...EC315 Homework week 5 Chapter 13 #’s 40, 44, &47 40. A. No because there are days where the number of occupied rooms went up and revenue went down. B. occupied | income | x - xbar | y - ybar | (x-xbar)(y-ybar) | Column1 | 23 | 1,452.00 | -13.24 | 16.44 | -217.6656 | | 47 | 1,361.00 | 10.76 | -74.56 | -802.2656 | | 21 | 1,426.00 | -15.24 | -9.56 | 145.6944 | | 39 | 1,470.00 | 2.76 | 34.44 | 95.0544 | | 37 | 1,456.00 | 0.76 | 20.44 | 15.5344 | | 29 | 1,430.00 | -7.24 | -5.56 | 40.2544 | | 23 | 1,354.00 | -13.24 | -81.56 | 1079.8544 | | 44 | 1,442.00 | 7.76 | 6.44 | 49.9744 | | 45 | 1,394.00 | 8.76 | -41.56 | -364.0656 | | 16 | 1,459.00 | -20.24 | 23.44 | -474.4256 | | 30 | 1,399.00 | -6.24 | -36.56 | 228.1344 | | 42 | 1,458.00 | 5.76 | 22.44 | 129.2544 | | 54 | 1,537.00 | 17.76 | 101.44 | 1801.5744 | | 27 | 1,425.00 | -9.24 | -10.56 | 97.5744 | | 34 | 1,445.00 | -2.24 | 9.44 | -21.1456 | | 15 | 1,439.00 | -21.24 | 3.44 | -73.0656 | | 19 | 1,348.00 | -17.24 | -87.56 | 1509.5344 | | 38 | 1,450.00 | 1.76 | 14.44 | 25.4144 | | 44 | 1,431.00 | 7.76 | -4.56 | -35.3856 | | 47 | 1,446.00 | 10.76 | 10.44 | 112.3344 | | 43 | 1,485.00 | 6.76 | 49.44 | 334.2144 | | 38 | 1,405.00 | 1.76 | -30.56 | -53.7856 | | 51 | 1,461.00 | 14.76 | 25.44 | 375.4944...
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...Week 4 EC315 Homework Chapter 10 34. A recent article in Vitality magazine reported that the mean amount of leisure time per week for American men is 40.0 hours. You believe this figure is too large and decide to conduct your own test. In a random sample of 60 men, you find that the mean is 37.8 hours of leisure per week and that the standard deviation of the sample is 12.2 hours. Can you conclude that the information in the article is untrue? Use the .05 significance level. Determine the p-value and explain its meaning. H0: u = 40 H1: u < 40 (my belief) test stat: t(37.8) = (37.8-40)/[12.2/sqrt(60)] = -1.3968 determine the p-value and explain its meaning. p-value = P(t25 Critical value: Statistic= t=(26.067-25)/(1.534/√15)=2.694 Critical value= inv-t(14,0.01) =2.624 Test value: Reject region: {t/t>2.624} Decision: statistic=2.694>2.624=critical value We reject H0, At the .01 significance level we conclude that the mean number of patients per day is more than 25. Decision: P-value= t(2.694,14)=0.0087 So p-value < 0.01 (we reject H0) Summary: We can interpret the p-value as: p-value= probability of obtaining a statistic value greater than 2.694 if μ =25 61. Refer to the Baseball 2010 data, which report information on the 30 Major League Baseball teams for the 2010 season. a. Conduct a test of hypothesis to determine whether the mean payroll of the teams was different form $80.0 million. Use the .05 significance level. b. Conduct a...
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...EC315 Quantitative Research Methods Dustin Carter Week 2 Homework Chapter 6 Questions 36 Find the mean and standard deviation of the payout I am sorry, but I am not sure how to do this problem taking into account the ticket cost and probability. Question 39 A. How many Policyholders would you expect to have filed a claim within the last year? 15 * .4 = 6 Policy holders B. What is the probability that 10 of the selected policyholders submitted a claim last year? P(x = 10) = 15C10 * .4 ^ 10 * .6 ^ 5 = 0.0245 C. What is the probability that 10 or more of the selected policyholders submitted a claim last year? P(10 <= x <= 15) = 1 - binomcdf(15,0.4,9) = 0.0338 D. What is the probability that more than 10 of the selected policyholders submitted a claim last year? P(11 <= x <= 15) = 1 - binomcdf(15,0.4,10) = 0.0093 Chapter 7 Question 32 A. How much toothpaste would you expect to be remaining in the tube? I would expect one half of the toothpaste to be there or 2.1 ounces B. What is the standard deviation of the amount remaining in the tube? Where B = 4.2 and A = 0 1.21 Ounces C. What is the likelihood there is less than 3.0 ounces remaining in the tube? 3.0 / 4.2 * 100% = .714 = 71.4% D. What is the probability there is more than 1.5 ounces remaining in the tube? (4.2 - 1.5) / 4.2 * 100% = .643 = 64.3% Question 37 A. What percent of the families spend more...
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...Multi-regression Analysis Summer 2013 EC315: Quantitative Research Methods Professor Scott Sowder Introduction One day I was sitting in class with my classmates. Our GPA, the number of classes were are taking, ages, IQ and the amount of time we spend studying were all different. I became curious and wanted to know what effect the different variables had on the student’s GPA, if any. So I decided to a survey of 30 students with varies GPAs, IQs, ages, number of classes being taken and the time they spend studying. My hypothesis statement is that all the independent variables will have the same or no effect on the dependent variable. The alternate statement is that at least one of the independent variables will have an effect on the dependent variable. I have applied a 95% confidence level, which means I am 95% sure that I will be able to show that at least one of the independent variables will have an effect on the GPA. Variable Identification My dependent variable is the students’ GPA. I chose GPA as my dependent variable because it relies on the other variables. The remaining variables are my independent variables. I chose them because they could all have an effect on a student’s GPA. Student | GPA (4.0) | # Classes | Age | IQ | Study time | 1 | 3.2 | 4 | 29 | 119 | 12 | 2 | 3.1 | 2 | 31 | 118 | 8 | 3 | 3.7 | 1 | 28 | 135 | 6 | 4 | 3.5 | 3 | 22 | 129 | 13 | 5 | 2.8 | 4 | 22 | 110 | 15 | 6 | 3.0 | 3 | 24 | 115 | 15 | 7 | 3.8 | 2 | 24 |...
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...Obesity: An American Crisis EC315 (Term Project Report) Michael Higgs Fall 2 2012 TABLE OF CONTENTS Purpose Statement…………………………………………………Page 1 Definition of Variables……………………………………………Page 1-3 Data Description…………………………………………………….Page 3-4 Results……………………………………………………………………Page 4-6 Works Cited……………………………………………………………Page 7 Appendix……………………………………………………………….Page 8-10 Purpose Statement This project will discuss the correlation between exercise and diet on the ever growing crisis of obesity in America. The dependent variable obesity is determined by independent variables; exercise (lack of) and diet. Americans are not getting adequate exercise to burn their caloric intake. This is not only a concern for adults, the CDC (center for disease control) reports that “most adolescents fall shorts of the recommended 60 minutes of aerobic physical activity each day, as only 18% of students in grades 9-12 met this recommendation in 2007.” Instead of exercising outdoors, children are turning to video games and television to occupy their time. Nicolas Stettler, MD performed a study that suggested that every hour children play video games or watch television may double their risk of obesity. With this being said I feel the most important independent variable in this relationship is exercise, or the lack of it. By teaching proper exercise and nutrition at a young age the likelihood of being obese as an adult diminishes. Definition of Variables The model used is: Y = X1 +...
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...Term Project The Effects Geographic Location and Age Have on A Credit Score Nicholas Rogers EC315 10 March 2013 TABLE OF CONTENTS PURPOSE STATEMENT AND MODEL………………………………………………………..3 DEFINITION OF VARIABLES…………………………………………………………………3 DATA DESCRIPTION…………………………………………………………………………..5 PRESENTATION AND INTERPRETATION OF RESULTS………………………………….7 WORKS CITED…………………………………………………………………………………10 DATA SOURCES……………………………………………………………………………….10 REGRESSION ANALYSIS AND CORRELATION MATRIX……………………attachment 1 PURPOSE STATEMENT AND MODEL With the current state of the economy and job market in the United States, many individuals are shocked to hear that credit scores are becoming even more important now than before not only when it comes to making purchases or financial decisions, but also in other aspects of their everyday life. According to Forbes.com staffer, Heather Struck, in A Bad Credit Score Affects A Lot More Than Credit, ones FICO score can affect their ability to get a job, their insurance rates, and even how their personal relationships work out (2011). Some people have differing opinions on what can hurt or help a credit score. To keep from going into each of those possible outcomes, I am just going to pay attention to geographic location and age of the person seeking credit. The purpose of this project is to see what, if any, effect where a person lives and his age will have on his credit...
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...Justin Andre EC315-Robert Simcoe Quantitative Research Paper 05/07/2015 I have decided to have a look at the exchange rate for the Euro Dollar to the United States Dollar for my research paper. The dependent variable is the daily high to low price movement of the Euro Dollar to the United States Dollar shown in percentage interest points where 100 is equal to 1 penny difference in price. The dependent variable is determined by independent variables average true range, volumes, volatility, and day of the week. The most important independent variable in this relationship is the average true range because the formula estimates daily hi to low price movement. The independent variable volumes is related to the daily hi to low price movement because it shows how many price ticks occurred during the trading day. The independent variable volatility is related to daily price change because the formula predicts how rapidly price can change. The independent variable day of the week is related to price change because market makers historically do more business on certain days. Our dependent data will be compared to each independent variable to see if there is negative, positive, or no correlation between them. Now that we have briefly gone over our variables let’s take a closer look at them before we start to run statistical analysis on the data. Variables My first variable is the dependent variable daily high to low of the price for the exchange rate of the...
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