| Tee off – starting point | | Loop de Loop – If the player misses the loop de loop, the player must start from the starting point and shoot again. | | Ramp – the player must hit the ball off the ramp to clear the grass trap. If the player misses the ramp or lands in the grass, they must put the ball on the ramp side of the loop de loop and go again until the make it to the green. | | Grass Trap | | Sand Trap | | Putting area – the green | | Hole – finish point |

Route one
Route one θ θ

The player starts at the starting point and the ball must travel 8 meters and make it through the loop de loop obstacle. NOTE: θ=60°
Note: If the player misses the loop de loop, or the ball does not go all the way around, they must start at the beginning and shoot again. Also they must add one point to their score.
At that point, once through the loop de loop, the player must then hit their ball at 10 meters, off of a ramp to clear the grass trap to
Note: If the player misses the ramp or lands in the grass trap, they must place their ball on the ramp side of the loop de loop and shoot again. Also add one point to their score.
If the player can hit the ball in the right direction off of the ramp, they could sink the ball in the hole, otherwise they will have to putt it in.

Route Two
Route Two θ θ
From the starting point, the player must hit the ball at a 60 degrees angle for 12 meters.
They must hug the side of the course so they do not hit their ball into the sand trap. Note: if the player hits their ball in the sand trap, there is no penalty, they must try and hit their ball out of the sand without hitting it too many times.
From the corner of where the two triangles meet the player must hit the ball 7 meters to bounce off of another corner to make it travel another 10 meters to the hole/green. The corner before the green is a 90 degrees angle.

b b a a c c C
C
A
A
| Given:C=60°, a=8 meters, b=12 metersc= 82+122-2810cos60° ≈10.588sinA=10.58sin60° so A is approx. 40.91° B=180-60-40.91=79.09 | A
A
a a b b d d D
D
B
B
| Given:d=10.58 meters, D=90°, b=7 metersIf Angle D is 90 degrees then the other two angles have to be 30 and 60.So A=30° and B is 60° a2+b2=c2a2= 72+10.582= so a is approx. 12.69 meters | E
E
D
D
e e b b d d B
B
| Given:e=12.69 meters, b=10 meters, d=10 metercosE= 102+102-12.69221010= .1948 E=78.77° 10sinD=12.69sin78.77° ≈50.62°B=180-78.77-50.62=50.61° |