...Energy, Work and power of the body All body activities including thinking, doing work, or keeping the body temp. constant involve energy changes, for example under resting(Basal)conditions the skeletal muscles and the heart using 25% of the body's energy ,another 19%is being used by the brain,10%is being used by the kidneys, and 27% is being used by the liver and the spleen. A small percent of about 5% of food energy being excreted in feces and urine. Extra food energy will be stored mainly as fat. External heat energy from environment can help maintain the body temp. , but it has no use in body function. Conservation of energy Change in the stored energy (i.e. food energy, body fat and the body heat) =Heat lost from the body + Work done Assumes that no food or drink is taken and no feces or urine is excreted during the interval of time considered. ●This is similar to the first law of thermodynamic:- ∆Q= ∆u + ∆w -1- ●Where ∆Q is the change of quantity of heat of the system. ● ● ∆u is the change in the internal or stored energy. ∆w is the work done. This can be written as ∆u= ∆Q - ∆w A body doing no work (∆w=0) and at constant temp. continues to lose heat to its surroundings, and ∆Q is negative. Therefore, ∆u is also negative, indicating a decrease in stored energy. The rate of change of their variables is just taken per unit time ( by dividing on ∆t) . ∆u / ∆t = ∆Q/∆t - ∆w/∆t The body's basic source of energy is the food energy; it must be chemically changed...
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...This front sheet must be completed by the learner where appropriate and included with the work submitted for assessment. Unit: 1 Fundamentals of Science Course: Extended Diploma in Applied Science (Forensic and Medical Science) (15VF0270) |Learner Name (Please enter your name): | | |Assessor Name: Claire Watkins |Issue Date: |End Date: | | | | | | |Group 1: 5.10.15 |Group 1:19.10.15 | | |Group 2: 6.10.15 |Group 2: 20.10.15 | |Assignment Title: Scientific Reports and Communication |Assignment Ref (if used): 1.3 | |Assessment Criteria |Achieved |Evidence Location |Comments/feedback from assessor | |P7 – Carry out a practical investigation into the |Yes/No |Scientific Report | ...
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...employers are laying off full-time workers, many are also trying to compensate by turning over some of the work to temp staff. Ironi cally, of course, many of those who've been laid off are highly qualified, and as they hit the job market willing to accept lower-level positions, the ranks of job hunters are being joined by a substantial number of highly qualified (which is to say, overqualified) workers. “The quality of candidates,” says Laura Long of Banner Personnel, a Chicago-area staffing agency, “is tremendous…. As an employer, you can get great employees for a great price.” As a matter of fact, if you're a U.S. employer, you've always been able to get temp workers at a relatively good price. As of December 2010, according to the BLS, the average cost of a full-time worker in private industry was $22.26 per hour in wages plus $9.75 in benefits, for a total of $32.01 in compensation. By contrast, the average wages for a temp were $12.14 and the average benefits were $3.42, for total compensation of $15.56. One of the results of this cost differential has been a long-term increase in the number of temp workers which, over the last 20 years, has far outstripped the increase in jobs occupied by full-time workers. Case Questions 1. You're a senior manager at a growing business and you're ready to add employees. Your HR manager has recommended a temp-to-perm policy. You know the advantages of this approach, but what might be some of the disadvantages? 2. Assume...
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...calorimeter (mL) | 20.0 mL | 20.0 mL | 1 | Time (s) | 0 | 30 | 60 | 90 | 120 | 150 | 180 | 210 | 240 | 270 | 300 | 330 | 360 | 390 | 420 | 1 | Temp(°C) | 26.1 | 26.2 | 26.3 | 26.3 | 26.2 | 26.2 | 26.2 | 26.9 | 27.1 | 27.4 | 27.2 | 27.2 | 27.1 | 27.1 | 27.1 | | | | | | | | | | | | | | | | | | 2 | Time (s) | 0 | 30 | 60 | 90 | 120 | 150 | 180 | 210 | 240 | 270 | 300 | 330 | 360 | 390 | 420 | 2 | Temp(°C) | 24.0 | 24.1 | 24.2 | 24.2 | 24.2 | 24.2 | 24.2 | 28.0 | 27.9 | 27.8 | 27.7 | 27.7 | 27.7 | 27.6 | 27.6 | Change in temperature of the water (°C) | 1.0°C | 3.6°C | Energy gained by the water (J) | 81.552J | 293.59J | Change in temperature of the metal (°C) | -72.9°C | -72.4°C | Calculated specific heat capacity (J/g°C) | 0.0958 J/g°C | 0.335 J/g°C | Molar mass approximation (g/mol) | 261.02g/mol | 74.73g/mol | Percent error of specific heat capacity (%) | 75.1% | 13.0% | Percent error of molar mass (%) | -310.76% | -17.60% | Enthalpy of Neutralization (Nitric Acid) | Trial 1 | Trial 2 | Volume of acid (mL) | 50.0 mL | 50.0 mL | Concentration of acid (M) | 1.1 M | 1.1 M | Volume of NaOH (mL) | 50.0 mL | 50.0 mL | Concentration of NaOH (M) | 1.0 M | 1.0 M | 1 | Time(s) | 0 | 30 | 60 | 90 | 120 | 150 | 180 | 200 | 220 | 240 | 260 | 280 | 300 | 320 | 340 | 360 | 380 | 400 | 420 | 1 | Temp(°C) | 23.5 | 23.4 | 23.4 | 23.4 | 23.4 | 23.4 | 23.5 | 30.5 | 30.4 | 30.4 | 30.4 | 30.4 | 30.3 | 30.3 | 30.2 | 30.2 | 30.1 | 30.1 | 30.0 | ...
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...wiL1084x_fm_i-xxiv_1.indd Page i 1/10/11 7:53:00 PM user-f499 /Users/user-f499/Desktop/Temp Work/Don't Delete Job/MHBR231:Wild:203 Managerial Accounting John J. Wild University of Wisconsin at Madison Ken W. Shaw University of Missouri at Columbia 3 rd edition wiL1084x_fm_i-xxiv_1.indd Page ii 1/10/11 9:14:31 PM user-f499 /Users/user-f499/Desktop/Temp Work/Don't Delete Job/MHBR231:Wild:203 To my students and family, especially Kimberly, Jonathan, Stephanie, and Trevor. To my wife Linda and children, Erin, Emily, and Jacob. MANAGERIAL ACCOUNTING Published by McGraw-Hill/Irwin, a business unit of The McGraw-Hill Companies, Inc., 1221 Avenue of the Americas, New York, NY, 10020. Copyright 2012, 2010, 2007 by The McGraw-Hill Companies, Inc. All rights reserved. No part of this publication may be reproduced or distributed in any form or by any means, or stored in a database or retrieval system, without the prior written consent of The McGraw-Hill Companies, Inc., including, but not limited to, in any network or other electronic storage or transmission, or broadcast for distance learning. Some ancillaries, including electronic and print components, may not be available to customers outside the United States. This book is printed on acid-free paper. 1 2 3 4 5 6 7 8 9 0 DOW/DOW 1 0 9 8 7 6 5 4 3 2 1 ISBN 978-0-07-811084-9 MHID 0-07-811084-X Vice president and editor-in-chief: Brent Gordon Editorial director: Stewart Mattson Publisher: Tim...
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...P-acid with 85% concentration, 0.1-0.2% oil weight.Start up neutral pot, make main shalf stirring at 60-70 r/min, finish de-gumming in 30 min. (2)alkali de-acid operation of cotton Cottonseed Oil Refining Machine After finish de-gumming process, at once add into lye carrying alkali refini- ng de-acid, lye concentration 16 ° Be ′, super alkali is 0.1-0.3% oil weight, afterfinish adding, continuous stirring 30min, when soap particles accumulated condensing, should reduce stirring speed, 30r/min avoid emulsion. After adding alkali, gradually rising temp to the end temp 65 ° C, see to th- at the rising temp speed should control at 1 degree per minute, not too fast. Shut off neutral pot drive part, the oil settled in the pot 6-8 hours, make oil separate from soap. (3)Water rinse operation of cottonseed oil refining machine Adjust the neutral pot oil temp to about 85 ° C, add into hot water whose temp higher oil temp 10-15° C, the water use amount each time is 10-15% oil weight.Start neutral pot drive part, make the main shalf stirring washing at 30r/m-in, make the oil and water fully contact, stirring time 5-10 min.If oil/soap separate not...
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...STARTING PROCEDURE FOR 45 MW STEAM TURBINE UTRAN CCPP 1. ESTABLISH ACW SYSTEM 2. RUN ONE COOLING WATER PUMP AND ESTABLISH THE SYSTEM 3. RUN THE OIL PUMPS OF STEAM TURBINE 4HRS. BEFORE STARTING THE UNIT AND CHECK FOR ANY OIL LEAKAGES AND ATTEND ACCORDINGLY. 4. RUN ONE OIL VAPOUR EXHAUSTER FAN. STA 5. CHECK THE INTERLOCK AND PROTECTIONS IN OIL SYSTEM IF THE UNIT WAS UNDER LONG S/D. 6. PUT THE MACHINE ON BARRING GEAR AT LEAST 4 HRS. BEFORE STARTING THE UNIT AND OBSERVE FOR ANY RUBBING NOISE S. OBSERVE TURBOVISORY READINGS IN CONTROL ROOM. SWITCH ON SGC OIL SUPPLY. 7. DRAIN WATER IN THE DEARETOR AND MAKE UP LEVEL WITH FRESH DM WATER. OBTAIN CHEMIST’S CLEARANCE. 8. CHECK THE OIL LEVEL IN BFP LUB OIL TANK AND MAKE UP IF REQUIRED. 9. RUN OIL PUMP OF THE BFP AND CHECK FOR ANY LEAKAGES AND ATTAND THE SAME IF ANY CHECK THAT OIL IS COMING OUT IN THE DRAIN LINE AS VIEWED FROM THE SIDE GLASS, PROVIDED IN THE DRAIN LINE. 10. CLEAN THE STRAINERS IN THE BFP SUCTION LINE IF DP WAS GREATER THAN 0.5 KG/SQCM BEFORE STARTING THE HP AND LP BFPs. 11. CHECK INTERLOCK AND PROTECTIONS OF BOILER FEED PUMPS IF IT WAS LONG S/D. CHECK SEQUENCE OPERATION. 12. CHARGE ALL BFPs BY OPENING THE SUCTION VALVE VENT UP TO THE DISCHARGE VALVE. 13. CHARGE THE SEALING AND COOLING WATER TO THE BFP GLANDS. ENSURE WATER IN THE RETURN LINE BY VIEWING THRU THE SIGHT GLASS. 14. START BOILER FEED PUMPS AND MAKE UP DRUM LEVEL BOTH HP AND LP DRUM LEVEL. 15. MONITOR THE...
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...Tray* 2 Put cookies in Oven, Set Timer & Temp. 1 Baking* 9 Remove cookies and cool 5 Bag cookies* 2 Accept payment 1 Total 26 * Per dozen cookies 2. How many orders can you fill in a night, assuming you are open four hours each night? If we use the capacity of the mixing bowl, which is 3 dozen cookies per cycle, we get a different time. Action Needed Time in min Clean Bowl, Add ingredients, and Mix 6 Same for 3 dozen: 6 Dish Cookies onto Tray 2 2x3=6 Put cookies in Oven, Set Timer & Temp. 1 1x3=3 Baking 9 9x3=27 Remove cookies and cool 5 Same for 3 dozen: 5 Bag cookies 2 2x3=6 Accept payment 1 Same for 3 dozen: 1 Total 54 If we produce 3 dozen cookies every 54 minutes, we will complete 240/54= 4,44 cycles which is equivalent to 13,33 dozen cookies. Because there is no half cycle we need to round down. We can produce 4 cycles which is equivalent to 12 dozen cookies in 4 hours. 3. How much of your own and your roommate's valuable time will it take to fill each order? Time used by me: Action Needed Time in min Clean Bowl, Add ingredients, and Mix 6 Dish Cookies onto Tray 2 Total 8 Time used by my roommate: Action Needed Time in min Put cookies in Oven, Set Timer & Temp. 1 Bag cookies* 2 Accept payment 1 ...
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...the heat absorbed (per mole of specified reactant or product) when the reaction occurs at constant pressure (chemistry textbook). By ‘change in enthalpy’ it means the increase in enthalpy going from reactants to products. The heat released is a direct measure of ΔH. ΔH is sometimes referred to as the heat of reaction. The enthalpy change for a reaction, ΔH, will be the energy required to break the necessary bonds in reactant molecules minus the energy released when the new bonds are formed. ΔH= energy to break (bonds in reactants) – energy to make (bonds in products). To calculate the heat released or absorbed the formula generally used is the q = m CΔ T (refer to appendix B for the general procedure). This formula is also used when calculating quantities of heat. The symbol (q) is to denote the quantity of heat (J) measured in joules. The amount of heat energy is different to temperature; for example, two objects can be at the same temperature but contain very different amounts of heat. This is because the amount of heat energy is proportional to the mass of the substance involved and also the amount of heat energy contained in equal masses of different substances depends upon the nature of the substances involved. Which then leads to (C) ‘specific heat capacity’, of a substance is the amount of heat required to raise the temperature of unit mass of the substance by 1ᴼC (or through 1 kelvin). Specific heat capacity is therefore measured in joules per kelvin per gram, J K–1 g–1...
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...NIAGARA COUNTY COMMUNITY COLLEGE THEORETICAL CARE PLAN DATE: NUR STUDENT NAME: MEDICAL DIAGNOSIS: Acute Abdominal Pain SURGICAL PROCEDURE & DATE: Hartman Procedure PATIENT'S INITIALS: AGE: 57/M ROOM #: ERICKSON'S DEVELOPMENTAL STAGE: VII generativity vs stagnation |A. Brief Description of Pathophysiology Including Signs & Symptoms: Hartman procedure-The Hartman procedure was developed by Dr. Henry Albert Hartmann in 1921 and involves the surgical resection of the | |rectosigmoid colon, closure of the rectum, and creation of a colostomy. It was initially created to improve the mortality rate of patients who had colonic adenocarcinomas but is now indicated for | |several pathologies including complicated and severe diverticulitis, rectosigmoid cancer, and in cases where a colon resection is needed but a primary anastomosis cannot be safely done. There are few | |contraindications to the procedure and is often the procedure of choice when other complicated procedures cannot be performed. Patients with hypotension, renal failure, diabetes, malnutrition, immune | |compromise, and ascites can have unfavorable performance...
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...6,Finland),(9.6,New Zealand),(9.5,Denmark) d. The relation in part (c) is a not a function because 9.6 corresponds to both Finland and New Zealand. Section 8.2 47. a. f(x)=.013(80)+56.46=57.50 F(80) represents (80,57.5) on the graph. This states that in 1980, the average temp. was 57.50 degrees. b. The graph shows 57.50 as the average temp. in 1980 which is overestimated by .10 degrees as the average temp in 1980 was actually 57.40 degrees. 49. a. f(x) = 1.27(50)+305=368.5 (50,367.5) f50 on the graph represents the average atmospheric concentration of carbon dioxide in parts per million as 368.5 in the year 2000. b. g(x)=.01(50)^2+.65(50)+310=367.50 parts per million was the average carbon dioxide concentration in 2000. c. The quadratic function 51. f(x)=.4(20)^2-36(20)+1000 (20,440) .4(400)-720+1000 160-720+1000 There are 440 accidents per 50 miles for 20 year old drivers. 53. (45,190) The value of x is 45 and the value of y is 190 when the graph is at its lowest point. .4(45)^2-36(45)+1000 .4(2025)-1620+1000 810-1620+1000=190 The minimum number of accidents occurs with 45 year old drivers at 190 accidents per 50 million miles driven. 55. f3 on this graph is (3,.78). This represents that it will cost $0.78 to mail a first class letter weighing 3 ounces. 57. It will cost $0.61 to mail a first class letter...
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...Valuation :: MINI CASE------------ C) Assume that temp force has a beta coefficient of 1.2, that the risk-free rate (the yield on T-bonds) is 7 percent, and that the market risk premium is 5 percent. What is the required rate of return on the firm’s stock? Using SML to calculate temp force’s required rate of return: rs = rRF + (rM – rRF)bTemp Force = 7% + (12% - 7%)(1.2) = 7% + (5%)(1.2) = 7% + 6% = 13%. D) Assume that Temp Force is a constant growth company whose last dividend (D0, which was paid yesterday) was $2.00, and whose dividend is expected to grow indefinitely at a 6 percent rate ? 1) What is the firm’s expected dividend stream over the next 3 years? Temp Force is a constant growth stock, and its dividend is expected to grow at a constant rate of 6 percent per year. Expressed as a time line, we have the following setup. 1 + g = 1.06 To get D1, D2, and D3: rs = 13% 0 1 2 3 4 g = 6% | | | | | D0 = 2.00 2.12 2.247 2.382 1.88 1.76 1.65 . . . 2) What is the firm’s current stock price? We could extend the time line on out forever, find the value of Temp Force’s dividends for every year on out into the...
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...ASSIGNMENT 1 For this assignment, you will write programs based on operators, selection statements, repetition statements and arrays. Instructions • There are 04 questions in this assignment. • Assignment submitted after due date will not be evaluated. • Upload a pdf version of the document on BlackBoard. • Do not submit the assignment via e-mail. • Write your answer after each question in this document. • Name the document as A1_ICP2015_John_Doe.pdf in case your name is John Doe. [You are required to strictly follow the naming convention.] • Materials copied from the Internet or otherwise will attract penalty as per course policy. Due Date: 5:00 pm, March 22, 2014. Grading Criteria Correct answers will be awarded full points. This assignment...
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...The national economy is sluggish and for businesses to continue moving forward it is imperative that they continue producing at an acceptable rate without incurring many additional costs. One of the chief components to success in this venture is employee attendance. The employee absenteeism can cost the company funds from an already tight budget by way of lost manpower, or hiring temps. Temps generally are not going to be as fast as the employee because they have not been acclimated to the system at the company and if a temp is not brought in the missing employee slows the work schedule regardless of the position the employee holds. The arguments about what causes employee absenteeism abound worldwide but the bottom line still equals dollars and cents. Recently there have been movements to create an atmosphere from which employees do not want to stay home from. Caregiver centers for children, buy back programs for sick days and many other avenues are being tried. Until businesses can determine the cause of absenteeism that is not illness related and find solutions they will continue to lose money. At the end of the last decade the employee absenteeism rate was lower than it had been in a decade. Many believe that family leave issues and personal leave problems had been dealt with in a successful manner and the problem was solved(Employee, 1997). Since that time however absences in the workplace have continued to plague business around the world including in the United States...
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...performance are summed up. Table no. 10.8 shows the total average response & the level of three parameter on Etch factor . The result shows that the optimum etching performance for the Etch factor is obtain at temp. of 600c, Conc. of 700 gm/lit, Time of 8min. This is the optimum setting obtained under the condition in which the experiments were performed. The Etch factor decreases with increase Concentration. The result of ANOVA for the Etch factor is presented in table 10.9. According to F-test, the 95% confidence...
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