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Sailboat Stability

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Submitted By verdie1991
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Real World Radical Formulas
Virginia Gates
MAT 222 Intermediate Algebra
Instructor: Chander Sekar
April 20, 2014

Real World Radical Formulas We are asked to discussion radical expressions and how why can be used to solve more complex equations when some of the exponents are known. We can manipulate the formula and by doing that we can solve those radicals and show how each equation is solved just by following the rules. With this we must remember our problems and variables may change but the rules don’t. So now we are going to see what we can do with the problem below:
Sailboat stability. To be considered safe for ocean sailing, the capsize screening value C should be less than 2 (www.sailing.com). For a boat with a beam (or width) b in feet and displacement d in pounds, C is determined by the function

a) | Find the capsize screening value for the Tartan 4100, which has a displacement of 23,245 pounds and a beam of 13.5 feet. | b) | Solve this formula for d.c) The accompanying graph shows C in terms of d for the Tartan 4100 (b = 13.5). For what displacement is the Tartan 4100 safe for ocean sailing? |
Now are going to look the problem 103 page 605 in our text material. It states for a sailboat to be considered safe for ocean sailing, the capsize screening valve of C should be less than 2. Also it is stated the boat with the beam which is width and our variable b in feet and displacement d in pounds. So we are going to solve for C, d in the formula and that is:
C=4d^-1/3b
Going to solve for c now. Giving the formula we will plug the values and the exponents are first.
C=4(23245)^-1/3(13.5) we will plug the values in for the variables. The exponents are first:
C=4(.035)(13.5) when solving d with the exponents first, we have to multiply next:
C=.14(13.5) now if we solve 4 with d for .14
C= 1.89
This is our resulting capsize screening value.

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