...alternative that best completes the statement or answers the question. 1) To an economist, ________ is anything that is generally accepted in payment for goods and services or in the repayment of debt. 1) _______ A) credit B) money C) wealth D) income 2) Money is 2) _______ A) a flow of earnings per unit of time. B) anything that is generally accepted in payment for goods and services or in the repayment of debt. C) always based on a precious metal like gold or silver. D) the total collection of pieces of property that are a store of value. 3) Currency includes 3) _______ A) paper money, coins, checks, and savings deposits. B) paper money and coins. C) paper money and checks. D) paper money, coins, and checks. 4) The total collection of pieces of property that serve to store value is a person's 4) _______ A) wealth. B) money. C) credit. D) income. 5) A person's house is part of her 5) _______ A) money. B) income. C) wealth. D) liabilities. 6) ________ is used to make purchases while ________ is the total collection of pieces of property that serve to store value. 6) _______ A) Money; wealth B) Income; money C) Money; income D) Wealth; income 7) ________ is a flow of earnings per unit of time. 7) _______ A) Money B) Income C) Wealth D) Currency 8) An individual's annual salary is her 8) _______ A) income. B) money. C) liabilities. D) wealth. 9) When we say that money is a stock variable, we mean that 9) _______ A) the quantity of money is measured at a given point in time...
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...Answer all questions: QUESTION 1 (20 Marks) (a) (i) continuous (a2) (ii) discrete (a2) (iii) continuous (a2) (b) (i) (m2, a1) (ii) arrange the data in ascending order 18, 18, 24, 27, 35, 36, 45, 47, 51, 61, 63, 81, 82, 87, 90 (a2) Median is 47 (a1) (iii) x | | (A) | x2 (B) | 24 | 27 | 729 | 576 | 47 | -4 | 16 | 2209 | 90 | 39 | 1521 | 8100 | 61 | 10 | 100 | 3721 | 51 | 0 | 0 | 2601 | 87 | 36 | 1296 | 7569 | 36 | -15 | 225 | 1296 | 35 | -16 | 256 | 1225 | 18 | -33 | 1089 | 324 | 81 | 30 | 900 | 6561 | 82 | 31 | 961 | 6724 | 18 | -33 | 1089 | 324 | 45 | -6 | 36 | 2025 | 63 | 12 | 144 | 3969 | 27 | -24 | 576 | 729 | 765 | - | 8938 | 47953 | (column A 2 marks, m1, a1 ) OR (column B 2 marks, m1, a1) (iv) range = 90 – 18 = 72 (a1) (v) (m2, a1) QUESTION 2 (15 Marks) (a) Index (Feb) = (m1, a1) Index (March) = (a1) Index (April) = (a1) Index (May) = (a1) (b) (i) Size | 2011 | 2012 | | | | | | Price P | Quantity | Price pn | Quantity | | | | | Large | 0.60 | 500 | 0.75 | 600 | 300 | 360 | 375 | 450 | Medium | 0.55 | 700 | 0.60 | 1000 | 385 | 550 | 420 | 600 | Small | 0.40 | 300 | 0.45 | 500 | 120 | 200 | 135 | 225 | | | | Total | 805 | 1110 | 930 | 1275 | (last 4 columns, 1 mark each) (a1) (a1) (ii) Size | Weighting | Po | Pn | Index Relative | Large | 25 | 0.60 | 0.75 | 125 | ...
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...is that A) money is a flow and income is a stock. B) money is a stock and income is a flow. C) there is no differencemoney and income are both stocks. D) there is no differencemoney and income are both flows. Answer: B 5) It is true that A) income and wealth are both stocks. B) money and income are both stocks. C) income is a flow and wealth is a stock. D) money and wealth are both flows. Answer: C 6) An individual's annual salary is her A) money. B) income. C) wealth. D) liabilities. Answer: B 7) A person's house is part of her A) money. B) income. C) liabilities. D) wealth. Answer: D 8) Money is A) anything that is generally accepted in payment for goods and services or in the repayment of debt. B) a flow of earnings per unit of time. C) the total collection of pieces of property that are a store of value. D) always based on a precious metal like gold or silver. Answer: A 9) Which of the following are true statements? A) Wealth is a stock variable. B) Money is a flow variable. C) Income is a stock variable. D) Wealth is a flow variable. Answer: A 10) ________ is used to...
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...Length Length | Name of unit | Symbol | Definition | Relation to SI units | angstrom | Å | ≡ 1×10−10 m | ≡ 0.1 nm | astronomical unit | AU | ≈ Distance from Earth to Sun | ≈ 149597871464 m [1] | barleycorn (H) | | = ⅓ in (see note above about rounding) | ≈ 8.46×10−3 m | bohr, atomic unit of length | a0 | ≡ Bohr radius of hydrogen | ≈ 5.2917720859×10−11 ± 3.6×10−20 m[2] | cable length (imperial) | | ≡ 608 ft | ≈ 185.3184 m | cable length (International) | | ≡ 1/10 nmi | ≡ 185.2 m | cable length (US) | | ≡ 720 ft | = 219.456 m | chain (Gunter's; Surveyor's) | ch | ≡ 66 ft(US) ≡ 4 rods [3] | ≈ 20.11684 m | cubit (H) | | ≡ Distance from fingers to elbow ≈ 18 in | ≈ 0.5 m | ell (H) | ell | ≡ 45 in [4] (In England usually) | = 1.143 m | fathom | fm | ≡ 6 ft [4] | = 1.8288 m | fermi | fm | ≡ 1×10−15 m[4] | ≡ 1×10−15 m | finger | | ≡ 7/8 in | = 0.022225 m | finger (cloth) | | ≡ 4½ in | = 0.1143 m | foot (Benoît) (H) | ft (Ben) | | ≈ 0.304799735 m | foot (Cape) (H) | | Legally defined as 1.033 English feet in 1859 | ≈ 0.314858 m | foot (Clarke's) (H) | ft (Cla) | | ≈ 0.3047972654 m | foot (Indian) (H) | ft Ind | | ≈ 0.304799514 m | foot (International) | ft | ≡ 1/3 yd ≡ 0.3048 m ≡ 12 inches | ≡ 0.3048 m | foot (Sear's) (H) | ft (Sear) | | ≈ 0.30479947 m | foot (US Survey) | ft (US) | ≡ 1200⁄3937 m [5] | ≈ 0.304800610 m | french; charriere | F | ≡ 1⁄3 mm | = 0.3 ×10−3 m | furlong | fur | ≡ 10 chains = 660 ft = 220 yd [4]...
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...Project Plan For NORSU Electronic Library Card Catalog System Researchers: Project Leader: Medura, Jess Linguaje, Ed Lorence Los Baños, Marilyn Maquiling, Marres Contents 1. Overview…………………………………………………………………………………………………………………………...3 2. Goals and scope………………………………………………………………………………………………………….….….4 2.1 Project Goals…………………………………………………………………………………………………………4 2.2Project Scope…………………………………………………………………………………………..……….……5 2.2.1 Included………………………………………………………………………………………………………….….5 2.2.2 Excluded .................................................................................................................5 3. Organization……………………………………………………………………………………………………………………….6 3.1 Organizational Boundaries and Interfaces…………………………………………………………….…...6 3.1.1 Resource Owners……………………………………………………………………………………………….6 3.1.2 Receivers…………………………………………………………………………………………………….……..6 3.1.3 Cross Functions…………………………………………………………………………………………………..7 3.2 Project Organization…………………………………………………………………………………………………..8 3.2.1 Project Manager…………………………………………………………………………………………….….8 3.2.2 Project Team……………………………………………………………………………………………………..9 4. Schedule and Budget…………………………………………………………………………………………………………10 4.1 Work Breakdown Structure…………………………………………………………………….…………...11 4.2 Schedule and Milestone………………………………………………………………………….……………12 4.3 Budget.......................................................................................................................13 4.4 Development Process…………………………………………………………………………………………...
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...Aim and purpose The aim of this unit is to introduce learners to recruitment and the importance of ensuring that the best people are selected to work in organisations. Learners will study selection and recruitment techniques and will set up, and take part in, a selection interview. Unit introduction Recruiting the right people is the key to the success of many organisations. These organisations ensure that the processes and procedures involved in recruitment and selection meet their needs and are legal. In this unit, learners will develop an understanding of the impact of the regulatory framework on the recruitment process. Potential applicants may decide to apply for a post based on the quality of information that they receive. Details of the post will usually be the first communication they have with the organisation. It is important that the organisation makes a good first impression on potential applicants to ensure that they attract sufficient applicants of the right calibre. Learners will develop their knowledge of the types of documentation used in an interview process. A structured and planned selection procedure is crucial to the success of the selection process. The impression a business makes may determine an applicant’s decision to accept an offer of appointment. Staff conducting the interview will also be forming their impressions of the applicant. It is important that interviewers are well organised and prepared. They will need to be familiar with the...
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...picked randomly from foreign, SOE, and local investment houses. The performance evaluation employs different methods namely Sharpe, Treynor, and Jensen indices. Analysis revealed that different methods yield different result. In order to enrich evaluation, Modigliani-risk adjusted performance metric and qualitative approach were included in the analysis. By using the mix criteria, it was found that the best investment is Schoder 90 Plus Equity Fund followed by Manulife Dana Saham and Mandiri Investa Dynamic Equity. This findings show that even though stock market performed negatively over the period, stock-based mutual fund may yield slightly better than the market. Key Words: Mutual Fund, Sharpe Index, Treynor Index, Jansen Index, M2. I. INTRODUCTION This paper aims at measuring portfolio performance of stock-based mutual funds from three different investment manager over the period of January 1, 2015 – July 30, 2015. Three randomly mutual fund was chosen, namely Schoder 90 Plus Equity Fund (Schroder Investment Management Indonesia), Mandiri Investa Dynamic Equity (Mandiri Manajemen Investasi), and Manulife Dana Saham (Manulife Aset Manajemen Indonesia). In the first step, all mutual funds data evaluated using Sharpe, Treynor, and Jensen indices. In the second step, other methods were introduced to test whether alternative evaluation give similar result. To conclude, all result from step one and step two evaluation would be presented in a radar or web chart...
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...CHAPTER 4 SI UNIT PROBLEMS SOLUTION MANUAL SONNTAG • BORGNAKKE • VAN WYLEN FUNDAMENTALS of Thermodynamics Sixth Edition Sonntag, Borgnakke and van Wylen CONTENT SUBSECTION Correspondence table Concept problems Force displacement work Boundary work: simple one-step process Polytropic process Boundary work: multistep process Other types of work and general concepts Rates of work Heat transfer rates Review problems English unit concept problems English unit problems PROB NO. 1-19 20-30 31-46 47-58 59-70 71-81 82-94 95-105 106-116 117-122 123-143 Sonntag, Borgnakke and van Wylen CHAPTER 4 6 ed. CORRESPONDANCE TABLE The new problem set relative to the problems in the fifth edition. New 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 5th 1 2mod new New New 3 4 new New new New New 18 27 new new 5 new New 13 new new New New New 22 45 mod 8 12 14 New New New New 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 5th new 19 20 33 mod 37 36 15 30 6 New 32 7 9 34 10 New New 26 39 New 40 New New New New 58 59 60 61 New New New New New 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 5th new new new 43 new New new new New 47 HT 48 HT 49 HT 50 HT mod 51 HT mod 52 HT 53 HT 54 HT 55 HT 56 HT 57 HT 31 mod 11 16 17 23 21 mod 28 29 24 44 35 th Sonntag, Borgnakke and van Wylen The English unit problem set is...
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...FACULTY OF BUSINESS AND MANAGEMENT MATHEMATICS FOR MANAGEMENT Question 1: A) 7 A + 10 B = 73 4 53 3 15 2 4 + 101 5 40 1 33 2 2 = 10 35 4221 21 735 14 28 + 10 50 400 10 3030 20 20 = 24 85 8221 31 3765 34 48 B) I. Matrix inverse method: 2x1 + 3x2 + 4x3 = 29 X1 + x2 + 2x3 = 13 3x1 + 2x2 + x3 = 16 1) Matrix form ,A: A =211 312 413121 122 223331 232 133 XX1 X2 X3 b291316 Ax = b ; x = A-1b A-1 =1A - A djoint A 2) Determine ( Row 2 as sample) A = (1) (-1)2+13421 + (1) (-1)2+2 2431 + 2(1)2+32332 = (-1) [(3)(1) – (4)(2)] + (1) [(2)(1)-(4)(3)] + (-2) [(2)(2)-(3)(3)] = (-1)(3-8) + (1)(2-12) + (-2)(4-9) = 5 – 10 + 10 A=5 3) Minor A A11 = 1221 = 1(1) – (2)(2) = 1 – 4 = -3 A12 = 1231 = 1(1) – (2)(3) = 1 – 6 = -5 A13 = 1232 = 1(1) – (1)(3) = 2 – 3 = -1 A21 = 3421 = 3(1) – (4)(2) = 3 – 8 = -5 A22 = 2431 = 2(1) – (4)(3) = 2 – 12 = -10 A23 = 2332 = 2(2) –(3)(3) = 4 – 9 = -5 A31 = 3412 = 3(2) – (4)(1) = 6 – 4 = 2 A33 = 2311 = 2(1) – (3)(1) = 2 – 3 = -1 Minor A = -3-5-1-5-10-520-1 4) Cofactor A = +-3--5+-1--5+-10--5+2-0+-1 = -35-15-10520-1 5) Ad-joint A = [Cofactor A] T = -35-15-10520-1T = -3525-100-15-1 6) Inverse A, A-1 A-1 = 1A – Ad-Joint A = 15-3525-100-15-1 = -3/512/51-20-1/55-1/5 7) Find X1...
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...Systems Glazing Painting Landscaping External Works Electrical Installation Air Conditioning Installation Fire Service Installation Low Voltage Cubicle Switchboards Installation Diesel Generating Sets Installation Uninterruptible Power Supply System Broadcast Reception Installation Compressed Air System Steam Boiler System Liquefied Petroleum Gas Installation Fuel Supply System Swimming Pool Water Treatment Installation MODBQ.1/1 MODBQ.2/1 MODBQ.3/1 MODBQ.4/1 MODBQ.5/1 MODBQ.6/1 MODBQ.7/1 MODBQ.8/1 MODBQ.9/1 MODBQ.10/1 MODBQ.11/1 MODBQ.12/1 MODBQ.13/1 MODBQ.14/1 MODBQ.15/1 MODBQ.16/1 MODBQ.17/1 MODBQ.18/1 MODBQ.19/1 MODBQ.20/1 MODBQ.21/1 MODBQ.22/1 MODBQ.23/1 MODBQ.24/1 MODBQ.25/1 MODBQ.26/1 MODBQ.27/1 MODBQ.28/1 MODBQ.29/1 MODBQ.30/1 MODBQ.31/1 MODBQ.32/1 6 22 3 8 4 18 7 12 10 7 3 23 8 22 30 19 5 10 7 19 27 55 30 9 5 4 10 6 10 9 7 14 Bill Nr. MODBQ.1 DEMOLITIONS AND ALTERATIONS DEMOLITIONS Demolishing or taking down to ground level Individual structures A * x * x * high to parapet ; * storeys ; reinforced concrete framed building ; as delineated on drawing nr. * ; shoring and scaffolding ( ACCD) * x * x * high to ridge ; * storeys ; steel framed building ; located at * ; materials remaining the property of Employer ; setting aside and storing materials on site ; shoring and...
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...Unit 2 Business Resources Student Name: | | Centre: | Leamington Spa | Course Title: | Extended Diploma in Business | Year of Course: | Year 1 | Unit Manager/Assessor: | Helen Morten | Internal Verifier: | L Cutter | Unit Title: | Milestone 3 Analysing Performance | Grading Criteria: UNIT 2 Business Resources | Evidenced inAssignment | P1 | Describe the recruitment documentation used in a selected organisation | Already covered in the recruitment project | P2 | Describe the main employability, personal and communication skills required when applying for a specific job role | Already covered in the recruitment project | P3 | Describe the main physical and technological resources required in the operation of a selected organisation | 1 | P4 | Describe the sources of internal and external finance for a selected business | 1 | P5 | Interpret the contents of a trading and profit and loss account and balance sheet for a selected company | 3 | P6 | Illustrate the use of budgets as a means of exercising financial control of a selected company | 2 | P7 | Illustrate the financial state of a given business | 3 | M1 | Explain how the management of human, physical and technological resources can improve the performance of a selected organisation | 1 | M2 | Assess the importance of employability and personal skills in the recruitment and retention of staff in a selected organisation | Already covered in the recruitment project | M3 | Interpret the contents...
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...ARTICLE IN PRESS Energy xxx (2009) 1–11 Contents lists available at ScienceDirect Energy journal homepage: www.elsevier.com/locate/energy Renewable energy in India: Status and potential Indu R. Pillai, Rangan Banerjee* Department of Energy Science and Engineering, Indian Institute of Technology Bombay, Powai, Mumbai 400076, India a r t i c l e i n f o Article history: Received 16 May 2007 Received in revised form 20 August 2008 Accepted 15 October 2008 Available online xxx Keywords: Renewable Energy Diffusion Potential India a b s t r a c t A majority of the Indian population does not have access to convenient energy services (LPG, electricity). Though India has made significant progress in renewable energy, the share of modern renewables in the energy mix is marginal. This paper reviews the status and potential of different renewables (except biomass) in India. This paper documents the trends in the growth of renewables in India and establishes diffusion model as a basis for setting targets. The diffusion model is fitted tot the past trends for wind, small hydro and solar water heating and is used to establish future targets. The economic viability and green house gas (GHG) saving potential is estimated for each option. Several renewables have high growth rates, for example wind, Photovoltaic (PV) module manufacture and solar water heaters. New technologies like Tidal, OTEC, Solar thermal power plants and geothermal power plants are at the demonstration stage and future dissemination...
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...CHAPTER 1 INTRODUCTION Even though modern technology has invested millions, even billions, into projection screen technology, high definition projectors, and even projectors for our cell phones, we have forgotten that we will always need something to project on. Unfortunately, with the tragic proliferation of advertising these days, we are probably looking at a future world where all the space on the buildings is taken for billboards and other various projected ads. The only place that would not be taken is the spaces that people walk through. However, that is an option that we can use, with the Heliodisplay or Fogscreen projector. [pic] Figure.1.1 Heliodisplay. Current technologies attempt to create the visual perception of a free-floating image through the manipulation of depth cues generated from two-dimensional data employing well-established techniques. A few examples of these include stereoscopic imaging via shutter or polarized glasses, as well as auto-stereoscopic technologies composed of lenticular screens directing light from a conventional display, or real-imaging devices utilizing concave mirror arrangements. All of these technologies suffer convergence and accommodation limitations. In order to resolve this visual limitation, the image and its perceived location must coincide spatially. A well-established method solving this constraint is by projection onto an invisible...
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...Assignment front Sheet |Qualification |Unit number and title | | | | |Business |10. Financial Accounting and Reporting | |Student name |Assessor name | | |Mehreen Bakht Haroon | |Date issued |Completion date |Submitted on | |15th July 2014 |15th August 2014 | | |Assignment Title |Financial statements interpretation and reporting | |Learning |Learning |Assessment |In this assessment you will have the opportunity to |Task |Evidence | |Outcome |Outcome |Criteria |present evidence that shows you are able to: |No. |(Page no.) | | ...
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...PHYSICS FORMULAS 2426 Electron = -1.602 19 × 10-19 C = 9.11 × 10-31 kg Proton = 1.602 19 × 10-19 C = 1.67 × 10-27 kg Neutron = 0 C = 1.67 × 10-27 kg 23 6.022 × 10 atoms in one atomic mass unit e is the elementary charge: 1.602 19 × 10-19 C Potential Energy, velocity of electron: PE = eV = ½ 2 mv 1V = 1J/C 1N/C = 1V/m 1J = 1 N·m = 1 C·V 1 amp = 6.21 × 1018 electrons/second = 1 Coulomb/second 1 hp = 0.756 kW 1 N = 1 T·A·m 1 Pa = 1 N/m2 Power = Joules/second = I2R = IV [watts W] Quadratic Kinetic Energy [J] − b ± b 2 − 4ac x= Equation: KE = 1 mv 2 2 2a [Natural Log: when eb = x, ln x = b ] n: 10-9 p: 10-12 m: 10-3 µ: 10-6 f: 10-15 a: 10-18 Rectangular Notation: Z = R ± jX where +j represents inductive reactance and -j represents capacitive reactance. For example, Z = 8 + j 6Ω means that a resistor of 8Ω is in series with an inductive reactance of 6Ω. Polar Notation: Z = M ∠θ, where M is the magnitude of the reactance and θ is the direction with respect to the horizontal (pure resistance) axis. For example, a resistor of 4Ω in series with a capacitor with a reactance of 3Ω would be expressed as 5 ∠-36.9° Ω. In the descriptions above, impedance is used as an example. Rectangular and Polar Notation can also be used to express amperage, voltage, and power. To convert from rectangular to polar notation: Given: X - jY (careful with the sign before the ”j”) Magnitude: Angle: Addition of Multiple Vectors: r r r r R = Ar+ B + C r Resultant = Sum of the vectors r r Rx...
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