ( 5 points ) 5 kg 11 kg 5 m/s 3 m/s 5 m/s 3 m/s 2. Oberon is the second largest moon of the planet Uranus. Astronomers have accumulated the following data for both Uranus and its moon Oberon. Radius of Uranus’ orbit about the Sun= 2.87099 x 109 km Radius...
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...! Experiment AccelerAtion! ! ! ! ! ! Acceleration! Observations ! ! ! Data!Table! ! Height/of/ramp:///1/ TRIAL/No.! 1! 2! 3! 4! 5! ! ! ! Time/(t)/ seconds! Velocity/(v)/–! m/s! Acceleration/(a)/–! m/s2! .30! .30! .30! .30! .30! .5! 1.2! 2.4! .48! 1.25! 2.604! .55! 1.091! 1.983! .595! 1.008! 1.695! .64! .9375! 1.465! Average!=.553! Average!=1.097! 1.132! 1.068! .98! 1.224! 1.249! 1.09! 1.101! 1.010! 1.03! 1.165! 1.131! .96! 1.25! 1.302! Average!=1.024! Average!=1.175! Average!=1.152! 1.34! 1.343! 1.002! 1.39! 1.295! .9316! 1.42! 1.268! .8927! 1.29! 1.395! 1.082! 1.33! .90! .90! .90! .90! .90! ! Average!=2.029! 1.06! .60! .60! .60! .60! .60! ! 11! 12! 13! 14! 15! Angle/of/incline/=///35/ /o! Distance/(x)! –//m! ! 6! 7! 8! 9! 10! ! ! m! 1.353! 1.018! Average!=1.354! Average!=1.331! www.HOLscience.com 1! Average!=.9852! ©Hands-On Labs, Inc. ! Experiment AccelerAtion! ! ! ! ! ! ! ! ! ! ! ! ! ! ! ! ! ! ! Questions A. Newton’s/first/law/says/a/body/at/rest/will/remain/at/rest/unless/acted/upon/by/an/outside/ force,/ and/ a/ body/ in/ motion/will/ continue/in/ motion/at/ the/ same/ speed/ and/ in/ the/ same/ direction/unless/acted/upon/by/an/outside/force./What/forces/were/acting/on/the/marble/as/ ...
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