count < 100 is always true at Point A count < 100 is always false at Point C
3 0
AB
CD
1 3 5 7 9
Pattern C
The program may not stop because of the phenomenon referred to as numerical inaccuracy for operating with floating-point numbers.

The program compiles despite the semicolon (;) on the for loop line, and displays 14.
The for loop in this program is same as for (i = 0; i < 10; i++) { }; System.out.println(i + 4);

add 0.01, 0.02, i is 4 followed by 9 is not prime
The program compiles and runs, but it is not effient and unnecessary to execute the Scanner input = new Scanner(System.in); statement inside the loop. You should move the statement before the loop.

int count = 0; while (count < 10) { System.out.println("Welcome to Java"); count++;
10

int count = 0; while (count++ < 10) { System.out.println("Welcome to Java");
10

int count = 0; do { System.out.println("Welcome to Java"); count++;
} while (count < 10);
10

int count = 0; do { System.out.println("Welcome to Java");
} while (count++ < 10);
11

int count = 0; do { System.out.println("Welcome to Java");
} while (++count < 10);
10

nt count = 0; do { System.out.println("Welcome to Java");
} while (count++ < 9);
System.out.println(count);
10

double sum = 0; for (double d = 0; d < 10;) { d += 0.1; sum += sum + d;
The program compiles and runs fine.

for (int i = 0; i<10; ++i) { sum += i;
}

(II): for (int i = 0; i<10; i++) { sum += i;
Yes
int y = 0; for (int i = 0; i<10; ++i) { y += i;
}
System.out.println(y)45

nt y = 0; for (int i = 0; i<10; ++i) { y += i; undefined for (; ; );
Yes

How many times is the println statement executed? for (int i = 0; i < 10; i++) for (int j = 0; j < i; j++) System.out.println(i * j)
45