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College Algebra

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Submitted By ellojello50
Words 2442
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Unit 7 Test

5/1/15, 4:09 PM

MAT 120.17, Spring 2015

Assessments

Unit 8 Test

Results

Unit 7 Test - Grade Report
Score:

100% (19 of 19 pts)

Submitted:

Apr 19 at 12:43pm
Question 1

Question Grade: 1.0
Weighted Grade: (1/1.0)

If q and f are inverse functions and q(−2) = 8, what is f (9) ?
Your Answer:

cannot be determined

Correct Answer:

cannot be determined

Comment:

If q and f are inverse functions and q(a) = b, then f (b) = a.
However, since 9 is not the given domain value for q, the answer cannot be determined.

Question 2

Question Grade: 1.0
Weighted Grade: (1/1.0)

Choose any false statements regarding the graph.
Select all that apply.
Choice

Selected

Points

The graph is a function.

Yes

+1

The graph is a function that has an inverse function. Yes

+1

The graph is a one-to-one function.

Yes

+1

The inverse of the graph is not a function.

No

The graph passes the horizontal line test.

Yes

+1

The graph passes the vertical line test.

Yes

+1

Number of available correct choices: 5
Comment:

A vertical line can be drawn through the graph intersecting the graph in more than one place, so the graph fails the vertical line test. Therefore, the graph does not represent a function.
A horizontal line can be drawn through the graph intersecting the graph in more than one place. So, the graph fails the horizontal line test. Therefore, the graph is not a one-to-one function and its inverse is not a function

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Unit 7 Test

5/1/15, 4:10 PM

Question 3

Question Grade: 1.0
Weighted Grade: (1/1.0)

If the two functions are inverses, which of the following statements correctly verifies this?
7x+7
f (x) = 11x−7 and g(x) =
7
11
Select all that apply.
Choice

Selected

Points

The graphs of f and g are reflections over the line y = x.
11x−7
7
+7
11x−7 ) = ( 7 ) g(f (x)) = g(
= x
7
11
7x+7
11(
−7
11 )
7x+7
g(f (x)) = g(
) =
= x
11
7
The functions f and g are not inverses.
7 11x−7 +7
11x−7 ) = ( 7 ) f (g(x)) = f (
= x
7
11
7x+7
11(
−7
11 )
7x+7
f (g(x)) = f (
) =
= x
11
7

Yes

+1

Yes

+1

No
No
No
Yes

+1

Number of available correct choices: 3
Comment:

The functions f and g are inverses because
7x+7
11(
−7
7x + 7
7x + 7 − 7
7x
11 ) f (g(x)) = f (
) =
=
=
= x
11
7
7
7 and 11x − 7 g(f (x)) = g(
) =
7

7(

11x−7
+7
7 )
11x − 7 + 7
11x
=
=
= x
11
11
11

and if two functions are inverses of each other, they are reflections over the line y = x.

Question 4

Question Grade: 1.0
Weighted Grade: (1/1.0)

Identify the graph of the inverse function of f, if it exists.

Your Answer:

The graph is a function that does not have an inverse function.

Correct Answer:

The graph is a function that does not have an inverse function.

Comment:

Any vertical line will intersect the graph at only one place, so the graph passes the
Vertical Line Test and is therefore a function.
A horizontal line can be drawn through the graph intersecting the graph in more than one place. So, the graph fails the Horizontal Line Test. Therefore, the graph is not a one-toone function and it does not have an inverse function.

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Unit 7 Test

5/1/15, 4:10 PM

Question 5

Question Grade: 1.0
Weighted Grade: (1/1.0)

Your response

Correct response

Find the inverse of f (x) =

8+5x
, if it exists.
7
Enter any noninteger coefficient as a fraction. If

Find the inverse of f (x) =

there is no inverse, enter "none". f −1 (x) = 7x−8 (100%)

If there is no inverse, enter "none". f −1 (x) = 7x−8

5

Comment:

8+5x
, if it exists.
7
Enter any noninteger coefficient as a fraction.

5

Replace f (x) with y. f (x) =

8 + 5x
8 + 5x
⇒ y =
7
7

Interchange x and y. y =

8 + 5x
8 + 5y
⇒ x =
7
7

Solve for y. x = 8+5y
7
7x

= 8 + 5y

7x − 8

= 5y

7x−8
=
5
−1 (x) = 7x−8 .
Thus, f
5
y

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Unit 7 Test

5/1/15, 4:10 PM

Question 6

Question Grade: 1.0
Weighted Grade: (1/1.0)

‾‾‾‾‾‾
Find the inverse of f (x) = √4x−16 , if it exists.
Enter any noninteger coefficient as a fraction. If there is no inverse, enter "none".

Your response

Correct response

The inverse function is

(a)

The inverse function is

x 2 +16 f −1 (x) =
(100%).
4
(b)

f −1 (x) =

x 2 +16
.
4

The domain of the inverse is given by:
Correct
Your Answer:

x ≥ 0

Correct Answer: x ≥ 0
Comments:
f is a square root function. Therefore, using the domain x ≥ 4, , the graph passes the horizontal line test, so the function is one-to-one and has an inverse function.
−1
The range of f is y ≥ 0, so the domain of f must be x ≥ 0.
Replace f (x) with y.
4x−16
4x−16 f (x) = √‾‾‾‾‾‾ ⇒ y = √‾‾‾‾‾‾
Interchange x and y .
‾‾‾‾‾‾
y = √4x−16 ⇒ x = √4y−16
‾‾‾‾‾‾
Square both sides and solve for y.
‾‾‾‾‾‾
x
= √4y−16 x2 = 4y−16

x 2 +16 = y
4
x 2 +16
, x ≥ 0.
Thus, f −1 (x) =
4

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Page 4 of 11

Unit 7 Test

5/1/15, 4:10 PM

Question 7

Question Grade: 1.0
Weighted Grade: (1/1.0)

Which of the following are exponential functions?
Select all that apply.
Choice

Selected

f (x) = 1x f (x) = π 6x

f (x) = −(5)x
6 x f (x) = ( 5 ) f (x) = x 5 f (x) = 54x

f (x) = 0.8x+2 f (x) = (−5)x

Points

No
Yes

+1

Yes

+1

Yes

+1

No
Yes

+1

Yes

+1

No

Number of available correct choices: 5
Comment:

By the definition of exponential function, an exponential function must include a power of the x form b where x is the variable b is the base where b > 0 and b ≠ 1.
The power itself or the variable exponent may have a coefficient and there may be a constant
6 x
4x
x
6x
term. Therefore, f (x) = 5 , f (x) = ( 5 ) , f (x) = −(5) , f (x) = π , and f (x) = 0.8x+2 are exponential functions. f (x) = x 5 , is not an exponential function because the variable is not in the exponent. f (x) = (−5)x , is not an exponential function because the base is negative. f (x) = 1x , is not an exponential function because the base is 1.

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Unit 7 Test

5/1/15, 4:10 PM

Question 8

Question Grade: 1.0

Your response

Correct response

Evaluate the exponential function
1 −x f (x) = ( ) .
12
Enter the exact answer. Do not enter a decimal approximation. Enter any radical, fractional terms, or factors in simplest form.

Evaluate the exponential function
1 −x f (x) = ( ) .
12
Enter the exact answer. Do not enter a decimal approximation. Enter any radical, fractional terms, or factors in simplest form.

f (3) = 1728 (33%)

Weighted Grade: (1/1.0)

f (3) = 1728

1 f (−3) =
(33%)
1728
1) = 2 3 f( √‾ (33%)
2
Comment:

1 f (−3) =
1728
‾ f ( 1 ) = 2 √3
2

Note that f (x) =

1 −x
−1 −x
(−1)(−x)
x
= (12 )
= (12)
= 12
( 12 )

therefore, f (3) = 123 = 1,728
1
1 f (−3) = 12−3 =
=
1,728
123
1
1
f ( ) = 12 2 = √12 = 2√3
‾‾

2

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Unit 7 Test

5/1/15, 4:10 PM

Question 9

Question Grade: 1.0

Your response

Correct response

How much should be deposited in an account paying 6.5% interest, compounded quarterly, in order to have a balance of $ 9,000 after 8 years

How much should be deposited in an account paying 6.5% interest, compounded quarterly, in order to have a balance of $ 9,000 after 8 years

and 3 months?
Enter the answer in dollars and cents, and round to the nearest cent, if needed. Do not include the dollar sign. For example, if the answer is

and 3 months?
Enter the answer in dollars and cents, and round to the nearest cent, if needed. Do not include the dollar sign. For example, if the

$0.61, only the number 0.61 should be entered.
Principal ≈ $ 5287.18 (100%)

Weighted Grade: (1/1.0)

answer is $0.61, only the number 0.61 should be entered.
Principal ≈ $ 5287.18

Comment:

r mt
Identify the values of the variables in the compound interest formula, A = P(1 + m ) .
The original amount deposited,P is unknown.
The interest rate is 6.5 %, so
The interest is compounded quarterly, so (because the interest is compounded times per year). The balance is calculated after years and months, so
Substitute these values into the formula yields
Do not round until the final step in the calculations.
=
=

Solve for P.

= 5,287.179751

Round to the nearest cent.

= 5,287.18
The amount deposited should be $

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Unit 7 Test

5/1/15, 4:10 PM

Question 10

Question Grade: 1.0

Your response

Correct response

Complete the table for the function
If the answer is not an integer, enter it either as a fraction or as a decimal rounded to the nearest hundredth, if needed.

Weighted Grade: (1/1.0)

Complete the table for the function
If the answer is not an integer, enter it either as a fraction or as a decimal rounded to the nearest hundredth, if needed.

36.95 (20%)

36.95

13.59 (20%)

13.59

5 (20%)

5

1.84 (20%)

1.84

0.68 (20%)

0.68

Comment:

Use a calculator to evaluate the function.

Question 11

Question Grade: 1.0

Your response

Correct response

A certain type of bacteria grows according to the function where is the number of bacteria present after hours.
Find the number of bacteria present after hours.
Enter the answer as an integer. Round to the

A certain type of bacteria grows according to the function where is the number of bacteria present after hours.
Find the number of bacteria present after hours.
Enter the answer as an integer. Round to the

nearest whole unit, if needed.

nearest whole unit, if needed.

The number of bacteria is 4123 (100%).

Weighted Grade: (1/1.0)

The number of bacteria is 4123
4123.

Comment:

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Unit 7 Test

5/1/15, 4:10 PM

Question 12

Question Grade: 1.0

Your response

Correct response

Find the value of

Find the value of

= 4 (100%)

Weighted Grade: (1/1.0)

=4

Comment:

The value of is the power to which is raised to get Since

Question 13

Question Grade: 1.0
Weighted Grade: (1/1.0)

Write in logarithmic form.
Your Answer:
Correct Answer:
Comment:

The power‘s base is and the exponent is so , and

Question 14

Question Grade: 1.0
Weighted Grade: (1/1.0)

Write in exponential form.
Your Answer:
Correct Answer:
Comment:

The log‘s base is and the value of the log is so , and
Confirm by evaluating the power.

Question 15

Question Grade: 1.0

Your response

Correct response

Find the value of
If the answer is not an integer, enter it as a fraction. Find the value of
If the answer is not an integer, enter it as a fraction. = 1/2 (100%)

Weighted Grade: (1/1.0)

= 1/2

Comment:

The value of is the power to which is raised to get
Remember that in a rational exponent, the denominator is the index of the radical.
So,

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Page 9 of 11

Unit 7 Test

5/1/15, 4:10 PM

Question 16

Question Grade: 1.0

Your response

Correct response

Find the value of .

Find the value of .

= 0 (100%)

Weighted Grade: (1/1.0)

=0

Comment:

By the property, the log base of is equal to Therefore, .

Question 17

Question Grade: 1.0

Your response

Correct response

Evaluate without using a calculator.
If the answer is not an integer, enter it as a

Evaluate without using a calculator.
If the answer is not an integer, enter it as a

fraction.

fraction.

= 4/3 (100%)

Weighted Grade: (1/1.0)

= 4/3

Comment:

Since

Question 18

Question Grade: 1.0

Your response

Correct response

Use a calculator to evaluate (log 4)÷(ln 2).
If the answer is not an integer, enter it as a decimal rounded to the nearest hundredth, if needed. Use a calculator to evaluate (log 4)÷(ln 2).
If the answer is not an integer, enter it as a decimal rounded to the nearest hundredth, if needed. (log 4)÷(ln 2) = 0.87 (100%)

Weighted Grade: (1/1.0)

(log 4)÷(ln 2) = 0.87

Comment:

Keystrokes: LOG 4 ÷ LN 2 ENTER

Question 19

Question Grade: 1.0

Your response

Correct response

The Richter scale magnitude, , of an earthquake of intensity is defined as where is a small threshold intensity. Find the magnitude of an earthquake with intensity .
If the answer is not an integer, enter it as a

The Richter scale magnitude, , of an earthquake of intensity is defined as where is a small threshold intensity. Find the magnitude of an earthquake with intensity .
If the answer is not an integer, enter it as a

decimal rounded to the nearest hundredth, if needed. decimal rounded to the nearest hundredth, if needed. magnitude 7.88 (100%)

Weighted Grade: (1/1.0)

magnitude 7.88

Comment:

Substitute into the formula for and simplify.

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Unit 7 Test

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