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Exothermics

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Mike's experimental setup is an example of a closed system. This is because the heat or energy can either come into or go from the system smoothly from the ballon and also to a much slighter degree, the Erlenmeyer flask, but in closed systems, the matter cannot come into or go from the system. This is also a closed system because matter cannot come into or go from the system if there are balloons involved which in this case, there is a balloon present.

The way to utilize the information in this potential energy diagram is to figure out the enthalpy change of the reaction and whether or not the reaction is exothermic or endothermic is to find whether or not the energy of the products is going to be higher than the energy of the reactants. In …show more content…
The second step that I did to determine the unrevealed substance was to use this answer and multiply it by the difference of the first temperature reached and the final temperature reached which looks like this 418*(5.5)°Celsius = 2,299. Therefore, there were 2,299 Joules that got lost by the unrevealed substance which also was gained by the water. The third step that I did to determine the unrevealed substance was to divide the total amount of Joules gained by the water by the difference of the heated substance and the final temperature reached which looks like this (2299 Joules) / (73.5)°Celsius = 31. The fourth step that I did to determine the unrevealed substance was to divide the 31 by how many grams of the unrevealed substance there are which can look like this 31 / (35.5 grams) = 0.881 Joules / (°Celsius * grams), which by utilizing significant digits, this answer can be rounded to 0.89 Joules / (°Celsius * grams). Therefore, the specific heat of the unrevealed substance is 0.89 Joules / (°Celsius *

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