...discussion, you will describe an operon. There are many examples listed in Chapter 14, but if you want to choose an operon not described in your book, please ask me for approval. Make sure you do not pick the same operon as your classmates; we want to expose ourselves to as many regulation proteins and bacteria as possible. In your initial discussion board post, please include the following: The Tryptophan(trp) Operon 1. Describe an operon, the regulatory proteins, the cellular process and the molecules being “sensed”. 2. Include details about the orientation of the genes and the promoter/operator sequences or activator binding site. 3. Provide details about the repressor/activator and inducer/inhibitor proteins. 4. Explain how the operon helps microbe survive and possibly thrive in its environment. 5. Include details about conditions that trigger expression of the gene(s). 6. Explain when this regulation occurs: During transcription, translation, or posttranslation An operon is the genetic regulatory system found in bacteria and their viruses where genes coding for functionally related protein are clustered along the DNA. This allows protein synthesis to be controlled coordinatly in response to the needs of the cell. The trp operon in E. coli us a negative control repressible system, the trp operon is negative control because the system produces a repressor which functions to turn off the operon. The trp operon is a repressor operon because repression occurs when...
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...by configuring clusters of genes together on the genome into operons that elicit a processive response in the presence of a specific metabolite. The Lac operon is responsible for the cleaving of the disaccharide lactose into two products. A myriad of components control the expression of the Lac operon when two conditions are met. First, the substrate, lactose, must be present. Second, no better substrate for example, glucose, is present (2). The three structural genes in the Lac operon are lacZ, lacY, and lacA. The gene lacZ encodes the tetramer, ß-galactosidase, which is responsible for hydrolyzing the ß-1,4 glycosidic linkage between galactose and glucose in lactose. The transport of lactose into the cell via the enzyme lactose permease is encoded by the gene lacY. The lacA gene encodes the enzyme, galactoside transacetylase, a trimer that transfers an acetyl group from acetyl-CoA to galactosides. Activation of these genes is dependent on the activity of a promoter and three operators based on the nutritional and environmental conditions available to the cell. The lac operon is a negatively controlled inducible operon that utilizes the product of the regulator gene lacI, to repress RNA polymerase from transcribing the lacZYA genes. The three operators involved in the lac operon: O1, O2, and O3 serve as binding sites for lacI and when bound repression is exhibited. Originally, the Jacob-Monod model of the Lac operon proposed only one operator existed. However, with the discovery...
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...At the transcriptional level, the gene expression of the lac operon is negatively controlled. In addition to lac operator O1, “pseudo-operators” O2 and O3 might play a role in the repression of the lac operon. Therefore, the purpose of the experiment was to address how each of these operators contribute to lac operon repression. It was hypothesized that DNA loop formation had the potential to mediate repression of O1, O2, and O3. The mutant lacI gene (i^adi), which is a stable and active, shortened Lac repressor protein, was used to investigate the stated hypothesis. Eight constructs, each with the lacZ gene under the native lac promoter and activated or inactivated O1, O2, and O3 in all possible combinations, were cloned in phage λIPI to yield phages λEwt123 and...
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...PYF12 3/21/05 8:04 PM Page 191 Chapter 12 Gene expression and regulation Bacterial genomes usually contain several thousand different genes. Some of the gene products are required by the cell under all growth conditions and are called housekeeping genes. These include the genes that encode such proteins as DNA polymerase, RNA polymerase, and DNA gyrase. Many other gene products are required under specific growth conditions. These include enzymes that synthesize amino acids, break down specific sugars, or respond to a specific environmental condition such as DNA damage. Housekeeping genes must be expressed at some level all of the time. Frequently, as the cell grows faster, more of the housekeeping gene products are needed. Even under very slow growth, some of each housekeeping gene product is made. The gene products required for specific growth conditions are not needed all of the time. These genes are frequently expressed at extremely low levels, or not expressed at all when they are not needed and yet made when they are needed. This chapter will examine gene regulation or how bacteria regulate the expression of their genes so that the genes that are being expressed meet the needs of the cell for a specific growth condition. Gene regulation can occur at three possible places in the production of an active gene product. First, the transcription of the gene can be regulated. This is known as transcriptional regulation. When the gene is transcribed and how much it is...
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...bacteria is the operon. Explain the function of an operon and why it is an evolutionarily advantageous for bacteria. 2 points. Operon is a unit made up of linked genes that is thought to regulate other genes responsible for protein synthesis. A Operon allows protein synthesis to be controlled in response to when the cell needs it. Energy is conserved due to the fact that it is in control of when protein is needed. A Operon is made up of a group of structural genes that codes for enzymes that are...
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...Problems from textbook 13.18 The streptomycin sensitive strain should be exposed to a mutagen (such as UV light or radiation) to create mutants that may be resistant to streptomycin. Next, prepare a plate that has streptomycin. The bacterial colonies that grow on this plate will all be resistant to streptomycin. Now, make a copy of these colonies using replica plating. Transfer the colonies to a plate that does not contain streptomycin. The colonies that grow on the plate without streptomycin are the strain that can live with or without streptomycin. The colonies that do not grow on the plate without streptomycin cannot live without streptomycin. 13.40 The original polypeptide strain and the double mutant differ in two amino acids. The Lys-Gly amino acids in the original polypeptide become Glu-Arg in the double mutant. The Lys-Gly amino acid sequence is: AAA-GGG By adding a G before the first A in the initial AAA sequence, and by deleting the final G, we get: GAA-AGG The resulting sequence codes for Lys-Arg. The entire nucleotide sequence in the double mutant is: 5’ – AUG CCC UUU GGG GAA AGG UUU CCC UAA—3’ 14.8 There are two genes. Gene 1: mutants 1,2,3,4,5,6,8 Gene 2: mutants 7 14.14 A cis-trans test can be performed to determine whether the two varieties are the results of mutations on the same gene, or on different genes. First, it is necessary to ensure that each white variety is true-breeding. Next, we need...
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...Choice Questions 1. Regarding the lac operon, if lactose is present, which of the following occurs? A) Lactose binds to the operator preventing the promoter from attracting RNA polymerase and preventing transcription. B) Lactose bind to RNA polymerase, which then binds to the promoter and transcribes the needed genes. C) Lactose binds to the repressor, which does not bind to the operator, and RNA polymerase transcribes the needed genes. D) Lactose binds to the operon, which attracts RNA polymerase, then transcription of the needed genes occurs. E) Lactose binds to the CAP site to prevent the CAP protein from binding Answer: C 2. Which of the following is likely to be expressed? A) euchromatin B) heterochromatin C) DNA without methyl groups D) DNA with many methyl groups E) euchromatin and DNA without methyl groups is more likely to be expressed Answer: E 3. Which of the following is a method of posttranscriptional control? A) transcription factors B) the life span of a mRNA molecule C) differential processing of mRNA D) how fast the mRNA leaves the nucleus E) both differential processing and how fast mRNA leaves the nucleus are involved in posttranscriptional control. Answer: E 4. Which gene in an operon is incorrectly matched with its function? ...
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...extracellular matrix. E) the position of cells within an embryo. Topic: Introduction Skill: Conceptual Understanding 3) The term gene expression refers to the A) fact that each individual of a species has a unique set of genes. B) fact that individuals of the same species have different phenotypes. C) process by which genetic information flows from genes to proteins. D) fact that certain genes are visible as dark stripes on a chromosome. E) flow of information from parent to offspring. Topic: 11.1 Skill: Conceptual Understanding 4) In a prokaryote, a group of genes with related functions, along with their associated control sequences, defines A) an allele. B) an operon. C) a locus. D) a transposon. E) a chromosome. Topic: 11.1 Skill: Factual Recall 5) The lac operon in E. coli A) prevents lactose-utilizing enzymes from being expressed when lactose is absent from the environment. B) coordinates the production of tryptophan-utilizing enzymes when it is present. C) allows...
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...promote or enhance gene activities. Control is exerted through chemical modifications that inactivate or activate specific gene regions or the histone proteins that organize the DNA. For instance, regions of newly replicated DNA can be shut down by methylation, the attachment of methyl group to nucleotide bases. 3. A. Repressor protein: protein that binds with an operator on bacterial DNA to block transcription. A special regulating protein formed in bacterial cells that halt transcription, which is the synthesis of messenger ribonucleic acid (m-RNA) from a specific operon (a group of genes that carry out the synthesis of functionally related enzymes). The number of different repressors corresponds to the number of operons. Activator protein: regulatory protein that enhances a cell activity (e.g., a radiolarian or heliozoan). For instance: CAP – this activator exerts positive control over the lactose operon by making a promoter more inviting the RNA polymerase. B. Promotor: base sequences that signal the start of a gene. Operator: a binding site for a...
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...Effects of Lactose on β-galactosidase Effect the Survival of Escherichia Coli Trina Duncan Introduction: Lac operon is a segment of DNA found in E. coli which is composed of two major DNA sequences: a promoter/operator sequence and structural genes (Kwiatkowski 2016). The promoter/operator sequence is basically the sequence of DNA that causes the process of transcription of the structural gene. Also when this sequence is ready to complete its job the structural genes will manufacture the β-galactosidase enzyme (KwiatkowskI 2016). ß-galactosidase converts lactose into glucose and galactose (Hampton). β-galactosidase was responsible for the breaking down of the disaccharide lactose into the two monosaccharides glucose and galactose (Kwiatkowski...
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...The objectives of the experiments performed in the past three weeks were to induce mutagenesis in the E.coli K-12 strain W3110 through short ultra violet light (UV). This particular strain of E.coli lacked photolyase (phr) and the uvr system, which are non-mutagenic repair mechanisms. A survival curve was constructed based off various irradiation times and number of viable cells obtained. Mutant strains were then isolated and purified on MacConkey (MAC) plates to rule out false positives. During week 7, the generation time of the potential Lac+ and lac- strands of E.coli were also determined. The lac operon was also induced via IPTG to determine if β-galactosidase induction is affected by mutations. During week 8, we determined if β-galactosidase...
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...1. Cells of all multicellular organisms arise during mitosis from a single cell known as a(n) A) gamete. B) zygote. C) embryo. D) clone. E) fetus. 2. Repressor proteins A) prevent binding of RNA polymerase to DNA. B) can be inactivated by an inducer (lactose). C) provide negative control D) prevent binding of RNA polymerase to DNA and can be inactivated by an inducer such as lactose. E) prevent binding of RNA polymerase to DNA. can be inactivated by an inducer such as lactose, and provide negative control. 3. During genetic modification, A) a prokaryote is changed into a eukaryote. B) a cell takes in DNA from another source. C) a cell’s own DNA is inserted into a plasmid. D) a cell is mutated. 4. What does the figure to the right show? A) gel electrophoresis B) DNA sequencing C) a restriction enzyme producing a DNA fragment D) polymerase chain reaction 5. Which of the following is the region that is the binding site for RNA polymerase? A) heterogeneous nuclear DNA B) repressor gene C) promoter sequence D) operator sequence E) all of these 6. Probes for cloned genes use A) complementary nucleotide sequences labeled with radioactive isotopes. B) certain media with specific antibodies. C) specific enzymes. D) certain bacteria sensitive to the genes. E) all of these 7. When a gene transcription occurs, which of the following is produced? A) more DNA B) protein or polypeptide sequences C) messenger RNA ...
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...ligase do during replication of DNA? a. Makes copies of mRNA from DNA b. Removes damaged sections of DNA c. Joins together mRNA d. Joins together DNA segments e. Digests mRNA when it is no longer needed 4. Which is mismatched? a. Replication = formation of 2 identical DNA molecules b. Transcription = mRNA synthesized from a DNA template c. Translation = tRNA transfers amino acids to the ribosomes based on mRNA codons d. Nonsense codons = terminator codons e. Anticodon = sequence of 3 nitrogenous bases on the gene 5. A red pigment produced by a bacterial species is an example of a(n)? a. Phenotype b. Genotype c. Operon d. Promoter e. Inducible enzyme 6. Which of the following best describes a plasmid? a. A gene within the chromosome b. Small circular piece of DNA outside the chromosome c. The genetic material of a bacteriophage d. Part of bacterial ribosomes e. A single, linear strand of DNA 7. Which of the following is NOT involved in bacterial conjugation? a. Bacteriophage b. F+ cells c. F- cells d. Plasmids e. Sex pili...
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...1-Shpjegoni se si çeshtja me te cilen perballet Elektrolux eshte strategjike. Çeshtja me te cilen perballet Elektrolux eshte strategjike sepse ato kane karakteristikat e meposhteme: Kane te bejne me fushen e aktivitetit te organizates- Ne fillim te viteve 20 kompania ishte e fokusuar ne prodhimin e frigorifereve dhe fshesave me korent. Ne 1950 kompania nisi prodhimin e makinave larese dhe lavapjatave. Ne vitet 90 kompania ishte e perfshire ne aktivitete ne industri te ndryshme. Perputh aktivitetet e organizates me mjedisin ku ajo operon – Fillimisht aktiviteti i kompanise ishte i perqendruar ne Suedi, por mne vitet 20 kompania zgjeroi aktivitetin e saj ne Gjermani, Angli, France, SHBA dhe Australi. Ne vitet 90 ajo u fut ne tregjet e Europes Lindore dhe Amerikes Latine. Mjedisi ne te cilen operon kompania ndryshon nga nje vend ne tjeterin, ndaj dhe stategjia e saj eshte e tille qe ti pershtatet ketij ndryshimi. Perputh aktivitet e organizates me burimet disponibel – Padyshim qe ishte pikerisht shfrytezimi i burimeve te saj ne teknologji, operacione, dhe njerez te kualifikuar te cilat ben qe kompania te prodhonte te gjithe gamen e produkteve elektroshtepiake, madje ajo fale shfrytezimin ne menyre efektive te burimeve te saj arriti qe te siguroj produkte jo vetem per konsumatoret final, por edhe per prodhues te tjere. Marrjen e vendimeve nga menaxhimi i larte- Gjate gjithe jetegjatesise se saj, kompania eshte drejtuar nga menaxherre te cilet kishin vizion te qarte per kompanine...
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...MCDB1A Lecture Schedule, Fall 2013 Part 1: Introduction to Biochemistry and Molecular Biology Dr. Stuart Feinstein Email: stu.feinstein@lifesci.ucsb.edu Office: Bio II, Rm. 5123; Office Hours: T and F after Lecture, in front of Campbell Hall and by appointment (after Oct. 22, T at 9 AM in Bio II, Rm. 5123). Approximate Lecture Schedule for Biochemistry/Molecular Biology Date | TOPIC | Reading in Text*[chapter (pages)] | | | | 9/27 | Introduction to class and Biochemical Principles | 1 (1-20); 2 (21-37) | | | | 9/30 | Introduction to Macromolecules/ Lipids and Polysaccharides | 3 (39-42; 51-61);6 (105-109) | | | | 10/1 | Macromolecules: Polysaccharides and Proteins | 3 (42-51) | | | | 10/2 | Macromolecules: Proteins and Nucleic Acids | 4 (62-67);13 (259-280) | | | | 10/4 | Macromolecules: Nucleic acids as Genetic Material | 13 (259-280) | | | | 10/7 | The Central Dogma: DNA Replication | 13 (259-280) | | | | 10/8 | The Central Dogma: Transcription and Translation | 14 (281-303) | | | | 10/9 | The Central Dogma: Translation and Mutations | 14 (281-303)15 (304-308) | 10/10 | First Honors Meeting | | 10/11 | The Central Dogma: Post-Translational Modifications, Alternative RNA Splicing and MicroRNAs | 14 (300-304;312-313) 16 (346-349) | | | | 10/14 | Energy, Enzymes and Metabolism | 8 (144-164) | | | | 10/15 | Chemical Pathways that Harvest Chemical Energy | 9 (165-184)...
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