...Acceleration Due to Gravity Tushar Agarwal 17st November 2014 Aim-In this experiment I will be calculating the value of gravity by the drop of the ball. I will be measuring the distance and finding out the time . Distance will be changed however the size of the ball and the type of the ball will remain constant , The time will be then give me the value of gravity by the suvat equation ,where acceleration will be the subject . Background Knowledge.For an object to move, a force that is greater than its opposite force needs to act upon an object. Force =Mxa where in this case at least acceleration is due tp gravity . Every falling object accelerates at a constant rate and this happens simply due to the force of gravity ,so mathematically the distance “s” that the object is travelling is half the acceleration times of time squared additional to the initial speed and time . Now , We are going to make a the subject of the equation .After making a the subject of the equation we find out that the acceleration due to gravity is twice the distance of Time Squared will equal to acceleration due to gravity . The answer should be somewhere close to 9.81m/s-2 Time (m/s) Distance(m) The graph above shows the relationship between the two variables .In this experiment distance is the independent variable and Dependent variable is time . As Distance increases time will...
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...Acceleration Due to Gravity Introduction In this lab you will measure the acceleration due to gravity near the earth’s surface with two experiments: first, by determining the time for a steel ball to fall a known vertical distance (free fall), and then second, by measuring the velocity of a cart at various points as it glides down a slightly inclined and nearly frictionless air track (slow fall). Equipment Part 1: Free-Fall • Free-fall apparatus (steel plate, drop mechanism) • Electronic Timer • Steel Ball Part 2: Slow-Fall • Air Track • Electronic Timer (may be different brand/model than in Part 1) • Gliding Car • Laser Photogate Background: Free Fall Acceleration Under the constant acceleration of gravity near the Earth’s surface, g, the vertical position, y, of a falling object is related to the time it has fallen by 1 y = y 0 + v 0 t " gt 2 2 where y0 and v0 are the initial position and velocity, respectively. The distance fallen after a time, t, has elapsed is: ! 1 y 0 " y = gt 2 " v 0 t 2 If you release the object from rest, v0 = 0, the equation simplifies to ! y0 " y = 1 2 gt 2 By varying the distance the ball drops and measuring the corresponding transit times, we can determine the acceleration of gravity from a best fit line to a linear graph of the experimental data. ! ! Procedure: Free-Fall Acceleration A diagram of the experimental apparatus is shown in Figure 1. When the ball loses contact with the release mechanism, the timer starts counting. It stops...
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...Motion of Freely Falling Objects Objectives: * To study the motion of free falling objects * To determine the acceleration due to gravity, g. * To derive quantities from the slope and intercept of graphs * To determine if the motion of a falling object changes by varying its mass Theory: The free fall is a known example or the most common example of a uniformly accelerated movement, with an acceleration a = -9.8m/s2 (vertical axis pointing vertically upward). If you choose the vertical axis pointing vertically downward, the acceleration is taken as + 9.8m/s2. The kinematic equations for a rectilinear movement under the acceleration of gravity are the same as any movement with constant acceleration: (1) v = vi - gt velocity as function of time. (2) y - yi = ½(vi + v)t displacement as function of time (3) y - yi = vit - ½gt2 displacement as function of time (4) v2 = vi2 -2g(x - xi) velocity as function of displacement The sub index i denotes initial quantities, g the gravity acceleration and t, the time. But for this type of motion, the displacement of the object as a function of time is described mathematically as: (5) ∆y=Vot + ½gt2 where Vo is the initial velocity of the object. If object if just drop velocity, Equation (5) becomes (6) ) ∆y=½gt2 Methodology Procedure: * A digital balance was used to measure the masses of the small and big steel balls. ...
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...Report: Acceleration of gravity, g Introduction In this experiment you will be measuring the acceleration of gravity using a pendulum like apparatus. The value of g is an important issue as it forms the basis for many mathematical theories and allows for life to exist on this planet. If we keep in contact with the Earth, ordinary tasks will be very difficult. Establishing due value for the acceleration of gravity allows to utilise many of theories that could allow us to solve the big problems. Everyday life would be difficult if we did not have gravity, we would be constant free fall and stopping us to function as a society. The concept of zero gravity can be seen on the International Space Station (ISS), however theoretically they should be not experiencing as they as still in the Earth's gravity field however as the constantly circling the Earth to stay above the surface this causes a state of free fall allowing for the zero gravity to occur in the ISS. You will be using this setup to calculate the acceleration due to gravity using pendulum motion. The investigation is designed to demonstrate: • Air friction • Pendulum motion • Acceleration due to gravity Historical Context: Gravity has been long-known concept, first conceived Isaac Newton with the famous moment of the apple dropping on his head. With that remarkable accident, he derived the law of universal gravitational attraction. F =G ( m1 m2 ) d 2 F = Attraction force between two objects (N) G = Universal Gravitational...
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...the objects fall at the same rate? * What if the objects are different sizes, does that make a difference? Questions: 1. The acceleration due to gravity calculated this way works well for objects near the Earth’s surface. How would you have to change the above equation if the object was 100,000 meters above the ground? (Note: this question refers to Newton’s equation for the force of gravity between two objects. How would that change if the radius of the earth or distance were increased by 100,000 meters. To help you answer this question, please review your textbook, chapter 3, Newton’s law of Gravitation section.) F= (6.67 x10-11N.m2/kg2)(m1)(m2) 100,0002 G is inversely proportional to the square of the distance from the center of the earth. 100 km above the earth's surface, g is reduced by a factor [6370/ (6370+100)] ^2 = 0.969 That would make it 9.51 m/s^2 6370 km is the radius of the earth. For questions 2 and 3, please consult the textbook and additional research materials on Newton’s Second Law of Motion. Pay particular attention to mass, gravity, acceleration and how they inter-relate. 2. How does air resistance alter the way we perceive falling objects? As a falling object accelerates through air, its speed increases and air resistance increases. While gravity pulls the object down, we find that air resistance is trying to limit the object's speed. Air resistance reduces the acceleration of a falling object. It would accelerate...
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...problem set 2 Gravity method (due on or before Thursday, February 19, 2015): The following data are collected from a gravity survey over some suspected buried targets. Column 1 shows the observation stations. The first station, situated at latitude 35° S is the reference station, and the other stations are placed successively in the South with distances in meters from the reference station as shown. Column 2 is the elevation in meters of each station with respect to the datum. Finally, column 3 is the measured gravity value at each station in gravity units (g.u.). Note, as we discussed, the measured values are NOT the absolute gravity, but the relative gravity field or the deviations (anomaly) from the mean gravity. Station (distance in m from the reference) Elev (m) Measured Gravity (g.u) 0 160 170.1 200 120 240.1 400 80 340.5 600 30 438.6 800 10 480.4 1000 60 480.2 1200 100 460.4 1400 120 365.7 1600 130 380.8 1800 140 406.3 2000 160 484.7 2200 170 436.7 2400 180 419.3 2600 190 418.7 2800 195 416.9 3000 192 417.8 3200 199 319.7 3600 198 300.3 3800 193 268.8 4000 197 217.5 4200 195 200.2 4400 196 198.7 4600 197 200.2 4800 199 207.1 5000 200 207.2 • Compute the latitude, free-air, and Bouguer corrections to the measured data at each observation point. For Bouguer correction, assume a density of 2.067 g/cm3. Show each correction in separate columns with headings. • Compute the Bouguer gravity anomaly...
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...MAT 117 Week 8 CONCEPT APPLICATION Answer the following questions. Use Equation Editor or MathType when writing mathematical expressions or equations. Points will be deducted if a math editor is not used to properly format your work. First, download and save this file to your hard drive by selecting Save As from the File menu. Save with the filename: yourLastnameFirstnameMat117Week8CA. Click the 3rd column to enter your work, the rows will automatically expand as you enter text. Attach your completed document and post to the Assignments Section. |# | |Show your work and final answer in this column. |- Pts |+ Pts | | | |Include units when applicable. | | | |1 |A plasma TV company determines that its total profit on the production and sale of x TVs is given by: [pic] | |0 |0 | |a |Will the graph of this function open up or down? | | |2 | | |How can you tell by looking at the equation? | | | | |b |As the number of TV’s produced increases, what | | |2 | | |happens with the profit? | ...
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...|European | |curriculum vitae | |format | | | |[pic] | |Personal information | |Name | |[ Surname, other name(s) ] | |Address | |[ House number, street name, postcode, city, country ] | |Telephone | | | |Fax | | | |E-mail | | | |Nationality | | | |Date of birth | |[ Day, month, year ] | |Work experience | |• Dates (from – to) ...
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...1. Introduction Free falling objects are very common around us. Everyone knows , at a same certain height, a stone will fall faster than a leave. There is a common asumption that the phenomenon is due to the gravity force applied on the stone is larger than the force applied on the leave. We will consider during this experiment. 2. Necessary Equipment Equipments/ devices | Quantities | Release unit | 1 | Impact switch | 1 | Universal counter | 1 | Support base | 1 | Right angle clamp | 2 | Plate holder | 1 | Cursors | 1 pair | Meter scale, demo, l = 1000 mm | 1 | Support rod, square, l = 1000 mm | 1 | Connecting cord, l = 1000 mm, red | 2 | Connecting cord, l = 1000 mm, blue | 2 | 3. Preparation and Setting Up The set-up is shown in Fig. 1. Activate the “Timer” operating mode on the universal counter by pressing the FUNCTION button as often as necessary for the LED alongside the “Timer” inscription to light up. Select the trigger type: To adjust the pan, use the adjusting screw under the arrest switch. A downward motion of a few tenths of a millimeter should close the stop circuit. The pan is raised by hand after each single measurement (initial position). For the effective determination of the height of fall using the marking on the release mechanism, the radius of the sphere must be taken into account (diameter 3/4 inch, approx. 19 mm). 4. Experiment Procedure * Set the universal counter. * hold the sphere by...
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...Ball Bearing Drop Lab Bijay Gurung Nathan Wells September 21, 2014 Physics 2425 Purpose: The purpose of this lab is to calculate the gravity constant. Procedure: The materials needed for this experiments are standard mechanism which includes the time calculator, bearing, and a ruler. Student has to measure the distance of mechanism. Further we have to setup the mechanism by placing the bearing ball in the holding mechanism a distance h above the impact sensor. Once the bearing ball is released, an electronic timer will begin and finally halt once the steel ball has hit the impact plate. One student in a group records the time and repeats the trial for fifteen times. The free fall time, t, can then be used along with the distance h to calculate the acceleration of gravity. Theory: After obtaining the data, we have to convert the distance from cm to m. 1 cm=0.01m. The total height from where the bearing was drop is 173.7 cm=1.737m. We can find the acceleration due to gravity or g value by using the formula, g=2h/t^2, where ‘g’ is the acceleration due to gravity, ‘h’ is the height where bearing was drop from, & ‘t’ is time taken by bearing to hit the floor. For example, for the first trial we have the height of 1.737m, and time it takes was 0.5924s. We can calculate the ‘g’ value by, g=2h/t^2 g=2*1.737m/(0.5924s)^2=9.899 m/s^2 We can also use graphic calculator to find the time. In order to find the “g” by using graphic calculator, we have to list...
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...Cover page: Unit 2 Lab 2.1.1 States of Matter . Survey of the Sciences Week 2 Assignment 2 – Lab 2.1.1 – States of Matter Date of assignment: 12/18/2013 Date turned in: 01/15/2014 Liquid at over 650K | Liquid under 650K | The molecules appear to be faster and more spread apart | Molecules are even faster, mostly touching and mostly compact | Gas at over 1540K | Gas at under 300K | Faster and mostly apart and randomly touching | Slower, more clustered and in ring shapes and mostly touching with less space apart | Solid at 350 – 360K and over 600K | Solid at under 10K | Moving from one position to another at accelerated pace but mostly touching at an even faster rate and mostly spread apart | Less movement, but still clustered and connected in ring forms | Solid is at 157K and appears to be moving slower and less close but compact in rings. Liquid is at 328K and appears to be closely bonded but moving around much faster. Gas is at 809K and appears to be moving much faster and occupying more space than solid and liquid. But when the temperature is reduced to about 97K the rate of movement decreases and the molecules get more clustered and compact, the reaction in liquid is almost the same as gas when the temperature is reduced to the same 97K. The reaction in solid liquid and gas stages of water are almost constant at a reduced temperature of 97K. Only the solid state resembles itself in heated and cooled stages. The others have different resemblance. In...
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...SCI109 The Cosmos Activity 3 – Newton’s Second Law and Motion Reference: Go to masteringastronomy.com; click Study Area/Self-guided Tutorial – Motion and Gravity There are two parts for this activity. You will work on both parts described below and also comment on one other student’s work. The first part is to learn how a net force causes acceleration, described by Newton’s second law F = ma. Read the Introduction and Objectives to understand the concept. In Lesson 1, you will see this simulation page: [pic] Play with this simulation by choosing three different masses (AVOID CHOOSING THE SAME MASS USED BY OTHER STUDENTS) . By clicking the button “Push”, you will produce a speed vs time graph (do it for three different masses), and then use F = ma to calculate the acceleration for each mass. Record the mass and acceleration values in the table below: |Mass 1 = 120 |a1 =.83 (100/120) | |Mass 2 = 180 |a2 =.55 (100/180) | |Mass 3 =300 |a3 =.33 (100/300) | Now you should have three straight lines in the graph. Each calculated acceleration should represent the slope of the corresponding line. Take a screen-shot of your graph image and then paste...
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...HIGH JUMP When holding the Olympics on the moon, there are a number of different factors that must be considered. The major one is the fact that the gravity on the moon is one sixth that on Earth. Therefore in the high jump event the results on the moon will be better than the results on Earth. The reasoning behind this is because the acceleration down due to gravity will be less on the moon. On the moon the acceleration is 1.6 m/s2 and the acceleration on the Earth is 9.8 m/s2. A smaller acceleration in the opposing direction of which the jumper is trying to maximize her jump will be beneficial to her results. This is due to the decrease in the pull downwards on the moon compared to the pull downwards on Earth. Since we know the displacement (how high she jumped) on Earth is 2.06 meters, the initial velocity on both the Earth and the moon is 0 m/s2, and the acceleration on Earth is 9.8 m/s2 and on the moon its 1.6 m/s2,, we can determine the velocity on Earth. This value for the velocity will be the same on both the Earth and the moon therefore we have enough information to determine the displacement on the moon. The Olympic record for the women’s high jump on the Earth is 2.06 meters and the Olympic record for the women’s high jump on the moon would be 12.6175 meters. WEIGHTLIFTING When the Olympics are held on the moon and the weightlifting event takes place, the results on the moon will be better than the results on the Earth. This is due to the fact that even though...
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...1. Introduction: In this section (of about an A4 size page, or less, in two to three paragraphs), you will first give a brief highlight of the principal activities of the organization where the project is being carried out; their prime goal; their position today in the particular business or sector; major opportunities and constraints they are facing ; major strengths and weaknesses. Then you will give a one or two sentence statement of what the company desires you to study (or address) in this project, or what they agree to let you study (the broad intent). 2. Project Objectives: In this section, you will delineate, as precisely as possible, the specific objectives of the project, using perhaps bullet style. The stated objectives should be consistent with the “broad intent” mentioned in Sec. The objectives should reflect an underlying principle / concept. 3. Scope: Relative to the objectives stated above, here you would explicitly specify the delimiting aspects, if any, that would define the scope of the current study. For example, if the study concerns “employee motivation,” and if it is agreed that only employees from production functions are to be studied, the scope would be restrictive to all the employees of the production function. If there are more plants than one, and if it is agreed that only a specified plant’s production function employees would be covered, then this would be a restriction. All such aspects would define the specific scope of the project. 4. Methodology:...
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...Objective The first objective of this lab was to determine if the coarse aggregate meets ASTM C33 standards for coarse aggregates. Also this lab was used to determine the specific gravities of the coarse aggregate. Lastly, this lab helped to determine if this coarse aggregate could be used to make a good gravel driveway. Apparatus and Materials 1. Ohaus Heavy Duty Solution Balance, model 1119, property of Bluefield State College. 2. Common sieves: 1 – ½”, 1”, ¾”, #4, #8, including the pan and lid. 3. Peerless Stove and Mfg. Co. oven, #2324DS (Solitest model L-90), property of Bluefield State College. 4. Common gravel aggregate. 5. Common flask. 6. “Bath Scale”, BSC # 18589. Method Sieve Analysis: This lab exercise determined the size of coarse aggregate as it passed through the given sieves resulting in a percent that passed though, and a percent that was isolated on the sieves. Gravel coarse aggregate was obtained and weighed using the Ohaus HD Solution Balance and approximately 1 kg of the gravel aggregate was measured. Sieves were obtained then stacked according to sieve size, from largest screen openings to finest, with the pan on the bottom. The 1kg of coarse aggregate was then poured over the top sieve and the lid was placed on top. The stack of sieves was then shaken by hand to sift the aggregate over the layers of sieves. The lid was removed and the coarse aggregate on each sieve was weighed and the weight was recorded...
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