...Andrew Yard Case Study Analysis 1 Running Head: Andrew Yard Case Study Analysis The Andrew Yard Case Study Analysis (A-C) Harvard Business School Publication 9-911-028,029,030 MBA 612: Leadership I Northwood University DeVos Graduate School September 2014 Dr. Tara Peters Running Head: Andrew Yard Case Study Analysis 2 The Andrew Yard circumstance portrays a remuneration settlement from a worldwide HR executive, Joseph Rogers, alongside a hopeful, Andrew Yard, for a high-level executive position. He is highly qualified and experienced professional in retailing home goods and electronics. The negotiated 600K salary plus 75% bonus, and other benefits such as health insurance, a car allowance, stock options and housing were appealing but also too came with a price. Problem Statement: The problem becomes awkward once Andrew feels offended by Joseph while he is offered a monetary motivator to join the association more quickly than at first arranged. Hypothesis/Analysis: The Business Development team identified growth potential in retail business but the retail business was declining due to the absence of a good leader. Hypothesis 1: Ayoub Companies was missing out on growth opportunities in retail business. The COO was acting as an interim leader and he was under much burden. As an example in the Harvard Business case study states, his recent emails to the team showed that the retail business was a critical juncture: “We’re putting fires out daily...
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...Case 1: Insulting Andrew i) Summary This situation describes a compensation settlement from a global HR director along with a candidate for any high-level executive position. The problem becomes awkward once the candidate feels insulted while he is offered a financial incentive to participate the organization more rapidly than initially planned. The situation offers an chance to evaluate settlement strategy and the significance of emotional intelligence and efficient social communication throughout a settlement. ii) Chronology iii) Key issues * Problems occurred in adopting top talent internationally * Defective solutions to attract top talent * Bad communication lead to the feeling of insulting iv) Case discussion questions 1) Motivating top talent to work in difficult international assignments is a major challenge for top international managers. What might be more important than money to make this work? Select the right people for the assignment. Selections for international assignments must be made for the right reasons and the location is desirable and the employee wants to go. We should assess whether candidates and their family members are a good fit for the post. We need to consider candidates’ job-related competencies, personality traits and family circumstances. Help the employee and family prepare before departure. Proper preparation can make the difference in the employee’s and the family’s adjustment to the host country and the ultimate success...
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...Score: ______ / ______ Name: ______________________________ Student Number: ______________________ | 1. Elsie is making a quilt using quilt blocks like the one in the diagram. a. How many lines of symmetry are there? Type your answer below. b. Does the quilt square have rotational symmetry? If so, what is the angle of rotation? Type your answers below. | | 2. Solve by simulating the problem. You have a 5-question multiple-choice test. Each question has four choices. You don’t know any of the answers. What is the experimental probability that you will guess exactly three out of five questions correctly? Type your answer below using complete sentences. | | 3. Use the diagram below to answer the following questions. Type your answers below each question. a. Name three points.b. Name four different segments.c. Write two other names for FG.d. Name three different rays. | | 4. Charlie is at a small airfield watching for the approach of a small plane with engine trouble. He sees the plane at an angle of elevation of 32. At the same time, the pilot radios Charlie and reports the plane’s altitude is 1,700 feet. Charlie’s eyes are 5.2 feet from the ground. Draw a sketch of this situation (you do not need to submit the sketch). Find the ground distance from Charlie to the plane. Type your answer below. Explain your work. | | _____ 5. Jason and Kyle both choose a number from 1 to 10 at random. What is the probability that both numbers are odd? Type...
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...1) The minimum and maximum number of items that he can purchase is Given: C=3x+5 X= (c-5)/3 Min: X= (50-5)/3 X=15 items minimum Max: x = (80 - 5)/3 x = 25 items maximum 2) Find the maximum horizontal distance that the projectile may cover. Using the quadratic formula Maximum distance of projectile 3) The maximum height of the arrow is: feet Answer is 629 Feet 4) Find the number of customers that arrived in the 6th hour. f(6) = 2^7 = 128 ______________ _______________ _______________ 64 customers arrived in the 6th hr. 5) If the net profit is 3800000, find the number of items sold. P(x) =x^2-4000x + 7800000 3800000=x^2-4000x + 7800000 X^2-4000x+4000000=0 (x-2000) ^2=0 x=2000 P (2000) =3800000 Number of items sold=2000 6) Find its value after 3 years f(x) = 20000(1/2)^x 20,000(.5)^3 20,000*.125=2,500 ans. The value of the Machine after 3 years is $2,500.00 7) Find the maximum height that the object may reach. f(x)=-x2+3x+6 use -b/2a -3/2(-1)=-3/-2=3/2 x=3/2 f(3/2)=-(3/2)2+(3)(3/2)+6 f(3/2)=-(9/4)+(9/2)+6 f(3/2)=-(9/4)+(18/4)+6 f(3/2)=(9/4)+6 f(3/2)=(2 1/4)+6 f(3/2)=8 1/4 meters or 8.25 meters 8) The sum of two numbers is 210. If one number is the square of the other, find the set of numbers. x +y = 210 y = x^2 substitute for y in first equation x^2 +x -210 = 0 factor equation (x+15)*(x-14) = 0 x = -15 or 14 y = 225 or 196 solution1...
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...A Test (How your brain work?) 1. You heard an indistinct “meow”. Without looking around, how well can you place the cat? a) If you think about it, you can point it. b) You can point straight to it. c) You don’t know, if you can point to it. 2. How good are you at remembering a song you’ve just heard? a) You find it easy, and you can sing a part of it. b) You can do it only if it’s simple and rhythmical. c) You find it difficult. 3. A person you’ve met a few times telephones you. How easy is it for you to recognize that voice in the few seconds before the person identifies himself? a) You find it easy. b) You recognize the voice at least half the time. c) You recognize the voice less than half the time. 4. You’re with a group of married friends. Two of them are having an affair. Would you detect this? a) Nearly always. b) Half the time. c) Seldom. 5. You’re introduced to five strangers at a large social gathering. If their names are mentioned the following day. How easy is it for you to picture their faces? a) You remember most of them. b) You remember a few of them. c) You seldom remember any of them. 6. In your early school days, how easy was spelling and the writing of them? a) Both were quite easy. b) One was easy. c) Neither was easy. 7. You spot a parking place, but you must reverse into it and it’s going to be a fairly tight squeeze: a) You look for another space. b) You back into it-carefully. c) You reverse...
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...How to Make a Tie-Blanket Supplies Needed: one pair of fabric scissors two yards of fleece two yards of different fleece a ruler (optional) I would recommend only using fleece to make this type of blanket. Fabric stores have a huge assortment of colors/designs to pick from, just make sure that you get two pieces of the same size. I'm on the taller side so I usually get two and a half yards unless I'm making the blanket for a baby or puppy. My friend is 6'7" and his blanket is three yards - fits him just fine! Again, it's completely up to you. For an example - since I wanted my friend's blanket three yards, I ended up with six yards of material total, because three yards of one design and three yards of another. You start out by laying the fleece down on a surface large enough for the fabric to be flat all of the way around with enough room for you to squeeze in to cut. Make sure the pieces are lined up one on top of the other. If one piece of fleece is longer than the other, simply trim the extra material off. Once the fabric is flat, start at one corner of the fleece. From the edge of the corner, go down three inches. At that spot, cut into the blanket three inches. Go back to the edge of the corner and do the same on the other side. You now have an inverted corner and a square piece of fabric that you can either put into your scrap pile or...
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... MGM 350 Production Schedule and loom assignment Decision Variable X1: Yards of fabric 1 on dobbie loom X2: Yards of fabric 2 on dobbie loom X3: Yards of fabric 3 on dobbie loom X4: Yards of fabric 4 on dobbie loom X5: Yards of fabric 5 on dobbie loom X6: Yards of fabric 3 on regular loom X7: Yards of fabric 4 on regular loom X8: Yards of fabric 5 on regular loom X9: Yards of fabric 1 purchased X10: Yards of fabric 2 purchased X11: Yards of fabric 3 purchased X12: Yards of fabric 4 purchased X13: Yards of fabric 5 purchased Profit Contribution per yard |Fabric |Manufacturing (Selling-Variable) |Purchasing (Selling-Purchasing) | |1 |0.33 (0.99-0.66) |0.19 (0.99-0.8) | |2 |0.31 (0.86-0.55) |0.16 (0.86-0.7) | |3 |0.61 (1.1-0.49) |0.5 (1.1-0.6) | |4 |0.73 (1.24-0.51) |0.54 (1.24-0.7) | |5 |0.2 (0.7-0.5) |0 (0.7-0.7) | Working Hour Dobbie: 8*24*30=5760 hours Regular: 30*24*30=21600 hours Hour per yard |Fabric |Dobbie |Regular | |1 |1/4...
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...400 Minimum Desired Cash Balance 10,000 Cash Surplus or (Deficit) $20,400 MEANING OF SALES BUDGET:The sales budgets the most important functional budget. The forecasted quantities of sales and value of sales are presented in this budget. TABLE 1 — SALES FORECAST Product Volume Price Total Sales Lace Shoes 16,000 $ 45.00 $ 720,000 MEANING OF PRODUCTION BUDGET:It is a plan of forecast of the output of the business divided into various products. TABLE-2PRODUCTION BUDGET Planned Sales (table 1) 16,000 Desired Ending Inventory 1,500 Total Units 17,500 Less Beginning Inventory (3,000) Planned Production 14,500 TABLE 3 — MATERIALS BUDGET Lace Shoes require .25 square yards of leather and leather is estimated to costs $ 5.00 per yard next year....
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...= quantity manufactured of fabric 4 = x4d + x4r x5m = quantity manufactured of fabric 5 = x5d + x5r x1p = quantity purchased of fabric 1 = D1 – x1m x2p = quantity purchased of fabric 2 = D2 – x2m x3p = quantity purchased of fabric 3 = D3 – x3m x4p = quantity purchased of fabric 4 = D4 – x4m x5p = quantity purchased of fabric 5 = D5 – x5m P1 = profit from fabric 1 = D1*s1 – xm1*v1 – xp1*p1 P2 to P5 are defined similarly P = P1 + P2 + P3 + P4 + P5 Tda = time available on 8 dobbie looms in a month = 8*24*30 = 5760 hours Tra = time available on 30 regular looms in a month = 30*24*30 = 21600 hours m1d = production rate of fabric 1 on dobbie looms = 4.63 yards/hour m2d = 4.63 yards/hour m3d = 5.23 yards/hour m4d = 5.23 yards/hour m5d = 4.17 yards/hour m3r = 5.23 yards/hour m4r = 5.23 yards/hour...
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...Last Modified: 06/11/09 Pre-Algebra Practice Exam This test is designed to be used with a Scantron form. Please fill out the information section of the form with your name, subject, “Practice Final” for “Test No.,” date, and section number (in the box marked “Period”). Circle the letter on the test paper that corresponds to the correct answer and fill in the appropriate space on the Scantron form with a Number 2 pencil. Be sure to fill in only one answer per question and to fully erase any changes. Also, be sure that you are marking your answer next to the correct question number. Evaluate the expressions for the given values of the variables for problems 1 – 3. 1. [pic] When x = –2, y = 3, and z = –2 a) –6.5 b) 2.5 c) 4 d) –6 2. [pic] When r = 2, s = –3 , and t = –1 a) –32 b) –24 c) 32 d) 18 3. [pic] When d = 3, e = 7, and f = 10 a) 9 b) 27 c) 47 d) 12 Divide: 4. [pic] a)[pic] b)[pic][pic] c) [pic] d) [pic] Simplify problems 5-7: 5. [pic] a) [pic] b) [pic] c) [pic] d) [pic] 6. [pic] a) [pic] b) [pic] c) [pic] d)[pic] 7. [pic] a) [pic] b) [pic] c) [pic] d) [pic] Simplify problems 8 – 16: 8. [pic] a) 4 b) 8 c) –2 d) –8 9. [pic] a) 64 b) 3 c) –41 d)...
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...CMIS102 Homework Assignment 1 (Worth 13% of your grade) Student Name: Angelica Hines Class/Section: CMIS 102.1202.7983 Professor Name: Ronald McFarland Assignment due date: 04/01/2012 Problem definition: Calculate the usable area in square feet of house. Assume that the house has a maximum of four rooms, and that each room is rectangular. A. Problem Analysis – Following the directions in the assignment, clearly write up your problem analysis in this section. In this program the overall goal is to obtain the usable area in square feet in a house. The results or overall goal would be considered the required output. To obtain the required output we would need the necessary input. The necessary information regarding the house is that it contains a maximum of four rooms that are rectangular in shape. I will obtain the required output from the given input by multiplying length x width to find the number of square feet in each rectangular room. Once the combined square footage of each room is determined this will give me the amount of usable living space. We would need to know each room length and width, then calculate each rooms area and then find the sum of all four rooms. Area of Room 1= Length1 x Width1 Area of Room 2= Length2 x Width2 Area of Room 3= Length3 x Width3 Area of Room 4= Length4 x Width4 Area of Room 1 + Room 2 + Room 3 =Room 4 = Total Square footage B. Program Design – Following the directions in the assignment, clearly...
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...| Christine | 3 | 24.98 | 9.9cm. | | Average: | 75.98 ÷ 3 = 25.32 | 29.45 ÷ 3 = 9.82 | %error=Exp. Value-Accepted ValueAccepted Value*100 Experimental value: 1 inch = 2.5 cm. Accepted value = 1 inch. = 2.54 cm. %error=2.54-2.52.5*100=7.2% Experimental value: 1 inch =26.8cm (meter stick) Accepted Value = 25.0 cm %error=26.8-2525*100=4% IV. Conclusion * The Metric system is based on increments of the number 10 in both volume and linear measurements. The units of linear measure are: Kilometer - 1,000; hectometer - 100; decimeter - 10; base - 1; decimeter - .1; centimeter - .01; millimeter - .001. While The English system of linear measurement is based on inches, feet, yards; 12 inches in a foot, 3 feet in a yard, 5,280 feet in a mile, etc. V. Post- Laboratory Questions 1. Discuss the merits of the metric and English systems of measurements. * In metric the measurements will be easier because of it is multiples of 10. 2. Why are several observations taken for each measurement? * The more trials would take, the more accurate it will be measure. 3. Is it advisable to start measurements at a mark other than the end of a foot rule or a meter stick? * It is a good idea to start measuring from the 1 cm or the 10 cm mark on a meter stick since the ends of the...
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...Wood model rough estimates 2x2x3 ft Outer walls (2) 2'x2' = 8 sq ft; two 24”x 24” pieces (2) 3'x2' = 12 sq ft, two 36” x 24” pieces For siding, we can use 1/4”, 3/8”, 1/2”, 3/4”inch Baltic birch plywood. Minimum should be 3/8” for structural integrity. Plywood is sold in 24” x 48” sheets, so ideally we would have to buy 3 sheets for the outer walls. Framing Plywood starts to chip/splinter when cut in small pieces, so it is preferable to use hardwood in the framing. Framing consists of four rectangles with supporting vertical braces. Also, the edges of plywood aren't really aesthetically pleasing. Given the size of the model, the beams and studs should be at least 1/2” inch thick. If we were to choose 3/4” inch stock, the width of each beam can be 1 – 1 ¼ inches (as to scale with real life lumber sizes) Assuming 1 inch width per piece and 3/4” stock: 1” x 36”; Lengthwise beams 1” x 22 1/2”; Vertical beams Assuming that there is a 4 inch gap between each support stud: Rough calculations, will refine when making designs Estimated 6 studs for front wall at 22 1/2” length 1” x 22 1/2” Side wall studs: (4) 1” x 22” lengthwise beams (6 or 8) 1” x 22.5” studs (approx 3 studs per side wall) Total ~(1) 36” x 24” sheet 4” x 36” piece Problem: hardwood isn't sold in 24 x 36 sheets, need to visit store to see actual dimensions Base flooring: (1) 24” x 36” sheet of...
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...Case 5-1 Let There Be Light Jul. 24 3 Packaging Information: Style A Style B Style C Manuf. Cost (Per Piece) 4.00$ 5.00$ 6.00$ Packaging Cost (Each) 0.60$ 2.00$ 3.00$ Package Size 12 by 12 by 12 Inches 12 by 12 by 48 Inches 12 by 12by 50 Inches Number of Pieces Per Pack 1 6 10 Package Weight ( Pounds) 10 62 101 Some Important Rules: 1 Foot = 12 Inches 1 ton = 2000 lbs. (Pounds) Cubic Feet = Length X Width X Height Case 5-1 Let There Be Light Jul. 24 4 Case Answers Q1: How many styles A shades can be loaded into an intermodal container? Since; the intermodal container Size = 8 feet wide by 8.5 feet high by 40 feet Long Then let’s turn these measurement into Cubic feet ; if we calculated them as they are 8 * 8.5 * 40 we will get 2720 cubic feet but we will ignore the 0.5 ( 6 inches area ) of the 8.5 height as they are not used since the normal package is of size 12 by 12 by 12 inches. So; the intermodal container Size in Cubic feet = 2560 1 Then we have to calculate the total size of one package of shades from style A; this will require the conversion of the given measurements into feet & then to Cubic feet to unify the units. So; 12 by 12 by 12 inches in feet = 12/12 by 12/12 by 12/12 feet = 1 by 1 by 1 feet Then convert these measurements into Cubic feet. So the package size of style A in cubic feet= 1 * 1 * 1 = 1 (referring to some important...
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...<Name> Intro to Problem Solving and Algorithm Design CMIS 102 Professor March 30, 2015 My House Room 1 Length: 25’ Width: 17’ | Room 2 Length: 23’ Width: 11’ | | Room 4 Length: 23’ Width: 15’ | Room 3 Length: 25’ Width: 12’ | | Program Description * To identify the total square footage of the entire house by using mathematical equation and creating a C++ program to run the equation showing the formula and total area. Analysis * First thing is to identify the dimensions of each room and add those dimensions to get the total square footage of the house. * Variables: * L = Length * W = Width * R1 = Room 1 * R2 = Room 2 * R3 = Room 3 * R4 = Room4 * Formula: * Dimension – L x W = Room Area (sq. ft.) * Total Square Footage – R1+R2+R3+R4 = House Area (sq. ft.) Test Plan Test Case # | Input | Expected Output | Room 1 | Length: 25’ x Width: 17’ | 425 square feet | Room 2 | Length: 23’ x Width: 11’ | 253 square feet | Room 3 | Length: 25’ x Width: 12’ | 300 square feet | Room 4 | Length: 23’ x Width: 15’ | 345 square feet | Entire House | Total Square Footage = 1323 square feet | Pseudocode #include <stdio.h> int main () { /* variable definition: */ int a, b, c, d, e, f, g, h, i, j, k, l; float m,n,o,p,q; /* variable initialization */ a = 25; b = 17; c = a * b; d = 23; ...
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