ALGORITHMS OF ENCRYPTION

This method will used two different type faces slightly differing in weight (boldness). it will broke up the ciphertext into 5 character groups, each of which would represent one character in his plaintext. Depending on which characters of the group were bold, one could determine the plaintext character using the following table (* stands for a plain character and B for a bold character).

A=***** G=**BB* M=*BB** S=B**B* Y=BB***
B=****B H=**BBB N=*BB*B T=B**BB Z=BB**B
C=***B* I=*B*** O=*BBB* U=B*B**
D=***BB J=*B**B P=*BBBB V=B*B*B
E=**B** K=*B*B* Q=B**** W=B*BB*
F=**B*B L=*B*BB R=B***B X=B*BBB

For example, our some secret message as above :

To be or not to be that is the question. Whether ‘tis nobler in the mind to suffer the slings and arrows of outrageous fortune or to take arms against a sea of troubles and by opposing end them?

To decipher, we just break the characters into groups of 5 and use the key above to find the plaintext message.

M E E T M E B E tobeo rnott obeth atist heque stion Wheth ertis

H I N D T H E G noble rinth emind tosuf ferth eslin gsand arrow

Y M A F T E R S sofou trage ousfo rtune ortot akear msaga insta

C H O O L seaof troub lesan dbyop posin gendt hem?

The answer is : MEET ME BEHINDTHE GYM AFTER SCHOOL.

COMPUTER SYSTEM SECURITY
SSK4505

ALGORITHM ENCRYPTION