...Analysis on triple bottom line and systems theory Corporate social responsibility is one of great debate for many years. Nobel prize-winning economist Milton Friedman believes the corporate responsibility a business has is to its shareholders making a profit, while Michael E. Porter and Mark R. Kramer believes businesses and society are interwoven (Newton, 2012). The purpose of this analysis is to analyze the ways in which systems theory and triple bottom line theory support or negate each other. First, the analysis will analyze CSR. Second, it will analyze how systems theory and triple bottom line theory support each other. Third, the analysis will analyze how systems theory and triple bottom line theory negate each other. Some companies believe corporate social responsibility builds good reputation and customer loyalty. Years ago corporate social responsibility was just about making a profit and providing employment. Today corporate social responsibility is more than just the bottom line. It is being involved in the community and being a benefit to society. Corporate social responsibility is the obligations of a business to society. Two types of corporate social responsibility theories are triple bottom line and systems theory. According to Savitz and Weber (2006), triple bottom line captures sustainability by measuring the impact of an organization’s activities on the world; this includes social, environmental, and financial performance (people, profit, and planet)...
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...* Link Mechanism A link mechanism can be defined as a system of connecting parts/rods that move or work together when a particular action is pre-determined. * Parabola The path traced out by a point, which moves in a plane, so that the ratio of its distance from a fixed point [FOCUS] to any point on the curve, and from the curve to a perpendicular distance on the directrix is always constant and equal to one. This constant is also known as the eccentricity. * Ellipse The path traced out by a point, which moves in a plane, so that the ratio of its distance from a fixed point [FOCUS] to any point on the curve, and from the curve to a perpendicular distance on the directrix is always constant and less than one. This constant is also known as the eccentricity. * Hyperbola: The path traced out by a point, which moves in a plane, so that the ratio of its distance from a fixed point [FOCUS] to any point on the curve, and from the curve to a perpendicular distance on the directrix is always constant and greater than one. This constant is also known as the eccentricity. * Archimedean Spiral The path traced out by a point along a rod, as the rod pivots about a fixed end. The linear movement of the point along the rod is constant with the angular movement of the rod. * Involute The path traced out by a point when an end of a plane figure is wrapped or unwrapped when held firm. * Epicycloid Tracing the path of a point as a circular disc rolls on the outside...
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...created a movement called Pythagoreanism. Euclid is sometimes called Euclid of Alexandria. He is also called the “Father of Geometry” and his elements were one of the most influential works in the history of mathematics, which served as a textbook used for teaching mathematics (especially Geometry) from when it was published till the late 19th century to early 20th century. In the Elements he included the principles of what is now called Euclidean Geometry. Euclidean Geometry is a mathematical system and consists of in a small set of appealing postulates that are accepted as true. In fact, Euclid was able to come up with a great portion of plane geometry from five postulates. These postulates include: A straight line segment can be drawn joining any two points, to extend a finite straight line continuously in a straight line, given any straight line segment, a circle can be drawn having the segment as radius and one endpoint as center, all right angles are congruent, and if two lines are drawn which intersect a...
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...different forms. These equations are often referred to as the "equations of the straight line." In what follows, x, y, t, and θ are variables; other letters represent constants (fixed numbers). General form where A and B are not both equal to zero. The equation is usually written so that A ≥ 0, by convention. The graph of the equation is a straight line, and every straight line can be represented by an equation in the above form. If A is nonzero, then the x-intercept, that is, the x-coordinate of the point where the graph crosses the x-axis (where, y is zero), is −C/A. If B is nonzero, then the y-intercept, that is the y-coordinate of the point where the graph crosses the y-axis (where x is zero), is −C/B, and the slope of the line is −A/B. Standard form where A and B are not both equal to zero, A, B, and C are coprime integers, and A is nonnegative (if zero, B must be positive). The standard form can be converted to the general form, but not always to all the other forms if A or B is zero. It is worth noting that, while the term occurs frequently in school-level US algebra textbooks, most lines cannot be described by such equations. For instance, the line x + y = √2 cannot be described by a linear equation with integer coefficients since √2 is irrational. Slope–intercept form where m is the slope of the line and b is the y-intercept, which is the y-coordinate of the location where line crosses the y axis. This can be seen by letting x = 0, which immediately gives y = b...
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...com/downloads/ma-170-final-exam-answers-all-possible-questions/ Points Awarded 100.00 Points Missed 0.00 Percentage 100% Determine whether the system of linear equations has one and only one solution, infinitely many solutions, or no solution. Find all solutions whenever they exist. 1. A) one and only one solution 1. B) one and only one solution 1. C) one and only one solution 1. D) infinitely many solutions 1. E) no solution Points Earned: 4.0/4.0 Solve the linear system of equations 1. A) Unique solution: 1. B) Unique solution: 1. C) Infinitely many solutions: 1. D) No solution Points Earned: 4.0/4.0 Find the simple interest on a $400 investment made for 5 years at an interest rate of 7%/year. What is the accumulated amount? 540. A) The simple interest is $140, the accumulated amount is $540. B) The simple interest is $115, the accumulated amount is $515. C) The simple interest is $120, the accumulated amount is $520. D) The simple interest is $125, the accumulated amount is $555. Points Earned: 4.0/4.0 Find the present value of $40,000 due in 4 years at the given rate of interest 8%/year compounded monthly. 948. A) The present value is $28,948.67. B) The present value is $29,433.94. C) The present value is $29,076.82. D) The present value is $29,748.06. Points Earned: 4.0/4.0 Solve the system of linear equations using the Gauss-Jordan elimination method. 1. A) B) C) D) E) Points Earned: 4.0/4.0 The following...
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...ELEC C4612 Po ower Sys stem Ana alysis Midsess sion SOL LUTION ( (Session 1, 2016) n QUES STION 1 For the system sho own in Figu 1, comp ure pute the matrix. T system has an off-nominal The tap chan nging transformer betw ween buses 1 and 2 wi a tap setting of 1.03 The line b ith 3. between buses 1 and 4 has half line charging sus sceptance o 0.25 pu at each end. There is a mutual of a . ng u d own. couplin of 0.15 pu between lines 2-3 and 4-3 as sho 2 t = 1.03 1 3 j0.45 j0.4 4 j0.15 j0.1 j0. 2 j0.3 j0.1 4 Figure 1 on Solutio etween line 2-3 and 4-3 es Mutual coupling be = = 0.4 0.15 5 0.15 0.1 0 3 − 2 3 − 4 3 − 2 − 5.7143 8.5714 = 8.5714 3 − 4 8.5714 Buildin block matrix ng Tempor rary values are, = − 5.7143 =− 2 2.8571 = − 2.8571 = − 11.4286 = 8.5714 = 14 4.2857 = 8.57 714 = 14.2 2857 = − 22 2.8571 Tap changing transformer in line 1-2 1 = = − 2.222 0.45 . . = = − 2.1575, = . Temporary values are, = − 2.0947 = 2.1575 = 2.1575 = − 2.2222 ( . . ) = 0.0628, = . ( . . ) = − 0.0647 Line 1-4 with half line charging susceptance of j0.25 at each end = = − 3.3333, = 0.25, = 0.25 . The =− = = = =− = = =− = =− matrix is therefore, 3.3333 + 0.25 − 2.0947 = − 5.178 = 2.1575 =0 = 3.3333 2.2222 − 5.7143 = − 7.9365 = − 2.8571 = 8.5714 11.4286 = 14.2857 3.3333 + 0.25 − 22.8571 = − 25.9404 ...
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...Construct an Equilateral Triangle II ........................................................................................ 16 Lesson 3: Copy and Bisect an Angle........................................................................................................ 21 Lesson 4: Construct a Perpendicular Bisector ........................................................................................ 30 Lesson 5: Points of Concurrencies .......................................................................................................... 37 Topic B: Unknown Angles (G-CO.9) ..................................................................................................................... 43 Lesson 6: Solve for Unknown Angles—Angles and Lines at a Point ....................................................... 44 Lesson 7: Solve for Unknown Angles—Transversals .............................................................................. 52 Lesson 8: Solve for Unknown Angles—Angles in a Triangle ................................................................... 60 Lesson 9: Unknown Angle Proofs—Writing Proofs ................................................................................ 66 Lesson 10: Unknown Angle Proofs—Proofs with Constructions...
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...Delight Dairy Company Executive Summary The Delight Dairy Company produces two product lines, ice cream and specialty products such as ice cream sandwiches and prepackaged ice cream. The management would like to optimize production to aid in the highest profitability. The two product lines ice cream and specialties utilize the same machine for ice cream processing as well as a shared work force of 150 man hours per week. Each product line utilizes a product specific packaging machines. One thousand gallons of ice cream is sold for $900 and specialties are sold for $1,500. Calculations & Statistical Analysis 1. Choose the unknowns. |X1 = Ice Cream | |X2 = Specialties | |2. Write the objective function. | |f( x, y) = 900X1 + 1500X2 | |3. Write the constraints as a system of inequalities | | |Product | | | | |X1 = Ice Cream |X2 = Specialties |X3 = Labor Time | |Machine |2 |1 |40 | |Packaging Line |1 |1 |40 | |Labor (hours) |3 |6 ...
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... Instructor Charlie Williams May 9, 2013 Introduction On Linear Inequalities Linear equations are special kinds of algebraic expressions that contains two variables. The value of one variable is dependent upon the other. The functions of inequalities are expressed as a line. The complexity of linear equations and linear equalities are sometimes compared concerning the complications of each. Unlike linear equations, linear inequalities incorporate the assessment of where to shade after a solution has been determined. Typically, two equations collaborate to compose a linear inequality. A linear equation will be made up of a combination of constants, a set of numbers and variables. The variables must be to the first power and cannot be squared or cubed. According to Michael Judge, the most common type of linear equation is in the form y = mx + b and describes a straight line (2010). In this case, the two variables are usually x and y and the constants are m and b which are numbers giving the slope and intercept of the line. Operations of Linear Equations Two equations and two variables are needed to find specific values. My variables are: c = # of classic maple rockers m = # modern rockers A classic maple requires 15 board feet of maple, and a total of 15c maple for all classic maple rockers. A modern rocker requires 12 board feet of maple, and a total of 12m for all modern...
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...APPENDIX vi Commands |Insert and replace | |i |insert before cursor | |I |insert at beginning of line | |a |append after cursor | |A |append after end of line | |o |open blank line below cursor to insert | |O |open blank line above cursor to insert | |r |replace current character | |R |replace characters at cursor position | |C |change rest of line beginning at cursor position | |ESC |quit Text-input mode and return to vi-command mode | |Operators | |x |delete character(s)at cursor ...
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...Setup dialog (Customize > Units Setup), and change the Display Unit Scale and System Unit Scale to “Centimeters”. Then, click on the ‘reactor’ settings. Change the Solver to “Havok 3”. Under Havok 3 World, changes need to be made for two(2) measurements or units: 1. 1m = 5.0 cm 2. Col. Tolerance = 0.2cm Then, open the Time Configuration dialog. Change the animation length to 25 seconds. Phase 2 Modelling 1. Firstly, a plane is made to act as the base for the dominos and other objects. 2. Then, a simple domino is drawn by using Box under Standard Primitives. The domino is then adjusted to this size shown in the picture below. 3. A Line is then drawn to make a pathway for the dominos and a simpler way of copying all the dominos at once. Select the previously drawn domino piece, and then open the Spacing Tool in Tools (Tools > Align > Spacing Tool). Click the “Pick Path” button, and select the line. Settings for Spacing Tool must be as follow: a. Spacing = 2.54cm b. Type of Object = Instance c. Under Context, depending on the scene/line, click on “Follow” to see if the dominos align with the line properly. The dominos are then adjusted accordingly to the scene below by using the line drawn. 4. To create slides/ramp for the balls, a Helix is drawn. The Helix is then adjusted to fit the scene as you require. Then, a Rectangle line is drawn and added vertices with the refine function under geometry. The Rectangle...
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...Xin Huo GRBU 506 Week 6 E6-31 a. Straight line: ($75000-$5000)/5=$14000 per year b. Double-declining-balance Twice straight-line rate: 2*(100%/5)=40% Year 1 $75000*0.4=$30000 Year2 $45000*0.4=$18000 Year3 $27000*0.4=$10800 Year4 $16200*0.4=$6480 Year5 $75000-$5000-$30000-$18000-$10800-$6480=$4720 E6-32 a. 1. Cumulative depreciation expense: [(920000-80000)/10]*7=$588000 2. Net book value of the plane 920000-588000=$332000 b. 1. If a cash amount equal to the plane’s net book value, the gain or loss is 0. 2. 195000-332000=-137000 $137000 loss on sale 3. 600000-332000=268000 $268000 gain on sale. E6-37 a. ($220000-$25000)/10=$19500 per year Annual straight-line depreciation is $19500 b. $220000-$19500*4=$142000 At the end of the fourth year, the net book value of the equipment is $142000. c. $115000<$14000, the equipment is impaired at the end of the fourth year because the expected cash flows that the equipment will generate is not bigger than the current net book value. d. $142000-$85000=$57000 The impairment loss is $57000. MA6-50 a. Reducing receivables Building a standardized system for follow up receivable. Company should set clear credit policies Providing multiple payment methods b. Reducing inventories Outsourcing Producing to order Reduce replenishment lead time c. Reducing plant, property and equipment. Consolidating and reorganizing production process, then sale of unnecessary assets. ...
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...routine application problems. Outcome 2 (7 marks) Apply mathematical processes in contexts related to the‘Applications’ area of study, and analyse and discuss these applications of mathematics. Outcome 3 (5 marks) Select and appropriately use technology to develop mathematical ideas, produce results and carry out analysis in situations requiring problem-solving, modelling or investigative techniques or approaches related to the selected modules for this unit from the ‘Applications’ area of study. Students need to demonstrate: Key knowledge This knowledge includes • key features of straight line, line segment and step graphs and the form of related tables of values; • the concept of break-even analysis and its relation to graphic and tabular representation of relations; • non-linear relations, constant of proportionality and key features; • linear inequalities, systems of linear inequalities and their properties; • the role of variables, constraints and objective functions...
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...where ‘the Colour Bill’ was discussed. It was the social concept that I had to really sit down and think about. “Flatland” takes place in a fictional country where the citizens are geometric shapes; the priests, who weren’t really priest as the author later explains, but the administrators, the scientists, the engineers, and the ruling class of Flatland who oversee all things of merit, are circles. Other men can have many sides; the more sides, the higher up the social class they become. An additional side is given to the off springs of the following generation. For example, the writer, a square, has children who are pentagons and their children are hexagons. The women in Flatland however are straight lines and they can never have sides or be anything other than straight line. At first, I found it very strange reading a number (no pun intended) of things; for example women are physically intimidating in...
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...1a. Answer: (1.0, 228,000), (2.0, 216,000) 1a. Key work steps 1b. Answer: $-12,000 1b. Key work steps Since M= y2-y1/x2-x1 then M= 216,000-228,000/2.0-1.0 M=-12,000/2.0-1.0 M=-12,000/1.0 M=-12,000 1c. Answer: Y= (-12,000)*x+240,000 1c. Key work steps Since Y=mx+b then and do figure m we use the formula m= (y2-y1)/(x2-x1) I know now what m is in my equation in this situation it’s -12,000 and to figure b is just the Y intercept which in this case is 240,000. So I get my linear equation Y= (-12,000)*x+240,000. 1d. Answer: $126.000 1d. Key work steps Now if this depreciation were to continue until 2019 then we use our formula to determine the value of the plane. Y=(-12,000)*x+240,000 now x is the number of years from the end of our graphing years which was half way through 2009. So in this case x will = 9.5 years now to plug this in. Y=(-12,000)*9.5+240,000 Y=114,000+240,000 Y= $126,000 2a. Answer: L=w-5 2a. Key work steps 2b. Answer: Width= 22.5 inches, Length is 17.5 inches 2b. Key work steps Since p=2L+2W and our equation L=W-5 then P=2(W-5)+2W P=2W-10+2W P=4W-10 We know that in this case P=80 inches so 80=4W-10 80+10=4W-10+10 90=4W 90/4=4W/4 22.5=W and since we know L= W-5 then L= (22.5)-5 L= 17.5 3a. Answer: C= $225+$10(x-2), C=(25x) 3a. Key work steps 3b. Answer:16.3 inches is needed 3b. Key work steps Our inequality for this problem is...
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